Excel VBA convert Date with time
I have 2 cells with time data that format as follows:
"A1" = Sep 01 2018 00:01:33.707
"A2" = Sep 01 2018 00:01:49.917
I need to create a button and method within excel VBA that will set "A3" cell to true if the time "A2" is more than "A1" by 90 seconds.
This is what i have so far but it does not work:
Sub Macro2()
Dim str1 As String, str2 As String
With Worksheets("sheet5")
str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text
'greater than 90m seconds in A3
.Cells(3, "A") = CBool(Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4)))) > _
TimeSerial(0, 0, 90))
'actual absolute difference in A4
.Cells(4, "A") = Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4))))
End With End Sub
The above gives error because Date functions works with system Locale, which in my case is Hebrew, while the Data is in English.
Another way that could help is to convert all the column "A" (which holds the dates) to a system local date that can be used with Date and time functions on VBA (don't know how to do that).
Please help
excel vba excel-vba
add a comment |
I have 2 cells with time data that format as follows:
"A1" = Sep 01 2018 00:01:33.707
"A2" = Sep 01 2018 00:01:49.917
I need to create a button and method within excel VBA that will set "A3" cell to true if the time "A2" is more than "A1" by 90 seconds.
This is what i have so far but it does not work:
Sub Macro2()
Dim str1 As String, str2 As String
With Worksheets("sheet5")
str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text
'greater than 90m seconds in A3
.Cells(3, "A") = CBool(Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4)))) > _
TimeSerial(0, 0, 90))
'actual absolute difference in A4
.Cells(4, "A") = Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4))))
End With End Sub
The above gives error because Date functions works with system Locale, which in my case is Hebrew, while the Data is in English.
Another way that could help is to convert all the column "A" (which holds the dates) to a system local date that can be used with Date and time functions on VBA (don't know how to do that).
Please help
excel vba excel-vba
1
Are the values in A1 and A2 real dates or strings that look like a date?
– FunThomas
Nov 13 '18 at 10:05
@FunThomas they are real dates from another system that exported as Strings
– user1610208
Nov 13 '18 at 10:26
add a comment |
I have 2 cells with time data that format as follows:
"A1" = Sep 01 2018 00:01:33.707
"A2" = Sep 01 2018 00:01:49.917
I need to create a button and method within excel VBA that will set "A3" cell to true if the time "A2" is more than "A1" by 90 seconds.
This is what i have so far but it does not work:
Sub Macro2()
Dim str1 As String, str2 As String
With Worksheets("sheet5")
str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text
'greater than 90m seconds in A3
.Cells(3, "A") = CBool(Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4)))) > _
TimeSerial(0, 0, 90))
'actual absolute difference in A4
.Cells(4, "A") = Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4))))
End With End Sub
The above gives error because Date functions works with system Locale, which in my case is Hebrew, while the Data is in English.
Another way that could help is to convert all the column "A" (which holds the dates) to a system local date that can be used with Date and time functions on VBA (don't know how to do that).
Please help
excel vba excel-vba
I have 2 cells with time data that format as follows:
"A1" = Sep 01 2018 00:01:33.707
"A2" = Sep 01 2018 00:01:49.917
I need to create a button and method within excel VBA that will set "A3" cell to true if the time "A2" is more than "A1" by 90 seconds.
This is what i have so far but it does not work:
Sub Macro2()
Dim str1 As String, str2 As String
With Worksheets("sheet5")
str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text
'greater than 90m seconds in A3
.Cells(3, "A") = CBool(Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4)))) > _
TimeSerial(0, 0, 90))
'actual absolute difference in A4
.Cells(4, "A") = Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4))))
End With End Sub
The above gives error because Date functions works with system Locale, which in my case is Hebrew, while the Data is in English.
Another way that could help is to convert all the column "A" (which holds the dates) to a system local date that can be used with Date and time functions on VBA (don't know how to do that).
Please help
excel vba excel-vba
excel vba excel-vba
asked Nov 13 '18 at 9:39
user1610208user1610208
791110
791110
1
Are the values in A1 and A2 real dates or strings that look like a date?
