Excel VBA convert Date with time












1















I have 2 cells with time data that format as follows:



"A1" = Sep 01 2018 00:01:33.707 
"A2" = Sep 01 2018 00:01:49.917


I need to create a button and method within excel VBA that will set "A3" cell to true if the time "A2" is more than "A1" by 90 seconds.
This is what i have so far but it does not work:



Sub Macro2()
Dim str1 As String, str2 As String

With Worksheets("sheet5")

str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text

'greater than 90m seconds in A3
.Cells(3, "A") = CBool(Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4)))) > _
TimeSerial(0, 0, 90))
'actual absolute difference in A4
.Cells(4, "A") = Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4))))
End With End Sub


The above gives error because Date functions works with system Locale, which in my case is Hebrew, while the Data is in English.



Another way that could help is to convert all the column "A" (which holds the dates) to a system local date that can be used with Date and time functions on VBA (don't know how to do that).



Please help










share|improve this question


















  • 1





    Are the values in A1 and A2 real dates or strings that look like a date?

    – FunThomas
    Nov 13 '18 at 10:05











  • @FunThomas they are real dates from another system that exported as Strings

    – user1610208
    Nov 13 '18 at 10:26


















1















I have 2 cells with time data that format as follows:



"A1" = Sep 01 2018 00:01:33.707 
"A2" = Sep 01 2018 00:01:49.917


I need to create a button and method within excel VBA that will set "A3" cell to true if the time "A2" is more than "A1" by 90 seconds.
This is what i have so far but it does not work:



Sub Macro2()
Dim str1 As String, str2 As String

With Worksheets("sheet5")

str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text

'greater than 90m seconds in A3
.Cells(3, "A") = CBool(Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4)))) > _
TimeSerial(0, 0, 90))
'actual absolute difference in A4
.Cells(4, "A") = Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4))))
End With End Sub


The above gives error because Date functions works with system Locale, which in my case is Hebrew, while the Data is in English.



Another way that could help is to convert all the column "A" (which holds the dates) to a system local date that can be used with Date and time functions on VBA (don't know how to do that).



Please help










share|improve this question


















  • 1





    Are the values in A1 and A2 real dates or strings that look like a date?

    – FunThomas
    Nov 13 '18 at 10:05











  • @FunThomas they are real dates from another system that exported as Strings

    – user1610208
    Nov 13 '18 at 10:26
















1












1








1








I have 2 cells with time data that format as follows:



"A1" = Sep 01 2018 00:01:33.707 
"A2" = Sep 01 2018 00:01:49.917


I need to create a button and method within excel VBA that will set "A3" cell to true if the time "A2" is more than "A1" by 90 seconds.
This is what i have so far but it does not work:



Sub Macro2()
Dim str1 As String, str2 As String

With Worksheets("sheet5")

str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text

'greater than 90m seconds in A3
.Cells(3, "A") = CBool(Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4)))) > _
TimeSerial(0, 0, 90))
'actual absolute difference in A4
.Cells(4, "A") = Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4))))
End With End Sub


The above gives error because Date functions works with system Locale, which in my case is Hebrew, while the Data is in English.



Another way that could help is to convert all the column "A" (which holds the dates) to a system local date that can be used with Date and time functions on VBA (don't know how to do that).



Please help










share|improve this question














I have 2 cells with time data that format as follows:



"A1" = Sep 01 2018 00:01:33.707 
"A2" = Sep 01 2018 00:01:49.917


I need to create a button and method within excel VBA that will set "A3" cell to true if the time "A2" is more than "A1" by 90 seconds.
This is what i have so far but it does not work:



Sub Macro2()
Dim str1 As String, str2 As String

With Worksheets("sheet5")

str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text

'greater than 90m seconds in A3
.Cells(3, "A") = CBool(Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4)))) > _
TimeSerial(0, 0, 90))
'actual absolute difference in A4
.Cells(4, "A") = Abs((DateValue(Left(str1, 6) & "," & Mid(str1, 7, 5)) + _
TimeValue(Mid(str1, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str1, 4))) - _
(DateValue(Left(str2, 6) & "," & Mid(str2, 7, 5)) + _
TimeValue(Mid(str2, 13, 8)) + TimeSerial(0, 0, 1) * CDbl(Right(str2, 4))))
End With End Sub


The above gives error because Date functions works with system Locale, which in my case is Hebrew, while the Data is in English.



Another way that could help is to convert all the column "A" (which holds the dates) to a system local date that can be used with Date and time functions on VBA (don't know how to do that).



