“Video select screen” via radio buttons











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i have the following problem. I try to make some kind of "video select screen" where you have the option to choose what kind of video you want to see AND choose what music genre you want to listen to while the video plays (there is one video-file for every possible choice). I tried to write a function that changes the src of the video but i just cant make it work and i dont know why.



This is my code so far:



HTML:



<form>
<h3>Customize your own Showreel</h3>
<fieldset>
<input type="radio" id="commercials" name="selection" value="com">
<label for="commercials">Commercials</label>

<input type="radio" id="mixed" name="selection" value="mix" checked="checked">
<label for="mixed">Mixed</label>

<input type="radio" id="videoclip" name="selection" value="vid">
<label for="videoclip">Videoclips</label>
</fieldset>

<h4>Select Music</h4>
<fieldset>
<input type="radio" id="pop" name="musicselection" value="pop" checked="checked">
<label for="pop">Pop</label>
<input type="radio" id="rock" name="musicselection" value="rock">
<label for="rock">Rock</label>
</fieldset>

<video id="theVideo" controls></video>
<button type="button" id="theVideo" onclick="playselected();">play</button>

</form>


Javascript:



function playselected() {
var music = document.getElementsByName("musicselection");
var selection = document.getElementsByName("selection");
var theVid = document.getElementById("theVideo");

if (music.value == "com" && selection.value == "pop") {
theVid.src = "videos/com_pop.mp4";
}

if (music.value == "com" && selection.value == "rock") {
theVid.src = "videos/com_rock.mp4";
}
if (music.value == "mix" && selection.value == "pop") {
theVid.src = "videos/mix_pop.mp4";
}
if (music.value == "mix" && selection.value == "rock") {
theVid.src = "videos/mix_rock.mp4";
}
if (music.value == "vid" && selection.value == "pop") {
theVid.src = "videos/vid_pop.mp4";
}
if (music.value == "vid" && selection.value == "rock") {
theVid.src = "videos/vid_rock.mp4";
}
}


This is what i came up with. I hope my attempt to takle the problem is even pointing in the right direction. (im new to javascript and html and im teaching myself how to code. please dont be too harsh)










share|improve this question






















  • Assuming those URLs are correct, that looks like you could - with some sanity-checking - just do: theVid.src = 'videos/' + music.value + '_' + selection.value + '.mp4'; (or, using template literals: theVid.src = `videos/${music.value}_${selection.value}.mp4;`)
    – David Thomas
    Nov 10 at 18:10

















up vote
1
down vote

favorite












i have the following problem. I try to make some kind of "video select screen" where you have the option to choose what kind of video you want to see AND choose what music genre you want to listen to while the video plays (there is one video-file for every possible choice). I tried to write a function that changes the src of the video but i just cant make it work and i dont know why.



This is my code so far:



HTML:



<form>
<h3>Customize your own Showreel</h3>
<fieldset>
<input type="radio" id="commercials" name="selection" value="com">
<label for="commercials">Commercials</label>

<input type="radio" id="mixed" name="selection" value="mix" checked="checked">
<label for="mixed">Mixed</label>

<input type="radio" id="videoclip" name="selection" value="vid">
<label for="videoclip">Videoclips</label>
</fieldset>

<h4>Select Music</h4>
<fieldset>
<input type="radio" id="pop" name="musicselection" value="pop" checked="checked">
<label for="pop">Pop</label>
<input type="radio" id="rock" name="musicselection" value="rock">
<label for="rock">Rock</label>
</fieldset>

<video id="theVideo" controls></video>
<button type="button" id="theVideo" onclick="playselected();">play</button>

</form>


Javascript:



function playselected() {
var music = document.getElementsByName("musicselection");
var selection = document.getElementsByName("selection");
var theVid = document.getElementById("theVideo");

if (music.value == "com" && selection.value == "pop") {
theVid.src = "videos/com_pop.mp4";
}

if (music.value == "com" && selection.value == "rock") {
theVid.src = "videos/com_rock.mp4";
}
if (music.value == "mix" && selection.value == "pop") {
theVid.src = "videos/mix_pop.mp4";
}
if (music.value == "mix" && selection.value == "rock") {
theVid.src = "videos/mix_rock.mp4";
}
if (music.value == "vid" && selection.value == "pop") {
theVid.src = "videos/vid_pop.mp4";
}
if (music.value == "vid" && selection.value == "rock") {
theVid.src = "videos/vid_rock.mp4";
}
}


