RxJS - receiving data in batches of time + max











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I'm playing with RxJS for the first time, and I'm trying to create a simple observable that will take both a maximum number of entries and wait for a time interval to pass before passing the data on to subscribers.



This is what I have:



import EventEmitter from "events";

import { fromEvent } from "rxjs";
import { bufferTime, filter, take } from "rxjs/operators";

const ev = new EventEmitter();
const observer = fromEvent(ev, "log").pipe(
take(10),
bufferTime(1000),
filter(logs => !!logs.length)
);

observer.subscribe(data => {
console.log(`received: ${data.length}`);
});

for (let i = 0; i < 100; i++) {
ev.emit("log", { hello: "world" });
}


What I expected to happen:



received: 10 to be printed 10x, at 1 second intervals.



What actually happened:



received: 10 was printed once, and then the script exits.



Why I think it's happening



I'm new to RxJS, but from what I can gather the take() operator emits a 'completed' status after it has taken 10 entries, which prevents any further subscriptions from firing.



How do I make this observable 'recurring' so that it'll a) take a maximum of 10, b) ensure it runs, at most, once every 1000ms, and c) repeat forever?










share|improve this question






















  • unfortunately cannot give your a solution for your problem, but you may have a look at bufferCount and bufferTime learnrxjs.io/operators/transformation/buffercount.html learnrxjs.io/operators/transformation/buffertime.html
    – Oleksandr Fedotov
    Nov 11 at 12:57












  • @OleksandrFedotov - thanks. I'm already (attempting to) use bufferTime in my example code, and bufferCount looks like it waits until the buffer is full, which is not what I want. I just want to take a maximum of 10 and run - at most - once per second... then repeat ad infinitum.
    – Lee Benson
    Nov 11 at 13:09










  • maybe the expand operator can help here for the recursion: learnrxjs.io/operators/transformation/expand.html
    – René Winkler
    Nov 11 at 14:52










  • @RenéWinkler - could you point to any examples of how expand might apply in this case, please?
    – Lee Benson
    Nov 11 at 15:16















up vote
0
down vote

favorite












I'm playing with RxJS for the first time, and I'm trying to create a simple observable that will take both a maximum number of entries and wait for a time interval to pass before passing the data on to subscribers.



This is what I have:



import EventEmitter from "events";

import { fromEvent } from "rxjs";
import { bufferTime, filter, take } from "rxjs/operators";

const ev = new EventEmitter();
const observer = fromEvent(ev, "log").pipe(
take(10),
bufferTime(1000),
filter(logs => !!logs.length)
);

observer.subscribe(data => {
console.log(`received: ${data.length}`);
});

for (let i = 0; i < 100; i++) {
ev.emit("log", { hello: "world" });
}


What I expected to happen:



received: 10 to be printed 10x, at 1 second intervals.



What actually happened:



received: 10 was printed once, and then the script exits.



Why I think it's happening



I'm new to RxJS, but from what I can gather the take() operator emits a 'completed' status after it has taken 10 entries, which prevents any further subscriptions from firing.



How do I make this observable 'recurring' so that it'll a) take a maximum of 10, b) ensure it runs, at most, once every 1000ms, and c) repeat forever?










share|improve this question






















  • unfortunately cannot give your a solution for your problem, but you may have a look at bufferCount and bufferTime learnrxjs.io/operators/transformation/buffercount.html learnrxjs.io/operators/transformation/buffertime.html
    – Oleksandr Fedotov
    Nov 11 at 12:57












  • @OleksandrFedotov - thanks. I'm already (attempting to) use bufferTime in my example code, and bufferCount looks like it waits until the buffer is full, which is not what I want. I just want to take a maximum of 10 and run - at most - once per second... then repeat ad infinitum.
    – Lee Benson
    Nov 11 at 13:09










  • maybe the expand operator can help here for the recursion: learnrxjs.io/operators/transformation/expand.html
    – René Winkler
    Nov 11 at 14:52










  • @RenéWinkler - could you point to any examples of how expand might apply in this case, please?
    – Lee Benson
    Nov 11 at 15:16













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I'm playing with RxJS for the first time, and I'm trying to create a simple observable that will take both a maximum number of entries and wait for a time interval to pass before passing the data on to subscribers.



This is what I have:



import EventEmitter from "events";

import { fromEvent } from "rxjs";
import { bufferTime, filter, take } from "rxjs/operators";

const ev = new EventEmitter();
const observer = fromEvent(ev, "log").pipe(
take(10),
bufferTime(1000),
filter(logs => !!logs.length)
);

observer.subscribe(data => {
console.log(`received: ${data.length}`);
});

for (let i = 0; i < 100; i++) {
ev.emit("log", { hello: "world" });
}


What I expected to happen:



received: 10 to be printed 10x, at 1 second intervals.



What actually happened:



received: 10 was printed once, and then the script exits.



Why I think it's happening



I'm new to RxJS, but from what I can gather the take() operator emits a 'completed' status after it has taken 10 entries, which prevents any further subscriptions from firing.



How do I make this observable 'recurring' so that it'll a) take a maximum of 10, b) ensure it runs, at most, once every 1000ms, and c) repeat forever?










share|improve this question













I'm playing with RxJS for the first time, and I'm trying to create a simple observable that will take both a maximum number of entries and wait for a time interval to pass before passing the data on to subscribers.



This is what I have:



import EventEmitter from "events";

import { fromEvent } from "rxjs";
import { bufferTime, filter, take } from "rxjs/operators";

const ev = new EventEmitter();
const observer = fromEvent(ev, "log").pipe(
take(10),
bufferTime(1000),
filter(logs => !!logs.length)
);

observer.subscribe(data => {
console.log(`received: ${data.length}`);
});

for (let i = 0; i < 100; i++) {
ev.emit("log", { hello: "world" });
}


What I expected to happen:



received: 10 to be printed 10x, at 1 second intervals.



What actually happened:



received: 10 was printed once, and then the script exits.



Why I think it's happening



I'm new to RxJS, but from what I can gather the take() operator emits a 'completed' status after it has taken 10 entries, which prevents any further subscriptions from firing.



