How can I write this R expression in the pipe operator format?
I am trying to rewrite this expression to magrittr’s pipe operator:
print(mean(pull(df, height), na.rm=TRUE))
which returns 175.4 for my dataset.
I know that I have to start with the data frame and write it as >df%>% but I’m confused about how to write it inside out. For example, should the na.rm=TRUE go inside mean(), pull() or print()?
UPDATE: I actually figured it out by trial and error...
>df%>%
+pull(height)%>%
+mean(na.rm=TRUE)
+print()
returns 175.4
r pipe programming-languages data-science magrittr
add a comment |
I am trying to rewrite this expression to magrittr’s pipe operator:
print(mean(pull(df, height), na.rm=TRUE))
which returns 175.4 for my dataset.
I know that I have to start with the data frame and write it as >df%>% but I’m confused about how to write it inside out. For example, should the na.rm=TRUE go inside mean(), pull() or print()?
UPDATE: I actually figured it out by trial and error...
>df%>%
+pull(height)%>%
+mean(na.rm=TRUE)
+print()
returns 175.4
r pipe programming-languages data-science magrittr
1
see?mean
.na.rm
is an argument tomean
– Richard Telford
Nov 11 at 19:11
1
have you experimented a little bit? Also, tangentially: I'm always a little bit puzzled why people are trying to get such "pure tidy" expressions, except maybe for pedagogical purposes:print(mean(df$height), na.rm=TRUE)
(or(mean(na.omit(df$height)))
) seems perfectly easy to understand ...
– Ben Bolker
Nov 11 at 19:23
what have you tried so far? please provide a minimal, complete, and verifiable example
– landru27
Nov 11 at 19:30
add a comment |
I am trying to rewrite this expression to magrittr’s pipe operator:
print(mean(pull(df, height), na.rm=TRUE))
which returns 175.4 for my dataset.
I know that I have to start with the data frame and write it as >df%>% but I’m confused about how to write it inside out. For example, should the na.rm=TRUE go inside mean(), pull() or print()?
UPDATE: I actually figured it out by trial and error...
>df%>%
+pull(height)%>%
+mean(na.rm=TRUE)
+print()
returns 175.4
r pipe programming-languages data-science magrittr
I am trying to rewrite this expression to magrittr’s pipe operator:
print(mean(pull(df, height), na.rm=TRUE))
which returns 175.4 for my dataset.
I know that I have to start with the data frame and write it as >df%>% but I’m confused about how to write it inside out. For example, should the na.rm=TRUE go inside mean(), pull() or print()?
UPDATE: I actually figured it out by trial and error...
>df%>%
+pull(height)%>%
+mean(na.rm=TRUE)
+print()
returns 175.4
r pipe programming-languages data-science magrittr
r pipe programming-languages data-science magrittr
edited Nov 11 at 19:30
asked Nov 11 at 19:09
P. SN
12
12
1
see?mean
.na.rm
is an argument tomean
– Richard Telford
Nov 11 at 19:11
1
have you experimented a little bit? Also, tangentially: I'm always a little bit puzzled why people are trying to get such "pure tidy" expressions, except maybe for pedagogical purposes:print(mean(df$height), na.rm=TRUE)
(or(mean(na.omit(df$height)))
) seems perfectly easy to understand ...
– Ben Bolker
Nov 11 at 19:23
what have you tried so far? please provide a minimal, complete, and verifiable example
– landru27
Nov 11 at 19:30
add a comment |
1
see?mean
.na.rm
is an argument tomean
– Richard Telford
Nov 11 at 19:11
1
have you experimented a little bit? Also, tangentially: I'm always a little bit puzzled why people are trying to get such "pure tidy" expressions, except maybe for pedagogical purposes:print(mean(df$height), na.rm=TRUE)
(or(mean(na.omit(df$height)))
) seems perfectly easy to understand ...
– Ben Bolker
Nov 11 at 19:23
what have you tried so far? please provide a minimal, complete, and verifiable example
– landru27
Nov 11 at 19:30
1
1
see
?mean
. na.rm
is an argument to mean
– Richard Telford
Nov 11 at 19:11
see
?mean
. na.rm
is an argument to mean
– Richard Telford
Nov 11 at 19:11
1
1
have you experimented a little bit? Also, tangentially: I'm always a little bit puzzled why people are trying to get such "pure tidy" expressions, except maybe for pedagogical purposes:
print(mean(df$height), na.rm=TRUE)
(or (mean(na.omit(df$height)))
) seems perfectly easy to understand ...– Ben Bolker
Nov 11 at 19:23
have you experimented a little bit? Also, tangentially: I'm always a little bit puzzled why people are trying to get such "pure tidy" expressions, except maybe for pedagogical purposes:
print(mean(df$height), na.rm=TRUE)
(or (mean(na.omit(df$height)))
) seems perfectly easy to understand ...– Ben Bolker
Nov 11 at 19:23
what have you tried so far? please provide a minimal, complete, and verifiable example
– landru27
Nov 11 at 19:30
what have you tried so far? please provide a minimal, complete, and verifiable example
– landru27
Nov 11 at 19:30
add a comment |
1 Answer
1
active
oldest
votes
It would be good practice to make a reproducible example, with dummy data like this:
height <- seq(1:30)
weight <- seq(1:30)
df <- data.frame(height, weight)
These pipe operators work with the majority of the tidyverse (not just magrittr). What you are trying to do is actually coming out of dplyr. The na.rm=T is required for many summary variables like mean, sd, as well as certain functions used to gather specific data points like min, max, etc. These functions don't play well with NA values.
