How do I replace all characters in a Python string?












-1














I found a solution on stackoverflow but it doesn't seem to work. I have made a string scanner that checks for character frequency and then replaces all characters with the "real" characters. I've made sure that the character recognition works but when I try replacing all characters in a string they no longer match up with the expected/calculated characters (when I try replacing for example only 2 characters it works fine and matches up perfectly). Here is my replacement code:



print(text.replace(re,'e').replace(rt,'t').replace(ra,'a').replace(ro,'o').replace(ri,'i').replace(rn,'n').replace(rs,'s').replace(rr,'r').replace(rh,'h').replace(rl,'l').replace(ru,'u').replace(rc,'c').replace(rm,'m').replace(rf,'f').replace(ry,'y').replace(rw,'w').replace(rg,'g').replace(rp,'p').replace(rb,'b').replace(rv,'v').replace(rk,'k').replace(rx,'x').replace(rq,'q').replace(rj,'j').replace(rz,'z').replace(rd,'d'))









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  • 2




    Has nothing to do with the Cryptography tag.
    – kelalaka
    Nov 11 at 22:47










  • Look at str.translate and str.maketrans
    – Michael Butscher
    Nov 11 at 22:49










  • Each call to replace is operating on the result of the previous. By the time you get to the 14th call, you are guaranteed to be replacing letters that you’ve already replaced. Use .translate as mentioned in the solution below.
    – soundstripe
    Nov 11 at 23:02






  • 1




    Are re/rt/ra etc. single characters, or multicharacter strings? str.translate can only replace based on matches of a single character (the replacement string can be any length).
    – ShadowRanger
    Nov 11 at 23:07










  • On a side note... if re/rt/ra etc... are the real characters... it looks like your arguments to replace are the wrong way around anyway...
    – Jon Clements
    Nov 11 at 23:23
















-1














I found a solution on stackoverflow but it doesn't seem to work. I have made a string scanner that checks for character frequency and then replaces all characters with the "real" characters. I've made sure that the character recognition works but when I try replacing all characters in a string they no longer match up with the expected/calculated characters (when I try replacing for example only 2 characters it works fine and matches up perfectly). Here is my replacement code:



print(text.replace(re,'e').replace(rt,'t').replace(ra,'a').replace(ro,'o').replace(ri,'i').replace(rn,'n').replace(rs,'s').replace(rr,'r').replace(rh,'h').replace(rl,'l').replace(ru,'u').replace(rc,'c').replace(rm,'m').replace(rf,'f').replace(ry,'y').replace(rw,'w').replace(rg,'g').replace(rp,'p').replace(rb,'b').replace(rv,'v').replace(rk,'k').replace(rx,'x').replace(rq,'q').replace(rj,'j').replace(rz,'z').replace(rd,'d'))









share|improve this question




















  • 2




    Has nothing to do with the Cryptography tag.
    – kelalaka
    Nov 11 at 22:47










  • Look at str.translate and str.maketrans
    – Michael Butscher
    Nov 11 at 22:49










  • Each call to replace is operating on the result of the previous. By the time you get to the 14th call, you are guaranteed to be replacing letters that you’ve already replaced. Use .translate as mentioned in the solution below.
    – soundstripe
    Nov 11 at 23:02






  • 1




    Are re/rt/ra etc. single characters, or multicharacter strings? str.translate can only replace based on matches of a single character (the replacement string can be any length).
    – ShadowRanger
    Nov 11 at 23:07










  • On a side note... if re/rt/ra etc... are the real characters... it looks like your arguments to replace are the wrong way around anyway...
    – Jon Clements
    Nov 11 at 23:23














-1












-1








-1


1





I found a solution on stackoverflow but it doesn't seem to work. I have made a string scanner that checks for character frequency and then replaces all characters with the "real" characters. I've made sure that the character recognition works but when I try replacing all characters in a string they no longer match up with the expected/calculated characters (when I try replacing for example only 2 characters it works fine and matches up perfectly). Here is my replacement code:



print(text.replace(re,'e').replace(rt,'t').replace(ra,'a').replace(ro,'o').replace(ri,'i').replace(rn,'n').replace(rs,'s').replace(rr,'r').replace(rh,'h').replace(rl,'l').replace(ru,'u').replace(rc,'c').replace(rm,'m').replace(rf,'f').replace(ry,'y').replace(rw,'w').replace(rg,'g').replace(rp,'p').replace(rb,'b').replace(rv,'v').replace(rk,'k').replace(rx,'x').replace(rq,'q').replace(rj,'j').replace(rz,'z').replace(rd,'d'))









