How can you update a table with an ascending order position based on different groups in MYSQL?
I am struggling with this complex query. I am trying to insert the order position of some products.
For example,
I have currently table 1 with a position of NULL, I want to group each Product ID and assign each size a menu position based on ProductID group and using this FIND_IN_SET:
FIND_IN_SET(size,"UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60") asc;
In other words, I want it to look like Table2.
Table1
ID | ProductID | Size | Menu_position
1 | 100 | S | NULL
2 | 100 | M | NULL
3 | 100 | L | NULL
4 | 101 | 40 | NULL
5 | 101 | 41 | NULL
6 | 101 | 42 | NULL
7 | 102 | XS | NULL
8 | 102 | L | NULL
Table2
ID | ProductID | Size | Menu_position
1 | 100 | S | 1
2 | 100 | M | 2
3 | 100 | L | 3
4 | 101 | 40 | 1
5 | 101 | 41 | 2
6 | 101 | 42 | 3
7 | 102 | XS | 1
8 | 102 | L | 2
What I collected so far:
Number of products Group:select count(distinct ProductID) from Table1
Sort size based on specific order: SELECT * FROM Table1 ORDER BY FIND_IN_SET(size,"UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60") asc;
mysql sql if-statement while-loop
|
show 6 more comments
I am struggling with this complex query. I am trying to insert the order position of some products.
For example,
I have currently table 1 with a position of NULL, I want to group each Product ID and assign each size a menu position based on ProductID group and using this FIND_IN_SET:
FIND_IN_SET(size,"UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60") asc;
In other words, I want it to look like Table2.
Table1
ID | ProductID | Size | Menu_position
1 | 100 | S | NULL
2 | 100 | M | NULL
3 | 100 | L | NULL
4 | 101 | 40 | NULL
5 | 101 | 41 | NULL
6 | 101 | 42 | NULL
7 | 102 | XS | NULL
8 | 102 | L | NULL
Table2
ID | ProductID | Size | Menu_position
1 | 100 | S | 1
2 | 100 | M | 2
3 | 100 | L | 3
4 | 101 | 40 | 1
5 | 101 | 41 | 2
6 | 101 | 42 | 3
7 | 102 | XS | 1
8 | 102 | L | 2
What I collected so far:
Number of products Group:select count(distinct ProductID) from Table1
Sort size based on specific order: SELECT * FROM Table1 ORDER BY FIND_IN_SET(size,"UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60") asc;
mysql sql if-statement while-loop
what's the logic behind assigning such menu position?
– vivek_23
Nov 11 at 18:54
Do the menu positions for a Product ID have to be ascending? For example, if a product had only sizes "S" and "L", should the menu positions be 1 and 2, or are positions of 1 and 3 OK?
– rd_nielsen
Nov 11 at 19:00
You can put your sizes and menu position values (integers) into a table and join to that table to get the menu position for each size.
– rd_nielsen
Nov 11 at 19:01
@rd_nielsen Yes menu has to be chronological order 1 and 2, it cannot skip. This is why I just can't hard assign each value.
– Beck
Nov 11 at 19:06
@vivek_23 It is for a dropdown menu
– Beck
Nov 11 at 19:06
|
show 6 more comments
I am struggling with this complex query. I am trying to insert the order position of some products.
For example,
I have currently table 1 with a position of NULL, I want to group each Product ID and assign each size a menu position based on ProductID group and using this FIND_IN_SET:
FIND_IN_SET(size,"UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60") asc;
In other words, I want it to look like Table2.
Table1
ID | ProductID | Size | Menu_position
1 | 100 | S | NULL
2 | 100 | M | NULL
3 | 100 | L | NULL
4 | 101 | 40 | NULL
5 | 101 | 41 | NULL
6 | 101 | 42 | NULL
7 | 102 | XS | NULL
8 | 102 | L | NULL
Table2
ID | ProductID | Size | Menu_position
1 | 100 | S | 1
2 | 100 | M | 2
3 | 100 | L | 3
4 | 101 | 40 | 1
5 | 101 | 41 | 2
6 | 101 | 42 | 3
7 | 102 | XS | 1
8 | 102 | L | 2
What I collected so far:
Number of products Group:select count(distinct ProductID) from Table1
Sort size based on specific order: SELECT * FROM Table1 ORDER BY FIND_IN_SET(size,"UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60") asc;
mysql sql if-statement while-loop
I am struggling with this complex query. I am trying to insert the order position of some products.