– FunThomas
Nov 13 '18 at 10:05
@FunThomas they are real dates from another system that exported as Strings
– user1610208
Nov 13 '18 at 10:26
add a comment |
1
Are the values in A1 and A2 real dates or strings that look like a date?
– FunThomas
Nov 13 '18 at 10:05
@FunThomas they are real dates from another system that exported as Strings
– user1610208
Nov 13 '18 at 10:26
1
1
Are the values in A1 and A2 real dates or strings that look like a date?
– FunThomas
Nov 13 '18 at 10:05
Are the values in A1 and A2 real dates or strings that look like a date?
– FunThomas
Nov 13 '18 at 10:05
@FunThomas they are real dates from another system that exported as Strings
– user1610208
Nov 13 '18 at 10:26
@FunThomas they are real dates from another system that exported as Strings
– user1610208
Nov 13 '18 at 10:26
add a comment |
4 Answers
4
active
oldest
votes
I have split your task into 3 functions.
a) a helper function converts the 3 characters of the month into an integer. It looks a little clumsy, there might be other approaches but the advantage of using a large Select Case
is it is easy to understand and easy to adapt if month names in a different language arise:
Function getMonthFromName(monthName As String) As Integer
Select Case UCase(monthName)
Case "JAN": getMonthFromName = 1
Case "FEB": getMonthFromName = 2
Case "MAR": getMonthFromName = 3
Case "APR": getMonthFromName = 4
(...)
Case "SEP": getMonthFromName = 9
(...)
End Select
End Function
b) a function that converts the string into a date. It assumes the date format in the form you provided, but it is easily adapted if the format changes (for simplicity, the seconds are rounded)
Function GetDateFromString(dt As String) As Date
Dim tokens() As String
tokens = Split(Replace(dt, ":", " "), " ")
Dim day As Integer, month As Integer, year As Integer
month = getMonthFromName(CStr(tokens(0)))
day = Val(tokens(1))
year = Val(tokens(2))
Dim hour As Integer, minute As Integer, second As Double
hour = Val(tokens(3))
minute = Val(tokens(4))
second = Round(Val(tokens(5)), 0)
GetDateFromString = DateSerial(year, month, day) + TimeSerial(hour, minute, second)
End Function
c) A function that calculated the difference of the 2 dates in seconds. A date in VBA (and many other environments) is stored as Double
, where the Date-Part is the integer part and the date is the remainder. This makes it easy to calculate with Date values.
Function DateDiffInSeconds(d1 As String, d2 As String) As Long
Dim diff As Double
diff = GetDateFromString(d2) - GetDateFromString(d1)
DateDiffInSeconds = diff * 24 * 60 * 60
End Function
Update to deal with milliseconds: Change the GetDateFromString
-function. In that case, DateDiffInSeconds
should return a double
rather than a long
.
Function GetDateFromString(dt As String) As Date
Const MillSecPerHour As Long = 24& * 60 * 60 * 1000
Dim tokens() As String
tokens = Split(Replace(Replace(dt, ".", " "), ":", " "), " ")
Dim day As Integer, month As Integer, year As Integer
month = getMonthFromName(CStr(tokens(0)))
day = Val(tokens(1))
year = Val(tokens(2))
Dim hour As Integer, minute As Integer, second As Integer, milli As Integer
hour = Val(tokens(3))
minute = Val(tokens(4))
second = Val(tokens(5))
milli = Val(tokens(6))
GetDateFromString = DateSerial(year, month, day) _
+ TimeSerial(hour, minute, second) _
+ milli / MillSecPerHour
End Function
thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?
– user1610208
Nov 14 '18 at 4:09
I have updated my answer to show a way to deal with milliseconds.
– FunThomas
Nov 14 '18 at 8:53
If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.
– FunThomas
Nov 14 '18 at 9:03
add a comment |
For your information, I've done what you are doing in a slightly different (and easier) way:
In cell B2, I put the value 13/11/2018 11:44:00
.
In cell B3, I put the value 13/11/2018 11:45:01
.
(For both cells, the cell formatting has been set to d/mm/jjjj u:mm:ss
).