This is what i came up with. I hope my attempt to takle the problem is even pointing in the right direction. (im new to javascript and html and im teaching myself how to code. please dont be too harsh)










share|improve this question






















  • Assuming those URLs are correct, that looks like you could - with some sanity-checking - just do: theVid.src = 'videos/' + music.value + '_' + selection.value + '.mp4'; (or, using template literals: theVid.src = `videos/${music.value}_${selection.value}.mp4;`)
    – David Thomas
    Nov 10 at 18:10















up vote
1
down vote

favorite









up vote
1
down vote

favorite











i have the following problem. I try to make some kind of "video select screen" where you have the option to choose what kind of video you want to see AND choose what music genre you want to listen to while the video plays (there is one video-file for every possible choice). I tried to write a function that changes the src of the video but i just cant make it work and i dont know why.



This is my code so far:



HTML:



<form>
<h3>Customize your own Showreel</h3>
<fieldset>
<input type="radio" id="commercials" name="selection" value="com">
<label for="commercials">Commercials</label>

<input type="radio" id="mixed" name="selection" value="mix" checked="checked">
<label for="mixed">Mixed</label>

<input type="radio" id="videoclip" name="selection" value="vid">
<label for="videoclip">Videoclips</label>
</fieldset>

<h4>Select Music</h4>
<fieldset>
<input type="radio" id="pop" name="musicselection" value="pop" checked="checked">
<label for="pop">Pop</label>
<input type="radio" id="rock" name="musicselection" value="rock">
<label for="rock">Rock</label>
</fieldset>

<video id="theVideo" controls></video>
<button type="button" id="theVideo" onclick="playselected();">play</button>

</form>


Javascript:



function playselected() {
var music = document.getElementsByName("musicselection");
var selection = document.getElementsByName("selection");
var theVid = document.getElementById("theVideo");

if (music.value == "com" && selection.value == "pop") {
theVid.src = "videos/com_pop.mp4";
}

if (music.value == "com" && selection.value == "rock") {
theVid.src = "videos/com_rock.mp4";
}
if (music.value == "mix" && selection.value == "pop") {
theVid.src = "videos/mix_pop.mp4";
}
if (music.value == "mix" && selection.value == "rock") {
theVid.src = "videos/mix_rock.mp4";
}
if (music.value == "vid" && selection.value == "pop") {
theVid.src = "videos/vid_pop.mp4";
}
if (music.value == "vid" && selection.value == "rock") {
theVid.src = "videos/vid_rock.mp4";
}
}


This is what i came up with. I hope my attempt to takle the problem is even pointing in the right direction. (im new to javascript and html and im teaching myself how to code. please dont be too harsh)










share|improve this question













i have the following problem. I try to make some kind of "video select screen" where you have the option to choose what kind of video you want to see AND choose what music genre you want to listen to while the video plays (there is one video-file for every possible choice). I tried to write a function that changes the src of the video but i just cant make it work and i dont know why.



This is my code so far:



HTML:



<form>
<h3>Customize your own Showreel</h3>
<fieldset>
<input type="radio" id="commercials" name="selection" value="com">
<label for="commercials">Commercials</label>

<input type="radio" id="mixed" name="selection" value="mix" checked="checked">
<label for="mixed">Mixed</label>

<input type="radio" id="videoclip" name="selection" value="vid">
<label for="videoclip">Videoclips</label>
</fieldset>

<h4>Select Music</h4>
<fieldset>
<input type="radio" id="pop" name="musicselection" value="pop" checked="checked">
<label for="pop">Pop</label>
<input type="radio" id="rock" name="musicselection" value="rock">
<label for="rock">Rock</label>
</fieldset>

<video id="theVideo" controls></video>
<button type="button" id="theVideo" onclick="playselected();">play</button>

