file_get_contents() returning raw data from url instead of json [duplicate]
-1
This question already has an answer here:
How to output JSON data correctly using PHP
7 answers
Display JSON as HTML [closed]
12 answers
This question have been asked many times before but none of the solution seems to works. I want to return JSON data from this url using file_get_contents() but it returning JSON data in raw format (string).
Here is my code:
$data = file_get_contents('https://dev.virtualearth.net/REST/v1/Routes/DistanceMatrix?origins=27.696694861033567,83.46625594498187&destinations=28.233514383842977,83.98651076641227&travelMode=driving&key=bingmaps_api_key&distanceUnit=km');
dd($data);
I have tried using curl but result is same it also return JSON data in raw format (string)
$url = 'https://dev.virtualearth.net/REST/v1/Routes/DistanceMatrix?origins=27.696694861033567,83.46625594498187&destinations=28.233514383842977,83.98651076641227&travelMode=driving&key=ingmaps_api_key&distanceUnit=km';
if (!function_exists('curl_init')) {
die('The cURL library is not installed.');
}
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$output = curl_exec($ch);
curl_close($ch);
dd($output);
Output I want
Output it gives
php laravel-5.6
asked Nov 12 '18 at 14:12
Milan TaramiMilan Tarami
416
marked as duplicate by mario php
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Nov 12 '18 at 14:23
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
-1
This question already has an answer here:
How to output JSON data correctly using PHP
7 answers
Display JSON as HTML [closed]
12 answers
This question have been asked many times before but none of the solution seems to works. I want to return JSON data from this url using file_get_contents() but it returning JSON data in raw format (string).
Here is my code:
$data = file_get_contents('https://dev.virtualearth.net/REST/v1/Routes/DistanceMatrix?origins=27.696694861033567,83.46625594498187&destinations=28.233514383842977,83.98651076641227&travelMode=driving&key=bingmaps_api_key&distanceUnit=km');
dd($data);
I have tried using curl but result is same it also return JSON data in raw format (string)
$url = 'https://dev.virtualearth.net/REST/v1/Routes/DistanceMatrix?origins=27.696694861033567,83.46625594498187&destinations=28.233514383842977,83.98651076641227&travelMode=driving&key=ingmaps_api_key&distanceUnit=km';
if (!function_exists('curl_init')) {
die('The cURL library is not installed.');
}
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$output = curl_exec($ch);
curl_close($ch);
dd($output);
Output I want
Output it gives
php laravel-5.6
asked Nov 12 '18 at 14:12
Milan TaramiMilan Tarami
416
marked as duplicate by mario php
Users with the php badge can single-handedly close php questions as duplicates and reopen them as needed.
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Nov 12 '18 at 14:23
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
The question linked as dupicate is not what he was asking for I guess. You're rather looking for theapplication/jsonheader. See: stackoverflow.com/questions/4064444/… - also, you should remove your API keys.
– maio290
Nov 12 '18 at 14:17
dd()is Laravel's debug output function, right? Then yes, it'll just show the literal string as is. Usually you'd decode the JSON, and do something with it. If this script is just about playback, then anechoand the right MIME type would make your browser JSON prettifier engage (if this is what you want, then it's perhaps worth mentioning).
– mario
Nov 12 '18 at 14:20
i will disable this key after a solution
– Milan Tarami
Nov 12 '18 at 14:23
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28
add a comment |
-1
-1
-1
This question already has an answer here:
How to output JSON data correctly using PHP
7 answers
Display JSON as HTML [closed]
12 answers
This question have been asked many times before but none of the solution seems to works. I want to return JSON data from this url using file_get_contents() but it returning JSON data in raw format (string).