Please help







excel vba excel-vba






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 13 '18 at 9:39









user1610208user1610208

791110




791110








  • 1





    Are the values in A1 and A2 real dates or strings that look like a date?

    – FunThomas
    Nov 13 '18 at 10:05











  • @FunThomas they are real dates from another system that exported as Strings

    – user1610208
    Nov 13 '18 at 10:26
















  • 1





    Are the values in A1 and A2 real dates or strings that look like a date?

    – FunThomas
    Nov 13 '18 at 10:05











  • @FunThomas they are real dates from another system that exported as Strings

    – user1610208
    Nov 13 '18 at 10:26










1




1





Are the values in A1 and A2 real dates or strings that look like a date?

– FunThomas
Nov 13 '18 at 10:05





Are the values in A1 and A2 real dates or strings that look like a date?

– FunThomas
Nov 13 '18 at 10:05













@FunThomas they are real dates from another system that exported as Strings

– user1610208
Nov 13 '18 at 10:26







@FunThomas they are real dates from another system that exported as Strings

– user1610208
Nov 13 '18 at 10:26














4 Answers
4






active

oldest

votes


















0














I have split your task into 3 functions.



a) a helper function converts the 3 characters of the month into an integer. It looks a little clumsy, there might be other approaches but the advantage of using a large Select Case is it is easy to understand and easy to adapt if month names in a different language arise:



Function getMonthFromName(monthName As String) As Integer

Select Case UCase(monthName)
Case "JAN": getMonthFromName = 1
Case "FEB": getMonthFromName = 2
Case "MAR": getMonthFromName = 3
Case "APR": getMonthFromName = 4
(...)
Case "SEP": getMonthFromName = 9
(...)
End Select

End Function


b) a function that converts the string into a date. It assumes the date format in the form you provided, but it is easily adapted if the format changes (for simplicity, the seconds are rounded)



Function GetDateFromString(dt As String) As Date

Dim tokens() As String
tokens = Split(Replace(dt, ":", " "), " ")

Dim day As Integer, month As Integer, year As Integer
month = getMonthFromName(CStr(tokens(0)))
day = Val(tokens(1))
year = Val(tokens(2))

Dim hour As Integer, minute As Integer, second As Double
hour = Val(tokens(3))
minute = Val(tokens(4))
second = Round(Val(tokens(5)), 0)

GetDateFromString = DateSerial(year, month, day) + TimeSerial(hour, minute, second)
End Function


c) A function that calculated the difference of the 2 dates in seconds. A date in VBA (and many other environments) is stored as Double, where the Date-Part is the integer part and the date is the remainder. This makes it easy to calculate with Date values.



Function DateDiffInSeconds(d1 As String, d2 As String) As Long
Dim diff As Double
diff = GetDateFromString(d2) - GetDateFromString(d1)
DateDiffInSeconds = diff * 24 * 60 * 60
End Function


Update to deal with milliseconds: Change the GetDateFromString-function. In that case, DateDiffInSeconds should return a double rather than a long.



Function GetDateFromString(dt As String) As Date

Const MillSecPerHour As Long = 24& * 60 * 60 * 1000

Dim tokens() As String
tokens = Split(Replace(Replace(dt, ".", " "), ":", " "), " ")

Dim day As Integer, month As Integer, year As Integer
month = getMonthFromName(CStr(tokens(0)))
day = Val(tokens(1))
year = Val(tokens(2))

Dim hour As Integer, minute As Integer, second As Integer, milli As Integer
hour = Val(tokens(3))
minute = Val(tokens(4))
second = Val(tokens(5))
milli = Val(tokens(6))

GetDateFromString = DateSerial(year, month, day) _
+ TimeSerial(hour, minute, second) _
+ milli / MillSecPerHour
End Function





share|improve this answer


























  • thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?

    – user1610208
    Nov 14 '18 at 4:09













  • I have updated my answer to show a way to deal with milliseconds.

    – FunThomas
    Nov 14 '18 at 8:53











  • If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.

    – FunThomas
    Nov 14 '18 at 9:03



















0














For your information, I've done what you are doing in a slightly different (and easier) way:



In cell B2, I put the value 13/11/2018 11:44:00.

In cell B3, I put the value 13/11/2018 11:45:01.

(For both cells, the cell formatting has been set to d/mm/jjjj u:mm:ss).



In another cell, I put following formula:



=IF((B3-B2)*86400>90;TRUE;FALSE)


The formula is based on the idea that a datetime value is set, based on the idea that one day equals 1, and there are 86400 seconds in one day.



Like this, you can calculate time differences without needing VBA.






share|improve this answer



















  • 1





    Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...

