grep - Get word from string
I have a bunch of strings that I have to fetch the 'port_num' from -
"76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
The word might be in a different place in the string and it might be a different length, but it always says 'port_num=' before it and ';' after it...
I only want this bit- 'switch01'
Currently I use-
| grep -Eo 'port_num=.+' | cut -d"=" -f2 | cut -d";" -f1'
But there has got to be a better way
grep
edited Nov 12 '18 at 14:29
Inian
39k63770
asked Nov 12 '18 at 14:09
BrickBrick
586
add a comment |
I have a bunch of strings that I have to fetch the 'port_num' from -
"76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
The word might be in a different place in the string and it might be a different length, but it always says 'port_num=' before it and ';' after it...
I only want this bit- 'switch01'
Currently I use-
| grep -Eo 'port_num=.+' | cut -d"=" -f2 | cut -d";" -f1'
But there has got to be a better way
grep
edited Nov 12 '18 at 14:29
Inian
39k63770
asked Nov 12 '18 at 14:09
BrickBrick
586
add a comment |
I have a bunch of strings that I have to fetch the 'port_num' from -
"76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
The word might be in a different place in the string and it might be a different length, but it always says 'port_num=' before it and ';' after it...
I only want this bit- 'switch01'
Currently I use-
| grep -Eo 'port_num=.+' | cut -d"=" -f2 | cut -d";" -f1'
But there has got to be a better way
grep
edited Nov 12 '18 at 14:29
Inian
39k63770
asked Nov 12 '18 at 14:09
BrickBrick
586
I have a bunch of strings that I have to fetch the 'port_num' from -
"76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
The word might be in a different place in the string and it might be a different length, but it always says 'port_num=' before it and ';' after it...
I only want this bit- 'switch01'
Currently I use-
| grep -Eo 'port_num=.+' | cut -d"=" -f2 | cut -d";" -f1'
But there has got to be a better way
grep
grep
edited Nov 12 '18 at 14:29
Inian
39k63770
asked Nov 12 '18 at 14:09
BrickBrick
586
edited Nov 12 '18 at 14:29
Inian
39k63770
asked Nov 12 '18 at 14:09
BrickBrick
586
edited Nov 12 '18 at 14:29
Inian
39k63770
edited Nov 12 '18 at 14:29
Inian
39k63770
edited Nov 12 '18 at 14:29
Inian
39k63770
39k63770
asked Nov 12 '18 at 14:09
BrickBrick
586
asked Nov 12 '18 at 14:09
BrickBrick
586
asked Nov 12 '18 at 14:09
BrickBrick
586
586
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
You can try grep -oP '(?<=port_num=).+(?=;)', if you run this:
echo "76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
| grep -oP '(?<=port_num=).+(?=;)'
result will be:
switch01
Updated answer: grep -oP '(?<=port_num=)[^;]+(?=;)'
answered Nov 12 '18 at 14:21
Vladimir KovpakVladimir Kovpak
10.6k43646
1
Perfect! thanks
– Brick
Nov 13 '18 at 16:04
Spoke to soon! sometimes there is a second ';' after the first... and it seems to continue until the last ';' in the line - any ideas?
– Brick
Nov 13 '18 at 16:21
grep -oP '(?<=port_num=)[^;]+(?=;)'
– Vladimir Kovpak
Nov 13 '18 at 16:49
add a comment |
This is what I would use:
... | grep -E 'port_num=.+' | sed 's/^.*port_num=([^;]*).*$/1/'
This works with or without the -o on grep, and the availability of -P will depend on the version of grep you have. (e.g., my grep does not have it). I'm not saying the other answers that rely on -P aren't any good -- they look fine to me. But grep -P will be less portable.
IMHO, piping grep with sed allows each utility to do what it specializes in -- grep is for selecting lines, sed is for modifying lines.
answered Nov 12 '18 at 14:15
landru27landru27
775213
add a comment |
This can be done in a simple sed command:
s="76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
sed 's/.*port_num=([^;]*);.*/1/' <<< "$s"
switch01
answered Nov 12 '18 at 15:14
anubhavaanubhava
521k46317391
add a comment |
... | grep -Po 'port_num.+(?=;)'
This uses grep's Perl Compatible Regular Expression (PCRE) syntax. The (?=;) is a look-ahead assertion which looks for a match with ";" but doesn't include it in the matched output.
This produces:
port_num=switch01
As @Vladimir Kovpak noted, if you want to exclude the "port_num=" string from this output, add a look-behind assertion:
... | grep -Po '(?<=port_num).+(?=;)'
answered Nov 12 '18 at 14:23
JRFergusonJRFerguson
5,99212231
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53263903%2fgrep-get-word-from-string%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can try grep -oP '(?<=port_num=).+(?=;)', if you run this:
echo "76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
| grep -oP '(?<=port_num=).+(?=;)'
result will be:
switch01
Updated answer: grep -oP '(?<=port_num=)[^;]+(?=;)'
answered Nov 12 '18 at 14:21
Vladimir KovpakVladimir Kovpak
10.6k43646
1
Perfect! thanks
– Brick
Nov 13 '18 at 16:04
Spoke to soon! sometimes there is a second ';' after the first... and it seems to continue until the last ';' in the line - any ideas?
