How to display decimal in specific format in Jackson (for JSON)
0
Suppose I have an object with
private Double test;
// Need specific output in JSON via Jackson: test = 24.6000
When output to JSON via Jackson, I get 24.6, but I need the exact 4-decimal output as in the example. Does Jackson allow this?
For example, for Dates, we found a way to force MM/dd/yyyy:
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "MM/dd/yyyy")
Date myDate;
We need something similar for Decimal formatting.
json spring jackson
asked Nov 13 '18 at 15:50
gene b.gene b.
1,77762554
add a comment |
0
Suppose I have an object with
private Double test;
// Need specific output in JSON via Jackson: test = 24.6000
When output to JSON via Jackson, I get 24.6, but I need the exact 4-decimal output as in the example. Does Jackson allow this?
For example, for Dates, we found a way to force MM/dd/yyyy:
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "MM/dd/yyyy")
Date myDate;
We need something similar for Decimal formatting.
json spring jackson
asked Nov 13 '18 at 15:50
gene b.gene b.
1,77762554
add a comment |
0
0
0
Suppose I have an object with
private Double test;
// Need specific output in JSON via Jackson: test = 24.6000
When output to JSON via Jackson, I get 24.6, but I need the exact 4-decimal output as in the example. Does Jackson allow this?
For example, for Dates, we found a way to force MM/dd/yyyy:
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "MM/dd/yyyy")
Date myDate;
We need something similar for Decimal formatting.
json spring jackson
asked Nov 13 '18 at 15:50
gene b.gene b.
1,77762554
Suppose I have an object with
private Double test;
// Need specific output in JSON via Jackson: test = 24.6000
When output to JSON via Jackson, I get 24.6, but I need the exact 4-decimal output as in the example. Does Jackson allow this?
For example, for Dates, we found a way to force MM/dd/yyyy:
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "MM/dd/yyyy")
Date myDate;
We need something similar for Decimal formatting.
json spring jackson
json spring jackson
asked Nov 13 '18 at 15:50
gene b.gene b.
1,77762554
asked Nov 13 '18 at 15:50
gene b.gene b.
1,77762554
edited Nov 13 '18 at 15:58
gene b.
asked Nov 13 '18 at 15:50
gene b.gene b.
1,77762554
asked Nov 13 '18 at 15:50
gene b.gene b.
1,77762554
asked Nov 13 '18 at 15:50
gene b.gene b.
1,77762554
1,77762554
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
1
One way of doing this is to use custom json serializer and specify in @JsonSerialize.
@JsonSerialize(using = CustomDoubleSerializer.class)
public Double getAmount()
public class CustomDoubleSerializer extends JsonSerializer<Double> {
@Override
public void serialize(Double value, JsonGenerator jgen, SerializerProvider provider) throws IOException, JsonGenerationException {
if (null == value) {
jgen.writeNull();
} else {
final String pattern = ".####";
final DecimalFormat myFormatter = new DecimalFormat(pattern);
final String output = myFormatter.format(value);
jgen.writeNumber(output);
}
}
}
answered Nov 13 '18 at 16:01
shakhawatshakhawat
1,6151026
thanks so there is no out-of-the-box Jackson annotation, in other words? For most cases there are.
– gene b.
Nov 13 '18 at 16:17
1
I don't think there is. But it would be a nice addition since this is a very common use case.
– shakhawat
Nov 14 '18 at 4:17
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
One way of doing this is to use custom json serializer and specify in @JsonSerialize.
@JsonSerialize(using = CustomDoubleSerializer.class)
public Double getAmount()
public class CustomDoubleSerializer extends JsonSerializer<Double> {
@Override
public void serialize(Double value, JsonGenerator jgen, SerializerProvider provider) throws IOException, JsonGenerationException {
if (null == value) {
jgen.writeNull();
} else {
final String pattern = ".####";
final DecimalFormat myFormatter = new DecimalFormat(pattern);
final String output = myFormatter.format(value);
jgen.writeNumber(output);
}
}
}
answered Nov 13 '18 at 16:01
shakhawatshakhawat
1,6151026
thanks so there is no out-of-the-box Jackson annotation, in other words? For most cases there are.