How do I make this observable 'recurring' so that it'll a) take a maximum of 10, b) ensure it runs, at most, once every 1000ms, and c) repeat forever?







rxjs rxjs6






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 11 at 12:16









Lee Benson

4,74533041




4,74533041












  • unfortunately cannot give your a solution for your problem, but you may have a look at bufferCount and bufferTime learnrxjs.io/operators/transformation/buffercount.html learnrxjs.io/operators/transformation/buffertime.html
    – Oleksandr Fedotov
    Nov 11 at 12:57












  • @OleksandrFedotov - thanks. I'm already (attempting to) use bufferTime in my example code, and bufferCount looks like it waits until the buffer is full, which is not what I want. I just want to take a maximum of 10 and run - at most - once per second... then repeat ad infinitum.
    – Lee Benson
    Nov 11 at 13:09










  • maybe the expand operator can help here for the recursion: learnrxjs.io/operators/transformation/expand.html
    – René Winkler
    Nov 11 at 14:52










  • @RenéWinkler - could you point to any examples of how expand might apply in this case, please?
    – Lee Benson
    Nov 11 at 15:16


















  • unfortunately cannot give your a solution for your problem, but you may have a look at bufferCount and bufferTime learnrxjs.io/operators/transformation/buffercount.html learnrxjs.io/operators/transformation/buffertime.html
    – Oleksandr Fedotov
    Nov 11 at 12:57












  • @OleksandrFedotov - thanks. I'm already (attempting to) use bufferTime in my example code, and bufferCount looks like it waits until the buffer is full, which is not what I want. I just want to take a maximum of 10 and run - at most - once per second... then repeat ad infinitum.
    – Lee Benson
    Nov 11 at 13:09










  • maybe the expand operator can help here for the recursion: learnrxjs.io/operators/transformation/expand.html
    – René Winkler
    Nov 11 at 14:52










  • @RenéWinkler - could you point to any examples of how expand might apply in this case, please?
    – Lee Benson
    Nov 11 at 15:16
















unfortunately cannot give your a solution for your problem, but you may have a look at bufferCount and bufferTime learnrxjs.io/operators/transformation/buffercount.html learnrxjs.io/operators/transformation/buffertime.html
– Oleksandr Fedotov
Nov 11 at 12:57






unfortunately cannot give your a solution for your problem, but you may have a look at bufferCount and bufferTime learnrxjs.io/operators/transformation/buffercount.html learnrxjs.io/operators/transformation/buffertime.html
– Oleksandr Fedotov
Nov 11 at 12:57














@OleksandrFedotov - thanks. I'm already (attempting to) use bufferTime in my example code, and bufferCount looks like it waits until the buffer is full, which is not what I want. I just want to take a maximum of 10 and run - at most - once per second... then repeat ad infinitum.
– Lee Benson
Nov 11 at 13:09




@OleksandrFedotov - thanks. I'm already (attempting to) use bufferTime in my example code, and bufferCount looks like it waits until the buffer is full, which is not what I want. I just want to take a maximum of 10 and run - at most - once per second... then repeat ad infinitum.
– Lee Benson
Nov 11 at 13:09












maybe the expand operator can help here for the recursion: learnrxjs.io/operators/transformation/expand.html
– René Winkler
Nov 11 at 14:52




maybe the expand operator can help here for the recursion: learnrxjs.io/operators/transformation/expand.html
– René Winkler
Nov 11 at 14:52












@RenéWinkler - could you point to any examples of how expand might apply in this case, please?
– Lee Benson
Nov 11 at 15:16




@RenéWinkler - could you point to any examples of how expand might apply in this case, please?
– Lee Benson
Nov 11 at 15:16












2 Answers
2






active

oldest

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up vote
0
down vote













Try to insert a simple tap(d => console.log(JSON.stringify(d))), operator before take(10) and after bufferTime and you see what happens.



Basically you have a loop that emits 100 events. Out of this loop you create an Observable which notifies 100 times the object emitted by you event loop.



This whole thing happens synchronously in your example.



Then the Observable is transformed by a pipe which does the following:




  • first takes just the first 10 notifications via the take operator

  • then says "accumulate all the notifications which happen in the first
    1 second and emit them in form of an array" - considering that the
    whole emission process is synchronous and that you take the first 10
    of them, then bufferTime(1000) will emit one array of 10 items
    after 1 second

  • nothing else will be emitted by this stream, since take(10)
    completes the source Observable after 10 synchronous notifications,
    so the filter operator is of no use

  • last, in the subscription you receive just 1 notification, i.e. the only one emitted by bufferTime


Said that, probably what you want to achieve can be accomplished by code along these lines



const ev = new EventEmitter();

function simpleObservable(maxEntries: number, waitTime: number) {
return fromEvent(ev, "log").pipe(
bufferCount(maxEntries),
filter(logs => !!logs.length),
mergeMap(logs => of(logs).pipe(delay(waitTime)), 1),
)
}

simpleObservable(10, 1000)
.subscribe(data => {
console.log(`received: ${data.length}`);
});

for (let i = 0; i < 100; i++) {
ev.emit("log", { hello: "world" });
}


The key here is that first you slice the stream of events into arrays of 10 events each, and this is done via the bufferCount operator.



Then you introduce the asynchronicity using mergeMap with concurrency level set to 1 (which is equivalent to the operator concatMap). You basically transform each array emitted by bufferCount into another Observable via the of function and apply a delay of 1 second to each of the new Observables. Then you concatenate them so that they are emitted each after the other with the time difference of 1 second.



UPDATED RESPONSE after @Lee Benson comment



bufferTime can be the answer to your problem.



bufferTime has 3 parameters:





  • bufferTimeSpan: specifies the lifespan of the buffer, i.e. the Observable emits the buffer and resets it after at each interval
    specified by bufferTimeSpan


  • bufferCreationInterval: to be left null for our purpose


  • maxBufferSize: specifies the max size of the buffer - if the size is reached, then the Observable emits the buffer and resets it


So, if we use the first and the last parameter we should be able to reach the desired objectives.