For example,
I have currently table 1 with a position of NULL, I want to group each Product ID and assign each size a menu position based on ProductID group and using this FIND_IN_SET:
FIND_IN_SET(size,"UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60") asc;
In other words, I want it to look like Table2.
Table1
ID | ProductID | Size | Menu_position
1 | 100 | S | NULL
2 | 100 | M | NULL
3 | 100 | L | NULL
4 | 101 | 40 | NULL
5 | 101 | 41 | NULL
6 | 101 | 42 | NULL
7 | 102 | XS | NULL
8 | 102 | L | NULL
Table2
ID | ProductID | Size | Menu_position
1 | 100 | S | 1
2 | 100 | M | 2
3 | 100 | L | 3
4 | 101 | 40 | 1
5 | 101 | 41 | 2
6 | 101 | 42 | 3
7 | 102 | XS | 1
8 | 102 | L | 2
What I collected so far:
Number of products Group:select count(distinct ProductID) from Table1
Sort size based on specific order: SELECT * FROM Table1 ORDER BY FIND_IN_SET(size,"UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60") asc;
mysql sql if-statement while-loop
mysql sql if-statement while-loop
edited Nov 11 at 19:21
asked Nov 11 at 18:51
Beck
175
175
what's the logic behind assigning such menu position?
– vivek_23
Nov 11 at 18:54
Do the menu positions for a Product ID have to be ascending? For example, if a product had only sizes "S" and "L", should the menu positions be 1 and 2, or are positions of 1 and 3 OK?
– rd_nielsen
Nov 11 at 19:00
You can put your sizes and menu position values (integers) into a table and join to that table to get the menu position for each size.
– rd_nielsen
Nov 11 at 19:01
@rd_nielsen Yes menu has to be chronological order 1 and 2, it cannot skip. This is why I just can't hard assign each value.
– Beck
Nov 11 at 19:06
@vivek_23 It is for a dropdown menu
– Beck
Nov 11 at 19:06
|
show 6 more comments
what's the logic behind assigning such menu position?
– vivek_23
Nov 11 at 18:54
Do the menu positions for a Product ID have to be ascending? For example, if a product had only sizes "S" and "L", should the menu positions be 1 and 2, or are positions of 1 and 3 OK?
– rd_nielsen
Nov 11 at 19:00
You can put your sizes and menu position values (integers) into a table and join to that table to get the menu position for each size.
– rd_nielsen
Nov 11 at 19:01
@rd_nielsen Yes menu has to be chronological order 1 and 2, it cannot skip. This is why I just can't hard assign each value.
– Beck
Nov 11 at 19:06
@vivek_23 It is for a dropdown menu
– Beck
Nov 11 at 19:06
what's the logic behind assigning such menu position?
– vivek_23
Nov 11 at 18:54
what's the logic behind assigning such menu position?
– vivek_23
Nov 11 at 18:54
Do the menu positions for a Product ID have to be ascending? For example, if a product had only sizes "S" and "L", should the menu positions be 1 and 2, or are positions of 1 and 3 OK?
– rd_nielsen
Nov 11 at 19:00
Do the menu positions for a Product ID have to be ascending? For example, if a product had only sizes "S" and "L", should the menu positions be 1 and 2, or are positions of 1 and 3 OK?
– rd_nielsen
Nov 11 at 19:00
You can put your sizes and menu position values (integers) into a table and join to that table to get the menu position for each size.
– rd_nielsen
Nov 11 at 19:01
You can put your sizes and menu position values (integers) into a table and join to that table to get the menu position for each size.
– rd_nielsen
Nov 11 at 19:01
@rd_nielsen Yes menu has to be chronological order 1 and 2, it cannot skip. This is why I just can't hard assign each value.
