How to round numbers to the nearest 1000?












8















I'm having some issue to round up and down of a list of number to the nearest 1000.



Below is my code:



rev_list = 

for i in range(12):
rev = int(round(random.normalvariate(100000, 12000)))
rev_list.append(rev)

print(rev_list)


The output is:



[97277, 96494, 104541, 132060, 98179, 87862, 84718, 95391, 94674, 89773, 92790, 86122]


I would like to round the list to the nearest 1000. How can I do that?










share|improve this question





























    8















    I'm having some issue to round up and down of a list of number to the nearest 1000.



    Below is my code:



    rev_list = 

    for i in range(12):
    rev = int(round(random.normalvariate(100000, 12000)))
    rev_list.append(rev)

    print(rev_list)


    The output is:



    [97277, 96494, 104541, 132060, 98179, 87862, 84718, 95391, 94674, 89773, 92790, 86122]


    I would like to round the list to the nearest 1000. How can I do that?










    share|improve this question



























      8












      8








      8


      1






      I'm having some issue to round up and down of a list of number to the nearest 1000.



      Below is my code:



      rev_list = 

      for i in range(12):
      rev = int(round(random.normalvariate(100000, 12000)))
      rev_list.append(rev)

      print(rev_list)


      The output is:



      [97277, 96494, 104541, 132060, 98179, 87862, 84718, 95391, 94674, 89773, 92790, 86122]


      I would like to round the list to the nearest 1000. How can I do that?










      share|improve this question
















      I'm having some issue to round up and down of a list of number to the nearest 1000.



      Below is my code:



      rev_list = 

      for i in range(12):
      rev = int(round(random.normalvariate(100000, 12000)))
      rev_list.append(rev)

      print(rev_list)


      The output is:



      [97277, 96494, 104541, 132060, 98179, 87862, 84718, 95391, 94674, 89773, 92790, 86122]


      I would like to round the list to the nearest 1000. How can I do that?







      python rounding






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 13 '18 at 20:02









      wim

      161k50308440




      161k50308440










      asked Sep 29 '17 at 3:24









      123cremepie123cremepie

      394




      394
























          2 Answers
          2






          active

          oldest

          votes


















          15














          The round function can take negative digits to round to, which causes it to round off to the left of the decimal. For example:



          >>> round(15768, -3)
          16000
          >>> round(1218, -3)
          1000


          So the short answer is: Call round with the second argument of -3 to round to the nearest 1000.






          share|improve this answer
























          • Note: My example behavior is the Python 3 behavior for round; if you're on Python 2, the results would be float values, but wrapping in int() would convert back to int.

            – ShadowRanger
            Sep 29 '17 at 3:32



















          -2














          List comprehension is a one-line loop which allows you to apply a function to the list items. (for more read List Comprehensions)



          [x for x in rev_list]


          In this case, round(num, -3) is the function.



          >>> round(1300,-3)
          1000
          >>>


          The answer



          You can apply a function on a list by this code



          rev_list=[round(x,-3) for x in rev_list]


          The example:



          >>> rev_list=[97277, 96494, 104541, 132060, 98179, 87862, 84718, 95391, 94674, 89773, 92790, 86122]
          >>> rev_list=[round(x,-3) for x in rev_list]
          >>> rev_list
          [97000, 96000, 105000, 132000, 98000, 88000, 85000, 95000, 95000, 90000, 93000, 86000]
          >>>





          share|improve this answer





















          • 5





            Usually it's better to explain a solution instead of just posting some rows of anonymous code. You can read How do I write a good answer, and also Explaining entirely code-based answers

            – Anh Pham
            Dec 30 '18 at 4:02






          • 2





            While this code may answer the question, it is better to explain how to solve the problem and provide the code as an example or reference. Code-only answers can be confusing and lack context.

            – Dima Kozhevin
            Dec 30 '18 at 7:04











          • @AnhPham, thank you for your comment. done

            – Reza energy
            Dec 30 '18 at 18:37











          Your Answer






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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          15














          The round function can take negative digits to round to, which causes it to round off to the left of the decimal. For example:



          >>> round(15768, -3)
          16000
          >>> round(1218, -3)
          1000


          So the short answer is: Call round with the second argument of -3 to round to the nearest 1000.






          share|improve this answer
























          • Note: My example behavior is the Python 3 behavior for round; if you're on Python 2, the results would be float values, but wrapping in int() would convert back to int.