    – user1610208
    Nov 13 '18 at 11:29











  • @user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?

    – Dominique
    Nov 13 '18 at 13:54



















0














I think you are over-complicating it, try this to get an idea how to do it:



Sub Macro2()
Dim str1 As String, str2 As String

With Worksheets("sheet5")

.Range("b1:e1") = Split(Range("A1"), " ")
.Range("B2:e2") = Split(Range("A2"), " ")


End Sub





share|improve this answer


























  • this does not take into considuration the Date itself (month, day or year), i need to include them as well...

    – user1610208
    Nov 13 '18 at 10:58













  • No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.

    – Michal Rosa
    Nov 13 '18 at 11:24











  • can you put up a complete solution please?

    – user1610208
    Nov 13 '18 at 11:32











  • Use something like =DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1) to convert the string into a date, add the time value and the rest should be simple.

    – Michal Rosa
    Nov 13 '18 at 11:32











  • I need it on VBA script since i got tons of sheets

    – user1610208
    Nov 13 '18 at 11:37



















0














Use UDF.



Sub Macro2()
Dim str1 As String, str2 As String
Dim mySecond As Double, t1 As Double, t2 As Double, t3 As Double
mySecond = TimeSerial(0, 0, 90)

With Worksheets("sheet5")
str1 = .Cells(1, "A").Text
str2 = .Cells(2, "A").Text
t1 = ConvertTime(str1)
t2 = ConvertTime(str2)
t3 = t2 - t1
.Cells(3, "a") = Abs(t3) >= mySecond
End With

End Sub
Function ConvertTime(s As String)
Dim vS
vS = Split(s, " ")
ConvertTime = DateValue(vS(0) & "-" & vS(1) & "-" & vS(2)) + TimeValue(Split(vS(3), ".")(0))
End Function





share|improve this answer

























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53277992%2fexcel-vba-convert-date-with-time%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    4 Answers
    4






    active

    oldest

    votes








    4 Answers
    4






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    I have split your task into 3 functions.



    a) a helper function converts the 3 characters of the month into an integer. It looks a little clumsy, there might be other approaches but the advantage of using a large Select Case is it is easy to understand and easy to adapt if month names in a different language arise:



    Function getMonthFromName(monthName As String) As Integer

    Select Case UCase(monthName)
    Case "JAN": getMonthFromName = 1
    Case "FEB": getMonthFromName = 2
    Case "MAR": getMonthFromName = 3
    Case "APR": getMonthFromName = 4
    (...)
    Case "SEP": getMonthFromName = 9
    (...)
    End Select

    End Function


    b) a function that converts the string into a date. It assumes the date format in the form you provided, but it is easily adapted if the format changes (for simplicity, the seconds are rounded)



    Function GetDateFromString(dt As String) As Date

    Dim tokens() As String
    tokens = Split(Replace(dt, ":", " "), " ")

    Dim day As Integer, month As Integer, year As Integer
    month = getMonthFromName(CStr(tokens(0)))
    day = Val(tokens(1))
    year = Val(tokens(2))

    Dim hour As Integer, minute As Integer, second As Double
    hour = Val(tokens(3))
    minute = Val(tokens(4))
    second = Round(Val(tokens(5)), 0)

    GetDateFromString = DateSerial(year, month, day) + TimeSerial(hour, minute, second)
    End Function


    c) A function that calculated the difference of the 2 dates in seconds. A date in VBA (and many other environments) is stored as Double, where the Date-Part is the integer part and the date is the remainder. This makes it easy to calculate with Date values.



    Function DateDiffInSeconds(d1 As String, d2 As String) As Long
    Dim diff As Double
    diff = GetDateFromString(d2) - GetDateFromString(d1)
    DateDiffInSeconds = diff * 24 * 60 * 60
    End Function


    Update to deal with milliseconds: Change the GetDateFromString-function. In that case, DateDiffInSeconds should return a double rather than a long.



    Function GetDateFromString(dt As String) As Date

    Const MillSecPerHour As Long = 24& * 60 * 60 * 1000

    Dim tokens() As String
    tokens = Split(Replace(Replace(dt, ".", " "), ":", " "), " ")

    Dim day As Integer, month As Integer, year As Integer
    month = getMonthFromName(CStr(tokens(0)))
    day = Val(tokens(1))
    year = Val(tokens(2))

    Dim hour As Integer, minute As Integer, second As Integer, milli As Integer
    hour = Val(tokens(3))
    minute = Val(tokens(4))
    second = Val(tokens(5))
    milli = Val(tokens(6))

    GetDateFromString = DateSerial(year, month, day) _
    + TimeSerial(hour, minute, second) _
    + milli / MillSecPerHour
    End Function





    share|improve this answer


























    • thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?