In another cell, I put following formula:
=IF((B3-B2)*86400>90;TRUE;FALSE)
The formula is based on the idea that a datetime value is set, based on the idea that one day equals 1, and there are 86400 seconds in one day.
Like this, you can calculate time differences without needing VBA.
1
Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...
– user1610208
Nov 13 '18 at 11:29
@user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?
– Dominique
Nov 13 '18 at 13:54
add a comment |
I think you are over-complicating it, try this to get an idea how to do it:
Sub Macro2()
Dim str1 As String, str2 As String
With Worksheets("sheet5")
.Range("b1:e1") = Split(Range("A1"), " ")
.Range("B2:e2") = Split(Range("A2"), " ")
End Sub
this does not take into considuration the Date itself (month, day or year), i need to include them as well...
– user1610208
Nov 13 '18 at 10:58
No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.
– Michal Rosa
Nov 13 '18 at 11:24
can you put up a complete solution please?
– user1610208
Nov 13 '18 at 11:32
Use something like=DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1)
to convert the string into a date, add the time value and the rest should be simple.
– Michal Rosa
Nov 13 '18 at 11:32
I need it on VBA script since i got tons of sheets
– user1610208
Nov 13 '18 at 11:37
add a comment |
Use UDF.
Sub Macro2()
Dim str1 As String, str2 As String
Dim mySecond As Double, t1 As Double, t2 As Double, t3 As Double
mySecond = TimeSerial(0, 0, 90)
With Worksheets("sheet5")
str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text
t1 = ConvertTime(str1)
t2 = ConvertTime(str2)
t3 = t2 - t1
.Cells(3, "a") = Abs(t3) >= mySecond
End With
End Sub
Function ConvertTime(s As String)
Dim vS
vS = Split(s, " ")
ConvertTime = DateValue(vS(0) & "-" & vS(1) & "-" & vS(2)) + TimeValue(Split(vS(3), ".")(0))
End Function
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
I have split your task into 3 functions.
a) a helper function converts the 3 characters of the month into an integer. It looks a little clumsy, there might be other approaches but the advantage of using a large Select Case
is it is easy to understand and easy to adapt if month names in a different language arise:
Function getMonthFromName(monthName As String) As Integer
Select Case UCase(monthName)
Case "JAN": getMonthFromName = 1
Case "FEB": getMonthFromName = 2
Case "MAR": getMonthFromName = 3
Case "APR": getMonthFromName = 4
(...)
Case "SEP": getMonthFromName = 9
(...)
End Select
End Function
b) a function that converts the string into a date. It assumes the date format in the form you provided, but it is easily adapted if the format changes (for simplicity, the seconds are rounded)
Function GetDateFromString(dt As String) As Date
Dim tokens() As String
tokens = Split(Replace(dt, ":", " "), " ")
Dim day As Integer, month As Integer, year As Integer
month = getMonthFromName(CStr(tokens(0)))
day = Val(tokens(1))
year = Val(tokens(2))
Dim hour As Integer, minute As Integer, second As Double
hour = Val(tokens(3))
minute = Val(tokens(4))
second = Round(Val(tokens(5)), 0)
GetDateFromString = DateSerial(year, month, day) + TimeSerial(hour, minute, second)
End Function
c) A function that calculated the difference of the 2 dates in seconds. A date in VBA (and many other environments) is stored as Double
, where the Date-Part is the integer part and the date is the remainder. This makes it easy to calculate with Date values.
Function DateDiffInSeconds(d1 As String, d2 As String) As Long
Dim diff As Double
diff = GetDateFromString(d2) - GetDateFromString(d1)
DateDiffInSeconds = diff * 24 * 60 * 60
End Function
Update to deal with milliseconds: Change the GetDateFromString
-function. In that case, DateDiffInSeconds
should return a double
rather than a long
.
Function GetDateFromString(dt As String) As Date
Const MillSecPerHour As Long = 24& * 60 * 60 * 1000
Dim tokens() As String
tokens = Split(Replace(Replace(dt, ".", " "), ":", " "), " ")
Dim day As Integer, month As Integer, year As Integer
month = getMonthFromName(CStr(tokens(0)))
day = Val(tokens(1))
year = Val(tokens(2))
Dim hour As Integer, minute As Integer, second As Integer, milli As Integer
hour = Val(tokens(3))
minute = Val(tokens(4))
second = Val(tokens(5))
milli = Val(tokens(6))
GetDateFromString = DateSerial(year, month, day) _
+ TimeSerial(hour, minute, second) _
+ milli / MillSecPerHour
End Function
thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?