– Beck
Nov 11 at 19:06
@rd_nielsen Yes menu has to be chronological order 1 and 2, it cannot skip. This is why I just can't hard assign each value.
– Beck
Nov 11 at 19:06
@vivek_23 It is for a dropdown menu
– Beck
Nov 11 at 19:06
@vivek_23 It is for a dropdown menu
– Beck
Nov 11 at 19:06
|
show 6 more comments
2 Answers
2
active
oldest
votes
You can use variables in pre-MySQL 8.0:
SELECT t1.*,
(@rn := if(@p = productid, @rn + 1,
if(@p := productid, 1, 1)
)
) as menu_position
FROM (SELECT t1.*
FROM Table1 t1
ORDER BY ProductId,
FIND_IN_SET(size, 'UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60') asc
) AS alias CROSS JOIN
(SELECT @p := -1, @rn := 0) params;
In MySQL 8+, this is much simpler:
select t1.*,
row_number() over (partition by productid order by FIND_IN_SET(size, 'UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60')) as menu_position
from table1 t1
You guys are beasts! Thank you so much, hope to get at your level someday!
– Beck
Nov 11 at 19:44
Is there a way I can add this as a view? I keep getting Error 1351: View's SELECT contains a variable or parameter SQL Statement: CREATE OR REPLACE ALGORITHM = UNDEFINED
– Beck
Nov 11 at 20:18
@Beck . . . There is not an easy way to add this to a view. It is possible, but not really worth the effort, because the view would have to use a correlated subquery and would be expensive.
– Gordon Linoff
Nov 12 at 2:12
Thank you, I manage to put it into a store produce and made a temporary table.
– Beck
Nov 12 at 18:58
add a comment |
Create a two-column table containing all the the Size
values in one column and the integer order of those sizes in the second column--call that table menu_pos
. Join this to your Table
on size, to produce a table or view (call this product_pos
) containing columns product_id
, size
, and menu_pos
. Then modify the menu_pos
values to ensure that they are strictly sequential using a window function, such as:
select
product_id,
size,
rank() over (partition by product_id order by menu_pos) as new_menu_pos
from
product_pos;
Window functions require MySQL 8.
This wouldn't work. We can't create a new table since we can't fix a menu position. It might be1
for a particular data set,2
for another etc.
– vivek_23
Nov 11 at 19:35
The accessory table only needs the integers to be in ascending order, not sequential. The window function will ensure that the numbers are sequential.
– rd_nielsen
Nov 11 at 19:37
@rd_nielsen Please tag. What do you mean bythe integer order of those sizes in the second column
? If the window function ensures it's sequential order, why create a separate table in the DB? I think we could have the same table with a different name self joined with managing integer order of those sizes as their id itself(since it would be in ascending order anyway).
– vivek_23
Nov 11 at 19:48
@vivek_23 "By integer order of those sizes," I mean that if "S" is to sort before "M", then the integers assigned to "S" and "M" should reflect that order--that is, the integer for "S" is smaller than the integer for "M". If you create a separate table for this information, then your data are all in the database, not partly in the database and partly in your interface code.
– rd_nielsen
Nov 11 at 19:53
1
@vivek_23 Because "L" and "40" are for different product IDs. With an accessory table,Table1
doesn't need theMenu_position
column at all. The accessory table of size labels and menu position ordering integers would have very few rows, but accomplish the same purpose.
– rd_nielsen
Nov 11 at 20:03
|
show 2 more comments
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2 Answers
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active
oldest
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2 Answers
2
active
oldest
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active
oldest
votes
active
oldest
votes
You can use variables in pre-MySQL 8.0:
SELECT t1.*,
(@rn := if(@p = productid, @rn + 1,
if(@p := productid, 1, 1)
)
) as menu_position
FROM (SELECT t1.*
FROM Table1 t1
ORDER BY ProductId,
FIND_IN_SET(size, 'UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60') asc
) AS alias CROSS JOIN
(SELECT @p := -1, @rn := 0) params;
In MySQL 8+, this is much simpler:
select t1.*,
row_number() over (partition by productid order by FIND_IN_SET(size, 'UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60')) as menu_position
from table1 t1
You guys are beasts! Thank you so much, hope to get at your level someday!
