How to check if a table contains a specific number of rows?
I have this query:
SELECT (COUNT(*) = SUM(status in (3, 5)) ) AS result
FROM `match` WHERE round_id = 15
this essentially check if the table match
have all the items with a status 3
or 5
for the round 15
. This works, but I actually want add another condition, in particular if the result
is true
I want check that all the records of that table with round_id = 15
are 20
. How can I perform this?
mysql sql
add a comment |
I have this query:
SELECT (COUNT(*) = SUM(status in (3, 5)) ) AS result
FROM `match` WHERE round_id = 15
this essentially check if the table match
have all the items with a status 3
or 5
for the round 15
. This works, but I actually want add another condition, in particular if the result
is true
I want check that all the records of that table with round_id = 15
are 20
. How can I perform this?
mysql sql
Based on the syntax, I added the mysql tag. If this is not correct, please add the correct tag for the database you are using.
– Gordon Linoff
Nov 13 '18 at 17:00
add a comment |
I have this query:
SELECT (COUNT(*) = SUM(status in (3, 5)) ) AS result
FROM `match` WHERE round_id = 15
this essentially check if the table match
have all the items with a status 3
or 5
for the round 15
. This works, but I actually want add another condition, in particular if the result
is true
I want check that all the records of that table with round_id = 15
are 20
. How can I perform this?
mysql sql
I have this query:
SELECT (COUNT(*) = SUM(status in (3, 5)) ) AS result
FROM `match` WHERE round_id = 15
this essentially check if the table match
have all the items with a status 3
or 5
for the round 15
. This works, but I actually want add another condition, in particular if the result
is true
I want check that all the records of that table with round_id = 15
are 20
. How can I perform this?
mysql sql
mysql sql
edited Nov 13 '18 at 17:00
Gordon Linoff
770k35304404
770k35304404
asked Nov 13 '18 at 16:50
SpartaokSpartaok
748
748
Based on the syntax, I added the mysql tag. If this is not correct, please add the correct tag for the database you are using.
– Gordon Linoff
Nov 13 '18 at 17:00
add a comment |
Based on the syntax, I added the mysql tag. If this is not correct, please add the correct tag for the database you are using.
– Gordon Linoff
Nov 13 '18 at 17:00
Based on the syntax, I added the mysql tag. If this is not correct, please add the correct tag for the database you are using.
– Gordon Linoff
Nov 13 '18 at 17:00
Based on the syntax, I added the mysql tag. If this is not correct, please add the correct tag for the database you are using.
– Gordon Linoff
Nov 13 '18 at 17:00
add a comment |
1 Answer
1
active
oldest
votes
Is this what you want?
SELECT (COUNT(*) = SUM(status in (3, 5)) AND COUNT(*) = 20) AS result
FROM `match`
WHERE round_id = 15;
This checks that there are 20 rows that match the conditions.
thanks was so simple
– Spartaok
Nov 13 '18 at 17:14
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Is this what you want?
SELECT (COUNT(*) = SUM(status in (3, 5)) AND COUNT(*) = 20) AS result
FROM `match`
WHERE round_id = 15;
This checks that there are 20 rows that match the conditions.
thanks was so simple
– Spartaok
Nov 13 '18 at 17:14
add a comment |
Is this what you want?
SELECT (COUNT(*) = SUM(status in (3, 5)) AND COUNT(*) = 20) AS result
FROM `match`
WHERE round_id = 15;
This checks that there are 20 rows that match the conditions.
thanks was so simple
– Spartaok
Nov 13 '18 at 17:14
add a comment |
Is this what you want?
SELECT (COUNT(*) = SUM(status in (3, 5)) AND COUNT(*) = 20) AS result
FROM `match`
WHERE round_id = 15;
This checks that there are 20 rows that match the conditions.
Is this what you want?
SELECT (COUNT(*) = SUM(status in (3, 5)) AND COUNT(*) = 20) AS result
FROM `match`
WHERE round_id = 15;
This checks that there are 20 rows that match the conditions.
answered Nov 13 '18 at 17:00
Gordon LinoffGordon Linoff
770k35304404
770k35304404
thanks was so simple
– Spartaok
Nov 13 '18 at 17:14
add a comment |
thanks was so simple
– Spartaok
Nov 13 '18 at 17:14
thanks was so simple
– Spartaok
Nov 13 '18 at 17:14
thanks was so simple
– Spartaok
Nov 13 '18 at 17:14
add a comment |
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Based on the syntax, I added the mysql tag. If this is not correct, please add the correct tag for the database you are using.
– Gordon Linoff
Nov 13 '18 at 17:00