– user1610208
Nov 14 '18 at 4:09
I have updated my answer to show a way to deal with milliseconds.
– FunThomas
Nov 14 '18 at 8:53
If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.
– FunThomas
Nov 14 '18 at 9:03
add a comment |
I have split your task into 3 functions.
a) a helper function converts the 3 characters of the month into an integer. It looks a little clumsy, there might be other approaches but the advantage of using a large Select Case
is it is easy to understand and easy to adapt if month names in a different language arise:
Function getMonthFromName(monthName As String) As Integer
Select Case UCase(monthName)
Case "JAN": getMonthFromName = 1
Case "FEB": getMonthFromName = 2
Case "MAR": getMonthFromName = 3
Case "APR": getMonthFromName = 4
(...)
Case "SEP": getMonthFromName = 9
(...)
End Select
End Function
b) a function that converts the string into a date. It assumes the date format in the form you provided, but it is easily adapted if the format changes (for simplicity, the seconds are rounded)
Function GetDateFromString(dt As String) As Date
Dim tokens() As String
tokens = Split(Replace(dt, ":", " "), " ")
Dim day As Integer, month As Integer, year As Integer
month = getMonthFromName(CStr(tokens(0)))
day = Val(tokens(1))
year = Val(tokens(2))
Dim hour As Integer, minute As Integer, second As Double
hour = Val(tokens(3))
minute = Val(tokens(4))
second = Round(Val(tokens(5)), 0)
GetDateFromString = DateSerial(year, month, day) + TimeSerial(hour, minute, second)
End Function
c) A function that calculated the difference of the 2 dates in seconds. A date in VBA (and many other environments) is stored as Double
, where the Date-Part is the integer part and the date is the remainder. This makes it easy to calculate with Date values.
Function DateDiffInSeconds(d1 As String, d2 As String) As Long
Dim diff As Double
diff = GetDateFromString(d2) - GetDateFromString(d1)
DateDiffInSeconds = diff * 24 * 60 * 60
End Function
Update to deal with milliseconds: Change the GetDateFromString
-function. In that case, DateDiffInSeconds
should return a double
rather than a long
.
Function GetDateFromString(dt As String) As Date
Const MillSecPerHour As Long = 24& * 60 * 60 * 1000
Dim tokens() As String
tokens = Split(Replace(Replace(dt, ".", " "), ":", " "), " ")
Dim day As Integer, month As Integer, year As Integer
month = getMonthFromName(CStr(tokens(0)))
day = Val(tokens(1))
year = Val(tokens(2))
Dim hour As Integer, minute As Integer, second As Integer, milli As Integer
hour = Val(tokens(3))
minute = Val(tokens(4))
second = Val(tokens(5))
milli = Val(tokens(6))
GetDateFromString = DateSerial(year, month, day) _
+ TimeSerial(hour, minute, second) _
+ milli / MillSecPerHour
End Function
thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?
– user1610208
Nov 14 '18 at 4:09
I have updated my answer to show a way to deal with milliseconds.
– FunThomas
Nov 14 '18 at 8:53
If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.
– FunThomas
Nov 14 '18 at 9:03
add a comment |
I have split your task into 3 functions.
a) a helper function converts the 3 characters of the month into an integer. It looks a little clumsy, there might be other approaches but the advantage of using a large Select Case
is it is easy to understand and easy to adapt if month names in a different language arise:
Function getMonthFromName(monthName As String) As Integer
Select Case UCase(monthName)
Case "JAN": getMonthFromName = 1
Case "FEB": getMonthFromName = 2
Case "MAR": getMonthFromName = 3
Case "APR": getMonthFromName = 4
(...)
Case "SEP": getMonthFromName = 9
(...)