            – ShadowRanger
            Sep 29 '17 at 3:32
















          15














          The round function can take negative digits to round to, which causes it to round off to the left of the decimal. For example:



          >>> round(15768, -3)
          16000
          >>> round(1218, -3)
          1000


          So the short answer is: Call round with the second argument of -3 to round to the nearest 1000.






          share|improve this answer
























          • Note: My example behavior is the Python 3 behavior for round; if you're on Python 2, the results would be float values, but wrapping in int() would convert back to int.

            – ShadowRanger
            Sep 29 '17 at 3:32














          15












          15








          15







          The round function can take negative digits to round to, which causes it to round off to the left of the decimal. For example:



          >>> round(15768, -3)
          16000
          >>> round(1218, -3)
          1000


          So the short answer is: Call round with the second argument of -3 to round to the nearest 1000.






          share|improve this answer













          The round function can take negative digits to round to, which causes it to round off to the left of the decimal. For example:



          >>> round(15768, -3)
          16000
          >>> round(1218, -3)
          1000


          So the short answer is: Call round with the second argument of -3 to round to the nearest 1000.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Sep 29 '17 at 3:28









          ShadowRangerShadowRanger

          60.1k55796




          60.1k55796













          • Note: My example behavior is the Python 3 behavior for round; if you're on Python 2, the results would be float values, but wrapping in int() would convert back to int.

            – ShadowRanger
            Sep 29 '17 at 3:32



















          • Note: My example behavior is the Python 3 behavior for round; if you're on Python 2, the results would be float values, but wrapping in int() would convert back to int.

            – ShadowRanger
            Sep 29 '17 at 3:32

















          Note: My example behavior is the Python 3 behavior for round; if you're on Python 2, the results would be float values, but wrapping in int() would convert back to int.

          – ShadowRanger
          Sep 29 '17 at 3:32





          Note: My example behavior is the Python 3 behavior for round; if you're on Python 2, the results would be float values, but wrapping in int() would convert back to int.

          – ShadowRanger
          Sep 29 '17 at 3:32













          -2














          List comprehension is a one-line loop which allows you to apply a function to the list items. (for more read List Comprehensions)



          [x for x in rev_list]


          In this case, round(num, -3) is the function.



          >>> round(1300,-3)
          1000
          >>>


          The answer



          You can apply a function on a list by this code



          rev_list=[round(x,-3) for x in rev_list]


          The example:



          >>> rev_list=[97277, 96494, 104541, 132060, 98179, 87862, 84718, 95391, 94674, 89773, 92790, 86122]
          >>> rev_list=[round(x,-3) for x in rev_list]
          >>> rev_list
          [97000, 96000, 105000, 132000, 98000, 88000, 85000, 95000, 95000, 90000, 93000, 86000]
          >>>





          share|improve this answer





















          • 5





            Usually it's better to explain a solution instead of just posting some rows of anonymous code. You can read How do I write a good answer, and also Explaining entirely code-based answers

            – Anh Pham
            Dec 30 '18 at 4:02






          • 2





            While this code may answer the question, it is better to explain how to solve the problem and provide the code as an example or reference. Code-only answers can be confusing and lack context.

            – Dima Kozhevin
            Dec 30 '18 at 7:04











          • @AnhPham, thank you for your comment. done

            – Reza energy
            Dec 30 '18 at 18:37
















          -2














          List comprehension is a one-line loop which allows you to apply a function to the list items. (for more read List Comprehensions)



          [x for x in rev_list]


          In this case, round(num, -3) is the function.



          >>> round(1300,-3)
          1000
          >>>


          The answer



          You can apply a function on a list by this code



          rev_list=[round(x,-3) for x in rev_list]


          The example:



          >>> rev_list=[97277, 96494, 104541, 132060, 98179, 87862, 84718, 95391, 94674, 89773, 92790, 86122]
          >>> rev_list=[round(x,-3) for x in rev_list]
          >>> rev_list
          [97000, 96000, 105000, 132000, 98000, 88000, 85000, 95000, 95000, 90000, 93000, 86000]
          >>>





          share|improve this answer





















          • 5





            Usually it's better to explain a solution instead of just posting some rows of anonymous code. You can read How do I write a good answer, and also Explaining entirely code-based answers

            – Anh Pham
            Dec 30 '18 at 4:02






          • 2





            While this code may answer the question, it is better to explain how to solve the problem and provide the code as an example or reference. Code-only answers can be confusing and lack context.