– Brick
Nov 13 '18 at 16:21
grep -oP '(?<=port_num=)[^;]+(?=;)'
– Vladimir Kovpak
Nov 13 '18 at 16:49
add a comment |
You can try grep -oP '(?<=port_num=).+(?=;)', if you run this:
echo "76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
| grep -oP '(?<=port_num=).+(?=;)'
result will be:
switch01
Updated answer: grep -oP '(?<=port_num=)[^;]+(?=;)'
answered Nov 12 '18 at 14:21
Vladimir KovpakVladimir Kovpak
10.6k43646
1
Perfect! thanks
– Brick
Nov 13 '18 at 16:04
Spoke to soon! sometimes there is a second ';' after the first... and it seems to continue until the last ';' in the line - any ideas?
– Brick
Nov 13 '18 at 16:21
grep -oP '(?<=port_num=)[^;]+(?=;)'
– Vladimir Kovpak
Nov 13 '18 at 16:49
add a comment |
You can try grep -oP '(?<=port_num=).+(?=;)', if you run this:
echo "76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
| grep -oP '(?<=port_num=).+(?=;)'
result will be:
switch01
Updated answer: grep -oP '(?<=port_num=)[^;]+(?=;)'
answered Nov 12 '18 at 14:21
Vladimir KovpakVladimir Kovpak
10.6k43646
You can try grep -oP '(?<=port_num=).+(?=;)', if you run this:
echo "76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
| grep -oP '(?<=port_num=).+(?=;)'
result will be:
switch01
Updated answer: grep -oP '(?<=port_num=)[^;]+(?=;)'
answered Nov 12 '18 at 14:21
Vladimir KovpakVladimir Kovpak
10.6k43646
edited Nov 13 '18 at 16:52
answered Nov 12 '18 at 14:21
Vladimir KovpakVladimir Kovpak
10.6k43646
answered Nov 12 '18 at 14:21
Vladimir KovpakVladimir Kovpak
10.6k43646
answered Nov 12 '18 at 14:21
Vladimir KovpakVladimir Kovpak
10.6k43646
10.6k43646
1
Perfect! thanks
– Brick
Nov 13 '18 at 16:04
Spoke to soon! sometimes there is a second ';' after the first... and it seems to continue until the last ';' in the line - any ideas?
– Brick
Nov 13 '18 at 16:21
grep -oP '(?<=port_num=)[^;]+(?=;)'
– Vladimir Kovpak
Nov 13 '18 at 16:49
add a comment |
1
Perfect! thanks
– Brick
Nov 13 '18 at 16:04
Spoke to soon! sometimes there is a second ';' after the first... and it seems to continue until the last ';' in the line - any ideas?
– Brick
Nov 13 '18 at 16:21
grep -oP '(?<=port_num=)[^;]+(?=;)'
– Vladimir Kovpak
Nov 13 '18 at 16:49
1
1
Perfect! thanks
– Brick
Nov 13 '18 at 16:04
Perfect! thanks
– Brick
Nov 13 '18 at 16:04
Spoke to soon! sometimes there is a second ';' after the first... and it seems to continue until the last ';' in the line - any ideas?
– Brick
Nov 13 '18 at 16:21
Spoke to soon! sometimes there is a second ';' after the first... and it seems to continue until the last ';' in the line - any ideas?
– Brick
Nov 13 '18 at 16:21
grep -oP '(?<=port_num=)[^;]+(?=;)'– Vladimir Kovpak
Nov 13 '18 at 16:49
grep -oP '(?<=port_num=)[^;]+(?=;)'– Vladimir Kovpak
Nov 13 '18 at 16:49
add a comment |
This is what I would use:
... | grep -E 'port_num=.+' | sed 's/^.*port_num=([^;]*).*$/1/'
This works with or without the -o on grep, and the availability of -P will depend on the version of grep you have. (e.g., my grep does not have it). I'm not saying the other answers that rely on -P aren't any good -- they look fine to me. But grep -P will be less portable.
IMHO, piping grep with sed allows each utility to do what it specializes in -- grep is for selecting lines, sed is for modifying lines.
answered Nov 12 '18 at 14:15
landru27landru27
775213
add a comment |
This is what I would use:
... | grep -E 'port_num=.+' | sed 's/^.*port_num=([^;]*).*$/1/'
This works with or without the -o on grep, and the availability of -P will depend on the version of grep you have. (e.g., my grep does not have it). I'm not saying the other answers that rely on -P aren't any good -- they look fine to me. But grep -P will be less portable.
IMHO, piping grep with sed allows each utility to do what it specializes in -- grep is for selecting lines, sed is for modifying lines.
answered Nov 12 '18 at 14:15
landru27landru27
775213
add a comment |
This is what I would use:
... | grep -E 'port_num=.+' | sed 's/^.*port_num=([^;]*).*$/1/'
This works with or without the -o on grep, and the availability of -P will depend on the version of grep you have. (e.g., my grep does not have it). I'm not saying the other answers that rely on -P aren't any good -- they look fine to me. But grep -P will be less portable.