End Select
End Function
b) a function that converts the string into a date. It assumes the date format in the form you provided, but it is easily adapted if the format changes (for simplicity, the seconds are rounded)
Function GetDateFromString(dt As String) As Date
Dim tokens() As String
tokens = Split(Replace(dt, ":", " "), " ")
Dim day As Integer, month As Integer, year As Integer
month = getMonthFromName(CStr(tokens(0)))
day = Val(tokens(1))
year = Val(tokens(2))
Dim hour As Integer, minute As Integer, second As Double
hour = Val(tokens(3))
minute = Val(tokens(4))
second = Round(Val(tokens(5)), 0)
GetDateFromString = DateSerial(year, month, day) + TimeSerial(hour, minute, second)
End Function
c) A function that calculated the difference of the 2 dates in seconds. A date in VBA (and many other environments) is stored as Double
, where the Date-Part is the integer part and the date is the remainder. This makes it easy to calculate with Date values.
Function DateDiffInSeconds(d1 As String, d2 As String) As Long
Dim diff As Double
diff = GetDateFromString(d2) - GetDateFromString(d1)
DateDiffInSeconds = diff * 24 * 60 * 60
End Function
Update to deal with milliseconds: Change the GetDateFromString
-function. In that case, DateDiffInSeconds
should return a double
rather than a long
.
Function GetDateFromString(dt As String) As Date
Const MillSecPerHour As Long = 24& * 60 * 60 * 1000
Dim tokens() As String
tokens = Split(Replace(Replace(dt, ".", " "), ":", " "), " ")
Dim day As Integer, month As Integer, year As Integer
month = getMonthFromName(CStr(tokens(0)))
day = Val(tokens(1))
year = Val(tokens(2))
Dim hour As Integer, minute As Integer, second As Integer, milli As Integer
hour = Val(tokens(3))
minute = Val(tokens(4))
second = Val(tokens(5))
milli = Val(tokens(6))
GetDateFromString = DateSerial(year, month, day) _
+ TimeSerial(hour, minute, second) _
+ milli / MillSecPerHour
End Function
I have split your task into 3 functions.
a) a helper function converts the 3 characters of the month into an integer. It looks a little clumsy, there might be other approaches but the advantage of using a large Select Case
is it is easy to understand and easy to adapt if month names in a different language arise:
Function getMonthFromName(monthName As String) As Integer
Select Case UCase(monthName)
Case "JAN": getMonthFromName = 1
Case "FEB": getMonthFromName = 2
Case "MAR": getMonthFromName = 3
Case "APR": getMonthFromName = 4
(...)
Case "SEP": getMonthFromName = 9
(...)
End Select
End Function
b) a function that converts the string into a date. It assumes the date format in the form you provided, but it is easily adapted if the format changes (for simplicity, the seconds are rounded)
Function GetDateFromString(dt As String) As Date
Dim tokens() As String
tokens = Split(Replace(dt, ":", " "), " ")
Dim day As Integer, month As Integer, year As Integer
month = getMonthFromName(CStr(tokens(0)))
day = Val(tokens(1))
year = Val(tokens(2))
Dim hour As Integer, minute As Integer, second As Double
hour = Val(tokens(3))
minute = Val(tokens(4))
second = Round(Val(tokens(5)), 0)
GetDateFromString = DateSerial(year, month, day) + TimeSerial(hour, minute, second)
End Function
c) A function that calculated the difference of the 2 dates in seconds. A date in VBA (and many other environments) is stored as Double
, where the Date-Part is the integer part and the date is the remainder. This makes it easy to calculate with Date values.
Function DateDiffInSeconds(d1 As String, d2 As String) As Long
Dim diff As Double
diff = GetDateFromString(d2) - GetDateFromString(d1)
DateDiffInSeconds = diff * 24 * 60 * 60
End Function
Update to deal with milliseconds: Change the GetDateFromString
-function. In that case, DateDiffInSeconds
should return a double
rather than a long
.