This is the test I have put together



const ev = new EventEmitter();
// I merge to the event stream created by 'ev' a single notification emitted after 5 seconds,
// just to make the thing a bit more complex
const sourceObs = merge(
fromEvent(ev, "log"),
of(1).pipe(delay(5000))
)

function simpleObservable(maxEntries: number, waitTime: number) {
return sourceObs.pipe(
bufferTime(waitTime, null, maxEntries),
filter(logs => !!logs.length),
)
}

simpleObservable(10, 2000)
.subscribe(data => {
console.log(`received: ${data.length}`);
});

for (let i = 0; i < 19; i++) {
ev.emit("log", { hello: "world" });
}
// some other events are fired after 6 seconds, to make the source more complex
setTimeout(() => {
for (let i = 0; i < 17; i++) {
ev.emit("log", { hello: "world" });
}
}, 6000);





share|improve this answer























  • thanks. The issue I with bufferCount is that it's waiting until there's 10 items, and not firing if there's fewer. I'm trying to build a queue that will invoke .subscribe() whenever there's at least 1 result and at least 1 second has passed, in batches of a maximum of 10 per time.
    – Lee Benson
    Nov 11 at 14:41












  • If I look at your example, you are emitting synchronously 100 events. What is the behavior expected in this case? Do you want to invoke subscribe 10 times, each time with an array of 10 notifications, with an interval of 1 seconds each? Do you expect the 10 notifications to be given to subscribe as fast as possible?
    – Picci
    Nov 11 at 21:01










  • I have updated my answer
    – Picci
    Nov 11 at 21:35










  • thanks, that's closer, but still not quite there. If we change maxEntries to 4 and leave waitTime at 1000, we get 4x "Received: 4" messages back in the console after 1s, rather than each message buffered at 1s intervals. Another example: Change the loop to emit 28 events instead of 19; we'll get "Received: 10" twice after 1000ms, followed by a final "Received: 8". What should happen is "Received: 10" after 1s, "Received: 10" after 2s, "Received: 8" after 3s.
    – Lee Benson
    Nov 12 at 10:57












  • Looking at bufferTime some more, it seems like it emits when either the time has been exhausted, or the buffer has been reached - whichever is first. Hence in your example, "Received: 10" is printed immediately, followed by a 1000ms pause, then "Received: 9". What I'm trying to achieve is for the buffer time to be awaited always, and then as a secondary criteria, to not exceed maxEntries. Any extra entries should be buffered in the next iteration of bufferTime.
    – Lee Benson
    Nov 12 at 11:20


















up vote
0
down vote













After reading your last comment, a way to consider to solve the problem could be to combine bufferTime with interval using zip.



Basically the idea is that you can set a rhythm of notifications using interval - for instance you set interval(1000) to have an Observable that emits every second.



Then you can use bufferTime(1000, null, 10) to make sure that you emit an array every 1 second or if your buffer reaches 10 items, whichever comes first.



Now if you zip these 2 Observables you obtain an Observable which emits every second, because of interval(1000), and it emits also whatever comes out of bufferTime(1000, 0, 10) in sequence. So, if the source Observable emits more than 10 items in a second, the first 10 will be emitted in the first notification, the others will remain buffered in the Observable and will be emitted in the subsequent notifications in chunks of 10 every second.



The code probably makes this clearer.



const ev = new EventEmitter();
// I merge to the event stream created by 'ev' a single notification emitted after 5 seconds,
// just to make the thing a bit more complex
const sourceObs = merge(
fromEvent(ev, "log"),
of(1).pipe(delay(5000))
)

function simpleObservable(maxEntries: number, waitTime: number) {
return zip(
timer(0, waitTime),
sourceObs.pipe(
bufferTime(waitTime, null, maxEntries),
)
)
.pipe(
filter(logs => !!logs[1].length),
map(logs => logs[1])
)
}

const maxEntries = 4;
const waitTime = 1000;
simpleObservable(maxEntries, waitTime)
.subscribe(data => {
console.log(`received: ${data.length}`);
});

for (let i = 0; i < 19; i++) {
ev.emit("log", { hello: "world " + i + 'A' });
}
// some other events are fired after 8 seconds, to make the source more complex
setTimeout(() => {
for (let i = 0; i < 17; i++) {
ev.emit("log", { hello: "world " + i + 'B' });
}
}, 8000);


Clearly you need to consider that, if the source Observable emits at an speed higher than your ability to consume notifications, you may end up with memory problems.






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    2 Answers
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    2 Answers
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    up vote
    0
    down vote













    Try to insert a simple tap(d => console.log(JSON.stringify(d))), operator before take(10) and after bufferTime and you see what happens.



    Basically you have a loop that emits 100 events. Out of this loop you create an Observable which notifies 100 times the object emitted by you event loop.



    This whole thing happens synchronously in your example.



    Then the Observable is transformed by a pipe which does the following:




    • first takes just the first 10 notifications via the take operator

    • then says "accumulate all the notifications which happen in the first
      1 second and emit them in form of an array" - considering that the
      whole emission process is synchronous and that you take the first 10
      of them, then bufferTime(1000) will emit one array of 10 items
      after 1 second

    • nothing else will be emitted by this stream, since take(10)
      completes the source Observable after 10 synchronous notifications,
      so the filter operator is of no use

    • last, in the subscription you receive just 1 notification, i.e. the only one emitted by bufferTime


    Said that, probably what you want to achieve can be accomplished by code along these lines



    const ev = new EventEmitter();

    function simpleObservable(maxEntries: number, waitTime: number) {
    return fromEvent(ev, "log").pipe(
    bufferCount(maxEntries),
    filter(logs => !!logs.length),
    mergeMap(logs => of(logs).pipe(delay(waitTime)), 1),
    )
    }

    simpleObservable(10, 1000)
    .subscribe(data => {
    console.log(`received: ${data.length}`);
    });

    for (let i = 0; i < 100; i++) {
    ev.emit("log", { hello: "world" });
    }


    The key here is that first you slice the stream of events into arrays of 10 events each, and this is done via the bufferCount operator.