Here is my code:
$data = file_get_contents('https://dev.virtualearth.net/REST/v1/Routes/DistanceMatrix?origins=27.696694861033567,83.46625594498187&destinations=28.233514383842977,83.98651076641227&travelMode=driving&key=bingmaps_api_key&distanceUnit=km');
dd($data);
I have tried using curl but result is same it also return JSON data in raw format (string)
$url = 'https://dev.virtualearth.net/REST/v1/Routes/DistanceMatrix?origins=27.696694861033567,83.46625594498187&destinations=28.233514383842977,83.98651076641227&travelMode=driving&key=ingmaps_api_key&distanceUnit=km';
if (!function_exists('curl_init')) {
die('The cURL library is not installed.');
}
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$output = curl_exec($ch);
curl_close($ch);
dd($output);
Output I want
Output it gives
php laravel-5.6
asked Nov 12 '18 at 14:12
Milan TaramiMilan Tarami
416
This question already has an answer here:
How to output JSON data correctly using PHP
7 answers
Display JSON as HTML [closed]
12 answers
This question have been asked many times before but none of the solution seems to works. I want to return JSON data from this url using file_get_contents() but it returning JSON data in raw format (string).
Here is my code:
$data = file_get_contents('https://dev.virtualearth.net/REST/v1/Routes/DistanceMatrix?origins=27.696694861033567,83.46625594498187&destinations=28.233514383842977,83.98651076641227&travelMode=driving&key=bingmaps_api_key&distanceUnit=km');
dd($data);
I have tried using curl but result is same it also return JSON data in raw format (string)
$url = 'https://dev.virtualearth.net/REST/v1/Routes/DistanceMatrix?origins=27.696694861033567,83.46625594498187&destinations=28.233514383842977,83.98651076641227&travelMode=driving&key=ingmaps_api_key&distanceUnit=km';
if (!function_exists('curl_init')) {
die('The cURL library is not installed.');
}
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$output = curl_exec($ch);
curl_close($ch);
dd($output);
Output I want
Output it gives
This question already has an answer here:
How to output JSON data correctly using PHP
7 answers
Display JSON as HTML [closed]
12 answers
php laravel-5.6
php laravel-5.6
asked Nov 12 '18 at 14:12
Milan TaramiMilan Tarami
416
asked Nov 12 '18 at 14:12
Milan TaramiMilan Tarami
416
edited Nov 12 '18 at 14:48
Milan Tarami
asked Nov 12 '18 at 14:12
Milan TaramiMilan Tarami
416
asked Nov 12 '18 at 14:12
Milan TaramiMilan Tarami
416
asked Nov 12 '18 at 14:12
Milan TaramiMilan Tarami
416
416
marked as duplicate by mario php
Users with the php badge can single-handedly close php questions as duplicates and reopen them as needed.
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Nov 12 '18 at 14:23
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by mario php
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Nov 12 '18 at 14:23
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
The question linked as dupicate is not what he was asking for I guess. You're rather looking for theapplication/jsonheader. See: stackoverflow.com/questions/4064444/… - also, you should remove your API keys.
– maio290
Nov 12 '18 at 14:17
dd()is Laravel's debug output function, right? Then yes, it'll just show the literal string as is. Usually you'd decode the JSON, and do something with it. If this script is just about playback, then anechoand the right MIME type would make your browser JSON prettifier engage (if this is what you want, then it's perhaps worth mentioning).
– mario
Nov 12 '18 at 14:20
i will disable this key after a solution
– Milan Tarami
Nov 12 '18 at 14:23
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28
add a comment |
1
The question linked as dupicate is not what he was asking for I guess. You're rather looking for theapplication/jsonheader. See: stackoverflow.com/questions/4064444/… - also, you should remove your API keys.
– maio290
Nov 12 '18 at 14:17
dd()is Laravel's debug output function, right? Then yes, it'll just show the literal string as is. Usually you'd decode the JSON, and do something with it. If this script is just about playback, then anechoand the right MIME type would make your browser JSON prettifier engage (if this is what you want, then it's perhaps worth mentioning).