      – user1610208
      Nov 14 '18 at 4:09













    • I have updated my answer to show a way to deal with milliseconds.

      – FunThomas
      Nov 14 '18 at 8:53











    • If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.

      – FunThomas
      Nov 14 '18 at 9:03
















    0














    I have split your task into 3 functions.



    a) a helper function converts the 3 characters of the month into an integer. It looks a little clumsy, there might be other approaches but the advantage of using a large Select Case is it is easy to understand and easy to adapt if month names in a different language arise:



    Function getMonthFromName(monthName As String) As Integer

    Select Case UCase(monthName)
    Case "JAN": getMonthFromName = 1
    Case "FEB": getMonthFromName = 2
    Case "MAR": getMonthFromName = 3
    Case "APR": getMonthFromName = 4
    (...)
    Case "SEP": getMonthFromName = 9
    (...)
    End Select

    End Function


    b) a function that converts the string into a date. It assumes the date format in the form you provided, but it is easily adapted if the format changes (for simplicity, the seconds are rounded)



    Function GetDateFromString(dt As String) As Date

    Dim tokens() As String
    tokens = Split(Replace(dt, ":", " "), " ")

    Dim day As Integer, month As Integer, year As Integer
    month = getMonthFromName(CStr(tokens(0)))
    day = Val(tokens(1))
    year = Val(tokens(2))

    Dim hour As Integer, minute As Integer, second As Double
    hour = Val(tokens(3))
    minute = Val(tokens(4))
    second = Round(Val(tokens(5)), 0)

    GetDateFromString = DateSerial(year, month, day) + TimeSerial(hour, minute, second)
    End Function


    c) A function that calculated the difference of the 2 dates in seconds. A date in VBA (and many other environments) is stored as Double, where the Date-Part is the integer part and the date is the remainder. This makes it easy to calculate with Date values.



    Function DateDiffInSeconds(d1 As String, d2 As String) As Long
    Dim diff As Double
    diff = GetDateFromString(d2) - GetDateFromString(d1)
    DateDiffInSeconds = diff * 24 * 60 * 60
    End Function


    Update to deal with milliseconds: Change the GetDateFromString-function. In that case, DateDiffInSeconds should return a double rather than a long.



    Function GetDateFromString(dt As String) As Date

    Const MillSecPerHour As Long = 24& * 60 * 60 * 1000

    Dim tokens() As String
    tokens = Split(Replace(Replace(dt, ".", " "), ":", " "), " ")

    Dim day As Integer, month As Integer, year As Integer
    month = getMonthFromName(CStr(tokens(0)))
    day = Val(tokens(1))
    year = Val(tokens(2))

    Dim hour As Integer, minute As Integer, second As Integer, milli As Integer
    hour = Val(tokens(3))
    minute = Val(tokens(4))
    second = Val(tokens(5))
    milli = Val(tokens(6))

    GetDateFromString = DateSerial(year, month, day) _
    + TimeSerial(hour, minute, second) _
    + milli / MillSecPerHour
    End Function





    share|improve this answer


























    • thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?

      – user1610208
      Nov 14 '18 at 4:09













    • I have updated my answer to show a way to deal with milliseconds.

      – FunThomas
      Nov 14 '18 at 8:53











    • If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.

      – FunThomas
      Nov 14 '18 at 9:03














    0












    0








    0







    I have split your task into 3 functions.



    a) a helper function converts the 3 characters of the month into an integer. It looks a little clumsy, there might be other approaches but the advantage of using a large Select Case is it is easy to understand and easy to adapt if month names in a different language arise:



    Function getMonthFromName(monthName As String) As Integer

    Select Case UCase(monthName)
    Case "JAN": getMonthFromName = 1
    Case "FEB": getMonthFromName = 2
    Case "MAR": getMonthFromName = 3
    Case "APR": getMonthFromName = 4
    (...)
    Case "SEP": getMonthFromName = 9
    (...)
    End Select

    End Function


    b) a function that converts the string into a date. It assumes the date format in the form you provided, but it is easily adapted if the format changes (for simplicity, the seconds are rounded)



    Function GetDateFromString(dt As String) As Date

    Dim tokens() As String
    tokens = Split(Replace(dt, ":", " "), " ")

    Dim day As Integer, month As Integer, year As Integer
    month = getMonthFromName(CStr(tokens(0)))
    day = Val(tokens(1))
    year = Val(tokens(2))

    Dim hour As Integer, minute As Integer, second As Double
    hour = Val(tokens(3))
    minute = Val(tokens(4))
    second = Round(Val(tokens(5)), 0)

    GetDateFromString = DateSerial(year, month, day) + TimeSerial(hour, minute, second)
    End Function


    c) A function that calculated the difference of the 2 dates in seconds. A date in VBA (and many other environments) is stored as Double, where the Date-Part is the integer part and the date is the remainder. This makes it easy to calculate with Date values.