            – Dima Kozhevin
            Dec 30 '18 at 7:04











          • @AnhPham, thank you for your comment. done

            – Reza energy
            Dec 30 '18 at 18:37














          -2












          -2








          -2







          List comprehension is a one-line loop which allows you to apply a function to the list items. (for more read List Comprehensions)



          [x for x in rev_list]


          In this case, round(num, -3) is the function.



          >>> round(1300,-3)
          1000
          >>>


          The answer



          You can apply a function on a list by this code



          rev_list=[round(x,-3) for x in rev_list]


          The example:



          >>> rev_list=[97277, 96494, 104541, 132060, 98179, 87862, 84718, 95391, 94674, 89773, 92790, 86122]
          >>> rev_list=[round(x,-3) for x in rev_list]
          >>> rev_list
          [97000, 96000, 105000, 132000, 98000, 88000, 85000, 95000, 95000, 90000, 93000, 86000]
          >>>





          share|improve this answer















          List comprehension is a one-line loop which allows you to apply a function to the list items. (for more read List Comprehensions)



          [x for x in rev_list]


          In this case, round(num, -3) is the function.



          >>> round(1300,-3)
          1000
          >>>


          The answer



          You can apply a function on a list by this code



          rev_list=[round(x,-3) for x in rev_list]


          The example:



          >>> rev_list=[97277, 96494, 104541, 132060, 98179, 87862, 84718, 95391, 94674, 89773, 92790, 86122]
          >>> rev_list=[round(x,-3) for x in rev_list]
          >>> rev_list
          [97000, 96000, 105000, 132000, 98000, 88000, 85000, 95000, 95000, 90000, 93000, 86000]
          >>>






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Dec 30 '18 at 18:35

























          answered Dec 30 '18 at 3:32









          Reza energyReza energy

          195




          195








          • 5





            Usually it's better to explain a solution instead of just posting some rows of anonymous code. You can read How do I write a good answer, and also Explaining entirely code-based answers

            – Anh Pham
            Dec 30 '18 at 4:02






          • 2





            While this code may answer the question, it is better to explain how to solve the problem and provide the code as an example or reference. Code-only answers can be confusing and lack context.

            – Dima Kozhevin
            Dec 30 '18 at 7:04











          • @AnhPham, thank you for your comment. done

            – Reza energy
            Dec 30 '18 at 18:37














          • 5





            Usually it's better to explain a solution instead of just posting some rows of anonymous code. You can read How do I write a good answer, and also Explaining entirely code-based answers

            – Anh Pham
            Dec 30 '18 at 4:02






          • 2





            While this code may answer the question, it is better to explain how to solve the problem and provide the code as an example or reference. Code-only answers can be confusing and lack context.

            – Dima Kozhevin
            Dec 30 '18 at 7:04











          • @AnhPham, thank you for your comment. done

            – Reza energy
            Dec 30 '18 at 18:37








          5




          5





          Usually it's better to explain a solution instead of just posting some rows of anonymous code. You can read How do I write a good answer, and also Explaining entirely code-based answers

          – Anh Pham
          Dec 30 '18 at 4:02





          Usually it's better to explain a solution instead of just posting some rows of anonymous code. You can read How do I write a good answer, and also Explaining entirely code-based answers

          – Anh Pham
          Dec 30 '18 at 4:02




          2




          2





          While this code may answer the question, it is better to explain how to solve the problem and provide the code as an example or reference. Code-only answers can be confusing and lack context.

          – Dima Kozhevin
          Dec 30 '18 at 7:04





          While this code may answer the question, it is better to explain how to solve the problem and provide the code as an example or reference. Code-only answers can be confusing and lack context.

          – Dima Kozhevin
          Dec 30 '18 at 7:04













          @AnhPham, thank you for your comment. done

          – Reza energy
          Dec 30 '18 at 18:37





          @AnhPham, thank you for your comment. done

          – Reza energy
          Dec 30 '18 at 18:37


















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