IMHO, piping grep with sed allows each utility to do what it specializes in -- grep is for selecting lines, sed is for modifying lines.
answered Nov 12 '18 at 14:15
landru27landru27
775213
This is what I would use:
... | grep -E 'port_num=.+' | sed 's/^.*port_num=([^;]*).*$/1/'
This works with or without the -o on grep, and the availability of -P will depend on the version of grep you have. (e.g., my grep does not have it). I'm not saying the other answers that rely on -P aren't any good -- they look fine to me. But grep -P will be less portable.
IMHO, piping grep with sed allows each utility to do what it specializes in -- grep is for selecting lines, sed is for modifying lines.
answered Nov 12 '18 at 14:15
landru27landru27
775213
edited Nov 12 '18 at 14:36
answered Nov 12 '18 at 14:15
landru27landru27
775213
answered Nov 12 '18 at 14:15
landru27landru27
775213
answered Nov 12 '18 at 14:15
landru27landru27
775213
775213
add a comment |
add a comment |
This can be done in a simple sed command:
s="76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
sed 's/.*port_num=([^;]*);.*/1/' <<< "$s"
switch01
answered Nov 12 '18 at 15:14
anubhavaanubhava
521k46317391
add a comment |
This can be done in a simple sed command:
s="76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
sed 's/.*port_num=([^;]*);.*/1/' <<< "$s"
switch01
answered Nov 12 '18 at 15:14
anubhavaanubhava
521k46317391
add a comment |
This can be done in a simple sed command:
s="76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
sed 's/.*port_num=([^;]*);.*/1/' <<< "$s"
switch01
answered Nov 12 '18 at 15:14
anubhavaanubhava
521k46317391
This can be done in a simple sed command:
s="76 : client=new; tags=circ, LINK; port_num=switch01; far_port=Gi1/0"
sed 's/.*port_num=([^;]*);.*/1/' <<< "$s"
switch01
answered Nov 12 '18 at 15:14
anubhavaanubhava
521k46317391
answered Nov 12 '18 at 15:14
anubhavaanubhava
521k46317391
answered Nov 12 '18 at 15:14
anubhavaanubhava
521k46317391
answered Nov 12 '18 at 15:14
anubhavaanubhava
521k46317391
521k46317391
add a comment |
add a comment |
... | grep -Po 'port_num.+(?=;)'
This uses grep's Perl Compatible Regular Expression (PCRE) syntax. The (?=;) is a look-ahead assertion which looks for a match with ";" but doesn't include it in the matched output.
This produces:
port_num=switch01
As @Vladimir Kovpak noted, if you want to exclude the "port_num=" string from this output, add a look-behind assertion:
... | grep -Po '(?<=port_num).+(?=;)'
answered Nov 12 '18 at 14:23
JRFergusonJRFerguson
5,99212231
add a comment |
... | grep -Po 'port_num.+(?=;)'
This uses grep's Perl Compatible Regular Expression (PCRE) syntax. The (?=;) is a look-ahead assertion which looks for a match with ";" but doesn't include it in the matched output.
This produces:
port_num=switch01
As @Vladimir Kovpak noted, if you want to exclude the "port_num=" string from this output, add a look-behind assertion:
... | grep -Po '(?<=port_num).+(?=;)'
answered Nov 12 '18 at 14:23
JRFergusonJRFerguson
5,99212231
add a comment |
... | grep -Po 'port_num.+(?=;)'
This uses grep's Perl Compatible Regular Expression (PCRE) syntax. The (?=;) is a look-ahead assertion which looks for a match with ";" but doesn't include it in the matched output.
This produces:
port_num=switch01
As @Vladimir Kovpak noted, if you want to exclude the "port_num=" string from this output, add a look-behind assertion:
... | grep -Po '(?<=port_num).+(?=;)'
answered Nov 12 '18 at 14:23
JRFergusonJRFerguson
5,99212231
... | grep -Po 'port_num.+(?=;)'
This uses grep's Perl Compatible Regular Expression (PCRE) syntax. The (?=;) is a look-ahead assertion which looks for a match with ";" but doesn't include it in the matched output.
This produces:
port_num=switch01
As @Vladimir Kovpak noted, if you want to exclude the "port_num=" string from this output, add a look-behind assertion:
... | grep -Po '(?<=port_num).+(?=;)'
answered Nov 12 '18 at 14:23
JRFergusonJRFerguson
5,99212231
edited Nov 12 '18 at 15:28
answered Nov 12 '18 at 14:23
JRFergusonJRFerguson
5,99212231
answered Nov 12 '18 at 14:23
JRFergusonJRFerguson
5,99212231
answered Nov 12 '18 at 14:23
JRFergusonJRFerguson
5,99212231
5,99212231
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53263903%2fgrep-get-word-from-string%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