    Function DateDiffInSeconds(d1 As String, d2 As String) As Long
    Dim diff As Double
    diff = GetDateFromString(d2) - GetDateFromString(d1)
    DateDiffInSeconds = diff * 24 * 60 * 60
    End Function


    Update to deal with milliseconds: Change the GetDateFromString-function. In that case, DateDiffInSeconds should return a double rather than a long.



    Function GetDateFromString(dt As String) As Date

    Const MillSecPerHour As Long = 24& * 60 * 60 * 1000

    Dim tokens() As String
    tokens = Split(Replace(Replace(dt, ".", " "), ":", " "), " ")

    Dim day As Integer, month As Integer, year As Integer
    month = getMonthFromName(CStr(tokens(0)))
    day = Val(tokens(1))
    year = Val(tokens(2))

    Dim hour As Integer, minute As Integer, second As Integer, milli As Integer
    hour = Val(tokens(3))
    minute = Val(tokens(4))
    second = Val(tokens(5))
    milli = Val(tokens(6))

    GetDateFromString = DateSerial(year, month, day) _
    + TimeSerial(hour, minute, second) _
    + milli / MillSecPerHour
    End Function





    share|improve this answer















    I have split your task into 3 functions.



    a) a helper function converts the 3 characters of the month into an integer. It looks a little clumsy, there might be other approaches but the advantage of using a large Select Case is it is easy to understand and easy to adapt if month names in a different language arise:



    Function getMonthFromName(monthName As String) As Integer

    Select Case UCase(monthName)
    Case "JAN": getMonthFromName = 1
    Case "FEB": getMonthFromName = 2
    Case "MAR": getMonthFromName = 3
    Case "APR": getMonthFromName = 4
    (...)
    Case "SEP": getMonthFromName = 9
    (...)
    End Select

    End Function


    b) a function that converts the string into a date. It assumes the date format in the form you provided, but it is easily adapted if the format changes (for simplicity, the seconds are rounded)



    Function GetDateFromString(dt As String) As Date

    Dim tokens() As String
    tokens = Split(Replace(dt, ":", " "), " ")

    Dim day As Integer, month As Integer, year As Integer
    month = getMonthFromName(CStr(tokens(0)))
    day = Val(tokens(1))
    year = Val(tokens(2))

    Dim hour As Integer, minute As Integer, second As Double
    hour = Val(tokens(3))
    minute = Val(tokens(4))
    second = Round(Val(tokens(5)), 0)

    GetDateFromString = DateSerial(year, month, day) + TimeSerial(hour, minute, second)
    End Function


    c) A function that calculated the difference of the 2 dates in seconds. A date in VBA (and many other environments) is stored as Double, where the Date-Part is the integer part and the date is the remainder. This makes it easy to calculate with Date values.



    Function DateDiffInSeconds(d1 As String, d2 As String) As Long
    Dim diff As Double
    diff = GetDateFromString(d2) - GetDateFromString(d1)
    DateDiffInSeconds = diff * 24 * 60 * 60
    End Function


    Update to deal with milliseconds: Change the GetDateFromString-function. In that case, DateDiffInSeconds should return a double rather than a long.



    Function GetDateFromString(dt As String) As Date

    Const MillSecPerHour As Long = 24& * 60 * 60 * 1000

    Dim tokens() As String
    tokens = Split(Replace(Replace(dt, ".", " "), ":", " "), " ")

    Dim day As Integer, month As Integer, year As Integer
    month = getMonthFromName(CStr(tokens(0)))
    day = Val(tokens(1))
    year = Val(tokens(2))

    Dim hour As Integer, minute As Integer, second As Integer, milli As Integer
    hour = Val(tokens(3))
    minute = Val(tokens(4))
    second = Val(tokens(5))
    milli = Val(tokens(6))

    GetDateFromString = DateSerial(year, month, day) _
    + TimeSerial(hour, minute, second) _
    + milli / MillSecPerHour
    End Function






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 14 '18 at 8:52

























    answered Nov 13 '18 at 13:39









    FunThomasFunThomas

    4,7611523




    4,7611523













    • thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?