– gene b.
Nov 13 '18 at 16:17
1
I don't think there is. But it would be a nice addition since this is a very common use case.
– shakhawat
Nov 14 '18 at 4:17
add a comment |
1
One way of doing this is to use custom json serializer and specify in @JsonSerialize.
@JsonSerialize(using = CustomDoubleSerializer.class)
public Double getAmount()
public class CustomDoubleSerializer extends JsonSerializer<Double> {
@Override
public void serialize(Double value, JsonGenerator jgen, SerializerProvider provider) throws IOException, JsonGenerationException {
if (null == value) {
jgen.writeNull();
} else {
final String pattern = ".####";
final DecimalFormat myFormatter = new DecimalFormat(pattern);
final String output = myFormatter.format(value);
jgen.writeNumber(output);
}
}
}
answered Nov 13 '18 at 16:01
shakhawatshakhawat
1,6151026
thanks so there is no out-of-the-box Jackson annotation, in other words? For most cases there are.
– gene b.
Nov 13 '18 at 16:17
1
I don't think there is. But it would be a nice addition since this is a very common use case.
– shakhawat
Nov 14 '18 at 4:17
add a comment |
1
1
1
One way of doing this is to use custom json serializer and specify in @JsonSerialize.
@JsonSerialize(using = CustomDoubleSerializer.class)
public Double getAmount()
public class CustomDoubleSerializer extends JsonSerializer<Double> {
@Override
public void serialize(Double value, JsonGenerator jgen, SerializerProvider provider) throws IOException, JsonGenerationException {
if (null == value) {
jgen.writeNull();
} else {
final String pattern = ".####";
final DecimalFormat myFormatter = new DecimalFormat(pattern);
final String output = myFormatter.format(value);
jgen.writeNumber(output);
}
}
}
answered Nov 13 '18 at 16:01
shakhawatshakhawat
1,6151026
One way of doing this is to use custom json serializer and specify in @JsonSerialize.
@JsonSerialize(using = CustomDoubleSerializer.class)
public Double getAmount()
public class CustomDoubleSerializer extends JsonSerializer<Double> {
@Override
public void serialize(Double value, JsonGenerator jgen, SerializerProvider provider) throws IOException, JsonGenerationException {
if (null == value) {
jgen.writeNull();
} else {
final String pattern = ".####";
final DecimalFormat myFormatter = new DecimalFormat(pattern);
final String output = myFormatter.format(value);
jgen.writeNumber(output);
}
}
}
answered Nov 13 '18 at 16:01
shakhawatshakhawat
1,6151026
edited Nov 13 '18 at 16:11
answered Nov 13 '18 at 16:01
shakhawatshakhawat
1,6151026
answered Nov 13 '18 at 16:01
shakhawatshakhawat
1,6151026
answered Nov 13 '18 at 16:01
shakhawatshakhawat
1,6151026
1,6151026
thanks so there is no out-of-the-box Jackson annotation, in other words? For most cases there are.
– gene b.
Nov 13 '18 at 16:17
1
I don't think there is. But it would be a nice addition since this is a very common use case.
– shakhawat
Nov 14 '18 at 4:17
add a comment |
thanks so there is no out-of-the-box Jackson annotation, in other words? For most cases there are.
– gene b.
Nov 13 '18 at 16:17
1
I don't think there is. But it would be a nice addition since this is a very common use case.
– shakhawat
Nov 14 '18 at 4:17
thanks so there is no out-of-the-box Jackson annotation, in other words? For most cases there are.
– gene b.
Nov 13 '18 at 16:17
thanks so there is no out-of-the-box Jackson annotation, in other words? For most cases there are.
– gene b.
Nov 13 '18 at 16:17
1
1
I don't think there is. But it would be a nice addition since this is a very common use case.
– shakhawat
Nov 14 '18 at 4:17
I don't think there is. But it would be a nice addition since this is a very common use case.
– shakhawat
Nov 14 '18 at 4:17
add a comment |
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