jQuery append on contenteditable adds invisible characters
I have an SQLite3 SQL prompt, to which one can append table/column name by clicking it in the list on the right.
Well, that's what I would like it to do. I've been forced to disable this feature because of an error I don't understand.
If I enter the request manually, everything works. But if I use the button to add `table`, I get this error from SQLite :
in "SELECT * FROM `table`": near "FROM ": syntax error
This error does not even happen on the appended text !!
However the input is visually the same. On the console and in the HTML tree (the inspector) too. No special character is shown.
I could check there is an invisible character thanks to a little dropdown that allows me to access previous SQL inputs. The error remains after accessing the faulty input and run it again.
Here is the HTML and Javascript so you can see what I want to do and that there's no visible difference :
$('i').click(function() {
$('#sql-input').append('`' + $(this).data('value') + '`');
});
$('#sql-form').submit(function(e) {
e.preventDefault();
console.log($("#sql-input").text());
/*
Here is the ajax request to execute the SQL
*/
});<script src="http://code.jquery.com/jquery-1.12.4.min.js"></script>
<form id="sql-form" action="" method="post">
<label for="sql-input">SQL PROMPT</label>
<br />
<div id="sql-input" style="height: 80px; width: 150px; border: solid 1px black;" contenteditable></div>
<br />
<input type="submit" value="send" />
<button type="button" onclick="console.clear();">clear console</button>
</form>
<div class="list">
<ul style="cursor: pointer;">
<li><i data-value="table1">table1</i></li>
<li><i data-value="col1_1">col1_1</i></li>
<li><i data-value="col2_1">col2_1</i></li>
<li><i data-value="col3_1">col3_1</i></li>
<li><i data-value="table1">table2</i></li>
<li><i data-value="col1_2">col1_2</i></li>
</ul>
</div>Something strange, though, is that If I touch the JQuery-inputted text, the error disappears.
What I already tried :
removing the quote marks : `table` => table
using $().text() or $().html() instead of $().append()
jquery html sqlite3 append
edited Nov 12 '18 at 15:28
wanttobeprofessional
98131223
asked Nov 12 '18 at 14:58
Jean-Marc ZimmerJean-Marc Zimmer
38414
add a comment |
I have an SQLite3 SQL prompt, to which one can append table/column name by clicking it in the list on the right.
Well, that's what I would like it to do. I've been forced to disable this feature because of an error I don't understand.
If I enter the request manually, everything works. But if I use the button to add `table`, I get this error from SQLite :
in "SELECT * FROM `table`": near "FROM ": syntax error
This error does not even happen on the appended text !!
However the input is visually the same. On the console and in the HTML tree (the inspector) too. No special character is shown.
I could check there is an invisible character thanks to a little dropdown that allows me to access previous SQL inputs. The error remains after accessing the faulty input and run it again.
Here is the HTML and Javascript so you can see what I want to do and that there's no visible difference :
$('i').click(function() {
$('#sql-input').append('`' + $(this).data('value') + '`');
});
$('#sql-form').submit(function(e) {
e.preventDefault();
console.log($("#sql-input").text());
/*
Here is the ajax request to execute the SQL
*/
});<script src="http://code.jquery.com/jquery-1.12.4.min.js"></script>
<form id="sql-form" action="" method="post">
<label for="sql-input">SQL PROMPT</label>
<br />
<div id="sql-input" style="height: 80px; width: 150px; border: solid 1px black;" contenteditable></div>
<br />
<input type="submit" value="send" />
<button type="button" onclick="console.clear();">clear console</button>
</form>
<div class="list">
<ul style="cursor: pointer;">
<li><i data-value="table1">table1</i></li>
<li><i data-value="col1_1">col1_1</i></li>
<li><i data-value="col2_1">col2_1</i></li>
<li><i data-value="col3_1">col3_1</i></li>
<li><i data-value="table1">table2</i></li>
<li><i data-value="col1_2">col1_2</i></li>
</ul>
</div>Something strange, though, is that If I touch the JQuery-inputted text, the error disappears.