      – user1610208
      Nov 14 '18 at 4:09













    • I have updated my answer to show a way to deal with milliseconds.

      – FunThomas
      Nov 14 '18 at 8:53











    • If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.

      – FunThomas
      Nov 14 '18 at 9:03



















    • thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?

      – user1610208
      Nov 14 '18 at 4:09













    • I have updated my answer to show a way to deal with milliseconds.

      – FunThomas
      Nov 14 '18 at 8:53











    • If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.

      – FunThomas
      Nov 14 '18 at 9:03

















    thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?

    – user1610208
    Nov 14 '18 at 4:09







    thank you for your excellent complete solution, it works great! I will try to make the first function faster by using an array with months names and return the index of the correct month. Is there away to include the milliseconds into calculations as well?

    – user1610208
    Nov 14 '18 at 4:09















    I have updated my answer to show a way to deal with milliseconds.

    – FunThomas
    Nov 14 '18 at 8:53





    I have updated my answer to show a way to deal with milliseconds.

    – FunThomas
    Nov 14 '18 at 8:53













    If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.

    – FunThomas
    Nov 14 '18 at 9:03





    If it is only for speed: Forget about changing it to an array: This function is so fast that you never will be able to measure it.

    – FunThomas
    Nov 14 '18 at 9:03













    0














    For your information, I've done what you are doing in a slightly different (and easier) way:



    In cell B2, I put the value 13/11/2018 11:44:00.

    In cell B3, I put the value 13/11/2018 11:45:01.

    (For both cells, the cell formatting has been set to d/mm/jjjj u:mm:ss).



    In another cell, I put following formula:



    =IF((B3-B2)*86400>90;TRUE;FALSE)


    The formula is based on the idea that a datetime value is set, based on the idea that one day equals 1, and there are 86400 seconds in one day.



    Like this, you can calculate time differences without needing VBA.






    share|improve this answer



















    • 1





      Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...

      – user1610208
      Nov 13 '18 at 11:29











    • @user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?

      – Dominique
      Nov 13 '18 at 13:54
















    0














    For your information, I've done what you are doing in a slightly different (and easier) way:



    In cell B2, I put the value 13/11/2018 11:44:00.

    In cell B3, I put the value 13/11/2018 11:45:01.

    (For both cells, the cell formatting has been set to d/mm/jjjj u:mm:ss).



    In another cell, I put following formula:



    =IF((B3-B2)*86400>90;TRUE;FALSE)


    The formula is based on the idea that a datetime value is set, based on the idea that one day equals 1, and there are 86400 seconds in one day.



    Like this, you can calculate time differences without needing VBA.






    share|improve this answer



















    • 1





      Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...

      – user1610208
      Nov 13 '18 at 11:29











    • @user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?

      – Dominique
      Nov 13 '18 at 13:54














    0












    0








    0







    For your information, I've done what you are doing in a slightly different (and easier) way:



    In cell B2, I put the value 13/11/2018 11:44:00.

    In cell B3, I put the value 13/11/2018 11:45:01.

    (For both cells, the cell formatting has been set to d/mm/jjjj u:mm:ss).



    In another cell, I put following formula:



    =IF((B3-B2)*86400>90;TRUE;FALSE)


    The formula is based on the idea that a datetime value is set, based on the idea that one day equals 1, and there are 86400 seconds in one day.



    Like this, you can calculate time differences without needing VBA.






    share|improve this answer













    For your information, I've done what you are doing in a slightly different (and easier) way:



    In cell B2, I put the value 13/11/2018 11:44:00.

    In cell B3, I put the value 13/11/2018 11:45:01.

    (For both cells, the cell formatting has been set to d/mm/jjjj u:mm:ss).



    In another cell, I put following formula:



    =IF((B3-B2)*86400>90;TRUE;FALSE)


    The formula is based on the idea that a datetime value is set, based on the idea that one day equals 1, and there are 86400 seconds in one day.



    Like this, you can calculate time differences without needing VBA.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 13 '18 at 11:02









    DominiqueDominique

    2,03741741




    2,03741741








    • 1





      Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...

      – user1610208
      Nov 13 '18 at 11:29











    • @user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?

      – Dominique
      Nov 13 '18 at 13:54














    • 1





      Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...

      – user1610208
      Nov 13 '18 at 11:29











    • @user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?

      – Dominique
      Nov 13 '18 at 13:54








    1




    1





    Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...

    – user1610208
    Nov 13 '18 at 11:29





    Thanks, but i really need it on VBA since it's going to be part of a bigger macro. Also, i see that you changed the values of the Cells, i don't have an option to change it since they are imported as is, this is why i needed a convert solution...

