Swift: Java equivalent of Arrays.copyOfRange for [UInt8]
0
I am translating a java code to swift, and I want to know what is the equivalent for swift of Arrays.copyOfRange:
public static byte copyOfRange(byte original, int from, int to)
for my example I want to translate the next line:
Arrays.copyOfRange(packet.value(), 2, packet.length())
Thanks
swift
asked Nov 12 '18 at 12:01
Mickael BelhassenMickael Belhassen
1719
add a comment |
0
I am translating a java code to swift, and I want to know what is the equivalent for swift of Arrays.copyOfRange:
public static byte copyOfRange(byte original, int from, int to)
for my example I want to translate the next line:
Arrays.copyOfRange(packet.value(), 2, packet.length())
Thanks
swift
asked Nov 12 '18 at 12:01
Mickael BelhassenMickael Belhassen
1719
Don't add the answer to your question. You can post your solution as an answer, or accept one of the existing answers.
– Martin R
Nov 12 '18 at 12:51
Ok edited......
– Mickael Belhassen
Nov 12 '18 at 12:53
add a comment |
0
0
0
I am translating a java code to swift, and I want to know what is the equivalent for swift of Arrays.copyOfRange:
public static byte copyOfRange(byte original, int from, int to)
for my example I want to translate the next line:
Arrays.copyOfRange(packet.value(), 2, packet.length())
Thanks
swift
asked Nov 12 '18 at 12:01
Mickael BelhassenMickael Belhassen
1719
I am translating a java code to swift, and I want to know what is the equivalent for swift of Arrays.copyOfRange:
public static byte copyOfRange(byte original, int from, int to)
for my example I want to translate the next line:
Arrays.copyOfRange(packet.value(), 2, packet.length())
Thanks
swift
swift
asked Nov 12 '18 at 12:01
Mickael BelhassenMickael Belhassen
1719
asked Nov 12 '18 at 12:01
Mickael BelhassenMickael Belhassen
1719
edited Nov 12 '18 at 12:52
Mickael Belhassen
asked Nov 12 '18 at 12:01
Mickael BelhassenMickael Belhassen
1719
asked Nov 12 '18 at 12:01
Mickael BelhassenMickael Belhassen
1719
asked Nov 12 '18 at 12:01
Mickael BelhassenMickael Belhassen
1719
1719
Don't add the answer to your question. You can post your solution as an answer, or accept one of the existing answers.
– Martin R
Nov 12 '18 at 12:51
Ok edited......
– Mickael Belhassen
Nov 12 '18 at 12:53
add a comment |
Don't add the answer to your question. You can post your solution as an answer, or accept one of the existing answers.
– Martin R
Nov 12 '18 at 12:51
Ok edited......
– Mickael Belhassen
Nov 12 '18 at 12:53
Don't add the answer to your question. You can post your solution as an answer, or accept one of the existing answers.
– Martin R
Nov 12 '18 at 12:51
Don't add the answer to your question. You can post your solution as an answer, or accept one of the existing answers.
– Martin R
Nov 12 '18 at 12:51
Ok edited......
– Mickael Belhassen
Nov 12 '18 at 12:53
Ok edited......
– Mickael Belhassen
Nov 12 '18 at 12:53
add a comment |
4 Answers
4
active
oldest
votes
1
Java's copyOfRange will also pad the resulting array with zeroes if the upper range value is greater than the array length. This function handles that case as well.
This function can be made generic. It works for any type that conforms to ExpressibleByIntegerLiteral which is needed for the 0 padding.
func copyOfRange<T>(arr: [T], from: Int, to: Int) -> [T]? where T: ExpressibleByIntegerLiteral {
guard from >= 0 && from <= arr.count && from <= to else { return nil }
var to = to
var padding = 0
if to > arr.count {
padding = to - arr.count
to = arr.count
}
return Array(arr[from..<to]) + [T](repeating: 0, count: padding)
}
Examples:
let arr: [UInt8] = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
if let result = copyOfRange(arr: arr, from: 0, to: 3) {
print(result) // [0, 1, 2]
}
if let result = copyOfRange(arr: arr, from: 7, to: 12) {
print(result) // [7, 8, 9, 0, 0]
}
answered Nov 12 '18 at 12:57
vacawamavacawama
95.8k13172197
add a comment |
0
This should definitfly work:
var array = [1,2,3,4,5,6,7,8,9]
var partOfArray = array[5...8]
print(partOfArray)
answered Nov 12 '18 at 12:15
JonathanJonathan
1
1
This answer could be much more helpful if you explain why it is correct ad relate it to the specifics of the question.