– mario
Nov 12 '18 at 14:20
i will disable this key after a solution
– Milan Tarami
Nov 12 '18 at 14:23
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28
1
1
The question linked as dupicate is not what he was asking for I guess. You're rather looking for the
application/json header. See: stackoverflow.com/questions/4064444/… - also, you should remove your API keys.– maio290
Nov 12 '18 at 14:17
The question linked as dupicate is not what he was asking for I guess. You're rather looking for the
application/json header. See: stackoverflow.com/questions/4064444/… - also, you should remove your API keys.– maio290
Nov 12 '18 at 14:17
dd() is Laravel's debug output function, right? Then yes, it'll just show the literal string as is. Usually you'd decode the JSON, and do something with it. If this script is just about playback, then an echo and the right MIME type would make your browser JSON prettifier engage (if this is what you want, then it's perhaps worth mentioning).– mario
Nov 12 '18 at 14:20
dd() is Laravel's debug output function, right? Then yes, it'll just show the literal string as is. Usually you'd decode the JSON, and do something with it. If this script is just about playback, then an echo and the right MIME type would make your browser JSON prettifier engage (if this is what you want, then it's perhaps worth mentioning).– mario
Nov 12 '18 at 14:20
i will disable this key after a solution
– Milan Tarami
Nov 12 '18 at 14:23
i will disable this key after a solution
– Milan Tarami
Nov 12 '18 at 14:23
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28
add a comment |
1 Answer
1
active
oldest
votes
0
JSON is nothing but a string. file_get_contents or cURL will always return string, you have to decode the string using json_decode method which should give you the JSON object.
answered Nov 12 '18 at 14:23
AppDevDAppDevD
913
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28
Looks like you don't have json extension enabled in your php configuration. you should install ext-json and enable it.
– AppDevD
Nov 12 '18 at 14:30
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
JSON is nothing but a string. file_get_contents or cURL will always return string, you have to decode the string using json_decode method which should give you the JSON object.
answered Nov 12 '18 at 14:23
AppDevDAppDevD
913
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28
Looks like you don't have json extension enabled in your php configuration. you should install ext-json and enable it.
– AppDevD
Nov 12 '18 at 14:30
add a comment |
0
JSON is nothing but a string. file_get_contents or cURL will always return string, you have to decode the string using json_decode method which should give you the JSON object.
answered Nov 12 '18 at 14:23
AppDevDAppDevD
913
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28
Looks like you don't have json extension enabled in your php configuration. you should install ext-json and enable it.
– AppDevD
Nov 12 '18 at 14:30
add a comment |
0
0
0
JSON is nothing but a string. file_get_contents or cURL will always return string, you have to decode the string using json_decode method which should give you the JSON object.
answered Nov 12 '18 at 14:23
AppDevDAppDevD
913
JSON is nothing but a string. file_get_contents or cURL will always return string, you have to decode the string using json_decode method which should give you the JSON object.
answered Nov 12 '18 at 14:23
AppDevDAppDevD
913
answered Nov 12 '18 at 14:23
AppDevDAppDevD
913
answered Nov 12 '18 at 14:23
AppDevDAppDevD
913
answered Nov 12 '18 at 14:23
AppDevDAppDevD
913
913
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28
Looks like you don't have json extension enabled in your php configuration. you should install ext-json and enable it.
– AppDevD
Nov 12 '18 at 14:30
add a comment |
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28
Looks like you don't have json extension enabled in your php configuration. you should install ext-json and enable it.
– AppDevD
Nov 12 '18 at 14:30
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28
Looks like you don't have json extension enabled in your php configuration. you should install ext-json and enable it.
– AppDevD
Nov 12 '18 at 14:30
Looks like you don't have json extension enabled in your php configuration. you should install ext-json and enable it.
– AppDevD
Nov 12 '18 at 14:30
add a comment |
1
The question linked as dupicate is not what he was asking for I guess. You're rather looking for the
application/jsonheader. See: stackoverflow.com/questions/4064444/… - also, you should remove your API keys.– maio290
Nov 12 '18 at 14:17
dd()is Laravel's debug output function, right? Then yes, it'll just show the literal string as is. Usually you'd decode the JSON, and do something with it. If this script is just about playback, then anechoand the right MIME type would make your browser JSON prettifier engage (if this is what you want, then it's perhaps worth mentioning).– mario
Nov 12 '18 at 14:20
i will disable this key after a solution
– Milan Tarami
Nov 12 '18 at 14:23
when i do json_decode() it gives me error Call to undefined function GuzzleHttpjson_decode()
– Milan Tarami
Nov 12 '18 at 14:28