Function GetDateFromString(dt As String) As Date
Const MillSecPerHour As Long = 24& * 60 * 60 * 1000
Dim tokens() As String
tokens = Split(Replace(Replace(dt, ".", " "), ":", " "), " ")
Dim day As Integer, month As Integer, year As Integer
month = getMonthFromName(CStr(tokens(0)))
day = Val(tokens(1))
year = Val(tokens(2))
Dim hour As Integer, minute As Integer, second As Integer, milli As Integer
hour = Val(tokens(3))
minute = Val(tokens(4))
second = Val(tokens(5))
milli = Val(tokens(6))
GetDateFromString = DateSerial(year, month, day) _
+ TimeSerial(hour, minute, second) _
+ milli / MillSecPerHour
End Function
edited Nov 14 '18 at 8:52
answered Nov 13 '18 at 13:39
FunThomasFunThomas
4,7611523
4,7611523
thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?
– user1610208
Nov 14 '18 at 4:09
I have updated my answer to show a way to deal with milliseconds.
– FunThomas
Nov 14 '18 at 8:53
If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.
– FunThomas
Nov 14 '18 at 9:03
add a comment |
thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?
– user1610208
Nov 14 '18 at 4:09
I have updated my answer to show a way to deal with milliseconds.
– FunThomas
Nov 14 '18 at 8:53
If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.
– FunThomas
Nov 14 '18 at 9:03
thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?
– user1610208
Nov 14 '18 at 4:09
thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?
– user1610208
Nov 14 '18 at 4:09
I have updated my answer to show a way to deal with milliseconds.
– FunThomas
Nov 14 '18 at 8:53
I have updated my answer to show a way to deal with milliseconds.
– FunThomas
Nov 14 '18 at 8:53
If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.
– FunThomas
Nov 14 '18 at 9:03
If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.
– FunThomas
Nov 14 '18 at 9:03
add a comment |
For your information, I've done what you are doing in a slightly different (and easier) way:
In cell B2, I put the value 13/11/2018 11:44:00
.
In cell B3, I put the value 13/11/2018 11:45:01
.
(For both cells, the cell formatting has been set to d/mm/jjjj u:mm:ss
).
In another cell, I put following formula:
=IF((B3-B2)*86400>90;TRUE;FALSE)
The formula is based on the idea that a datetime value is set, based on the idea that one day equals 1, and there are 86400 seconds in one day.
Like this, you can calculate time differences without needing VBA.
1
Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...
– user1610208
Nov 13 '18 at 11:29
@user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?
– Dominique
Nov 13 '18 at 13:54
add a comment |
For your information, I've done what you are doing in a slightly different (and easier) way:
In cell B2, I put the value 13/11/2018 11:44:00
.
In cell B3, I put the value 13/11/2018 11:45:01
.
(For both cells, the cell formatting has been set to d/mm/jjjj u:mm:ss
).
In another cell, I put following formula:
=IF((B3-B2)*86400>90;TRUE;FALSE)
The formula is based on the idea that a datetime value is set, based on the idea that one day equals 1, and there are 86400 seconds in one day.
Like this, you can calculate time differences without needing VBA.
1
Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...
– user1610208
Nov 13 '18 at 11:29
@user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?
– Dominique
Nov 13 '18 at 13:54
add a comment |
For your information, I've done what you are doing in a slightly different (and easier) way:
In cell B2, I put the value 13/11/2018 11:44:00
.
In cell B3, I put the value 13/11/2018 11:45:01
.
(For both cells, the cell formatting has been set to d/mm/jjjj u:mm:ss
).
In another cell, I put following formula:
=IF((B3-B2)*86400>90;TRUE;FALSE)
The formula is based on the idea that a datetime value is set, based on the idea that one day equals 1, and there are 86400 seconds in one day.
Like this, you can calculate time differences without needing VBA.
For your information, I've done what you are doing in a slightly different (and easier) way:
In cell B2, I put the value 13/11/2018 11:44:00
.
In cell B3, I put the value 13/11/2018 11:45:01
.
(For both cells, the cell formatting has been set to d/mm/jjjj u:mm:ss
).
In another cell, I put following formula:
=IF((B3-B2)*86400>90;TRUE;FALSE)
The formula is based on the idea that a datetime value is set, based on the idea that one day equals 1, and there are 86400 seconds in one day.
Like this, you can calculate time differences without needing VBA.
answered Nov 13 '18 at 11:02
DominiqueDominique
2,03741741
2,03741741
1
Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...