</form>


Javascript:



function playselected() {
var music = document.getElementsByName("musicselection");
var selection = document.getElementsByName("selection");
var theVid = document.getElementById("theVideo");

if (music.value == "com" && selection.value == "pop") {
theVid.src = "videos/com_pop.mp4";
}

if (music.value == "com" && selection.value == "rock") {
theVid.src = "videos/com_rock.mp4";
}
if (music.value == "mix" && selection.value == "pop") {
theVid.src = "videos/mix_pop.mp4";
}
if (music.value == "mix" && selection.value == "rock") {
theVid.src = "videos/mix_rock.mp4";
}
if (music.value == "vid" && selection.value == "pop") {
theVid.src = "videos/vid_pop.mp4";
}
if (music.value == "vid" && selection.value == "rock") {
theVid.src = "videos/vid_rock.mp4";
}
}


This is what i came up with. I hope my attempt to takle the problem is even pointing in the right direction. (im new to javascript and html and im teaching myself how to code. please dont be too harsh)







javascript html






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share|improve this question











share|improve this question




share|improve this question










asked Nov 10 at 18:05









Joshua

82




82












  • Assuming those URLs are correct, that looks like you could - with some sanity-checking - just do: theVid.src = 'videos/' + music.value + '_' + selection.value + '.mp4'; (or, using template literals: theVid.src = `videos/${music.value}_${selection.value}.mp4;`)
    – David Thomas
    Nov 10 at 18:10




















  • Assuming those URLs are correct, that looks like you could - with some sanity-checking - just do: theVid.src = 'videos/' + music.value + '_' + selection.value + '.mp4'; (or, using template literals: theVid.src = `videos/${music.value}_${selection.value}.mp4;`)
    – David Thomas
    Nov 10 at 18:10


















Assuming those URLs are correct, that looks like you could - with some sanity-checking - just do: theVid.src = 'videos/' + music.value + '_' + selection.value + '.mp4'; (or, using template literals: theVid.src = `videos/${music.value}_${selection.value}.mp4;`)
– David Thomas
Nov 10 at 18:10






Assuming those URLs are correct, that looks like you could - with some sanity-checking - just do: theVid.src = 'videos/' + music.value + '_' + selection.value + '.mp4'; (or, using template literals: theVid.src = `videos/${music.value}_${selection.value}.mp4;`)
– David Thomas
Nov 10 at 18:10














1 Answer
1






active

oldest

votes

















up vote
0
down vote



accepted










That's because getElementsByName returns a NodeList, which means that you have to iterate through the collection to access the value of the selected radio button. Therefore, you can convert the NodeList into an array using Array.prototype.slice.call(<NodeList>), perform filtering on it to return radio buttons that are checked, and then use it to access its value:



var musicValue = Array.prototype.slice.call(music).filter(function(musicRadioButton) {
return musicRadioButton.checked;
})[0].value;

var selectionValue = Array.prototype.slice.call(selection).filter(function(selectionRadioButton) {
return selectionRadiobutton.checked;
})[0].value;


Further explanation on the code block above:





  1. Array.prototype.slice.call(music) converts the music NodeList into an array of elements

  2. We then use .filter() to go through the returned array. In the callback, we ensure that we only select/filter for radio buttons that are checked, i.e. .checked property returns a truthy value.

  3. Chain [0] after the .filter() call to get the first checked radio button

  4. Chain .value to get the value of the first checked radio button


Then in your if/else blocks, instead of checking for music.value or selection.value, you can refer to musicValue and selectionValue instead:






function playselected() {
var music = document.getElementsByName("musicselection");
var selection = document.getElementsByName("selection");
var theVid = document.getElementById("theVideo");

var musicValue = Array.prototype.slice.call(music).filter(function(musicRadioButton) {

return musicRadioButton.checked;
})[0].value;
var selectionValue = Array.prototype.slice.call(selection).filter(function(selectionRadioButton) {
return selectionRadiobutton.checked;
})[0].value;

if (musicValue == "com" && selectionValue == "pop") {
theVid.src = "videos/com_pop.mp4";
}

if (musicValue == "com" && selectionValue == "rock") {
theVid.src = "videos/com_rock.mp4";
}
if (musicValue == "mix" && selectionValue == "pop") {
theVid.src = "videos/mix_pop.mp4";
}
if (musicValue == "mix" && selectionValue == "rock") {
theVid.src = "videos/mix_rock.mp4";
}
if (musicValue == "vid" && selectionValue == "pop") {
theVid.src = "videos/vid_pop.mp4";
}
if (musicValue == "vid" && selectionValue == "rock") {
theVid.src = "videos/vid_rock.mp4";
}
}