– Dragonthoughts
Nov 12 '18 at 12:30
add a comment |
0
You can try
func getRange (arr:[Int],from:Int,to:Int) -> [Int]? {
if from >= 0 && from < arr.count && to >= 0 && to < arr.count && from < to {
return Array(arr[from...to])
}
return nil
}
May write
extension Array {
func getRenage (from:Int,to:Int) -> [Element]? {
if from >= 0 && from < self.count && to >= 0 && to < self.count && from < to {
return Array(self[from...to])
}
return nil
}
}
answered Nov 12 '18 at 12:05
Sh_KhanSh_Khan
40.1k51125
1
Did you check your code before posting? This does not compile.
– Martin R
Nov 12 '18 at 12:06
I was just about to press "Post Your Answer" when I saw yours come up. Mine was essentially the same. The key part to this answer is the range subscriptarr[from...to]which is essentially doing the equivalent ofcopyOfRange. (Except that in Swift you can also use this syntax to write to a subset of the array as well as to extract it.)
– Steven W. Klassen
Nov 12 '18 at 12:08
@MartinR hand write it
– Sh_Khan
Nov 12 '18 at 12:09
Thanks for your quick answer, I want to give it a byteArray so I just have to replace Int by UInt8?
– Mickael Belhassen
Nov 12 '18 at 12:11
@MickaelBelhassen yeah
– Shubham Bakshi
Nov 12 '18 at 12:12
|
show 7 more comments
0
Answer
func getRange(arr: [UInt8], from: Int, to: Int) -> [UInt8]? {
if from >= 0 && to >= from && to <= arr.count{
return Array(arr[from..<to])
}
return nil
}
answered Nov 12 '18 at 12:53
Mickael BelhassenMickael Belhassen
1719
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Java's copyOfRange will also pad the resulting array with zeroes if the upper range value is greater than the array length. This function handles that case as well.
This function can be made generic. It works for any type that conforms to ExpressibleByIntegerLiteral which is needed for the 0 padding.
func copyOfRange<T>(arr: [T], from: Int, to: Int) -> [T]? where T: ExpressibleByIntegerLiteral {
guard from >= 0 && from <= arr.count && from <= to else { return nil }
var to = to
var padding = 0
if to > arr.count {
padding = to - arr.count
to = arr.count
}
return Array(arr[from..<to]) + [T](repeating: 0, count: padding)
}
Examples:
let arr: [UInt8] = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
if let result = copyOfRange(arr: arr, from: 0, to: 3) {
print(result) // [0, 1, 2]
}
if let result = copyOfRange(arr: arr, from: 7, to: 12) {
print(result) // [7, 8, 9, 0, 0]
}
answered Nov 12 '18 at 12:57
vacawamavacawama
95.8k13172197
add a comment |
1
Java's copyOfRange will also pad the resulting array with zeroes if the upper range value is greater than the array length. This function handles that case as well.
This function can be made generic. It works for any type that conforms to ExpressibleByIntegerLiteral which is needed for the 0 padding.
func copyOfRange<T>(arr: [T], from: Int, to: Int) -> [T]? where T: ExpressibleByIntegerLiteral {
guard from >= 0 && from <= arr.count && from <= to else { return nil }
var to = to
var padding = 0
if to > arr.count {
padding = to - arr.count
to = arr.count
}
return Array(arr[from..<to]) + [T](repeating: 0, count: padding)
}
Examples:
let arr: [UInt8] = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
if let result = copyOfRange(arr: arr, from: 0, to: 3) {
print(result) // [0, 1, 2]
}
if let result = copyOfRange(arr: arr, from: 7, to: 12) {
print(result) // [7, 8, 9, 0, 0]
}
answered Nov 12 '18 at 12:57
vacawamavacawama
95.8k13172197
add a comment |
1
1
1
Java's copyOfRange will also pad the resulting array with zeroes if the upper range value is greater than the array length. This function handles that case as well.