    Then you introduce the asynchronicity using mergeMap with concurrency level set to 1 (which is equivalent to the operator concatMap). You basically transform each array emitted by bufferCount into another Observable via the of function and apply a delay of 1 second to each of the new Observables. Then you concatenate them so that they are emitted each after the other with the time difference of 1 second.



    UPDATED RESPONSE after @Lee Benson comment



    bufferTime can be the answer to your problem.



    bufferTime has 3 parameters:





    • bufferTimeSpan: specifies the lifespan of the buffer, i.e. the Observable emits the buffer and resets it after at each interval
      specified by bufferTimeSpan


    • bufferCreationInterval: to be left null for our purpose


    • maxBufferSize: specifies the max size of the buffer - if the size is reached, then the Observable emits the buffer and resets it


    So, if we use the first and the last parameter we should be able to reach the desired objectives.



    This is the test I have put together



    const ev = new EventEmitter();
    // I merge to the event stream created by 'ev' a single notification emitted after 5 seconds,
    // just to make the thing a bit more complex
    const sourceObs = merge(
    fromEvent(ev, "log"),
    of(1).pipe(delay(5000))
    )

    function simpleObservable(maxEntries: number, waitTime: number) {
    return sourceObs.pipe(
    bufferTime(waitTime, null, maxEntries),
    filter(logs => !!logs.length),
    )
    }

    simpleObservable(10, 2000)
    .subscribe(data => {
    console.log(`received: ${data.length}`);
    });

    for (let i = 0; i < 19; i++) {
    ev.emit("log", { hello: "world" });
    }
    // some other events are fired after 6 seconds, to make the source more complex
    setTimeout(() => {
    for (let i = 0; i < 17; i++) {
    ev.emit("log", { hello: "world" });
    }
    }, 6000);





    share|improve this answer























    • thanks. The issue I with bufferCount is that it's waiting until there's 10 items, and not firing if there's fewer. I'm trying to build a queue that will invoke .subscribe() whenever there's at least 1 result and at least 1 second has passed, in batches of a maximum of 10 per time.
      – Lee Benson
      Nov 11 at 14:41












    • If I look at your example, you are emitting synchronously 100 events. What is the behavior expected in this case? Do you want to invoke subscribe 10 times, each time with an array of 10 notifications, with an interval of 1 seconds each? Do you expect the 10 notifications to be given to subscribe as fast as possible?
      – Picci
      Nov 11 at 21:01










    • I have updated my answer
      – Picci
      Nov 11 at 21:35










    • thanks, that's closer, but still not quite there. If we change maxEntries to 4 and leave waitTime at 1000, we get 4x "Received: 4" messages back in the console after 1s, rather than each message buffered at 1s intervals. Another example: Change the loop to emit 28 events instead of 19; we'll get "Received: 10" twice after 1000ms, followed by a final "Received: 8". What should happen is "Received: 10" after 1s, "Received: 10" after 2s, "Received: 8" after 3s.
      – Lee Benson
      Nov 12 at 10:57












    • Looking at bufferTime some more, it seems like it emits when either the time has been exhausted, or the buffer has been reached - whichever is first. Hence in your example, "Received: 10" is printed immediately, followed by a 1000ms pause, then "Received: 9". What I'm trying to achieve is for the buffer time to be awaited always, and then as a secondary criteria, to not exceed maxEntries. Any extra entries should be buffered in the next iteration of bufferTime.
      – Lee Benson
      Nov 12 at 11:20















    up vote
    0
    down vote













    Try to insert a simple tap(d => console.log(JSON.stringify(d))), operator before take(10) and after bufferTime and you see what happens.



    Basically you have a loop that emits 100 events. Out of this loop you create an Observable which notifies 100 times the object emitted by you event loop.



    This whole thing happens synchronously in your example.



    Then the Observable is transformed by a pipe which does the following:




    • first takes just the first 10 notifications via the take operator

    • then says "accumulate all the notifications which happen in the first
      1 second and emit them in form of an array" - considering that the
      whole emission process is synchronous and that you take the first 10
      of them, then bufferTime(1000) will emit one array of 10 items
      after 1 second

    • nothing else will be emitted by this stream, since take(10)
      completes the source Observable after 10 synchronous notifications,
      so the filter operator is of no use

    • last, in the subscription you receive just 1 notification, i.e. the only one emitted by bufferTime


    Said that, probably what you want to achieve can be accomplished by code along these lines



    const ev = new EventEmitter();

    function simpleObservable(maxEntries: number, waitTime: number) {
    return fromEvent(ev, "log").pipe(
    bufferCount(maxEntries),
    filter(logs => !!logs.length),
    mergeMap(logs => of(logs).pipe(delay(waitTime)), 1),
    )
    }

    simpleObservable(10, 1000)
    .subscribe(data => {
    console.log(`received: ${data.length}`);
    });

    for (let i = 0; i < 100; i++) {
    ev.emit("log", { hello: "world" });
    }


    The key here is that first you slice the stream of events into arrays of 10 events each, and this is done via the bufferCount operator.



    Then you introduce the asynchronicity using mergeMap with concurrency level set to 1 (which is equivalent to the operator concatMap). You basically transform each array emitted by bufferCount into another Observable via the of function and apply a delay of 1 second to each of the new Observables. Then you concatenate them so that they are emitted each after the other with the time difference of 1 second.



    UPDATED RESPONSE after @Lee Benson comment



    bufferTime can be the answer to your problem.



    bufferTime has 3 parameters:





    • bufferTimeSpan: specifies the lifespan of the buffer, i.e. the Observable emits the buffer and resets it after at each interval
      specified by bufferTimeSpan


    • bufferCreationInterval: to be left null for our purpose


    • maxBufferSize: specifies the max size of the buffer - if the size is reached, then the Observable emits the buffer and resets it


    So, if we use the first and the last parameter we should be able to reach the desired objectives.