– user1610208
Nov 13 '18 at 11:29
@user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?
– Dominique
Nov 13 '18 at 13:54
add a comment |
1
Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...
– user1610208
Nov 13 '18 at 11:29
@user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?
– Dominique
Nov 13 '18 at 13:54
1
1
Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...
– user1610208
Nov 13 '18 at 11:29
Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...
– user1610208
Nov 13 '18 at 11:29
@user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?
– Dominique
Nov 13 '18 at 13:54
@user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?
– Dominique
Nov 13 '18 at 13:54
add a comment |
I think you are over-complicating it, try this to get an idea how to do it:
Sub Macro2()
Dim str1 As String, str2 As String
With Worksheets("sheet5")
.Range("b1:e1") = Split(Range("A1"), " ")
.Range("B2:e2") = Split(Range("A2"), " ")
End Sub
this does not take into considuration the Date itself (month, day or year), i need to include them as well...
– user1610208
Nov 13 '18 at 10:58
No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.
– Michal Rosa
Nov 13 '18 at 11:24
can you put up a complete solution please?
– user1610208
Nov 13 '18 at 11:32
Use something like=DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1)
to convert the string into a date, add the time value and the rest should be simple.
– Michal Rosa
Nov 13 '18 at 11:32
I need it on VBA script since i got tons of sheets
– user1610208
Nov 13 '18 at 11:37
add a comment |
I think you are over-complicating it, try this to get an idea how to do it:
Sub Macro2()
Dim str1 As String, str2 As String
With Worksheets("sheet5")
.Range("b1:e1") = Split(Range("A1"), " ")
.Range("B2:e2") = Split(Range("A2"), " ")
End Sub
this does not take into considuration the Date itself (month, day or year), i need to include them as well...
– user1610208
Nov 13 '18 at 10:58
No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.
– Michal Rosa
Nov 13 '18 at 11:24
can you put up a complete solution please?
– user1610208
Nov 13 '18 at 11:32
Use something like=DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1)
to convert the string into a date, add the time value and the rest should be simple.
– Michal Rosa
Nov 13 '18 at 11:32
I need it on VBA script since i got tons of sheets
– user1610208
Nov 13 '18 at 11:37
add a comment |
I think you are over-complicating it, try this to get an idea how to do it:
Sub Macro2()
Dim str1 As String, str2 As String
With Worksheets("sheet5")
.Range("b1:e1") = Split(Range("A1"), " ")
.Range("B2:e2") = Split(Range("A2"), " ")
End Sub
I think you are over-complicating it, try this to get an idea how to do it:
Sub Macro2()
Dim str1 As String, str2 As String
With Worksheets("sheet5")
.Range("b1:e1") = Split(Range("A1"), " ")
.Range("B2:e2") = Split(Range("A2"), " ")
End Sub
edited Nov 13 '18 at 11:23
answered Nov 13 '18 at 10:27
Michal RosaMichal Rosa
1,3191814
1,3191814
this does not take into considuration the Date itself (month, day or year), i need to include them as well...
– user1610208
Nov 13 '18 at 10:58
No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.
– Michal Rosa
Nov 13 '18 at 11:24
can you put up a complete solution please?
– user1610208
Nov 13 '18 at 11:32
Use something like=DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1)
to convert the string into a date, add the time value and the rest should be simple.
– Michal Rosa
Nov 13 '18 at 11:32
I need it on VBA script since i got tons of sheets
– user1610208
Nov 13 '18 at 11:37
add a comment |
this does not take into considuration the Date itself (month, day or year), i need to include them as well...
– user1610208
Nov 13 '18 at 10:58
No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.
– Michal Rosa
Nov 13 '18 at 11:24
can you put up a complete solution please?
– user1610208
Nov 13 '18 at 11:32
Use something like=DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1)
to convert the string into a date, add the time value and the rest should be simple.
– Michal Rosa
Nov 13 '18 at 11:32
I need it on VBA script since i got tons of sheets
– user1610208
Nov 13 '18 at 11:37
this does not take into considuration the Date itself (month, day or year), i need to include them as well...