– Beck
Nov 11 at 19:44
Is there a way I can add this as a view? I keep getting Error 1351: View's SELECT contains a variable or parameter SQL Statement: CREATE OR REPLACE ALGORITHM = UNDEFINED
– Beck
Nov 11 at 20:18
@Beck . . . There is not an easy way to add this to a view. It is possible, but not really worth the effort, because the view would have to use a correlated subquery and would be expensive.
– Gordon Linoff
Nov 12 at 2:12
Thank you, I manage to put it into a store produce and made a temporary table.
– Beck
Nov 12 at 18:58
add a comment |
You can use variables in pre-MySQL 8.0:
SELECT t1.*,
(@rn := if(@p = productid, @rn + 1,
if(@p := productid, 1, 1)
)
) as menu_position
FROM (SELECT t1.*
FROM Table1 t1
ORDER BY ProductId,
FIND_IN_SET(size, 'UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60') asc
) AS alias CROSS JOIN
(SELECT @p := -1, @rn := 0) params;
In MySQL 8+, this is much simpler:
select t1.*,
row_number() over (partition by productid order by FIND_IN_SET(size, 'UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60')) as menu_position
from table1 t1
You guys are beasts! Thank you so much, hope to get at your level someday!
– Beck
Nov 11 at 19:44
Is there a way I can add this as a view? I keep getting Error 1351: View's SELECT contains a variable or parameter SQL Statement: CREATE OR REPLACE ALGORITHM = UNDEFINED
– Beck
Nov 11 at 20:18
@Beck . . . There is not an easy way to add this to a view. It is possible, but not really worth the effort, because the view would have to use a correlated subquery and would be expensive.
– Gordon Linoff
Nov 12 at 2:12
Thank you, I manage to put it into a store produce and made a temporary table.
– Beck
Nov 12 at 18:58
add a comment |
You can use variables in pre-MySQL 8.0:
SELECT t1.*,
(@rn := if(@p = productid, @rn + 1,
if(@p := productid, 1, 1)
)
) as menu_position
FROM (SELECT t1.*
FROM Table1 t1
ORDER BY ProductId,
FIND_IN_SET(size, 'UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60') asc
) AS alias CROSS JOIN
(SELECT @p := -1, @rn := 0) params;
In MySQL 8+, this is much simpler:
select t1.*,
row_number() over (partition by productid order by FIND_IN_SET(size, 'UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60')) as menu_position
from table1 t1
You can use variables in pre-MySQL 8.0:
SELECT t1.*,
(@rn := if(@p = productid, @rn + 1,
if(@p := productid, 1, 1)
)
) as menu_position
FROM (SELECT t1.*
FROM Table1 t1
ORDER BY ProductId,
FIND_IN_SET(size, 'UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60') asc
) AS alias CROSS JOIN
(SELECT @p := -1, @rn := 0) params;
In MySQL 8+, this is much simpler:
select t1.*,
row_number() over (partition by productid order by FIND_IN_SET(size, 'UNI,XS,S,M,L,XL,XXL,3XL,4XL,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60')) as menu_position
from table1 t1
edited Nov 11 at 19:30
Raymond Nijland
7,78921328
7,78921328
answered Nov 11 at 19:25
Gordon Linoff
757k35291399
757k35291399
You guys are beasts! Thank you so much, hope to get at your level someday!
– Beck
Nov 11 at 19:44
Is there a way I can add this as a view? I keep getting Error 1351: View's SELECT contains a variable or parameter SQL Statement: CREATE OR REPLACE ALGORITHM = UNDEFINED
– Beck
Nov 11 at 20:18
@Beck . . . There is not an easy way to add this to a view. It is possible, but not really worth the effort, because the view would have to use a correlated subquery and would be expensive.
– Gordon Linoff
Nov 12 at 2:12
Thank you, I manage to put it into a store produce and made a temporary table.
– Beck
Nov 12 at 18:58
add a comment |
You guys are beasts! Thank you so much, hope to get at your level someday!