df %>% pull(height) %>% mean(na.rm=T) %>% print()
Unless your data is nested you may not even need to use pull
df %>% summarise(mean = mean(height,na.rm=T))
Also, using summarise you can pipe these into another dataframe rather than just printing, and call them out of the dataframe whenever you want.
df %>% summarise(meanHt = mean(height,na.rm=T), sdHt = sd(height,na.rm=T)) -> summary
summary[1]
summary[2]
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
It would be good practice to make a reproducible example, with dummy data like this:
height <- seq(1:30)
weight <- seq(1:30)
df <- data.frame(height, weight)
These pipe operators work with the majority of the tidyverse (not just magrittr). What you are trying to do is actually coming out of dplyr. The na.rm=T is required for many summary variables like mean, sd, as well as certain functions used to gather specific data points like min, max, etc. These functions don't play well with NA values.
df %>% pull(height) %>% mean(na.rm=T) %>% print()
Unless your data is nested you may not even need to use pull
df %>% summarise(mean = mean(height,na.rm=T))
Also, using summarise you can pipe these into another dataframe rather than just printing, and call them out of the dataframe whenever you want.
df %>% summarise(meanHt = mean(height,na.rm=T), sdHt = sd(height,na.rm=T)) -> summary
summary[1]
summary[2]
add a comment |
It would be good practice to make a reproducible example, with dummy data like this:
height <- seq(1:30)
weight <- seq(1:30)
df <- data.frame(height, weight)
These pipe operators work with the majority of the tidyverse (not just magrittr). What you are trying to do is actually coming out of dplyr. The na.rm=T is required for many summary variables like mean, sd, as well as certain functions used to gather specific data points like min, max, etc. These functions don't play well with NA values.
df %>% pull(height) %>% mean(na.rm=T) %>% print()
Unless your data is nested you may not even need to use pull
df %>% summarise(mean = mean(height,na.rm=T))
Also, using summarise you can pipe these into another dataframe rather than just printing, and call them out of the dataframe whenever you want.
df %>% summarise(meanHt = mean(height,na.rm=T), sdHt = sd(height,na.rm=T)) -> summary
summary[1]
summary[2]
add a comment |
It would be good practice to make a reproducible example, with dummy data like this:
height <- seq(1:30)
weight <- seq(1:30)
df <- data.frame(height, weight)
These pipe operators work with the majority of the tidyverse (not just magrittr). What you are trying to do is actually coming out of dplyr. The na.rm=T is required for many summary variables like mean, sd, as well as certain functions used to gather specific data points like min, max, etc. These functions don't play well with NA values.
df %>% pull(height) %>% mean(na.rm=T) %>% print()
Unless your data is nested you may not even need to use pull
df %>% summarise(mean = mean(height,na.rm=T))
Also, using summarise you can pipe these into another dataframe rather than just printing, and call them out of the dataframe whenever you want.
df %>% summarise(meanHt = mean(height,na.rm=T), sdHt = sd(height,na.rm=T)) -> summary
summary[1]
summary[2]
It would be good practice to make a reproducible example, with dummy data like this:
height <- seq(1:30)
weight <- seq(1:30)
df <- data.frame(height, weight)
These pipe operators work with the majority of the tidyverse (not just magrittr). What you are trying to do is actually coming out of dplyr. The na.rm=T is required for many summary variables like mean, sd, as well as certain functions used to gather specific data points like min, max, etc. These functions don't play well with NA values.
df %>% pull(height) %>% mean(na.rm=T) %>% print()
Unless your data is nested you may not even need to use pull
df %>% summarise(mean = mean(height,na.rm=T))
Also, using summarise you can pipe these into another dataframe rather than just printing, and call them out of the dataframe whenever you want.
df %>% summarise(meanHt = mean(height,na.rm=T), sdHt = sd(height,na.rm=T)) -> summary
summary[1]
summary[2]
answered Nov 11 at 19:27
Michael
1439
1439
add a comment |
add a comment |
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1
see
?mean
.na.rm
is an argument tomean
– Richard Telford
Nov 11 at 19:11
1
have you experimented a little bit? Also, tangentially: I'm always a little bit puzzled why people are trying to get such "pure tidy" expressions, except maybe for pedagogical purposes:
print(mean(df$height), na.rm=TRUE)
(or(mean(na.omit(df$height)))
) seems perfectly easy to understand ...– Ben Bolker
Nov 11 at 19:23
what have you tried so far? please provide a minimal, complete, and verifiable example
– landru27
Nov 11 at 19:30