MySqlConnection.Open() Error in xamarin.android












0















I am following this tutorial https://www.youtube.com/watch?v=FOZ8HNJMXXg to try to access database. My Code is exactly the same I have add the needed references(System.Data; , MySql.Data.MySqlClient;), but I get a System.TypeInitializationException when I call the Open() function.



Here is my code just in case:



MySqlConnection conn = new MySqlConnection("Server = db4free.net; Port = 3306; Database = XXX; User Id = XXX; Password=XXX; charset=utf8");

if(conn.State == ConnectionState.Closed)
{
conn.Open();
msg.Text = "Opened successfully"; //just a textview
conn.Close();
}









share|improve this question



























    0















    I am following this tutorial https://www.youtube.com/watch?v=FOZ8HNJMXXg to try to access database. My Code is exactly the same I have add the needed references(System.Data; , MySql.Data.MySqlClient;), but I get a System.TypeInitializationException when I call the Open() function.



    Here is my code just in case:



    MySqlConnection conn = new MySqlConnection("Server = db4free.net; Port = 3306; Database = XXX; User Id = XXX; Password=XXX; charset=utf8");

    if(conn.State == ConnectionState.Closed)
    {
    conn.Open();
    msg.Text = "Opened successfully"; //just a textview
    conn.Close();
    }









    share|improve this question

























      0












      0








      0








      I am following this tutorial https://www.youtube.com/watch?v=FOZ8HNJMXXg to try to access database. My Code is exactly the same I have add the needed references(System.Data; , MySql.Data.MySqlClient;), but I get a System.TypeInitializationException when I call the Open() function.



      Here is my code just in case:



      MySqlConnection conn = new MySqlConnection("Server = db4free.net; Port = 3306; Database = XXX; User Id = XXX; Password=XXX; charset=utf8");

      if(conn.State == ConnectionState.Closed)
      {
      conn.Open();
      msg.Text = "Opened successfully"; //just a textview
      conn.Close();
      }









      share|improve this question














      I am following this tutorial https://www.youtube.com/watch?v=FOZ8HNJMXXg to try to access database. My Code is exactly the same I have add the needed references(System.Data; , MySql.Data.MySqlClient;), but I get a System.TypeInitializationException when I call the Open() function.



      Here is my code just in case:



      MySqlConnection conn = new MySqlConnection("Server = db4free.net; Port = 3306; Database = XXX; User Id = XXX; Password=XXX; charset=utf8");

      if(conn.State == ConnectionState.Closed)
      {
      conn.Open();
      msg.Text = "Opened successfully"; //just a textview
      conn.Close();
      }






      mysql database xamarin.android






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      asked Nov 13 '18 at 9:06









      Georgi YakovGeorgi Yakov

      188




      188
























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          I try the code that you provided, but I also have the same issue at my side, so I suggest you don't connect your app to database directly.



          You can use web services instead, the web services will handle the interaction between your client and server.



          https://docs.microsoft.com/en-us/xamarin/cross-platform/data-cloud/web-services/



          https://docs.microsoft.com/en-us/xamarin/cross-platform/troubleshooting/component-nuget?tabs=windows






          share|improve this answer
























          • I will take a look at it, thx.

            – Georgi Yakov
            Nov 15 '18 at 10:28











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          oldest

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          0














          I try the code that you provided, but I also have the same issue at my side, so I suggest you don't connect your app to database directly.



          You can use web services instead, the web services will handle the interaction between your client and server.



          https://docs.microsoft.com/en-us/xamarin/cross-platform/data-cloud/web-services/



          https://docs.microsoft.com/en-us/xamarin/cross-platform/troubleshooting/component-nuget?tabs=windows






          share|improve this answer
























          • I will take a look at it, thx.

            – Georgi Yakov
            Nov 15 '18 at 10:28
















          0














          I try the code that you provided, but I also have the same issue at my side, so I suggest you don't connect your app to database directly.



          You can use web services instead, the web services will handle the interaction between your client and server.



          https://docs.microsoft.com/en-us/xamarin/cross-platform/data-cloud/web-services/



          https://docs.microsoft.com/en-us/xamarin/cross-platform/troubleshooting/component-nuget?tabs=windows






          share|improve this answer
























          • I will take a look at it, thx.

            – Georgi Yakov
            Nov 15 '18 at 10:28














          0












          0








          0







          I try the code that you provided, but I also have the same issue at my side, so I suggest you don't connect your app to database directly.



          You can use web services instead, the web services will handle the interaction between your client and server.



          https://docs.microsoft.com/en-us/xamarin/cross-platform/data-cloud/web-services/



          https://docs.microsoft.com/en-us/xamarin/cross-platform/troubleshooting/component-nuget?tabs=windows






          share|improve this answer













          I try the code that you provided, but I also have the same issue at my side, so I suggest you don't connect your app to database directly.



          You can use web services instead, the web services will handle the interaction between your client and server.



          https://docs.microsoft.com/en-us/xamarin/cross-platform/data-cloud/web-services/



          https://docs.microsoft.com/en-us/xamarin/cross-platform/troubleshooting/component-nuget?tabs=windows







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 15 '18 at 9:05









          Cherry BuCherry Bu

          87328




          87328













          • I will take a look at it, thx.

            – Georgi Yakov
            Nov 15 '18 at 10:28



















          • I will take a look at it, thx.

            – Georgi Yakov
            Nov 15 '18 at 10:28

















          I will take a look at it, thx.

          – Georgi Yakov
          Nov 15 '18 at 10:28





          I will take a look at it, thx.

          – Georgi Yakov
          Nov 15 '18 at 10:28


















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