– Beck
Nov 11 at 19:44
Is there a way I can add this as a view? I keep getting Error 1351: View's SELECT contains a variable or parameter SQL Statement: CREATE OR REPLACE ALGORITHM = UNDEFINED
– Beck
Nov 11 at 20:18
@Beck . . . There is not an easy way to add this to a view. It is possible, but not really worth the effort, because the view would have to use a correlated subquery and would be expensive.
– Gordon Linoff
Nov 12 at 2:12
Thank you, I manage to put it into a store produce and made a temporary table.
– Beck
Nov 12 at 18:58
You guys are beasts! Thank you so much, hope to get at your level someday!
– Beck
Nov 11 at 19:44
You guys are beasts! Thank you so much, hope to get at your level someday!
– Beck
Nov 11 at 19:44
Is there a way I can add this as a view? I keep getting Error 1351: View's SELECT contains a variable or parameter SQL Statement: CREATE OR REPLACE ALGORITHM = UNDEFINED
– Beck
Nov 11 at 20:18
Is there a way I can add this as a view? I keep getting Error 1351: View's SELECT contains a variable or parameter SQL Statement: CREATE OR REPLACE ALGORITHM = UNDEFINED
– Beck
Nov 11 at 20:18
@Beck . . . There is not an easy way to add this to a view. It is possible, but not really worth the effort, because the view would have to use a correlated subquery and would be expensive.
– Gordon Linoff
Nov 12 at 2:12
@Beck . . . There is not an easy way to add this to a view. It is possible, but not really worth the effort, because the view would have to use a correlated subquery and would be expensive.
– Gordon Linoff
Nov 12 at 2:12
Thank you, I manage to put it into a store produce and made a temporary table.
– Beck
Nov 12 at 18:58
Thank you, I manage to put it into a store produce and made a temporary table.
– Beck
Nov 12 at 18:58
add a comment |
Create a two-column table containing all the the Size
values in one column and the integer order of those sizes in the second column--call that table menu_pos
. Join this to your Table
on size, to produce a table or view (call this product_pos
) containing columns product_id
, size
, and menu_pos
. Then modify the menu_pos
values to ensure that they are strictly sequential using a window function, such as:
select
product_id,
size,
rank() over (partition by product_id order by menu_pos) as new_menu_pos
from
product_pos;
Window functions require MySQL 8.
This wouldn't work. We can't create a new table since we can't fix a menu position. It might be1
for a particular data set,2
for another etc.
– vivek_23
Nov 11 at 19:35
The accessory table only needs the integers to be in ascending order, not sequential. The window function will ensure that the numbers are sequential.
– rd_nielsen
Nov 11 at 19:37
@rd_nielsen Please tag. What do you mean bythe integer order of those sizes in the second column
? If the window function ensures it's sequential order, why create a separate table in the DB? I think we could have the same table with a different name self joined with managing integer order of those sizes as their id itself(since it would be in ascending order anyway).
– vivek_23
Nov 11 at 19:48
@vivek_23 "By integer order of those sizes," I mean that if "S" is to sort before "M", then the integers assigned to "S" and "M" should reflect that order--that is, the integer for "S" is smaller than the integer for "M". If you create a separate table for this information, then your data are all in the database, not partly in the database and partly in your interface code.
– rd_nielsen
Nov 11 at 19:53
1
@vivek_23 Because "L" and "40" are for different product IDs. With an accessory table,Table1
doesn't need theMenu_position
column at all. The accessory table of size labels and menu position ordering integers would have very few rows, but accomplish the same purpose.
– rd_nielsen
Nov 11 at 20:03
|
show 2 more comments
Create a two-column table containing all the the Size
values in one column and the integer order of those sizes in the second column--call that table menu_pos
. Join this to your Table
on size, to produce a table or view (call this product_pos
) containing columns product_id
, size
, and menu_pos
. Then modify the menu_pos
values to ensure that they are strictly sequential using a window function, such as:
select
product_id,
size,
rank() over (partition by product_id order by menu_pos) as new_menu_pos
from
product_pos;
Window functions require MySQL 8.