    This is the test I have put together



    const ev = new EventEmitter();
    // I merge to the event stream created by 'ev' a single notification emitted after 5 seconds,
    // just to make the thing a bit more complex
    const sourceObs = merge(
    fromEvent(ev, "log"),
    of(1).pipe(delay(5000))
    )

    function simpleObservable(maxEntries: number, waitTime: number) {
    return sourceObs.pipe(
    bufferTime(waitTime, null, maxEntries),
    filter(logs => !!logs.length),
    )
    }

    simpleObservable(10, 2000)
    .subscribe(data => {
    console.log(`received: ${data.length}`);
    });

    for (let i = 0; i < 19; i++) {
    ev.emit("log", { hello: "world" });
    }
    // some other events are fired after 6 seconds, to make the source more complex
    setTimeout(() => {
    for (let i = 0; i < 17; i++) {
    ev.emit("log", { hello: "world" });
    }
    }, 6000);





    share|improve this answer























    • thanks. The issue I with bufferCount is that it's waiting until there's 10 items, and not firing if there's fewer. I'm trying to build a queue that will invoke .subscribe() whenever there's at least 1 result and at least 1 second has passed, in batches of a maximum of 10 per time.
      – Lee Benson
      Nov 11 at 14:41












    • If I look at your example, you are emitting synchronously 100 events. What is the behavior expected in this case? Do you want to invoke subscribe 10 times, each time with an array of 10 notifications, with an interval of 1 seconds each? Do you expect the 10 notifications to be given to subscribe as fast as possible?
      – Picci
      Nov 11 at 21:01










    • I have updated my answer
      – Picci
      Nov 11 at 21:35










    • thanks, that's closer, but still not quite there. If we change maxEntries to 4 and leave waitTime at 1000, we get 4x "Received: 4" messages back in the console after 1s, rather than each message buffered at 1s intervals. Another example: Change the loop to emit 28 events instead of 19; we'll get "Received: 10" twice after 1000ms, followed by a final "Received: 8". What should happen is "Received: 10" after 1s, "Received: 10" after 2s, "Received: 8" after 3s.
      – Lee Benson
      Nov 12 at 10:57












    • Looking at bufferTime some more, it seems like it emits when either the time has been exhausted, or the buffer has been reached - whichever is first. Hence in your example, "Received: 10" is printed immediately, followed by a 1000ms pause, then "Received: 9". What I'm trying to achieve is for the buffer time to be awaited always, and then as a secondary criteria, to not exceed maxEntries. Any extra entries should be buffered in the next iteration of bufferTime.
      – Lee Benson
      Nov 12 at 11:20













    up vote
    0
    down vote










    up vote
    0
    down vote









    Try to insert a simple tap(d => console.log(JSON.stringify(d))), operator before take(10) and after bufferTime and you see what happens.



    Basically you have a loop that emits 100 events. Out of this loop you create an Observable which notifies 100 times the object emitted by you event loop.



    This whole thing happens synchronously in your example.



    Then the Observable is transformed by a pipe which does the following:




    • first takes just the first 10 notifications via the take operator

    • then says "accumulate all the notifications which happen in the first
      1 second and emit them in form of an array" - considering that the
      whole emission process is synchronous and that you take the first 10
      of them, then bufferTime(1000) will emit one array of 10 items
      after 1 second

    • nothing else will be emitted by this stream, since take(10)
      completes the source Observable after 10 synchronous notifications,
      so the filter operator is of no use

    • last, in the subscription you receive just 1 notification, i.e. the only one emitted by bufferTime


    Said that, probably what you want to achieve can be accomplished by code along these lines



    const ev = new EventEmitter();

    function simpleObservable(maxEntries: number, waitTime: number) {
    return fromEvent(ev, "log").pipe(
    bufferCount(maxEntries),
    filter(logs => !!logs.length),
    mergeMap(logs => of(logs).pipe(delay(waitTime)), 1),
    )
    }

    simpleObservable(10, 1000)
    .subscribe(data => {
    console.log(`received: ${data.length}`);
    });

    for (let i = 0; i < 100; i++) {
    ev.emit("log", { hello: "world" });
    }


    The key here is that first you slice the stream of events into arrays of 10 events each, and this is done via the bufferCount operator.



    Then you introduce the asynchronicity using mergeMap with concurrency level set to 1 (which is equivalent to the operator concatMap). You basically transform each array emitted by bufferCount into another Observable via the of function and apply a delay of 1 second to each of the new Observables. Then you concatenate them so that they are emitted each after the other with the time difference of 1 second.



    UPDATED RESPONSE after @Lee Benson comment



    bufferTime can be the answer to your problem.



    bufferTime has 3 parameters:





    • bufferTimeSpan: specifies the lifespan of the buffer, i.e. the Observable emits the buffer and resets it after at each interval
      specified by bufferTimeSpan


    • bufferCreationInterval: to be left null for our purpose


    • maxBufferSize: specifies the max size of the buffer - if the size is reached, then the Observable emits the buffer and resets it


    So, if we use the first and the last parameter we should be able to reach the desired objectives.



    This is the test I have put together



    const ev = new EventEmitter();
    // I merge to the event stream created by 'ev' a single notification emitted after 5 seconds,
    // just to make the thing a bit more complex
    const sourceObs = merge(
    fromEvent(ev, "log"),
    of(1).pipe(delay(5000))
    )

    function simpleObservable(maxEntries: number, waitTime: number) {
    return sourceObs.pipe(
    bufferTime(waitTime, null, maxEntries),
    filter(logs => !!logs.length),
    )
    }

    simpleObservable(10, 2000)
    .subscribe(data => {
    console.log(`received: ${data.length}`);
    });

    for (let i = 0; i < 19; i++) {
    ev.emit("log", { hello: "world" });
    }
    // some other events are fired after 6 seconds, to make the source more complex
    setTimeout(() => {
    for (let i = 0; i < 17; i++) {
    ev.emit("log", { hello: "world" });
    }
    }, 6000);





    share|improve this answer














    Try to insert a simple tap(d => console.log(JSON.stringify(d))), operator before take(10) and after bufferTime and you see what happens.