<form>
<h3>Customize your own Showreel</h3>
<fieldset>
<input type="radio" id="commercials" name="selection" value="com">
<label for="commercials">Commercials</label>

<input type="radio" id="mixed" name="selection" value="mix" checked="checked">
<label for="mixed">Mixed</label>

<input type="radio" id="videoclip" name="selection" value="vid">
<label for="videoclip">Videoclips</label>
</fieldset>

<h4>Select Music</h4>
<fieldset>
<input type="radio" id="pop" name="musicselection" value="pop" checked="checked">
<label for="pop">Pop</label>
<input type="radio" id="rock" name="musicselection" value="rock">
<label for="rock">Rock</label>
</fieldset>

<video id="theVideo" controls></video>
<button type="button" id="theVideo" onclick="playselected();">play</button>

</form>








share|improve this answer





















  • Thank you for the detailed answer. I tried to implement your answer into my code, but when i hit the "play" button its still not loading the chosen video. I really dont know why, can you point me in the right direction?
    – Joshua
    Nov 11 at 2:52










  • @Joshua Setting the video source does not automatically play the video. You need to invoke .play() on the video element manually. Note that this runs into the territory of video auto play, which browsers have recently placed a lot of restrictions on.
    – Terry
    Nov 11 at 9:10











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote



accepted










That's because getElementsByName returns a NodeList, which means that you have to iterate through the collection to access the value of the selected radio button. Therefore, you can convert the NodeList into an array using Array.prototype.slice.call(<NodeList>), perform filtering on it to return radio buttons that are checked, and then use it to access its value:



var musicValue = Array.prototype.slice.call(music).filter(function(musicRadioButton) {
return musicRadioButton.checked;
})[0].value;

var selectionValue = Array.prototype.slice.call(selection).filter(function(selectionRadioButton) {
return selectionRadiobutton.checked;
})[0].value;


Further explanation on the code block above:





  1. Array.prototype.slice.call(music) converts the music NodeList into an array of elements

  2. We then use .filter() to go through the returned array. In the callback, we ensure that we only select/filter for radio buttons that are checked, i.e. .checked property returns a truthy value.

  3. Chain [0] after the .filter() call to get the first checked radio button

  4. Chain .value to get the value of the first checked radio button


Then in your if/else blocks, instead of checking for music.value or selection.value, you can refer to musicValue and selectionValue instead:






function playselected() {
var music = document.getElementsByName("musicselection");
var selection = document.getElementsByName("selection");
var theVid = document.getElementById("theVideo");

var musicValue = Array.prototype.slice.call(music).filter(function(musicRadioButton) {

return musicRadioButton.checked;
})[0].value;
var selectionValue = Array.prototype.slice.call(selection).filter(function(selectionRadioButton) {
return selectionRadiobutton.checked;
})[0].value;

if (musicValue == "com" && selectionValue == "pop") {
theVid.src = "videos/com_pop.mp4";
}

if (musicValue == "com" && selectionValue == "rock") {
theVid.src = "videos/com_rock.mp4";
}
if (musicValue == "mix" && selectionValue == "pop") {
theVid.src = "videos/mix_pop.mp4";
}
if (musicValue == "mix" && selectionValue == "rock") {
theVid.src = "videos/mix_rock.mp4";
}
if (musicValue == "vid" && selectionValue == "pop") {
theVid.src = "videos/vid_pop.mp4";
}
if (musicValue == "vid" && selectionValue == "rock") {
theVid.src = "videos/vid_rock.mp4";
}
}

<form>
<h3>Customize your own Showreel</h3>
<fieldset>
<input type="radio" id="commercials" name="selection" value="com">
<label for="commercials">Commercials</label>