What I already tried :
removing the quote marks : `table` => table
using $().text() or $().html() instead of $().append()
jquery html sqlite3 append
edited Nov 12 '18 at 15:28
wanttobeprofessional
98131223
asked Nov 12 '18 at 14:58
Jean-Marc ZimmerJean-Marc Zimmer
38414
add a comment |
I have an SQLite3 SQL prompt, to which one can append table/column name by clicking it in the list on the right.
Well, that's what I would like it to do. I've been forced to disable this feature because of an error I don't understand.
If I enter the request manually, everything works. But if I use the button to add `table`, I get this error from SQLite :
in "SELECT * FROM `table`": near "FROM ": syntax error
This error does not even happen on the appended text !!
However the input is visually the same. On the console and in the HTML tree (the inspector) too. No special character is shown.
I could check there is an invisible character thanks to a little dropdown that allows me to access previous SQL inputs. The error remains after accessing the faulty input and run it again.
Here is the HTML and Javascript so you can see what I want to do and that there's no visible difference :
$('i').click(function() {
$('#sql-input').append('`' + $(this).data('value') + '`');
});
$('#sql-form').submit(function(e) {
e.preventDefault();
console.log($("#sql-input").text());
/*
Here is the ajax request to execute the SQL
*/
});<script src="http://code.jquery.com/jquery-1.12.4.min.js"></script>
<form id="sql-form" action="" method="post">
<label for="sql-input">SQL PROMPT</label>
<br />
<div id="sql-input" style="height: 80px; width: 150px; border: solid 1px black;" contenteditable></div>
<br />
<input type="submit" value="send" />
<button type="button" onclick="console.clear();">clear console</button>
</form>
<div class="list">
<ul style="cursor: pointer;">
<li><i data-value="table1">table1</i></li>
<li><i data-value="col1_1">col1_1</i></li>
<li><i data-value="col2_1">col2_1</i></li>
<li><i data-value="col3_1">col3_1</i></li>
<li><i data-value="table1">table2</i></li>
<li><i data-value="col1_2">col1_2</i></li>
</ul>
</div>Something strange, though, is that If I touch the JQuery-inputted text, the error disappears.
What I already tried :
removing the quote marks : `table` => table
using $().text() or $().html() instead of $().append()
jquery html sqlite3 append
edited Nov 12 '18 at 15:28
wanttobeprofessional
98131223
asked Nov 12 '18 at 14:58
Jean-Marc ZimmerJean-Marc Zimmer
38414
I have an SQLite3 SQL prompt, to which one can append table/column name by clicking it in the list on the right.
Well, that's what I would like it to do. I've been forced to disable this feature because of an error I don't understand.
If I enter the request manually, everything works. But if I use the button to add `table`, I get this error from SQLite :
in "SELECT * FROM `table`": near "FROM ": syntax error
This error does not even happen on the appended text !!
However the input is visually the same. On the console and in the HTML tree (the inspector) too. No special character is shown.
I could check there is an invisible character thanks to a little dropdown that allows me to access previous SQL inputs. The error remains after accessing the faulty input and run it again.
Here is the HTML and Javascript so you can see what I want to do and that there's no visible difference :
$('i').click(function() {
$('#sql-input').append('`' + $(this).data('value') + '`');
});
$('#sql-form').submit(function(e) {
e.preventDefault();
console.log($("#sql-input").text());
/*
Here is the ajax request to execute the SQL
*/
});<script src="http://code.jquery.com/jquery-1.12.4.min.js"></script>
<form id="sql-form" action="" method="post">
<label for="sql-input">SQL PROMPT</label>
<br />
<div id="sql-input" style="height: 80px; width: 150px; border: solid 1px black;" contenteditable></div>
<br />
<input type="submit" value="send" />
<button type="button" onclick="console.clear();">clear console</button>
</form>
<div class="list">
<ul style="cursor: pointer;">
<li><i data-value="table1">table1</i></li>
<li><i data-value="col1_1">col1_1</i></li>
<li><i data-value="col2_1">col2_1</i></li>
<li><i data-value="col3_1">col3_1</i></li>
<li><i data-value="table1">table2</i></li>
<li><i data-value="col1_2">col1_2</i></li>
</ul>
</div>Something strange, though, is that If I touch the JQuery-inputted text, the error disappears.
