How To Convert a nested for Loop to Recursive












-3














Can anyone help me converting this for loop into a recursive method:
So far I added these two methods but I still want to change the second loop.
Thank you in advance.



       public void makeDesign1() {
int x;
for (int i = 0; i < 5; i++) // For loop is the one creating the rows
{
for (x = 4; x > i; x--) // Nested loop is the one creating the columns
{
System.out.print("*");
}
System.out.println();
}
System.out.println();

}

public static int makeDesign1Recur(int i) {

if (i == 0) {
return 0;
}
System.out.print("*");
return (makeDesign1Recur(i-1));
}
// How to convert this second loop recursive?
public static void makeDesignRow(int i){
for ( int x = i; x>=0; x--){
makeDesign1Recur(x);
System.out.println("");
}


}









share|improve this question




















  • 1




    Your inner for loop won't even execute, I think, because i has a max value of 4. You might want to add a problem statement to your question. There is nothing wrong with expressing a problem using two for loops, by the way.
    – Tim Biegeleisen
    Nov 12 '18 at 1:14






  • 1




    Please show your attempt and highlight where you are having problems. We won't do your work for you, but will help you if you show what you have done.
    – Erwin Bolwidt
    Nov 12 '18 at 1:15










  • it does work. It prints something like:
    – sannicko
    Nov 12 '18 at 1:16










  • something like this, a few starts on screen: **** *** ** *
    – sannicko
    Nov 12 '18 at 1:16










  • I need to convert the same for loop into recursive method.
    – sannicko
    Nov 12 '18 at 1:17
















-3














Can anyone help me converting this for loop into a recursive method:
So far I added these two methods but I still want to change the second loop.
Thank you in advance.



       public void makeDesign1() {
int x;
for (int i = 0; i < 5; i++) // For loop is the one creating the rows
{
for (x = 4; x > i; x--) // Nested loop is the one creating the columns
{
System.out.print("*");
}
System.out.println();
}
System.out.println();

}

public static int makeDesign1Recur(int i) {

if (i == 0) {
return 0;
}
System.out.print("*");
return (makeDesign1Recur(i-1));
}
// How to convert this second loop recursive?
public static void makeDesignRow(int i){
for ( int x = i; x>=0; x--){
makeDesign1Recur(x);
System.out.println("");
}


}









share|improve this question




















  • 1




    Your inner for loop won't even execute, I think, because i has a max value of 4. You might want to add a problem statement to your question. There is nothing wrong with expressing a problem using two for loops, by the way.
    – Tim Biegeleisen
    Nov 12 '18 at 1:14






  • 1




    Please show your attempt and highlight where you are having problems. We won't do your work for you, but will help you if you show what you have done.
    – Erwin Bolwidt
    Nov 12 '18 at 1:15










  • it does work. It prints something like:
    – sannicko
    Nov 12 '18 at 1:16










  • something like this, a few starts on screen: **** *** ** *
    – sannicko
    Nov 12 '18 at 1:16










  • I need to convert the same for loop into recursive method.
    – sannicko
    Nov 12 '18 at 1:17














-3












-3








-3







Can anyone help me converting this for loop into a recursive method:
So far I added these two methods but I still want to change the second loop.
Thank you in advance.



       public void makeDesign1() {
int x;
for (int i = 0; i < 5; i++) // For loop is the one creating the rows
{
for (x = 4; x > i; x--) // Nested loop is the one creating the columns
{
System.out.print("*");
}
System.out.println();
}
System.out.println();

}

public static int makeDesign1Recur(int i) {

if (i == 0) {
return 0;
}
System.out.print("*");
return (makeDesign1Recur(i-1));
}
// How to convert this second loop recursive?
public static void makeDesignRow(int i){
for ( int x = i; x>=0; x--){
makeDesign1Recur(x);
System.out.println("");
}


}









share|improve this question















Can anyone help me converting this for loop into a recursive method:
So far I added these two methods but I still want to change the second loop.
Thank you in advance.



       public void makeDesign1() {
int x;
for (int i = 0; i < 5; i++) // For loop is the one creating the rows
{
for (x = 4; x > i; x--) // Nested loop is the one creating the columns
{
System.out.print("*");
}
System.out.println();
}
System.out.println();

}

public static int makeDesign1Recur(int i) {

if (i == 0) {
return 0;
}
System.out.print("*");
return (makeDesign1Recur(i-1));
}
// How to convert this second loop recursive?
public static void makeDesignRow(int i){
for ( int x = i; x>=0; x--){
makeDesign1Recur(x);
System.out.println("");
}


}






java loops for-loop recursion






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edited Nov 12 '18 at 3:17

























asked Nov 12 '18 at 1:12









sannicko

12




12








  • 1




    Your inner for loop won't even execute, I think, because i has a max value of 4. You might want to add a problem statement to your question. There is nothing wrong with expressing a problem using two for loops, by the way.
    – Tim Biegeleisen
    Nov 12 '18 at 1:14






  • 1




    Please show your attempt and highlight where you are having problems. We won't do your work for you, but will help you if you show what you have done.
    – Erwin Bolwidt
    Nov 12 '18 at 1:15