<input type="radio" id="mixed" name="selection" value="mix" checked="checked">
<label for="mixed">Mixed</label>

<input type="radio" id="videoclip" name="selection" value="vid">
<label for="videoclip">Videoclips</label>
</fieldset>

<h4>Select Music</h4>
<fieldset>
<input type="radio" id="pop" name="musicselection" value="pop" checked="checked">
<label for="pop">Pop</label>
<input type="radio" id="rock" name="musicselection" value="rock">
<label for="rock">Rock</label>
</fieldset>

<video id="theVideo" controls></video>
<button type="button" id="theVideo" onclick="playselected();">play</button>

</form>








share|improve this answer





















  • Thank you for the detailed answer. I tried to implement your answer into my code, but when i hit the "play" button its still not loading the chosen video. I really dont know why, can you point me in the right direction?
    – Joshua
    Nov 11 at 2:52










  • @Joshua Setting the video source does not automatically play the video. You need to invoke .play() on the video element manually. Note that this runs into the territory of video auto play, which browsers have recently placed a lot of restrictions on.
    – Terry
    Nov 11 at 9:10















up vote
0
down vote



accepted










That's because getElementsByName returns a NodeList, which means that you have to iterate through the collection to access the value of the selected radio button. Therefore, you can convert the NodeList into an array using Array.prototype.slice.call(<NodeList>), perform filtering on it to return radio buttons that are checked, and then use it to access its value:



var musicValue = Array.prototype.slice.call(music).filter(function(musicRadioButton) {
return musicRadioButton.checked;
})[0].value;

var selectionValue = Array.prototype.slice.call(selection).filter(function(selectionRadioButton) {
return selectionRadiobutton.checked;
})[0].value;


Further explanation on the code block above:





  1. Array.prototype.slice.call(music) converts the music NodeList into an array of elements

  2. We then use .filter() to go through the returned array. In the callback, we ensure that we only select/filter for radio buttons that are checked, i.e. .checked property returns a truthy value.

  3. Chain [0] after the .filter() call to get the first checked radio button

  4. Chain .value to get the value of the first checked radio button


Then in your if/else blocks, instead of checking for music.value or selection.value, you can refer to musicValue and selectionValue instead:






function playselected() {
var music = document.getElementsByName("musicselection");
var selection = document.getElementsByName("selection");
var theVid = document.getElementById("theVideo");

var musicValue = Array.prototype.slice.call(music).filter(function(musicRadioButton) {

return musicRadioButton.checked;
})[0].value;
var selectionValue = Array.prototype.slice.call(selection).filter(function(selectionRadioButton) {
return selectionRadiobutton.checked;
})[0].value;

if (musicValue == "com" && selectionValue == "pop") {
theVid.src = "videos/com_pop.mp4";
}

if (musicValue == "com" && selectionValue == "rock") {
theVid.src = "videos/com_rock.mp4";
}
if (musicValue == "mix" && selectionValue == "pop") {
theVid.src = "videos/mix_pop.mp4";
}
if (musicValue == "mix" && selectionValue == "rock") {
theVid.src = "videos/mix_rock.mp4";
}
if (musicValue == "vid" && selectionValue == "pop") {
theVid.src = "videos/vid_pop.mp4";
}
if (musicValue == "vid" && selectionValue == "rock") {
theVid.src = "videos/vid_rock.mp4";
}
}

<form>
<h3>Customize your own Showreel</h3>
<fieldset>
<input type="radio" id="commercials" name="selection" value="com">
<label for="commercials">Commercials</label>

<input type="radio" id="mixed" name="selection" value="mix" checked="checked">
<label for="mixed">Mixed</label>

<input type="radio" id="videoclip" name="selection" value="vid">
<label for="videoclip">Videoclips</label>
</fieldset>

<h4>Select Music</h4>
<fieldset>
<input type="radio" id="pop" name="musicselection" value="pop" checked="checked">
<label for="pop">Pop</label>
<input type="radio" id="rock" name="musicselection" value="rock">
<label for="rock">Rock</label>
</fieldset>

<video id="theVideo" controls></video>
<button type="button" id="theVideo" onclick="playselected();">play</button>