What I already tried :
removing the quote marks : `table` => table
using $().text() or $().html() instead of $().append()
$('i').click(function() {
$('#sql-input').append('`' + $(this).data('value') + '`');
});
$('#sql-form').submit(function(e) {
e.preventDefault();
console.log($("#sql-input").text());
/*
Here is the ajax request to execute the SQL
*/
});<script src="http://code.jquery.com/jquery-1.12.4.min.js"></script>
<form id="sql-form" action="" method="post">
<label for="sql-input">SQL PROMPT</label>
<br />
<div id="sql-input" style="height: 80px; width: 150px; border: solid 1px black;" contenteditable></div>
<br />
<input type="submit" value="send" />
<button type="button" onclick="console.clear();">clear console</button>
</form>
<div class="list">
<ul style="cursor: pointer;">
<li><i data-value="table1">table1</i></li>
<li><i data-value="col1_1">col1_1</i></li>
<li><i data-value="col2_1">col2_1</i></li>
<li><i data-value="col3_1">col3_1</i></li>
<li><i data-value="table1">table2</i></li>
<li><i data-value="col1_2">col1_2</i></li>
</ul>
</div>$('i').click(function() {
$('#sql-input').append('`' + $(this).data('value') + '`');
});
$('#sql-form').submit(function(e) {
e.preventDefault();
console.log($("#sql-input").text());
/*
Here is the ajax request to execute the SQL
*/
});<script src="http://code.jquery.com/jquery-1.12.4.min.js"></script>
<form id="sql-form" action="" method="post">
<label for="sql-input">SQL PROMPT</label>
<br />
<div id="sql-input" style="height: 80px; width: 150px; border: solid 1px black;" contenteditable></div>
<br />
<input type="submit" value="send" />
<button type="button" onclick="console.clear();">clear console</button>
</form>
<div class="list">
<ul style="cursor: pointer;">
<li><i data-value="table1">table1</i></li>
<li><i data-value="col1_1">col1_1</i></li>
<li><i data-value="col2_1">col2_1</i></li>
<li><i data-value="col3_1">col3_1</i></li>
<li><i data-value="table1">table2</i></li>
<li><i data-value="col1_2">col1_2</i></li>
</ul>
</div>jquery html sqlite3 append
jquery html sqlite3 append
edited Nov 12 '18 at 15:28
wanttobeprofessional
98131223
asked Nov 12 '18 at 14:58
Jean-Marc ZimmerJean-Marc Zimmer
38414
edited Nov 12 '18 at 15:28
wanttobeprofessional
98131223
asked Nov 12 '18 at 14:58
Jean-Marc ZimmerJean-Marc Zimmer
38414
edited Nov 12 '18 at 15:28
wanttobeprofessional
98131223
edited Nov 12 '18 at 15:28
wanttobeprofessional
98131223
edited Nov 12 '18 at 15:28
wanttobeprofessional
98131223
98131223
asked Nov 12 '18 at 14:58
Jean-Marc ZimmerJean-Marc Zimmer
38414
asked Nov 12 '18 at 14:58
Jean-Marc ZimmerJean-Marc Zimmer
38414
asked Nov 12 '18 at 14:58
Jean-Marc ZimmerJean-Marc Zimmer
38414
38414
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53264776%2fjquery-append-on-contenteditable-adds-invisible-characters%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53264776%2fjquery-append-on-contenteditable-adds-invisible-characters%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