    Basically you have a loop that emits 100 events. Out of this loop you create an Observable which notifies 100 times the object emitted by you event loop.



    This whole thing happens synchronously in your example.



    Then the Observable is transformed by a pipe which does the following:




    • first takes just the first 10 notifications via the take operator

    • then says "accumulate all the notifications which happen in the first
      1 second and emit them in form of an array" - considering that the
      whole emission process is synchronous and that you take the first 10
      of them, then bufferTime(1000) will emit one array of 10 items
      after 1 second

    • nothing else will be emitted by this stream, since take(10)
      completes the source Observable after 10 synchronous notifications,
      so the filter operator is of no use

    • last, in the subscription you receive just 1 notification, i.e. the only one emitted by bufferTime


    Said that, probably what you want to achieve can be accomplished by code along these lines



    const ev = new EventEmitter();

    function simpleObservable(maxEntries: number, waitTime: number) {
    return fromEvent(ev, "log").pipe(
    bufferCount(maxEntries),
    filter(logs => !!logs.length),
    mergeMap(logs => of(logs).pipe(delay(waitTime)), 1),
    )
    }

    simpleObservable(10, 1000)
    .subscribe(data => {
    console.log(`received: ${data.length}`);
    });

    for (let i = 0; i < 100; i++) {
    ev.emit("log", { hello: "world" });
    }


    The key here is that first you slice the stream of events into arrays of 10 events each, and this is done via the bufferCount operator.



    Then you introduce the asynchronicity using mergeMap with concurrency level set to 1 (which is equivalent to the operator concatMap). You basically transform each array emitted by bufferCount into another Observable via the of function and apply a delay of 1 second to each of the new Observables. Then you concatenate them so that they are emitted each after the other with the time difference of 1 second.



    UPDATED RESPONSE after @Lee Benson comment



    bufferTime can be the answer to your problem.



    bufferTime has 3 parameters:





    • bufferTimeSpan: specifies the lifespan of the buffer, i.e. the Observable emits the buffer and resets it after at each interval
      specified by bufferTimeSpan


    • bufferCreationInterval: to be left null for our purpose


    • maxBufferSize: specifies the max size of the buffer - if the size is reached, then the Observable emits the buffer and resets it


    So, if we use the first and the last parameter we should be able to reach the desired objectives.



    This is the test I have put together



    const ev = new EventEmitter();
    // I merge to the event stream created by 'ev' a single notification emitted after 5 seconds,
    // just to make the thing a bit more complex
    const sourceObs = merge(
    fromEvent(ev, "log"),
    of(1).pipe(delay(5000))
    )

    function simpleObservable(maxEntries: number, waitTime: number) {
    return sourceObs.pipe(
    bufferTime(waitTime, null, maxEntries),
    filter(logs => !!logs.length),
    )
    }

    simpleObservable(10, 2000)
    .subscribe(data => {
    console.log(`received: ${data.length}`);
    });

    for (let i = 0; i < 19; i++) {
    ev.emit("log", { hello: "world" });
    }
    // some other events are fired after 6 seconds, to make the source more complex
    setTimeout(() => {
    for (let i = 0; i < 17; i++) {
    ev.emit("log", { hello: "world" });
    }
    }, 6000);






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 11 at 21:35

























    answered Nov 11 at 14:05









    Picci

    5,08252348




    5,08252348












    • thanks. The issue I with bufferCount is that it's waiting until there's 10 items, and not firing if there's fewer. I'm trying to build a queue that will invoke .subscribe() whenever there's at least 1 result and at least 1 second has passed, in batches of a maximum of 10 per time.
      – Lee Benson
      Nov 11 at 14:41












    • If I look at your example, you are emitting synchronously 100 events. What is the behavior expected in this case? Do you want to invoke subscribe 10 times, each time with an array of 10 notifications, with an interval of 1 seconds each? Do you expect the 10 notifications to be given to subscribe as fast as possible?
      – Picci
      Nov 11 at 21:01










    • I have updated my answer
      – Picci
      Nov 11 at 21:35










    • thanks, that's closer, but still not quite there. If we change maxEntries to 4 and leave waitTime at 1000, we get 4x "Received: 4" messages back in the console after 1s, rather than each message buffered at 1s intervals. Another example: Change the loop to emit 28 events instead of 19; we'll get "Received: 10" twice after 1000ms, followed by a final "Received: 8". What should happen is "Received: 10" after 1s, "Received: 10" after 2s, "Received: 8" after 3s.
      – Lee Benson
      Nov 12 at 10:57












    • Looking at bufferTime some more, it seems like it emits when either the time has been exhausted, or the buffer has been reached - whichever is first. Hence in your example, "Received: 10" is printed immediately, followed by a 1000ms pause, then "Received: 9". What I'm trying to achieve is for the buffer time to be awaited always, and then as a secondary criteria, to not exceed maxEntries. Any extra entries should be buffered in the next iteration of bufferTime.
      – Lee Benson
      Nov 12 at 11:20


















    • thanks. The issue I with bufferCount is that it's waiting until there's 10 items, and not firing if there's fewer. I'm trying to build a queue that will invoke .subscribe() whenever there's at least 1 result and at least 1 second has passed, in batches of a maximum of 10 per time.
      – Lee Benson
      Nov 11 at 14:41












    • If I look at your example, you are emitting synchronously 100 events. What is the behavior expected in this case? Do you want to invoke subscribe 10 times, each time with an array of 10 notifications, with an interval of 1 seconds each? Do you expect the 10 notifications to be given to subscribe as fast as possible?
      – Picci
      Nov 11 at 21:01










    • I have updated my answer
      – Picci
      Nov 11 at 21:35










    • thanks, that's closer, but still not quite there. If we change maxEntries to 4 and leave waitTime at 1000, we get 4x "Received: 4" messages back in the console after 1s, rather than each message buffered at 1s intervals. Another example: Change the loop to emit 28 events instead of 19; we'll get "Received: 10" twice after 1000ms, followed by a final "Received: 8". What should happen is "Received: 10" after 1s, "Received: 10" after 2s, "Received: 8" after 3s.
      – Lee Benson
      Nov 12 at 10:57