</form>








share|improve this answer





















  • Thank you for the detailed answer. I tried to implement your answer into my code, but when i hit the "play" button its still not loading the chosen video. I really dont know why, can you point me in the right direction?
    – Joshua
    Nov 11 at 2:52










  • @Joshua Setting the video source does not automatically play the video. You need to invoke .play() on the video element manually. Note that this runs into the territory of video auto play, which browsers have recently placed a lot of restrictions on.
    – Terry
    Nov 11 at 9:10













up vote
0
down vote



accepted







up vote
0
down vote



accepted






That's because getElementsByName returns a NodeList, which means that you have to iterate through the collection to access the value of the selected radio button. Therefore, you can convert the NodeList into an array using Array.prototype.slice.call(<NodeList>), perform filtering on it to return radio buttons that are checked, and then use it to access its value:



var musicValue = Array.prototype.slice.call(music).filter(function(musicRadioButton) {
return musicRadioButton.checked;
})[0].value;

var selectionValue = Array.prototype.slice.call(selection).filter(function(selectionRadioButton) {
return selectionRadiobutton.checked;
})[0].value;


Further explanation on the code block above:





  1. Array.prototype.slice.call(music) converts the music NodeList into an array of elements

  2. We then use .filter() to go through the returned array. In the callback, we ensure that we only select/filter for radio buttons that are checked, i.e. .checked property returns a truthy value.

  3. Chain [0] after the .filter() call to get the first checked radio button

  4. Chain .value to get the value of the first checked radio button


Then in your if/else blocks, instead of checking for music.value or selection.value, you can refer to musicValue and selectionValue instead:






function playselected() {
var music = document.getElementsByName("musicselection");
var selection = document.getElementsByName("selection");
var theVid = document.getElementById("theVideo");

var musicValue = Array.prototype.slice.call(music).filter(function(musicRadioButton) {

return musicRadioButton.checked;
})[0].value;
var selectionValue = Array.prototype.slice.call(selection).filter(function(selectionRadioButton) {
return selectionRadiobutton.checked;
})[0].value;

if (musicValue == "com" && selectionValue == "pop") {
theVid.src = "videos/com_pop.mp4";
}

if (musicValue == "com" && selectionValue == "rock") {
theVid.src = "videos/com_rock.mp4";
}
if (musicValue == "mix" && selectionValue == "pop") {
theVid.src = "videos/mix_pop.mp4";
}
if (musicValue == "mix" && selectionValue == "rock") {
theVid.src = "videos/mix_rock.mp4";
}
if (musicValue == "vid" && selectionValue == "pop") {
theVid.src = "videos/vid_pop.mp4";
}
if (musicValue == "vid" && selectionValue == "rock") {
theVid.src = "videos/vid_rock.mp4";
}
}

<form>
<h3>Customize your own Showreel</h3>
<fieldset>
<input type="radio" id="commercials" name="selection" value="com">
<label for="commercials">Commercials</label>

<input type="radio" id="mixed" name="selection" value="mix" checked="checked">
<label for="mixed">Mixed</label>

<input type="radio" id="videoclip" name="selection" value="vid">
<label for="videoclip">Videoclips</label>
</fieldset>

<h4>Select Music</h4>
<fieldset>
<input type="radio" id="pop" name="musicselection" value="pop" checked="checked">
<label for="pop">Pop</label>
<input type="radio" id="rock" name="musicselection" value="rock">
<label for="rock">Rock</label>
</fieldset>

<video id="theVideo" controls></video>
<button type="button" id="theVideo" onclick="playselected();">play</button>

</form>








share|improve this answer












That's because getElementsByName returns a NodeList, which means that you have to iterate through the collection to access the value of the selected radio button. Therefore, you can convert the NodeList into an array using Array.prototype.slice.call(<NodeList>), perform filtering on it to return radio buttons that are checked, and then use it to access its value:



var musicValue = Array.prototype.slice.call(music).filter(function(musicRadioButton) {
return musicRadioButton.checked;
})[0].value;

var selectionValue = Array.prototype.slice.call(selection).filter(function(selectionRadioButton) {
return selectionRadiobutton.checked;
})[0].value;


Further explanation on the code block above:





  1. Array.prototype.slice.call(music) converts the music NodeList into an array of elements

  2. We then use .filter() to go through the returned array. In the callback, we ensure that we only select/filter for radio buttons that are checked, i.e. .checked property returns a truthy value.