This function can be made generic. It works for any type that conforms to ExpressibleByIntegerLiteral which is needed for the 0 padding.
func copyOfRange<T>(arr: [T], from: Int, to: Int) -> [T]? where T: ExpressibleByIntegerLiteral {
guard from >= 0 && from <= arr.count && from <= to else { return nil }
var to = to
var padding = 0
if to > arr.count {
padding = to - arr.count
to = arr.count
}
return Array(arr[from..<to]) + [T](repeating: 0, count: padding)
}
Examples:
let arr: [UInt8] = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
if let result = copyOfRange(arr: arr, from: 0, to: 3) {
print(result) // [0, 1, 2]
}
if let result = copyOfRange(arr: arr, from: 7, to: 12) {
print(result) // [7, 8, 9, 0, 0]
}
answered Nov 12 '18 at 12:57
vacawamavacawama
95.8k13172197
Java's copyOfRange will also pad the resulting array with zeroes if the upper range value is greater than the array length. This function handles that case as well.
This function can be made generic. It works for any type that conforms to ExpressibleByIntegerLiteral which is needed for the 0 padding.
func copyOfRange<T>(arr: [T], from: Int, to: Int) -> [T]? where T: ExpressibleByIntegerLiteral {
guard from >= 0 && from <= arr.count && from <= to else { return nil }
var to = to
var padding = 0
if to > arr.count {
padding = to - arr.count
to = arr.count
}
return Array(arr[from..<to]) + [T](repeating: 0, count: padding)
}
Examples:
let arr: [UInt8] = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
if let result = copyOfRange(arr: arr, from: 0, to: 3) {
print(result) // [0, 1, 2]
}
if let result = copyOfRange(arr: arr, from: 7, to: 12) {
print(result) // [7, 8, 9, 0, 0]
}
answered Nov 12 '18 at 12:57
vacawamavacawama
95.8k13172197
edited Nov 12 '18 at 14:30
answered Nov 12 '18 at 12:57
vacawamavacawama
95.8k13172197
answered Nov 12 '18 at 12:57
vacawamavacawama
95.8k13172197
answered Nov 12 '18 at 12:57
vacawamavacawama
95.8k13172197
95.8k13172197
add a comment |
add a comment |
0
This should definitfly work:
var array = [1,2,3,4,5,6,7,8,9]
var partOfArray = array[5...8]
print(partOfArray)
answered Nov 12 '18 at 12:15
JonathanJonathan
1
1
This answer could be much more helpful if you explain why it is correct ad relate it to the specifics of the question.
– Dragonthoughts
Nov 12 '18 at 12:30
add a comment |
0
This should definitfly work:
var array = [1,2,3,4,5,6,7,8,9]
var partOfArray = array[5...8]
print(partOfArray)
answered Nov 12 '18 at 12:15
JonathanJonathan
1
1
This answer could be much more helpful if you explain why it is correct ad relate it to the specifics of the question.
– Dragonthoughts
Nov 12 '18 at 12:30
add a comment |
0
0
0
This should definitfly work:
var array = [1,2,3,4,5,6,7,8,9]
var partOfArray = array[5...8]
print(partOfArray)
answered Nov 12 '18 at 12:15
JonathanJonathan
1
This should definitfly work:
var array = [1,2,3,4,5,6,7,8,9]
var partOfArray = array[5...8]
print(partOfArray)
answered Nov 12 '18 at 12:15
JonathanJonathan
1
answered Nov 12 '18 at 12:15
JonathanJonathan
1
answered Nov 12 '18 at 12:15
JonathanJonathan
1
answered Nov 12 '18 at 12:15
JonathanJonathan
1
1
1
This answer could be much more helpful if you explain why it is correct ad relate it to the specifics of the question.
– Dragonthoughts
Nov 12 '18 at 12:30
add a comment |
1
This answer could be much more helpful if you explain why it is correct ad relate it to the specifics of the question.
– Dragonthoughts
Nov 12 '18 at 12:30
1
1
This answer could be much more helpful if you explain why it is correct ad relate it to the specifics of the question.
– Dragonthoughts
Nov 12 '18 at 12:30
This answer could be much more helpful if you explain why it is correct ad relate it to the specifics of the question.
– Dragonthoughts
Nov 12 '18 at 12:30
add a comment |
0
You can try
func getRange (arr:[Int],from:Int,to:Int) -> [Int]? {
if from >= 0 && from < arr.count && to >= 0 && to < arr.count && from < to {
return Array(arr[from...to])
}
return nil
}
May write
extension Array {
func getRenage (from:Int,to:Int) -> [Element]? {
if from >= 0 && from < self.count && to >= 0 && to < self.count && from < to {
return Array(self[from...to])
}
return nil
}
}
answered Nov 12 '18 at 12:05
Sh_KhanSh_Khan
40.1k51125
1
Did you check your code before posting? This does not compile.