  • it does work. It prints something like:
    – sannicko
    Nov 12 '18 at 1:16










  • something like this, a few starts on screen: **** *** ** *
    – sannicko
    Nov 12 '18 at 1:16










  • I need to convert the same for loop into recursive method.
    – sannicko
    Nov 12 '18 at 1:17














  • 1




    Your inner for loop won't even execute, I think, because i has a max value of 4. You might want to add a problem statement to your question. There is nothing wrong with expressing a problem using two for loops, by the way.
    – Tim Biegeleisen
    Nov 12 '18 at 1:14






  • 1




    Please show your attempt and highlight where you are having problems. We won't do your work for you, but will help you if you show what you have done.
    – Erwin Bolwidt
    Nov 12 '18 at 1:15










  • it does work. It prints something like:
    – sannicko
    Nov 12 '18 at 1:16










  • something like this, a few starts on screen: **** *** ** *
    – sannicko
    Nov 12 '18 at 1:16










  • I need to convert the same for loop into recursive method.
    – sannicko
    Nov 12 '18 at 1:17








1




1




Your inner for loop won't even execute, I think, because i has a max value of 4. You might want to add a problem statement to your question. There is nothing wrong with expressing a problem using two for loops, by the way.
– Tim Biegeleisen
Nov 12 '18 at 1:14




Your inner for loop won't even execute, I think, because i has a max value of 4. You might want to add a problem statement to your question. There is nothing wrong with expressing a problem using two for loops, by the way.
– Tim Biegeleisen
Nov 12 '18 at 1:14




1




1




Please show your attempt and highlight where you are having problems. We won't do your work for you, but will help you if you show what you have done.
– Erwin Bolwidt
Nov 12 '18 at 1:15




Please show your attempt and highlight where you are having problems. We won't do your work for you, but will help you if you show what you have done.
– Erwin Bolwidt
Nov 12 '18 at 1:15












it does work. It prints something like:
– sannicko
Nov 12 '18 at 1:16




it does work. It prints something like:
– sannicko
Nov 12 '18 at 1:16












something like this, a few starts on screen: **** *** ** *
– sannicko
Nov 12 '18 at 1:16




something like this, a few starts on screen: **** *** ** *
– sannicko
Nov 12 '18 at 1:16












I need to convert the same for loop into recursive method.
– sannicko
Nov 12 '18 at 1:17




I need to convert the same for loop into recursive method.
– sannicko
Nov 12 '18 at 1:17












1 Answer
1






active

oldest

votes


















0














I see the first step as redefining makeDesign1() correctly. We want to pass in a size for our drawing. We also want to change the bounds slightly so a size of 1 draws one star, instead of none like the original:



public static void makeDesign(int n) 
{
for (int i = 0; i < n; i++) // For loop is the one creating the rows
{
for (int x = n; x > i; x--) // Nested loop is the one creating the columns
{
System.out.print("*");
}

System.out.println();
}

System.out.println();
}


The next step is to get both loops to count down to 1 to simplify the recursion when the time comes:



public static void makeDesign(int n) 
{
for (int i = n; i > 0; i--) // For loop is the one creating the rows
{
for (int x = i; x > 0; x--) // Nested loop is the one creating the columns
{
System.out.print("*");
}

System.out.println();
}

System.out.println();
}


Now we can simply convert each loop into it's own recursive function, one calling the other:



public static void makeDesign(int n) 
{
if (n > 0)
{
makeDesignRow(n);
makeDesign(n - 1);
}
else
{
System.out.println();
}
}

public static void makeDesignRow(int x)
{
if (x > 0)
{
System.out.print("*");
makeDesignRow(x - 1);
}
else
{
System.out.println();
}
}


OUTPUT



Passing makeDesign() an argument of 10, we get:



> java Main
**********
*********
********
*******
******
*****
****
***
**
*

>





share|improve this answer





















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    active

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    oldest

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    active

    oldest

    votes









    0














    I see the first step as redefining makeDesign1() correctly. We want to pass in a size for our drawing. We also want to change the bounds slightly so a size of 1 draws one star, instead of none like the original:



    public static void makeDesign(int n) 
    {
    for (int i = 0; i < n; i++) // For loop is the one creating the rows
    {
    for (int x = n; x > i; x--) // Nested loop is the one creating the columns
    {
    System.out.print("*");
    }

    System.out.println();
    }

    System.out.println();
    }


    The next step is to get both loops to count down to 1 to simplify the recursion when the time comes:



    public static void makeDesign(int n) 
    {
    for (int i = n; i > 0; i--) // For loop is the one creating the rows
    {
    for (int x = i; x > 0; x--) // Nested loop is the one creating the columns
    {
    System.out.print("*");
    }

    System.out.println();
    }

    System.out.println();
    }


    Now we can simply convert each loop into it's own recursive function, one calling the other:



    public static void makeDesign(int n) 
    {
    if (n > 0)
    {
    makeDesignRow(n);
    makeDesign(n - 1);
    }
    else
    {
    System.out.println();
    }
    }

    public static void makeDesignRow(int x)
    {
    if (x > 0)
    {
    System.out.print("*");
    makeDesignRow(x - 1);
    }
    else
    {
    System.out.println();
    }
    }