  3. Chain [0] after the .filter() call to get the first checked radio button

  4. Chain .value to get the value of the first checked radio button


Then in your if/else blocks, instead of checking for music.value or selection.value, you can refer to musicValue and selectionValue instead:






function playselected() {
var music = document.getElementsByName("musicselection");
var selection = document.getElementsByName("selection");
var theVid = document.getElementById("theVideo");

var musicValue = Array.prototype.slice.call(music).filter(function(musicRadioButton) {

return musicRadioButton.checked;
})[0].value;
var selectionValue = Array.prototype.slice.call(selection).filter(function(selectionRadioButton) {
return selectionRadiobutton.checked;
})[0].value;

if (musicValue == "com" && selectionValue == "pop") {
theVid.src = "videos/com_pop.mp4";
}

if (musicValue == "com" && selectionValue == "rock") {
theVid.src = "videos/com_rock.mp4";
}
if (musicValue == "mix" && selectionValue == "pop") {
theVid.src = "videos/mix_pop.mp4";
}
if (musicValue == "mix" && selectionValue == "rock") {
theVid.src = "videos/mix_rock.mp4";
}
if (musicValue == "vid" && selectionValue == "pop") {
theVid.src = "videos/vid_pop.mp4";
}
if (musicValue == "vid" && selectionValue == "rock") {
theVid.src = "videos/vid_rock.mp4";
}
}

<form>
<h3>Customize your own Showreel</h3>
<fieldset>
<input type="radio" id="commercials" name="selection" value="com">
<label for="commercials">Commercials</label>

<input type="radio" id="mixed" name="selection" value="mix" checked="checked">
<label for="mixed">Mixed</label>

<input type="radio" id="videoclip" name="selection" value="vid">
<label for="videoclip">Videoclips</label>
</fieldset>

<h4>Select Music</h4>
<fieldset>
<input type="radio" id="pop" name="musicselection" value="pop" checked="checked">
<label for="pop">Pop</label>
<input type="radio" id="rock" name="musicselection" value="rock">
<label for="rock">Rock</label>
</fieldset>

<video id="theVideo" controls></video>
<button type="button" id="theVideo" onclick="playselected();">play</button>

</form>








function playselected() {
var music = document.getElementsByName("musicselection");
var selection = document.getElementsByName("selection");
var theVid = document.getElementById("theVideo");

var musicValue = Array.prototype.slice.call(music).filter(function(musicRadioButton) {

return musicRadioButton.checked;
})[0].value;
var selectionValue = Array.prototype.slice.call(selection).filter(function(selectionRadioButton) {
return selectionRadiobutton.checked;
})[0].value;

if (musicValue == "com" && selectionValue == "pop") {
theVid.src = "videos/com_pop.mp4";
}

if (musicValue == "com" && selectionValue == "rock") {
theVid.src = "videos/com_rock.mp4";
}
if (musicValue == "mix" && selectionValue == "pop") {
theVid.src = "videos/mix_pop.mp4";
}
if (musicValue == "mix" && selectionValue == "rock") {
theVid.src = "videos/mix_rock.mp4";
}
if (musicValue == "vid" && selectionValue == "pop") {
theVid.src = "videos/vid_pop.mp4";
}
if (musicValue == "vid" && selectionValue == "rock") {
theVid.src = "videos/vid_rock.mp4";
}
}

<form>
<h3>Customize your own Showreel</h3>
<fieldset>
<input type="radio" id="commercials" name="selection" value="com">
<label for="commercials">Commercials</label>

<input type="radio" id="mixed" name="selection" value="mix" checked="checked">
<label for="mixed">Mixed</label>

<input type="radio" id="videoclip" name="selection" value="vid">
<label for="videoclip">Videoclips</label>
</fieldset>