    • Looking at bufferTime some more, it seems like it emits when either the time has been exhausted, or the buffer has been reached - whichever is first. Hence in your example, "Received: 10" is printed immediately, followed by a 1000ms pause, then "Received: 9". What I'm trying to achieve is for the buffer time to be awaited always, and then as a secondary criteria, to not exceed maxEntries. Any extra entries should be buffered in the next iteration of bufferTime.
      – Lee Benson
      Nov 12 at 11:20
















    thanks. The issue I with bufferCount is that it's waiting until there's 10 items, and not firing if there's fewer. I'm trying to build a queue that will invoke .subscribe() whenever there's at least 1 result and at least 1 second has passed, in batches of a maximum of 10 per time.
    – Lee Benson
    Nov 11 at 14:41






    thanks. The issue I with bufferCount is that it's waiting until there's 10 items, and not firing if there's fewer. I'm trying to build a queue that will invoke .subscribe() whenever there's at least 1 result and at least 1 second has passed, in batches of a maximum of 10 per time.
    – Lee Benson
    Nov 11 at 14:41














    If I look at your example, you are emitting synchronously 100 events. What is the behavior expected in this case? Do you want to invoke subscribe 10 times, each time with an array of 10 notifications, with an interval of 1 seconds each? Do you expect the 10 notifications to be given to subscribe as fast as possible?
    – Picci
    Nov 11 at 21:01




    If I look at your example, you are emitting synchronously 100 events. What is the behavior expected in this case? Do you want to invoke subscribe 10 times, each time with an array of 10 notifications, with an interval of 1 seconds each? Do you expect the 10 notifications to be given to subscribe as fast as possible?
    – Picci
    Nov 11 at 21:01












    I have updated my answer
    – Picci
    Nov 11 at 21:35




    I have updated my answer
    – Picci
    Nov 11 at 21:35












    thanks, that's closer, but still not quite there. If we change maxEntries to 4 and leave waitTime at 1000, we get 4x "Received: 4" messages back in the console after 1s, rather than each message buffered at 1s intervals. Another example: Change the loop to emit 28 events instead of 19; we'll get "Received: 10" twice after 1000ms, followed by a final "Received: 8". What should happen is "Received: 10" after 1s, "Received: 10" after 2s, "Received: 8" after 3s.
    – Lee Benson
    Nov 12 at 10:57






    thanks, that's closer, but still not quite there. If we change maxEntries to 4 and leave waitTime at 1000, we get 4x "Received: 4" messages back in the console after 1s, rather than each message buffered at 1s intervals. Another example: Change the loop to emit 28 events instead of 19; we'll get "Received: 10" twice after 1000ms, followed by a final "Received: 8". What should happen is "Received: 10" after 1s, "Received: 10" after 2s, "Received: 8" after 3s.
    – Lee Benson
    Nov 12 at 10:57














    Looking at bufferTime some more, it seems like it emits when either the time has been exhausted, or the buffer has been reached - whichever is first. Hence in your example, "Received: 10" is printed immediately, followed by a 1000ms pause, then "Received: 9". What I'm trying to achieve is for the buffer time to be awaited always, and then as a secondary criteria, to not exceed maxEntries. Any extra entries should be buffered in the next iteration of bufferTime.
    – Lee Benson
    Nov 12 at 11:20




    Looking at bufferTime some more, it seems like it emits when either the time has been exhausted, or the buffer has been reached - whichever is first. Hence in your example, "Received: 10" is printed immediately, followed by a 1000ms pause, then "Received: 9". What I'm trying to achieve is for the buffer time to be awaited always, and then as a secondary criteria, to not exceed maxEntries. Any extra entries should be buffered in the next iteration of bufferTime.
    – Lee Benson
    Nov 12 at 11:20












    up vote
    0
    down vote













    After reading your last comment, a way to consider to solve the problem could be to combine bufferTime with interval using zip.



    Basically the idea is that you can set a rhythm of notifications using interval - for instance you set interval(1000) to have an Observable that emits every second.



    Then you can use bufferTime(1000, null, 10) to make sure that you emit an array every 1 second or if your buffer reaches 10 items, whichever comes first.



    Now if you zip these 2 Observables you obtain an Observable which emits every second, because of interval(1000), and it emits also whatever comes out of bufferTime(1000, 0, 10) in sequence. So, if the source Observable emits more than 10 items in a second, the first 10 will be emitted in the first notification, the others will remain buffered in the Observable and will be emitted in the subsequent notifications in chunks of 10 every second.



    The code probably makes this clearer.



    const ev = new EventEmitter();
    // I merge to the event stream created by 'ev' a single notification emitted after 5 seconds,
    // just to make the thing a bit more complex
    const sourceObs = merge(
    fromEvent(ev, "log"),
    of(1).pipe(delay(5000))
    )

    function simpleObservable(maxEntries: number, waitTime: number) {
    return zip(
    timer(0, waitTime),
    sourceObs.pipe(
    bufferTime(waitTime, null, maxEntries),
    )
    )
    .pipe(
    filter(logs => !!logs[1].length),
    map(logs => logs[1])
    )
    }

    const maxEntries = 4;
    const waitTime = 1000;
    simpleObservable(maxEntries, waitTime)
    .subscribe(data => {
    console.log(`received: ${data.length}`);
    });

    for (let i = 0; i < 19; i++) {
    ev.emit("log", { hello: "world " + i + 'A' });
    }
    // some other events are fired after 8 seconds, to make the source more complex
    setTimeout(() => {
    for (let i = 0; i < 17; i++) {
    ev.emit("log", { hello: "world " + i + 'B' });
    }
    }, 8000);


    Clearly you need to consider that, if the source Observable emits at an speed higher than your ability to consume notifications, you may end up with memory problems.






    share|improve this answer

























      up vote
      0
      down vote













      After reading your last comment, a way to consider to solve the problem could be to combine bufferTime with interval using zip.



