How can I convert a column of Excel into a specific dictionary format?











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I have one column in my excel file, i want to convert all the rows of the column into a specific dictionary format.
that is, the keys and values between double quotation and values between brackets and parentheses and before that, the word is set, as seen in the picture:



I use this code but This does not give me the format I want:



import openpyxl

# Access active worksheet of excel file
book = openpyxl.load_workbook('workbook.xlsx')
sheet = book.active

# Access first column
column = sheet['A']

# Use dictionary comprehension on the cells in the column
d = {
'item{}'.format(num): cell.value
for (num, cell) in enumerate(column, 1)
}









share|improve this question




























    up vote
    -2
    down vote

    favorite












    I have one column in my excel file, i want to convert all the rows of the column into a specific dictionary format.
    that is, the keys and values between double quotation and values between brackets and parentheses and before that, the word is set, as seen in the picture:



    I use this code but This does not give me the format I want:



    import openpyxl

    # Access active worksheet of excel file
    book = openpyxl.load_workbook('workbook.xlsx')
    sheet = book.active

    # Access first column
    column = sheet['A']

    # Use dictionary comprehension on the cells in the column
    d = {
    'item{}'.format(num): cell.value
    for (num, cell) in enumerate(column, 1)
    }









    share|improve this question


























      up vote
      -2
      down vote

      favorite









      up vote
      -2
      down vote

      favorite











      I have one column in my excel file, i want to convert all the rows of the column into a specific dictionary format.
      that is, the keys and values between double quotation and values between brackets and parentheses and before that, the word is set, as seen in the picture:



      I use this code but This does not give me the format I want:



      import openpyxl

      # Access active worksheet of excel file
      book = openpyxl.load_workbook('workbook.xlsx')
      sheet = book.active

      # Access first column
      column = sheet['A']

      # Use dictionary comprehension on the cells in the column
      d = {
      'item{}'.format(num): cell.value
      for (num, cell) in enumerate(column, 1)
      }









      share|improve this question















      I have one column in my excel file, i want to convert all the rows of the column into a specific dictionary format.
      that is, the keys and values between double quotation and values between brackets and parentheses and before that, the word is set, as seen in the picture:



      I use this code but This does not give me the format I want:



      import openpyxl

      # Access active worksheet of excel file
      book = openpyxl.load_workbook('workbook.xlsx')
      sheet = book.active

      # Access first column
      column = sheet['A']

      # Use dictionary comprehension on the cells in the column
      d = {
      'item{}'.format(num): cell.value
      for (num, cell) in enumerate(column, 1)
      }






      python dictionary openpyxl






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      edited Nov 12 at 14:34









      Anony-Mousse

      56.6k796158




      56.6k796158










      asked Nov 11 at 5:20









      mina

      14




      14
























          1 Answer
          1






          active

          oldest

          votes

















          up vote
          0
          down vote



          accepted










          Your image shows the values in the dictionary as single value sets, rather than integers. You can put the cell.value into a set:



          d = {
          'item{}'.format(num): {cell.value} for (num, cell) in enumerate(column, 1)
          }


          To check:



          >>> from pprint import pprint
          >>> pprint.pprint(d)
          {'item1': {5},
          'item2': {2},
          'item3': {0},
          'item4': {1},
          'item5': {6},
          'item6': {6},
          'item7': {1}}
          >>> pprint([type(d[key]) for key in d.keys()])
          [<class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>]





          share|improve this answer





















          • Thank you very very very much Orix.
            – mina
            Nov 11 at 17:02










          • Glad my answer helped you. :) If you don't mind please accept my answer and mark this question as solved as well
            – Orix Au Yeung
            Nov 12 at 2:48











          Your Answer






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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          0
          down vote



          accepted










          Your image shows the values in the dictionary as single value sets, rather than integers. You can put the cell.value into a set:



          d = {
          'item{}'.format(num): {cell.value} for (num, cell) in enumerate(column, 1)
          }


          To check:



          >>> from pprint import pprint
          >>> pprint.pprint(d)
          {'item1': {5},
          'item2': {2},
          'item3': {0},
          'item4': {1},
          'item5': {6},
          'item6': {6},
          'item7': {1}}
          >>> pprint([type(d[key]) for key in d.keys()])
          [<class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>]





          share|improve this answer





















          • Thank you very very very much Orix.
            – mina
            Nov 11 at 17:02










          • Glad my answer helped you. :) If you don't mind please accept my answer and mark this question as solved as well
            – Orix Au Yeung
            Nov 12 at 2:48















          up vote
          0
          down vote



          accepted










          Your image shows the values in the dictionary as single value sets, rather than integers. You can put the cell.value into a set:



          d = {
          'item{}'.format(num): {cell.value} for (num, cell) in enumerate(column, 1)
          }


          To check:



          >>> from pprint import pprint
          >>> pprint.pprint(d)
          {'item1': {5},
          'item2': {2},
          'item3': {0},
          'item4': {1},
          'item5': {6},
          'item6': {6},
          'item7': {1}}
          >>> pprint([type(d[key]) for key in d.keys()])
          [<class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>]





          share|improve this answer





















          • Thank you very very very much Orix.
            – mina
            Nov 11 at 17:02










          • Glad my answer helped you. :) If you don't mind please accept my answer and mark this question as solved as well
            – Orix Au Yeung
            Nov 12 at 2:48













          up vote
          0
          down vote



          accepted







          up vote
          0
          down vote



          accepted






          Your image shows the values in the dictionary as single value sets, rather than integers. You can put the cell.value into a set:



          d = {
          'item{}'.format(num): {cell.value} for (num, cell) in enumerate(column, 1)
          }


          To check:



          >>> from pprint import pprint
          >>> pprint.pprint(d)
          {'item1': {5},
          'item2': {2},
          'item3': {0},
          'item4': {1},
          'item5': {6},
          'item6': {6},
          'item7': {1}}
          >>> pprint([type(d[key]) for key in d.keys()])
          [<class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>]





          share|improve this answer












          Your image shows the values in the dictionary as single value sets, rather than integers. You can put the cell.value into a set:



          d = {
          'item{}'.format(num): {cell.value} for (num, cell) in enumerate(column, 1)
          }


          To check:



          >>> from pprint import pprint
          >>> pprint.pprint(d)
          {'item1': {5},
          'item2': {2},
          'item3': {0},
          'item4': {1},
          'item5': {6},
          'item6': {6},
          'item7': {1}}
          >>> pprint([type(d[key]) for key in d.keys()])
          [<class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>,
          <class 'set'>]






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 11 at 6:47









          Orix Au Yeung

          514




          514












          • Thank you very very very much Orix.
            – mina
            Nov 11 at 17:02










          • Glad my answer helped you. :) If you don't mind please accept my answer and mark this question as solved as well
            – Orix Au Yeung
            Nov 12 at 2:48


















          • Thank you very very very much Orix.
            – mina
            Nov 11 at 17:02










          • Glad my answer helped you. :) If you don't mind please accept my answer and mark this question as solved as well
            – Orix Au Yeung
            Nov 12 at 2:48
















          Thank you very very very much Orix.
          – mina
          Nov 11 at 17:02




          Thank you very very very much Orix.
          – mina
          Nov 11 at 17:02












          Glad my answer helped you. :) If you don't mind please accept my answer and mark this question as solved as well
          – Orix Au Yeung
          Nov 12 at 2:48




          Glad my answer helped you. :) If you don't mind please accept my answer and mark this question as solved as well
          – Orix Au Yeung
          Nov 12 at 2:48


















           

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