    OUTPUT



    Passing makeDesign() an argument of 10, we get:



    > java Main
    **********
    *********
    ********
    *******
    ******
    *****
    ****
    ***
    **
    *

    >





    share|improve this answer


























      0














      I see the first step as redefining makeDesign1() correctly. We want to pass in a size for our drawing. We also want to change the bounds slightly so a size of 1 draws one star, instead of none like the original:



      public static void makeDesign(int n) 
      {
      for (int i = 0; i < n; i++) // For loop is the one creating the rows
      {
      for (int x = n; x > i; x--) // Nested loop is the one creating the columns
      {
      System.out.print("*");
      }

      System.out.println();
      }

      System.out.println();
      }


      The next step is to get both loops to count down to 1 to simplify the recursion when the time comes:



      public static void makeDesign(int n) 
      {
      for (int i = n; i > 0; i--) // For loop is the one creating the rows
      {
      for (int x = i; x > 0; x--) // Nested loop is the one creating the columns
      {
      System.out.print("*");
      }

      System.out.println();
      }

      System.out.println();
      }


      Now we can simply convert each loop into it's own recursive function, one calling the other:



      public static void makeDesign(int n) 
      {
      if (n > 0)
      {
      makeDesignRow(n);
      makeDesign(n - 1);
      }
      else
      {
      System.out.println();
      }
      }

      public static void makeDesignRow(int x)
      {
      if (x > 0)
      {
      System.out.print("*");
      makeDesignRow(x - 1);
      }
      else
      {
      System.out.println();
      }
      }


      OUTPUT



      Passing makeDesign() an argument of 10, we get:



      > java Main
      **********
      *********
      ********
      *******
      ******
      *****
      ****
      ***
      **
      *

      >





      share|improve this answer
























        0












        0








        0






        I see the first step as redefining makeDesign1() correctly. We want to pass in a size for our drawing. We also want to change the bounds slightly so a size of 1 draws one star, instead of none like the original:



        public static void makeDesign(int n) 
        {
        for (int i = 0; i < n; i++) // For loop is the one creating the rows
        {
        for (int x = n; x > i; x--) // Nested loop is the one creating the columns
        {
        System.out.print("*");
        }

        System.out.println();
        }

        System.out.println();
        }


        The next step is to get both loops to count down to 1 to simplify the recursion when the time comes:



        public static void makeDesign(int n) 
        {
        for (int i = n; i > 0; i--) // For loop is the one creating the rows
        {
        for (int x = i; x > 0; x--) // Nested loop is the one creating the columns
        {
        System.out.print("*");
        }

        System.out.println();
        }

        System.out.println();
        }


        Now we can simply convert each loop into it's own recursive function, one calling the other:



        public static void makeDesign(int n) 
        {
        if (n > 0)
        {
        makeDesignRow(n);
        makeDesign(n - 1);
        }
        else
        {
        System.out.println();
        }
        }

        public static void makeDesignRow(int x)
        {
        if (x > 0)
        {
        System.out.print("*");
        makeDesignRow(x - 1);
        }
        else
        {
        System.out.println();
        }
        }


        OUTPUT



        Passing makeDesign() an argument of 10, we get:



        > java Main
        **********
        *********
        ********
        *******
        ******
        *****
        ****
        ***
        **
        *

        >





        share|improve this answer












        I see the first step as redefining makeDesign1() correctly. We want to pass in a size for our drawing. We also want to change the bounds slightly so a size of 1 draws one star, instead of none like the original:



        public static void makeDesign(int n) 
        {
        for (int i = 0; i < n; i++) // For loop is the one creating the rows
        {
        for (int x = n; x > i; x--) // Nested loop is the one creating the columns
        {
        System.out.print("*");
        }

        System.out.println();
        }

        System.out.println();
        }


        The next step is to get both loops to count down to 1 to simplify the recursion when the time comes:



        public static void makeDesign(int n) 
        {
        for (int i = n; i > 0; i--) // For loop is the one creating the rows
        {
        for (int x = i; x > 0; x--) // Nested loop is the one creating the columns
        {
        System.out.print("*");
        }

        System.out.println();
        }

        System.out.println();
        }


        Now we can simply convert each loop into it's own recursive function, one calling the other:



        public static void makeDesign(int n) 
        {
        if (n > 0)
        {
        makeDesignRow(n);
        makeDesign(n - 1);
        }
        else
        {
        System.out.println();
        }
        }

        public static void makeDesignRow(int x)
        {
        if (x > 0)
        {
        System.out.print("*");
        makeDesignRow(x - 1);
        }
        else
        {
        System.out.println();
        }
        }


        OUTPUT



        Passing makeDesign() an argument of 10, we get:



        > java Main
        **********
        *********
        ********
        *******
        ******
        *****
        ****
        ***
        **
        *

        >






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 '18 at 6:57









        cdlane

        17.2k21043




        17.2k21043






























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