<h4>Select Music</h4>
<fieldset>
<input type="radio" id="pop" name="musicselection" value="pop" checked="checked">
<label for="pop">Pop</label>
<input type="radio" id="rock" name="musicselection" value="rock">
<label for="rock">Rock</label>
</fieldset>

<video id="theVideo" controls></video>
<button type="button" id="theVideo" onclick="playselected();">play</button>

</form>





function playselected() {
var music = document.getElementsByName("musicselection");
var selection = document.getElementsByName("selection");
var theVid = document.getElementById("theVideo");

var musicValue = Array.prototype.slice.call(music).filter(function(musicRadioButton) {

return musicRadioButton.checked;
})[0].value;
var selectionValue = Array.prototype.slice.call(selection).filter(function(selectionRadioButton) {
return selectionRadiobutton.checked;
})[0].value;

if (musicValue == "com" && selectionValue == "pop") {
theVid.src = "videos/com_pop.mp4";
}

if (musicValue == "com" && selectionValue == "rock") {
theVid.src = "videos/com_rock.mp4";
}
if (musicValue == "mix" && selectionValue == "pop") {
theVid.src = "videos/mix_pop.mp4";
}
if (musicValue == "mix" && selectionValue == "rock") {
theVid.src = "videos/mix_rock.mp4";
}
if (musicValue == "vid" && selectionValue == "pop") {
theVid.src = "videos/vid_pop.mp4";
}
if (musicValue == "vid" && selectionValue == "rock") {
theVid.src = "videos/vid_rock.mp4";
}
}

<form>
<h3>Customize your own Showreel</h3>
<fieldset>
<input type="radio" id="commercials" name="selection" value="com">
<label for="commercials">Commercials</label>

<input type="radio" id="mixed" name="selection" value="mix" checked="checked">
<label for="mixed">Mixed</label>

<input type="radio" id="videoclip" name="selection" value="vid">
<label for="videoclip">Videoclips</label>
</fieldset>

<h4>Select Music</h4>
<fieldset>
<input type="radio" id="pop" name="musicselection" value="pop" checked="checked">
<label for="pop">Pop</label>
<input type="radio" id="rock" name="musicselection" value="rock">
<label for="rock">Rock</label>
</fieldset>

<video id="theVideo" controls></video>
<button type="button" id="theVideo" onclick="playselected();">play</button>

</form>






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 10 at 18:18









Terry

27.1k44067




27.1k44067












  • Thank you for the detailed answer. I tried to implement your answer into my code, but when i hit the "play" button its still not loading the chosen video. I really dont know why, can you point me in the right direction?
    – Joshua
    Nov 11 at 2:52










  • @Joshua Setting the video source does not automatically play the video. You need to invoke .play() on the video element manually. Note that this runs into the territory of video auto play, which browsers have recently placed a lot of restrictions on.
    – Terry
    Nov 11 at 9:10


















  • Thank you for the detailed answer. I tried to implement your answer into my code, but when i hit the "play" button its still not loading the chosen video. I really dont know why, can you point me in the right direction?
    – Joshua
    Nov 11 at 2:52










  • @Joshua Setting the video source does not automatically play the video. You need to invoke .play() on the video element manually. Note that this runs into the territory of video auto play, which browsers have recently placed a lot of restrictions on.
    – Terry
    Nov 11 at 9:10
















Thank you for the detailed answer. I tried to implement your answer into my code, but when i hit the "play" button its still not loading the chosen video. I really dont know why, can you point me in the right direction?
– Joshua
Nov 11 at 2:52




Thank you for the detailed answer. I tried to implement your answer into my code, but when i hit the "play" button its still not loading the chosen video. I really dont know why, can you point me in the right direction?
– Joshua
Nov 11 at 2:52












@Joshua Setting the video source does not automatically play the video. You need to invoke .play() on the video element manually. Note that this runs into the territory of video auto play, which browsers have recently placed a lot of restrictions on.
– Terry
Nov 11 at 9:10




@Joshua Setting the video source does not automatically play the video. You need to invoke .play() on the video element manually. Note that this runs into the territory of video auto play, which browsers have recently placed a lot of restrictions on.
– Terry
Nov 11 at 9:10


















 

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