– Martin R
Nov 12 '18 at 12:06
I was just about to press "Post Your Answer" when I saw yours come up. Mine was essentially the same. The key part to this answer is the range subscriptarr[from...to]which is essentially doing the equivalent ofcopyOfRange. (Except that in Swift you can also use this syntax to write to a subset of the array as well as to extract it.)
– Steven W. Klassen
Nov 12 '18 at 12:08
@MartinR hand write it
– Sh_Khan
Nov 12 '18 at 12:09
Thanks for your quick answer, I want to give it a byteArray so I just have to replace Int by UInt8?
– Mickael Belhassen
Nov 12 '18 at 12:11
@MickaelBelhassen yeah
– Shubham Bakshi
Nov 12 '18 at 12:12
|
show 7 more comments
0
You can try
func getRange (arr:[Int],from:Int,to:Int) -> [Int]? {
if from >= 0 && from < arr.count && to >= 0 && to < arr.count && from < to {
return Array(arr[from...to])
}
return nil
}
May write
extension Array {
func getRenage (from:Int,to:Int) -> [Element]? {
if from >= 0 && from < self.count && to >= 0 && to < self.count && from < to {
return Array(self[from...to])
}
return nil
}
}
answered Nov 12 '18 at 12:05
Sh_KhanSh_Khan
40.1k51125
1
Did you check your code before posting? This does not compile.
– Martin R
Nov 12 '18 at 12:06
I was just about to press "Post Your Answer" when I saw yours come up. Mine was essentially the same. The key part to this answer is the range subscriptarr[from...to]which is essentially doing the equivalent ofcopyOfRange. (Except that in Swift you can also use this syntax to write to a subset of the array as well as to extract it.)
– Steven W. Klassen
Nov 12 '18 at 12:08
@MartinR hand write it
– Sh_Khan
Nov 12 '18 at 12:09
Thanks for your quick answer, I want to give it a byteArray so I just have to replace Int by UInt8?
– Mickael Belhassen
Nov 12 '18 at 12:11
@MickaelBelhassen yeah
– Shubham Bakshi
Nov 12 '18 at 12:12
|
show 7 more comments
0
0
0
You can try
func getRange (arr:[Int],from:Int,to:Int) -> [Int]? {
if from >= 0 && from < arr.count && to >= 0 && to < arr.count && from < to {
return Array(arr[from...to])
}
return nil
}
May write
extension Array {
func getRenage (from:Int,to:Int) -> [Element]? {
if from >= 0 && from < self.count && to >= 0 && to < self.count && from < to {
return Array(self[from...to])
}
return nil
}
}
answered Nov 12 '18 at 12:05
Sh_KhanSh_Khan
40.1k51125
You can try
func getRange (arr:[Int],from:Int,to:Int) -> [Int]? {
if from >= 0 && from < arr.count && to >= 0 && to < arr.count && from < to {
return Array(arr[from...to])
}
return nil
}
May write
extension Array {
func getRenage (from:Int,to:Int) -> [Element]? {
if from >= 0 && from < self.count && to >= 0 && to < self.count && from < to {
return Array(self[from...to])
}
return nil
}
}
answered Nov 12 '18 at 12:05
Sh_KhanSh_Khan
40.1k51125
edited Nov 12 '18 at 12:22
answered Nov 12 '18 at 12:05
Sh_KhanSh_Khan
40.1k51125
answered Nov 12 '18 at 12:05
Sh_KhanSh_Khan
40.1k51125
answered Nov 12 '18 at 12:05
Sh_KhanSh_Khan
40.1k51125
40.1k51125
1
Did you check your code before posting? This does not compile.
– Martin R
Nov 12 '18 at 12:06
I was just about to press "Post Your Answer" when I saw yours come up. Mine was essentially the same. The key part to this answer is the range subscriptarr[from...to]which is essentially doing the equivalent ofcopyOfRange. (Except that in Swift you can also use this syntax to write to a subset of the array as well as to extract it.)
– Steven W. Klassen
Nov 12 '18 at 12:08
@MartinR hand write it
– Sh_Khan
Nov 12 '18 at 12:09
Thanks for your quick answer, I want to give it a byteArray so I just have to replace Int by UInt8?
