Firestore - Pass Array To arrayUnion()
How do you pass an array to the firebase firestore arrayUnion()
function?
I am getting this error when I try to pass an array.
Error
Error: 3 INVALID_ARGUMENT: Cannot convert an array value in an array value.
Example
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(myArray)
});
javascript firebase google-cloud-firestore
add a comment |
How do you pass an array to the firebase firestore arrayUnion()
function?
I am getting this error when I try to pass an array.
Error
Error: 3 INVALID_ARGUMENT: Cannot convert an array value in an array value.
Example
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(myArray)
});
javascript firebase google-cloud-firestore
add a comment |
How do you pass an array to the firebase firestore arrayUnion()
function?
I am getting this error when I try to pass an array.
Error
Error: 3 INVALID_ARGUMENT: Cannot convert an array value in an array value.
Example
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(myArray)
});
javascript firebase google-cloud-firestore
How do you pass an array to the firebase firestore arrayUnion()
function?
I am getting this error when I try to pass an array.
Error
Error: 3 INVALID_ARGUMENT: Cannot convert an array value in an array value.
Example
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(myArray)
});
javascript firebase google-cloud-firestore
javascript firebase google-cloud-firestore
edited Nov 11 at 19:34
Frank van Puffelen
227k28370396
227k28370396
asked Nov 11 at 19:15
Matthew Rideout
851418
851418
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I eventually found the answer of using Function.prototype.apply() in another stack overflow answer.
Example For Function.prototype.apply()
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion.apply(this, myArray)
});
Example For ECMAScript 6
using the spread argument
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(...myArray)
});
When passing an array using either of the above methods, Firestore will only add new array elements to that do not already exist in the Firestore array.
For example, running the above, then running the following
let myArray = ["2", "3", "5", "7"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(...myArray)
});
would only add "5" and 7" to the array in Firestore. This works for an array of objects as well.
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I eventually found the answer of using Function.prototype.apply() in another stack overflow answer.
Example For Function.prototype.apply()
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion.apply(this, myArray)
});
Example For ECMAScript 6
using the spread argument
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(...myArray)
});
When passing an array using either of the above methods, Firestore will only add new array elements to that do not already exist in the Firestore array.
For example, running the above, then running the following
let myArray = ["2", "3", "5", "7"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(...myArray)
});
would only add "5" and 7" to the array in Firestore. This works for an array of objects as well.
add a comment |
I eventually found the answer of using Function.prototype.apply() in another stack overflow answer.
Example For Function.prototype.apply()
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion.apply(this, myArray)
});
Example For ECMAScript 6
using the spread argument
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(...myArray)
});
When passing an array using either of the above methods, Firestore will only add new array elements to that do not already exist in the Firestore array.
For example, running the above, then running the following
let myArray = ["2", "3", "5", "7"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(...myArray)
});
would only add "5" and 7" to the array in Firestore. This works for an array of objects as well.
add a comment |
I eventually found the answer of using Function.prototype.apply() in another stack overflow answer.
Example For Function.prototype.apply()
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion.apply(this, myArray)
});
Example For ECMAScript 6
using the spread argument
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(...myArray)
});
When passing an array using either of the above methods, Firestore will only add new array elements to that do not already exist in the Firestore array.
For example, running the above, then running the following
let myArray = ["2", "3", "5", "7"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(...myArray)
});
would only add "5" and 7" to the array in Firestore. This works for an array of objects as well.
I eventually found the answer of using Function.prototype.apply() in another stack overflow answer.
Example For Function.prototype.apply()
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion.apply(this, myArray)
});
Example For ECMAScript 6
using the spread argument
let myArray = ["1", "2", "3"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(...myArray)
});
When passing an array using either of the above methods, Firestore will only add new array elements to that do not already exist in the Firestore array.
For example, running the above, then running the following
let myArray = ["2", "3", "5", "7"];
docRef.update({
test: firebase.firestore.FieldValue.arrayUnion(...myArray)
});
would only add "5" and 7" to the array in Firestore. This works for an array of objects as well.
answered Nov 11 at 19:15
Matthew Rideout
851418
851418
add a comment |
add a comment |
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