This wouldn't work. We can't create a new table since we can't fix a menu position. It might be1
for a particular data set,2
for another etc.
– vivek_23
Nov 11 at 19:35
The accessory table only needs the integers to be in ascending order, not sequential. The window function will ensure that the numbers are sequential.
– rd_nielsen
Nov 11 at 19:37
@rd_nielsen Please tag. What do you mean bythe integer order of those sizes in the second column
? If the window function ensures it's sequential order, why create a separate table in the DB? I think we could have the same table with a different name self joined with managing integer order of those sizes as their id itself(since it would be in ascending order anyway).
– vivek_23
Nov 11 at 19:48
@vivek_23 "By integer order of those sizes," I mean that if "S" is to sort before "M", then the integers assigned to "S" and "M" should reflect that order--that is, the integer for "S" is smaller than the integer for "M". If you create a separate table for this information, then your data are all in the database, not partly in the database and partly in your interface code.
– rd_nielsen
Nov 11 at 19:53
1
@vivek_23 Because "L" and "40" are for different product IDs. With an accessory table,Table1
doesn't need theMenu_position
column at all. The accessory table of size labels and menu position ordering integers would have very few rows, but accomplish the same purpose.
– rd_nielsen
Nov 11 at 20:03
|
show 2 more comments
Create a two-column table containing all the the Size
values in one column and the integer order of those sizes in the second column--call that table menu_pos
. Join this to your Table
on size, to produce a table or view (call this product_pos
) containing columns product_id
, size
, and menu_pos
. Then modify the menu_pos
values to ensure that they are strictly sequential using a window function, such as:
select
product_id,
size,
rank() over (partition by product_id order by menu_pos) as new_menu_pos
from
product_pos;
Window functions require MySQL 8.
Create a two-column table containing all the the Size
values in one column and the integer order of those sizes in the second column--call that table menu_pos
. Join this to your Table
on size, to produce a table or view (call this product_pos
) containing columns product_id
, size
, and menu_pos
. Then modify the menu_pos
values to ensure that they are strictly sequential using a window function, such as:
select
product_id,
size,
rank() over (partition by product_id order by menu_pos) as new_menu_pos
from
product_pos;
Window functions require MySQL 8.
edited Nov 11 at 19:32
answered Nov 11 at 19:25
rd_nielsen
1,6152615
1,6152615
This wouldn't work. We can't create a new table since we can't fix a menu position. It might be1
for a particular data set,2
for another etc.
– vivek_23
Nov 11 at 19:35
The accessory table only needs the integers to be in ascending order, not sequential. The window function will ensure that the numbers are sequential.
– rd_nielsen
Nov 11 at 19:37
@rd_nielsen Please tag. What do you mean bythe integer order of those sizes in the second column
? If the window function ensures it's sequential order, why create a separate table in the DB? I think we could have the same table with a different name self joined with managing integer order of those sizes as their id itself(since it would be in ascending order anyway).
– vivek_23
Nov 11 at 19:48
@vivek_23 "By integer order of those sizes," I mean that if "S" is to sort before "M", then the integers assigned to "S" and "M" should reflect that order--that is, the integer for "S" is smaller than the integer for "M". If you create a separate table for this information, then your data are all in the database, not partly in the database and partly in your interface code.
– rd_nielsen
Nov 11 at 19:53
1
@vivek_23 Because "L" and "40" are for different product IDs. With an accessory table,Table1
doesn't need theMenu_position
column at all. The accessory table of size labels and menu position ordering integers would have very few rows, but accomplish the same purpose.
– rd_nielsen
Nov 11 at 20:03
|
show 2 more comments
This wouldn't work. We can't create a new table since we can't fix a menu position. It might be1
for a particular data set,2
for another etc.
– vivek_23
Nov 11 at 19:35
The accessory table only needs the integers to be in ascending order, not sequential. The window function will ensure that the numbers are sequential.