    – user1610208
    Nov 13 '18 at 11:29













    @user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?

    – Dominique
    Nov 13 '18 at 13:54





    @user1610208: my idea is based on the automatic conversion of dates. I've just entered "01/04/2014" in an Excel sheet, and it gets automatically converted to a date. If you can find a way to convert your cell values automatically to dates, your problem might be solved. Can you get rid of the downvote of my answer?

    – Dominique
    Nov 13 '18 at 13:54











    0














    I think you are over-complicating it, try this to get an idea how to do it:



    Sub Macro2()
    Dim str1 As String, str2 As String

    With Worksheets("sheet5")

    .Range("b1:e1") = Split(Range("A1"), " ")
    .Range("B2:e2") = Split(Range("A2"), " ")


    End Sub





    share|improve this answer


























    • this does not take into considuration the Date itself (month, day or year), i need to include them as well...

      – user1610208
      Nov 13 '18 at 10:58













    • No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.

      – Michal Rosa
      Nov 13 '18 at 11:24











    • can you put up a complete solution please?

      – user1610208
      Nov 13 '18 at 11:32











    • Use something like =DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1) to convert the string into a date, add the time value and the rest should be simple.

      – Michal Rosa
      Nov 13 '18 at 11:32











    • I need it on VBA script since i got tons of sheets

      – user1610208
      Nov 13 '18 at 11:37
















    0














    I think you are over-complicating it, try this to get an idea how to do it:



    Sub Macro2()
    Dim str1 As String, str2 As String

    With Worksheets("sheet5")

    .Range("b1:e1") = Split(Range("A1"), " ")
    .Range("B2:e2") = Split(Range("A2"), " ")


    End Sub





    share|improve this answer


























    • this does not take into considuration the Date itself (month, day or year), i need to include them as well...

      – user1610208
      Nov 13 '18 at 10:58













    • No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.

      – Michal Rosa
      Nov 13 '18 at 11:24











    • can you put up a complete solution please?

      – user1610208
      Nov 13 '18 at 11:32











    • Use something like =DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1) to convert the string into a date, add the time value and the rest should be simple.

      – Michal Rosa
      Nov 13 '18 at 11:32











    • I need it on VBA script since i got tons of sheets

      – user1610208
      Nov 13 '18 at 11:37














    0












    0








    0







    I think you are over-complicating it, try this to get an idea how to do it:



    Sub Macro2()
    Dim str1 As String, str2 As String

    With Worksheets("sheet5")

    .Range("b1:e1") = Split(Range("A1"), " ")
    .Range("B2:e2") = Split(Range("A2"), " ")


    End Sub





    share|improve this answer















    I think you are over-complicating it, try this to get an idea how to do it:



    Sub Macro2()
    Dim str1 As String, str2 As String

    With Worksheets("sheet5")

    .Range("b1:e1") = Split(Range("A1"), " ")
    .Range("B2:e2") = Split(Range("A2"), " ")


    End Sub






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 13 '18 at 11:23

























    answered Nov 13 '18 at 10:27









    Michal RosaMichal Rosa

    1,3191814




    1,3191814













    • this does not take into considuration the Date itself (month, day or year), i need to include them as well...

      – user1610208
      Nov 13 '18 at 10:58













    • No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.

      – Michal Rosa
      Nov 13 '18 at 11:24











    • can you put up a complete solution please?

      – user1610208
      Nov 13 '18 at 11:32











    • Use something like =DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1) to convert the string into a date, add the time value and the rest should be simple.

      – Michal Rosa
      Nov 13 '18 at 11:32











    • I need it on VBA script since i got tons of sheets

      – user1610208
      Nov 13 '18 at 11:37



















    • this does not take into considuration the Date itself (month, day or year), i need to include them as well...

      – user1610208
      Nov 13 '18 at 10:58













    • No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.

      – Michal Rosa
      Nov 13 '18 at 11:24











    • can you put up a complete solution please?

      – user1610208
      Nov 13 '18 at 11:32











    • Use something like =DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1) to convert the string into a date, add the time value and the rest should be simple.

      – Michal Rosa
      Nov 13 '18 at 11:32











    • I need it on VBA script since i got tons of sheets

      – user1610208
      Nov 13 '18 at 11:37

















    this does not take into considuration the Date itself (month, day or year), i need to include them as well...

    – user1610208
    Nov 13 '18 at 10:58







    this does not take into considuration the Date itself (month, day or year), i need to include them as well...

    – user1610208
    Nov 13 '18 at 10:58















    No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.

