How to use CURL over SSH and get the file as well as the return value?
0
I want to load a file from a clients webserver. This webserver is running local only. To get there I have to use ssh. I need the content as well as the return value (e.g. SSH connection broke, webserver down).
What do I have to change? My first try:
#!/bin/bash
RETURN=0
CONTENT=""
sshpass -p xxxxxx ssh root@172.17.1.33 "curl -X POST http://127.0.0.1:10000/status -H 'Content-Type: application/json' > $CONTENT | bash; RETURN=$?"
bash curl ssh
asked Nov 13 '18 at 16:39
user1587451user1587451
445718
add a comment |
0
I want to load a file from a clients webserver. This webserver is running local only. To get there I have to use ssh. I need the content as well as the return value (e.g. SSH connection broke, webserver down).
What do I have to change? My first try:
#!/bin/bash
RETURN=0
CONTENT=""
sshpass -p xxxxxx ssh root@172.17.1.33 "curl -X POST http://127.0.0.1:10000/status -H 'Content-Type: application/json' > $CONTENT | bash; RETURN=$?"
bash curl ssh
asked Nov 13 '18 at 16:39
user1587451user1587451
445718
1
The exit status ofsshwill be the exit status ofcurlif that's the only command you run.sshpassdoesn't allow you to retrieve the exit status ofssh, which is another reason to set up public-key authentication instead of usingsshpass.
– chepner
Nov 13 '18 at 17:00
add a comment |
0
0
0
I want to load a file from a clients webserver. This webserver is running local only. To get there I have to use ssh. I need the content as well as the return value (e.g. SSH connection broke, webserver down).
What do I have to change? My first try:
#!/bin/bash
RETURN=0
CONTENT=""
sshpass -p xxxxxx ssh root@172.17.1.33 "curl -X POST http://127.0.0.1:10000/status -H 'Content-Type: application/json' > $CONTENT | bash; RETURN=$?"
bash curl ssh
asked Nov 13 '18 at 16:39
user1587451user1587451
445718
I want to load a file from a clients webserver. This webserver is running local only. To get there I have to use ssh. I need the content as well as the return value (e.g. SSH connection broke, webserver down).
What do I have to change? My first try:
#!/bin/bash
RETURN=0
CONTENT=""
sshpass -p xxxxxx ssh root@172.17.1.33 "curl -X POST http://127.0.0.1:10000/status -H 'Content-Type: application/json' > $CONTENT | bash; RETURN=$?"
bash curl ssh
bash curl ssh
asked Nov 13 '18 at 16:39
user1587451user1587451
445718
asked Nov 13 '18 at 16:39
user1587451user1587451
445718
asked Nov 13 '18 at 16:39
user1587451user1587451
445718
asked Nov 13 '18 at 16:39
user1587451user1587451
445718
asked Nov 13 '18 at 16:39
user1587451user1587451
445718
445718
1
The exit status ofsshwill be the exit status ofcurlif that's the only command you run.sshpassdoesn't allow you to retrieve the exit status ofssh, which is another reason to set up public-key authentication instead of usingsshpass.
– chepner
Nov 13 '18 at 17:00
add a comment |
1
The exit status ofsshwill be the exit status ofcurlif that's the only command you run.sshpassdoesn't allow you to retrieve the exit status ofssh, which is another reason to set up public-key authentication instead of usingsshpass.
– chepner
Nov 13 '18 at 17:00
1
1
The exit status of
ssh will be the exit status of curl if that's the only command you run. sshpass doesn't allow you to retrieve the exit status of ssh, which is another reason to set up public-key authentication instead of using sshpass.– chepner
Nov 13 '18 at 17:00
The exit status of
ssh will be the exit status of curl if that's the only command you run. sshpass doesn't allow you to retrieve the exit status of ssh, which is another reason to set up public-key authentication instead of using sshpass.– chepner
Nov 13 '18 at 17:00
add a comment |
1 Answer
1
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oldest
votes
1
If you want to get the exit code of curl and the return value of curl:
#!/bin/bash
CONTENT=$(sshpass -p xxxxxx ssh root@172.17.1.33 "curl -X POST http://127.0.0.1:10000/status -H 'Content-Type: application/json'")
RETURN=$?
echo "$RETURN, $CONTENT"
In your script you set the variables on the server you ssh'ed into.
answered Nov 13 '18 at 17:03
maxmax
360319
Almost there. When I do this,$CONTENTshows a mixture in a single line of the multiline-output of the servers output. Why is that?
– user1587451
Nov 13 '18 at 17:07
Whats the actual output and what do you expect the output to be?
– max
Nov 13 '18 at 17:09
8 lines of json output
– user1587451
Nov 13 '18 at 17:19
1
Sounds like you forgot to put double quotes around"$CONTENT"or maybe the value contains DOS carriage returns.
– tripleee
Nov 13 '18 at 17:21
You are a bash master...
– user1587451
Nov 13 '18 at 17:27
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
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oldest
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votes
1
If you want to get the exit code of curl and the return value of curl:
#!/bin/bash
CONTENT=$(sshpass -p xxxxxx ssh root@172.17.1.33 "curl -X POST http://127.0.0.1:10000/status -H 'Content-Type: application/json'")
RETURN=$?
echo "$RETURN, $CONTENT"
In your script you set the variables on the server you ssh'ed into.
answered Nov 13 '18 at 17:03
maxmax
360319
Almost there. When I do this,$CONTENTshows a mixture in a single line of the multiline-output of the servers output. Why is that?