– rd_nielsen
Nov 11 at 19:37
@rd_nielsen Please tag. What do you mean bythe integer order of those sizes in the second column
? If the window function ensures it's sequential order, why create a separate table in the DB? I think we could have the same table with a different name self joined with managing integer order of those sizes as their id itself(since it would be in ascending order anyway).
– vivek_23
Nov 11 at 19:48
@vivek_23 "By integer order of those sizes," I mean that if "S" is to sort before "M", then the integers assigned to "S" and "M" should reflect that order--that is, the integer for "S" is smaller than the integer for "M". If you create a separate table for this information, then your data are all in the database, not partly in the database and partly in your interface code.
– rd_nielsen
Nov 11 at 19:53
1
@vivek_23 Because "L" and "40" are for different product IDs. With an accessory table,Table1
doesn't need theMenu_position
column at all. The accessory table of size labels and menu position ordering integers would have very few rows, but accomplish the same purpose.
– rd_nielsen
Nov 11 at 20:03
This wouldn't work. We can't create a new table since we can't fix a menu position. It might be
1
for a particular data set, 2
for another etc.– vivek_23
Nov 11 at 19:35
This wouldn't work. We can't create a new table since we can't fix a menu position. It might be
1
for a particular data set, 2
for another etc.– vivek_23
Nov 11 at 19:35
The accessory table only needs the integers to be in ascending order, not sequential. The window function will ensure that the numbers are sequential.
– rd_nielsen
Nov 11 at 19:37
The accessory table only needs the integers to be in ascending order, not sequential. The window function will ensure that the numbers are sequential.
– rd_nielsen
Nov 11 at 19:37
@rd_nielsen Please tag. What do you mean by
the integer order of those sizes in the second column
? If the window function ensures it's sequential order, why create a separate table in the DB? I think we could have the same table with a different name self joined with managing integer order of those sizes as their id itself(since it would be in ascending order anyway).– vivek_23
Nov 11 at 19:48
@rd_nielsen Please tag. What do you mean by
the integer order of those sizes in the second column
? If the window function ensures it's sequential order, why create a separate table in the DB? I think we could have the same table with a different name self joined with managing integer order of those sizes as their id itself(since it would be in ascending order anyway).– vivek_23
Nov 11 at 19:48
@vivek_23 "By integer order of those sizes," I mean that if "S" is to sort before "M", then the integers assigned to "S" and "M" should reflect that order--that is, the integer for "S" is smaller than the integer for "M". If you create a separate table for this information, then your data are all in the database, not partly in the database and partly in your interface code.
– rd_nielsen
Nov 11 at 19:53
@vivek_23 "By integer order of those sizes," I mean that if "S" is to sort before "M", then the integers assigned to "S" and "M" should reflect that order--that is, the integer for "S" is smaller than the integer for "M". If you create a separate table for this information, then your data are all in the database, not partly in the database and partly in your interface code.
– rd_nielsen
Nov 11 at 19:53
1
1
@vivek_23 Because "L" and "40" are for different product IDs. With an accessory table,
Table1
doesn't need the Menu_position
column at all. The accessory table of size labels and menu position ordering integers would have very few rows, but accomplish the same purpose.– rd_nielsen
Nov 11 at 20:03
@vivek_23 Because "L" and "40" are for different product IDs. With an accessory table,
Table1
doesn't need the Menu_position
column at all. The accessory table of size labels and menu position ordering integers would have very few rows, but accomplish the same purpose.– rd_nielsen
Nov 11 at 20:03
|
show 2 more comments
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what's the logic behind assigning such menu position?
– vivek_23
Nov 11 at 18:54
Do the menu positions for a Product ID have to be ascending? For example, if a product had only sizes "S" and "L", should the menu positions be 1 and 2, or are positions of 1 and 3 OK?
– rd_nielsen
Nov 11 at 19:00
You can put your sizes and menu position values (integers) into a table and join to that table to get the menu position for each size.
– rd_nielsen
Nov 11 at 19:01
@rd_nielsen Yes menu has to be chronological order 1 and 2, it cannot skip. This is why I just can't hard assign each value.
– Beck
Nov 11 at 19:06
@vivek_23 It is for a dropdown menu
– Beck
Nov 11 at 19:06