– Mickael Belhassen
Nov 12 '18 at 12:11
@MickaelBelhassen yeah
– Shubham Bakshi
Nov 12 '18 at 12:12
|
show 7 more comments
1
Did you check your code before posting? This does not compile.
– Martin R
Nov 12 '18 at 12:06
I was just about to press "Post Your Answer" when I saw yours come up. Mine was essentially the same. The key part to this answer is the range subscriptarr[from...to]which is essentially doing the equivalent ofcopyOfRange. (Except that in Swift you can also use this syntax to write to a subset of the array as well as to extract it.)
– Steven W. Klassen
Nov 12 '18 at 12:08
@MartinR hand write it
– Sh_Khan
Nov 12 '18 at 12:09
Thanks for your quick answer, I want to give it a byteArray so I just have to replace Int by UInt8?
– Mickael Belhassen
Nov 12 '18 at 12:11
@MickaelBelhassen yeah
– Shubham Bakshi
Nov 12 '18 at 12:12
1
1
Did you check your code before posting? This does not compile.
– Martin R
Nov 12 '18 at 12:06
Did you check your code before posting? This does not compile.
– Martin R
Nov 12 '18 at 12:06
I was just about to press "Post Your Answer" when I saw yours come up. Mine was essentially the same. The key part to this answer is the range subscript
arr[from...to] which is essentially doing the equivalent of copyOfRange. (Except that in Swift you can also use this syntax to write to a subset of the array as well as to extract it.)– Steven W. Klassen
Nov 12 '18 at 12:08
I was just about to press "Post Your Answer" when I saw yours come up. Mine was essentially the same. The key part to this answer is the range subscript
arr[from...to] which is essentially doing the equivalent of copyOfRange. (Except that in Swift you can also use this syntax to write to a subset of the array as well as to extract it.)– Steven W. Klassen
Nov 12 '18 at 12:08
@MartinR hand write it
– Sh_Khan
Nov 12 '18 at 12:09
@MartinR hand write it
– Sh_Khan
Nov 12 '18 at 12:09
Thanks for your quick answer, I want to give it a byteArray so I just have to replace Int by UInt8?
– Mickael Belhassen
Nov 12 '18 at 12:11
Thanks for your quick answer, I want to give it a byteArray so I just have to replace Int by UInt8?
– Mickael Belhassen
Nov 12 '18 at 12:11
@MickaelBelhassen yeah
– Shubham Bakshi
Nov 12 '18 at 12:12
@MickaelBelhassen yeah
– Shubham Bakshi
Nov 12 '18 at 12:12
|
show 7 more comments
0
Answer
func getRange(arr: [UInt8], from: Int, to: Int) -> [UInt8]? {
if from >= 0 && to >= from && to <= arr.count{
return Array(arr[from..<to])
}
return nil
}
answered Nov 12 '18 at 12:53
Mickael BelhassenMickael Belhassen
1719
add a comment |
0
Answer
func getRange(arr: [UInt8], from: Int, to: Int) -> [UInt8]? {
if from >= 0 && to >= from && to <= arr.count{
return Array(arr[from..<to])
}
return nil
}
answered Nov 12 '18 at 12:53
Mickael BelhassenMickael Belhassen
1719
add a comment |
0
0
0
Answer
func getRange(arr: [UInt8], from: Int, to: Int) -> [UInt8]? {
if from >= 0 && to >= from && to <= arr.count{
return Array(arr[from..<to])
}
return nil
}
answered Nov 12 '18 at 12:53
Mickael BelhassenMickael Belhassen
1719
Answer
func getRange(arr: [UInt8], from: Int, to: Int) -> [UInt8]? {
if from >= 0 && to >= from && to <= arr.count{
return Array(arr[from..<to])
}
return nil
}
answered Nov 12 '18 at 12:53
Mickael BelhassenMickael Belhassen
1719
answered Nov 12 '18 at 12:53
Mickael BelhassenMickael Belhassen
1719
answered Nov 12 '18 at 12:53
Mickael BelhassenMickael Belhassen
1719
answered Nov 12 '18 at 12:53
Mickael BelhassenMickael Belhassen
1719
1719
add a comment |
add a comment |
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Don't add the answer to your question. You can post your solution as an answer, or accept one of the existing answers.
– Martin R
Nov 12 '18 at 12:51
Ok edited......
– Mickael Belhassen
Nov 12 '18 at 12:53