    – Michal Rosa
    Nov 13 '18 at 11:24





    No it didn't. Sorry, but if you split your string in the suggested way, you can recreate the date using a lookup for the month value.

    – Michal Rosa
    Nov 13 '18 at 11:24













    can you put up a complete solution please?

    – user1610208
    Nov 13 '18 at 11:32





    can you put up a complete solution please?

    – user1610208
    Nov 13 '18 at 11:32













    Use something like =DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1) to convert the string into a date, add the time value and the rest should be simple.

    – Michal Rosa
    Nov 13 '18 at 11:32





    Use something like =DATE(D1,MATCH(B1,{"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"},0),C1) to convert the string into a date, add the time value and the rest should be simple.

    – Michal Rosa
    Nov 13 '18 at 11:32













    I need it on VBA script since i got tons of sheets

    – user1610208
    Nov 13 '18 at 11:37





    I need it on VBA script since i got tons of sheets

    – user1610208
    Nov 13 '18 at 11:37











    0














    Use UDF.



    Sub Macro2()
    Dim str1 As String, str2 As String
    Dim mySecond As Double, t1 As Double, t2 As Double, t3 As Double
    mySecond = TimeSerial(0, 0, 90)

    With Worksheets("sheet5")
    str1 = .Cells(1, "A").Text
    str2 = .Cells(2, "A").Text
    t1 = ConvertTime(str1)
    t2 = ConvertTime(str2)
    t3 = t2 - t1
    .Cells(3, "a") = Abs(t3) >= mySecond
    End With

    End Sub
    Function ConvertTime(s As String)
    Dim vS
    vS = Split(s, " ")
    ConvertTime = DateValue(vS(0) & "-" & vS(1) & "-" & vS(2)) + TimeValue(Split(vS(3), ".")(0))
    End Function





    share|improve this answer






























      0














      Use UDF.



      Sub Macro2()
      Dim str1 As String, str2 As String
      Dim mySecond As Double, t1 As Double, t2 As Double, t3 As Double
      mySecond = TimeSerial(0, 0, 90)

      With Worksheets("sheet5")
      str1 = .Cells(1, "A").Text
      str2 = .Cells(2, "A").Text
      t1 = ConvertTime(str1)
      t2 = ConvertTime(str2)
      t3 = t2 - t1
      .Cells(3, "a") = Abs(t3) >= mySecond
      End With

      End Sub
      Function ConvertTime(s As String)
      Dim vS
      vS = Split(s, " ")
      ConvertTime = DateValue(vS(0) & "-" & vS(1) & "-" & vS(2)) + TimeValue(Split(vS(3), ".")(0))
      End Function





      share|improve this answer




























        0












        0








        0







        Use UDF.



        Sub Macro2()
        Dim str1 As String, str2 As String
        Dim mySecond As Double, t1 As Double, t2 As Double, t3 As Double
        mySecond = TimeSerial(0, 0, 90)

        With Worksheets("sheet5")
        str1 = .Cells(1, "A").Text
        str2 = .Cells(2, "A").Text
        t1 = ConvertTime(str1)
        t2 = ConvertTime(str2)
        t3 = t2 - t1
        .Cells(3, "a") = Abs(t3) >= mySecond
        End With

        End Sub
        Function ConvertTime(s As String)
        Dim vS
        vS = Split(s, " ")
        ConvertTime = DateValue(vS(0) & "-" & vS(1) & "-" & vS(2)) + TimeValue(Split(vS(3), ".")(0))
        End Function





        share|improve this answer















        Use UDF.



        Sub Macro2()
        Dim str1 As String, str2 As String
        Dim mySecond As Double, t1 As Double, t2 As Double, t3 As Double
        mySecond = TimeSerial(0, 0, 90)

        With Worksheets("sheet5")
        str1 = .Cells(1, "A").Text
        str2 = .Cells(2, "A").Text
        t1 = ConvertTime(str1)
        t2 = ConvertTime(str2)
        t3 = t2 - t1
        .Cells(3, "a") = Abs(t3) >= mySecond
        End With

        End Sub
        Function ConvertTime(s As String)
        Dim vS
        vS = Split(s, " ")
        ConvertTime = DateValue(vS(0) & "-" & vS(1) & "-" & vS(2)) + TimeValue(Split(vS(3), ".")(0))
        End Function






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 13 '18 at 14:24

























        answered Nov 13 '18 at 13:53









        Dy.LeeDy.Lee

        3,6421510




        3,6421510






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53277992%2fexcel-vba-convert-date-with-time%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Full-time equivalent

            Bicuculline

            さくらももこ