– user1610208
Nov 13 '18 at 10:58
this does not take into considuration the Date itself (month, day or year), i need to include them as well...
– user1610208
Nov 13 '18 at 10:58
No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.
– Michal Rosa
Nov 13 '18 at 11:24
No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.
– Michal Rosa
Nov 13 '18 at 11:24
can you put up a complete solution please?
– user1610208
Nov 13 '18 at 11:32
can you put up a complete solution please?
– user1610208
Nov 13 '18 at 11:32
Use something like
=DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1)
to convert the string into a date, add the time value and the rest should be simple.– Michal Rosa
Nov 13 '18 at 11:32
Use something like
=DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1)
to convert the string into a date, add the time value and the rest should be simple.– Michal Rosa
Nov 13 '18 at 11:32
I need it on VBA script since i got tons of sheets
– user1610208
Nov 13 '18 at 11:37
I need it on VBA script since i got tons of sheets
– user1610208
Nov 13 '18 at 11:37
add a comment |
Use UDF.
Sub Macro2()
Dim str1 As String, str2 As String
Dim mySecond As Double, t1 As Double, t2 As Double, t3 As Double
mySecond = TimeSerial(0, 0, 90)
With Worksheets("sheet5")
str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text
t1 = ConvertTime(str1)
t2 = ConvertTime(str2)
t3 = t2 - t1
.Cells(3, "a") = Abs(t3) >= mySecond
End With
End Sub
Function ConvertTime(s As String)
Dim vS
vS = Split(s, " ")
ConvertTime = DateValue(vS(0) & "-" & vS(1) & "-" & vS(2)) + TimeValue(Split(vS(3), ".")(0))
End Function
add a comment |
Use UDF.
Sub Macro2()
Dim str1 As String, str2 As String
Dim mySecond As Double, t1 As Double, t2 As Double, t3 As Double
mySecond = TimeSerial(0, 0, 90)
With Worksheets("sheet5")
str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text
t1 = ConvertTime(str1)
t2 = ConvertTime(str2)
t3 = t2 - t1
.Cells(3, "a") = Abs(t3) >= mySecond
End With
End Sub
Function ConvertTime(s As String)
Dim vS
vS = Split(s, " ")
ConvertTime = DateValue(vS(0) & "-" & vS(1) & "-" & vS(2)) + TimeValue(Split(vS(3), ".")(0))
End Function
add a comment |
Use UDF.
Sub Macro2()
Dim str1 As String, str2 As String
Dim mySecond As Double, t1 As Double, t2 As Double, t3 As Double
mySecond = TimeSerial(0, 0, 90)
With Worksheets("sheet5")
str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text
t1 = ConvertTime(str1)
t2 = ConvertTime(str2)
t3 = t2 - t1
.Cells(3, "a") = Abs(t3) >= mySecond
End With
End Sub
Function ConvertTime(s As String)
Dim vS
vS = Split(s, " ")
ConvertTime = DateValue(vS(0) & "-" & vS(1) & "-" & vS(2)) + TimeValue(Split(vS(3), ".")(0))
End Function
Use UDF.
Sub Macro2()
Dim str1 As String, str2 As String
Dim mySecond As Double, t1 As Double, t2 As Double, t3 As Double
mySecond = TimeSerial(0, 0, 90)
With Worksheets("sheet5")
str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text
t1 = ConvertTime(str1)
t2 = ConvertTime(str2)
t3 = t2 - t1
.Cells(3, "a") = Abs(t3) >= mySecond
End With
End Sub
Function ConvertTime(s As String)
Dim vS
vS = Split(s, " ")
ConvertTime = DateValue(vS(0) & "-" & vS(1) & "-" & vS(2)) + TimeValue(Split(vS(3), ".")(0))
End Function
edited Nov 13 '18 at 14:24
answered Nov 13 '18 at 13:53
Dy.LeeDy.Lee
3,6421510
3,6421510
add a comment |
add a comment |
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1
Are the values in A1 and A2 real dates or strings that look like a date?
– FunThomas
Nov 13 '18 at 10:05
@FunThomas they are real dates from another system that exported as Strings
– user1610208
Nov 13 '18 at 10:26