– user1587451
Nov 13 '18 at 17:07
Whats the actual output and what do you expect the output to be?
– max
Nov 13 '18 at 17:09
8 lines of json output
– user1587451
Nov 13 '18 at 17:19
1
Sounds like you forgot to put double quotes around"$CONTENT"or maybe the value contains DOS carriage returns.
– tripleee
Nov 13 '18 at 17:21
You are a bash master...
– user1587451
Nov 13 '18 at 17:27
add a comment |
1
If you want to get the exit code of curl and the return value of curl:
#!/bin/bash
CONTENT=$(sshpass -p xxxxxx ssh root@172.17.1.33 "curl -X POST http://127.0.0.1:10000/status -H 'Content-Type: application/json'")
RETURN=$?
echo "$RETURN, $CONTENT"
In your script you set the variables on the server you ssh'ed into.
answered Nov 13 '18 at 17:03
maxmax
360319
Almost there. When I do this,$CONTENTshows a mixture in a single line of the multiline-output of the servers output. Why is that?
– user1587451
Nov 13 '18 at 17:07
Whats the actual output and what do you expect the output to be?
– max
Nov 13 '18 at 17:09
8 lines of json output
– user1587451
Nov 13 '18 at 17:19
1
Sounds like you forgot to put double quotes around"$CONTENT"or maybe the value contains DOS carriage returns.
– tripleee
Nov 13 '18 at 17:21
You are a bash master...
– user1587451
Nov 13 '18 at 17:27
add a comment |
1
1
1
If you want to get the exit code of curl and the return value of curl:
#!/bin/bash
CONTENT=$(sshpass -p xxxxxx ssh root@172.17.1.33 "curl -X POST http://127.0.0.1:10000/status -H 'Content-Type: application/json'")
RETURN=$?
echo "$RETURN, $CONTENT"
In your script you set the variables on the server you ssh'ed into.
answered Nov 13 '18 at 17:03
maxmax
360319
If you want to get the exit code of curl and the return value of curl:
#!/bin/bash
CONTENT=$(sshpass -p xxxxxx ssh root@172.17.1.33 "curl -X POST http://127.0.0.1:10000/status -H 'Content-Type: application/json'")
RETURN=$?
echo "$RETURN, $CONTENT"
In your script you set the variables on the server you ssh'ed into.
answered Nov 13 '18 at 17:03
maxmax
360319
edited Nov 13 '18 at 17:10
answered Nov 13 '18 at 17:03
maxmax
360319
answered Nov 13 '18 at 17:03
maxmax
360319
answered Nov 13 '18 at 17:03
maxmax
360319
360319
Almost there. When I do this,$CONTENTshows a mixture in a single line of the multiline-output of the servers output. Why is that?
– user1587451
Nov 13 '18 at 17:07
Whats the actual output and what do you expect the output to be?
– max
Nov 13 '18 at 17:09
8 lines of json output
– user1587451
Nov 13 '18 at 17:19
1
Sounds like you forgot to put double quotes around"$CONTENT"or maybe the value contains DOS carriage returns.
– tripleee
Nov 13 '18 at 17:21
You are a bash master...
– user1587451
Nov 13 '18 at 17:27
add a comment |
Almost there. When I do this,$CONTENTshows a mixture in a single line of the multiline-output of the servers output. Why is that?
– user1587451
Nov 13 '18 at 17:07
Whats the actual output and what do you expect the output to be?
– max
Nov 13 '18 at 17:09
8 lines of json output
– user1587451
Nov 13 '18 at 17:19
1
Sounds like you forgot to put double quotes around"$CONTENT"or maybe the value contains DOS carriage returns.
– tripleee
Nov 13 '18 at 17:21
You are a bash master...
– user1587451
Nov 13 '18 at 17:27
Almost there. When I do this,
$CONTENT shows a mixture in a single line of the multiline-output of the servers output. Why is that?– user1587451
Nov 13 '18 at 17:07
Almost there. When I do this,
$CONTENT shows a mixture in a single line of the multiline-output of the servers output. Why is that?– user1587451
Nov 13 '18 at 17:07
Whats the actual output and what do you expect the output to be?
– max
Nov 13 '18 at 17:09
Whats the actual output and what do you expect the output to be?
– max
Nov 13 '18 at 17:09
8 lines of json output
– user1587451
Nov 13 '18 at 17:19
8 lines of json output
– user1587451
Nov 13 '18 at 17:19
1
1
Sounds like you forgot to put double quotes around
"$CONTENT" or maybe the value contains DOS carriage returns.– tripleee
Nov 13 '18 at 17:21
Sounds like you forgot to put double quotes around
"$CONTENT" or maybe the value contains DOS carriage returns.– tripleee
Nov 13 '18 at 17:21
You are a bash master...
– user1587451
Nov 13 '18 at 17:27
You are a bash master...
– user1587451
Nov 13 '18 at 17:27
add a comment |
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1
The exit status of
sshwill be the exit status ofcurlif that's the only command you run.sshpassdoesn't allow you to retrieve the exit status ofssh, which is another reason to set up public-key authentication instead of usingsshpass.– chepner
Nov 13 '18 at 17:00