Having from address in PHP form the senders address
I have this simple form code here
<?php
$EmailFrom = "form@form.com";
$EmailTo = "s@outlook.com";
$Subject = "Form";
$Name = Trim(stripslashes($_POST['Name']));
$Budget = Trim(stripslashes($_POST['Budget']));
$Email = Trim(stripslashes($_POST['Email']));
$Message = Trim(stripslashes($_POST['Message']));
// validation
$validationOK=true;
if (!$validationOK) {
print "<meta http-equiv="refresh" content="0;URL=error.htm">";
exit;
}
// prepare email body text
$Body = "";
$Body .= "Name: ";
$Body .= $Name;
$Body .= "n";
$Body .= "Budget: ";
$Body .= $Budget;
$Body .= "n";
$Body .= "Email: ";
$Body .= $Email;
$Body .= "n";
$Body .= "Message: ";
$Body .= $Message;
$Body .= "n";
// send email
$success = mail($EmailTo, $Subject, $Body, "From: <$EmailFrom>");
// redirect to success page
if ($success){
print "<meta http-equiv="refresh" content="0;URL=contactthanks.php">";
}
else{
print "<meta http-equiv="refresh" content="0;URL=error.htm">";
}
?>
And I was wondering how to make the from address in the top the same as the one submitted.
javascript php html forms
add a comment |
I have this simple form code here
<?php
$EmailFrom = "form@form.com";
$EmailTo = "s@outlook.com";
$Subject = "Form";
$Name = Trim(stripslashes($_POST['Name']));
$Budget = Trim(stripslashes($_POST['Budget']));
$Email = Trim(stripslashes($_POST['Email']));
$Message = Trim(stripslashes($_POST['Message']));
// validation
$validationOK=true;
if (!$validationOK) {
print "<meta http-equiv="refresh" content="0;URL=error.htm">";
exit;
}
// prepare email body text
$Body = "";
$Body .= "Name: ";
$Body .= $Name;
$Body .= "n";
$Body .= "Budget: ";
$Body .= $Budget;
$Body .= "n";
$Body .= "Email: ";
$Body .= $Email;
$Body .= "n";
$Body .= "Message: ";
$Body .= $Message;
$Body .= "n";
// send email
$success = mail($EmailTo, $Subject, $Body, "From: <$EmailFrom>");
// redirect to success page
if ($success){
print "<meta http-equiv="refresh" content="0;URL=contactthanks.php">";
}
else{
print "<meta http-equiv="refresh" content="0;URL=error.htm">";
}
?>
And I was wondering how to make the from address in the top the same as the one submitted.
javascript php html forms
Possible duplicate of PHP mail function 'from' address
– Francesco de Guytenaere
Feb 24 '16 at 9:03
add a comment |
I have this simple form code here
<?php
$EmailFrom = "form@form.com";
$EmailTo = "s@outlook.com";
$Subject = "Form";
$Name = Trim(stripslashes($_POST['Name']));
$Budget = Trim(stripslashes($_POST['Budget']));
$Email = Trim(stripslashes($_POST['Email']));
$Message = Trim(stripslashes($_POST['Message']));
// validation
$validationOK=true;
if (!$validationOK) {
print "<meta http-equiv="refresh" content="0;URL=error.htm">";
exit;
}
// prepare email body text
$Body = "";
$Body .= "Name: ";
$Body .= $Name;
$Body .= "n";
$Body .= "Budget: ";
$Body .= $Budget;
$Body .= "n";
$Body .= "Email: ";
$Body .= $Email;
$Body .= "n";
$Body .= "Message: ";
$Body .= $Message;
$Body .= "n";
// send email
$success = mail($EmailTo, $Subject, $Body, "From: <$EmailFrom>");
// redirect to success page
if ($success){
print "<meta http-equiv="refresh" content="0;URL=contactthanks.php">";
}
else{
print "<meta http-equiv="refresh" content="0;URL=error.htm">";
}
?>
And I was wondering how to make the from address in the top the same as the one submitted.