      Basically the idea is that you can set a rhythm of notifications using interval - for instance you set interval(1000) to have an Observable that emits every second.



      Then you can use bufferTime(1000, null, 10) to make sure that you emit an array every 1 second or if your buffer reaches 10 items, whichever comes first.



      Now if you zip these 2 Observables you obtain an Observable which emits every second, because of interval(1000), and it emits also whatever comes out of bufferTime(1000, 0, 10) in sequence. So, if the source Observable emits more than 10 items in a second, the first 10 will be emitted in the first notification, the others will remain buffered in the Observable and will be emitted in the subsequent notifications in chunks of 10 every second.



      The code probably makes this clearer.



      const ev = new EventEmitter();
      // I merge to the event stream created by 'ev' a single notification emitted after 5 seconds,
      // just to make the thing a bit more complex
      const sourceObs = merge(
      fromEvent(ev, "log"),
      of(1).pipe(delay(5000))
      )

      function simpleObservable(maxEntries: number, waitTime: number) {
      return zip(
      timer(0, waitTime),
      sourceObs.pipe(
      bufferTime(waitTime, null, maxEntries),
      )
      )
      .pipe(
      filter(logs => !!logs[1].length),
      map(logs => logs[1])
      )
      }

      const maxEntries = 4;
      const waitTime = 1000;
      simpleObservable(maxEntries, waitTime)
      .subscribe(data => {
      console.log(`received: ${data.length}`);
      });

      for (let i = 0; i < 19; i++) {
      ev.emit("log", { hello: "world " + i + 'A' });
      }
      // some other events are fired after 8 seconds, to make the source more complex
      setTimeout(() => {
      for (let i = 0; i < 17; i++) {
      ev.emit("log", { hello: "world " + i + 'B' });
      }
      }, 8000);


      Clearly you need to consider that, if the source Observable emits at an speed higher than your ability to consume notifications, you may end up with memory problems.






      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        After reading your last comment, a way to consider to solve the problem could be to combine bufferTime with interval using zip.



        Basically the idea is that you can set a rhythm of notifications using interval - for instance you set interval(1000) to have an Observable that emits every second.



        Then you can use bufferTime(1000, null, 10) to make sure that you emit an array every 1 second or if your buffer reaches 10 items, whichever comes first.



        Now if you zip these 2 Observables you obtain an Observable which emits every second, because of interval(1000), and it emits also whatever comes out of bufferTime(1000, 0, 10) in sequence. So, if the source Observable emits more than 10 items in a second, the first 10 will be emitted in the first notification, the others will remain buffered in the Observable and will be emitted in the subsequent notifications in chunks of 10 every second.



        The code probably makes this clearer.



        const ev = new EventEmitter();
        // I merge to the event stream created by 'ev' a single notification emitted after 5 seconds,
        // just to make the thing a bit more complex
        const sourceObs = merge(
        fromEvent(ev, "log"),
        of(1).pipe(delay(5000))
        )

        function simpleObservable(maxEntries: number, waitTime: number) {
        return zip(
        timer(0, waitTime),
        sourceObs.pipe(
        bufferTime(waitTime, null, maxEntries),
        )
        )
        .pipe(
        filter(logs => !!logs[1].length),
        map(logs => logs[1])
        )
        }

        const maxEntries = 4;
        const waitTime = 1000;
        simpleObservable(maxEntries, waitTime)
        .subscribe(data => {
        console.log(`received: ${data.length}`);
        });

        for (let i = 0; i < 19; i++) {
        ev.emit("log", { hello: "world " + i + 'A' });
        }
        // some other events are fired after 8 seconds, to make the source more complex
        setTimeout(() => {
        for (let i = 0; i < 17; i++) {
        ev.emit("log", { hello: "world " + i + 'B' });
        }
        }, 8000);


        Clearly you need to consider that, if the source Observable emits at an speed higher than your ability to consume notifications, you may end up with memory problems.






        share|improve this answer












        After reading your last comment, a way to consider to solve the problem could be to combine bufferTime with interval using zip.



        Basically the idea is that you can set a rhythm of notifications using interval - for instance you set interval(1000) to have an Observable that emits every second.



        Then you can use bufferTime(1000, null, 10) to make sure that you emit an array every 1 second or if your buffer reaches 10 items, whichever comes first.



        Now if you zip these 2 Observables you obtain an Observable which emits every second, because of interval(1000), and it emits also whatever comes out of bufferTime(1000, 0, 10) in sequence. So, if the source Observable emits more than 10 items in a second, the first 10 will be emitted in the first notification, the others will remain buffered in the Observable and will be emitted in the subsequent notifications in chunks of 10 every second.



        The code probably makes this clearer.



        const ev = new EventEmitter();
        // I merge to the event stream created by 'ev' a single notification emitted after 5 seconds,
        // just to make the thing a bit more complex
        const sourceObs = merge(
        fromEvent(ev, "log"),
        of(1).pipe(delay(5000))
        )

        function simpleObservable(maxEntries: number, waitTime: number) {
        return zip(
        timer(0, waitTime),
        sourceObs.pipe(
        bufferTime(waitTime, null, maxEntries),
        )
        )
        .pipe(
        filter(logs => !!logs[1].length),
        map(logs => logs[1])
        )
        }

        const maxEntries = 4;
        const waitTime = 1000;
        simpleObservable(maxEntries, waitTime)
        .subscribe(data => {
        console.log(`received: ${data.length}`);
        });

        for (let i = 0; i < 19; i++) {
        ev.emit("log", { hello: "world " + i + 'A' });
        }
        // some other events are fired after 8 seconds, to make the source more complex
        setTimeout(() => {
        for (let i = 0; i < 17; i++) {
        ev.emit("log", { hello: "world " + i + 'B' });
        }
        }, 8000);


        Clearly you need to consider that, if the source Observable emits at an speed higher than your ability to consume notifications, you may end up with memory problems.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 at 17:52









        Picci

        5,08252348




        5,08252348






























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