javascript php html forms
I have this simple form code here
<?php
$EmailFrom = "form@form.com";
$EmailTo = "s@outlook.com";
$Subject = "Form";
$Name = Trim(stripslashes($_POST['Name']));
$Budget = Trim(stripslashes($_POST['Budget']));
$Email = Trim(stripslashes($_POST['Email']));
$Message = Trim(stripslashes($_POST['Message']));
// validation
$validationOK=true;
if (!$validationOK) {
print "<meta http-equiv="refresh" content="0;URL=error.htm">";
exit;
}
// prepare email body text
$Body = "";
$Body .= "Name: ";
$Body .= $Name;
$Body .= "n";
$Body .= "Budget: ";
$Body .= $Budget;
$Body .= "n";
$Body .= "Email: ";
$Body .= $Email;
$Body .= "n";
$Body .= "Message: ";
$Body .= $Message;
$Body .= "n";
// send email
$success = mail($EmailTo, $Subject, $Body, "From: <$EmailFrom>");
// redirect to success page
if ($success){
print "<meta http-equiv="refresh" content="0;URL=contactthanks.php">";
}
else{
print "<meta http-equiv="refresh" content="0;URL=error.htm">";
}
?>
And I was wondering how to make the from address in the top the same as the one submitted.
javascript php html forms
javascript php html forms
edited Nov 12 '18 at 15:48
Cœur
17.5k9104145
17.5k9104145
asked Feb 24 '16 at 8:44
NicoleNicole
132
132
Possible duplicate of PHP mail function 'from' address
– Francesco de Guytenaere
Feb 24 '16 at 9:03
add a comment |
Possible duplicate of PHP mail function 'from' address
– Francesco de Guytenaere
Feb 24 '16 at 9:03
Possible duplicate of PHP mail function 'from' address
– Francesco de Guytenaere
Feb 24 '16 at 9:03
Possible duplicate of PHP mail function 'from' address
– Francesco de Guytenaere
Feb 24 '16 at 9:03
add a comment |
1 Answer
1
active
oldest
votes
If I understand correctly, you can do away entirely with this variable:
$EmailFrom = "form@form.com";
And this revised mail()
function should do what you're asking:
// send email
$success = mail($EmailTo, $Subject, $Body, "From: " . $Email . "rn");
Note I've used the following variable you've already declared:
$Email = Trim(stripslashes($_POST['Email']));
Thank you so much!!!
– Nicole
Feb 24 '16 at 9:22
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f35597232%2fhaving-from-address-in-php-form-the-senders-address%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If I understand correctly, you can do away entirely with this variable:
$EmailFrom = "form@form.com";
And this revised mail()
function should do what you're asking:
// send email
$success = mail($EmailTo, $Subject, $Body, "From: " . $Email . "rn");
Note I've used the following variable you've already declared:
$Email = Trim(stripslashes($_POST['Email']));
Thank you so much!!!
– Nicole
Feb 24 '16 at 9:22
add a comment |
If I understand correctly, you can do away entirely with this variable:
$EmailFrom = "form@form.com";
And this revised mail()
function should do what you're asking:
// send email
$success = mail($EmailTo, $Subject, $Body, "From: " . $Email . "rn");
Note I've used the following variable you've already declared:
$Email = Trim(stripslashes($_POST['Email']));
Thank you so much!!!
– Nicole
Feb 24 '16 at 9:22
add a comment |
If I understand correctly, you can do away entirely with this variable:
$EmailFrom = "form@form.com";
And this revised mail()
function should do what you're asking:
// send email
$success = mail($EmailTo, $Subject, $Body, "From: " . $Email . "rn");
Note I've used the following variable you've already declared:
$Email = Trim(stripslashes($_POST['Email']));
If I understand correctly, you can do away entirely with this variable:
$EmailFrom = "form@form.com";
And this revised mail()
function should do what you're asking:
// send email
$success = mail($EmailTo, $Subject, $Body, "From: " . $Email . "rn");
Note I've used the following variable you've already declared:
$Email = Trim(stripslashes($_POST['Email']));
answered Feb 24 '16 at 9:02
David WilkinsonDavid Wilkinson
4,38511128
4,38511128
Thank you so much!!!
– Nicole
Feb 24 '16 at 9:22
add a comment |
Thank you so much!!!
– Nicole
Feb 24 '16 at 9:22
Thank you so much!!!
– Nicole
Feb 24 '16 at 9:22
Thank you so much!!!
– Nicole
Feb 24 '16 at 9:22
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f35597232%2fhaving-from-address-in-php-form-the-senders-address%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Possible duplicate of PHP mail function 'from' address
– Francesco de Guytenaere
Feb 24 '16 at 9:03