share|improve this question















I found a solution on stackoverflow but it doesn't seem to work. I have made a string scanner that checks for character frequency and then replaces all characters with the "real" characters. I've made sure that the character recognition works but when I try replacing all characters in a string they no longer match up with the expected/calculated characters (when I try replacing for example only 2 characters it works fine and matches up perfectly). Here is my replacement code:



print(text.replace(re,'e').replace(rt,'t').replace(ra,'a').replace(ro,'o').replace(ri,'i').replace(rn,'n').replace(rs,'s').replace(rr,'r').replace(rh,'h').replace(rl,'l').replace(ru,'u').replace(rc,'c').replace(rm,'m').replace(rf,'f').replace(ry,'y').replace(rw,'w').replace(rg,'g').replace(rp,'p').replace(rb,'b').replace(rv,'v').replace(rk,'k').replace(rx,'x').replace(rq,'q').replace(rj,'j').replace(rz,'z').replace(rd,'d'))






python python-3.x






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edited Nov 11 at 22:48









coldspeed

119k19115193




119k19115193










asked Nov 11 at 22:45









Malik

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215








  • 2




    Has nothing to do with the Cryptography tag.
    – kelalaka
    Nov 11 at 22:47










  • Look at str.translate and str.maketrans
    – Michael Butscher
    Nov 11 at 22:49










  • Each call to replace is operating on the result of the previous. By the time you get to the 14th call, you are guaranteed to be replacing letters that you’ve already replaced. Use .translate as mentioned in the solution below.
    – soundstripe
    Nov 11 at 23:02






  • 1




    Are re/rt/ra etc. single characters, or multicharacter strings? str.translate can only replace based on matches of a single character (the replacement string can be any length).
    – ShadowRanger
    Nov 11 at 23:07










  • On a side note... if re/rt/ra etc... are the real characters... it looks like your arguments to replace are the wrong way around anyway...
    – Jon Clements
    Nov 11 at 23:23














  • 2




    Has nothing to do with the Cryptography tag.
    – kelalaka
    Nov 11 at 22:47










  • Look at str.translate and str.maketrans
    – Michael Butscher
    Nov 11 at 22:49










  • Each call to replace is operating on the result of the previous. By the time you get to the 14th call, you are guaranteed to be replacing letters that you’ve already replaced. Use .translate as mentioned in the solution below.
    – soundstripe
    Nov 11 at 23:02






  • 1




    Are re/rt/ra etc. single characters, or multicharacter strings? str.translate can only replace based on matches of a single character (the replacement string can be any length).
    – ShadowRanger
    Nov 11 at 23:07










  • On a side note... if re/rt/ra etc... are the real characters... it looks like your arguments to replace are the wrong way around anyway...
    – Jon Clements
    Nov 11 at 23:23








2




2




Has nothing to do with the Cryptography tag.
– kelalaka
Nov 11 at 22:47




Has nothing to do with the Cryptography tag.
– kelalaka
Nov 11 at 22:47












Look at str.translate and str.maketrans
– Michael Butscher
Nov 11 at 22:49




Look at str.translate and str.maketrans
– Michael Butscher
Nov 11 at 22:49












Each call to replace is operating on the result of the previous. By the time you get to the 14th call, you are guaranteed to be replacing letters that you’ve already replaced. Use .translate as mentioned in the solution below.
– soundstripe
Nov 11 at 23:02




Each call to replace is operating on the result of the previous. By the time you get to the 14th call, you are guaranteed to be replacing letters that you’ve already replaced. Use .translate as mentioned in the solution below.
– soundstripe
Nov 11 at 23:02




1




1




Are re/rt/ra etc. single characters, or multicharacter strings? str.translate can only replace based on matches of a single character (the replacement string can be any length).
– ShadowRanger
Nov 11 at 23:07




Are re/rt/ra etc. single characters, or multicharacter strings? str.translate can only replace based on matches of a single character (the replacement string can be any length).
– ShadowRanger
Nov 11 at 23:07












On a side note... if re/rt/ra etc... are the real characters... it looks like your arguments to replace are the wrong way around anyway...
– Jon Clements
Nov 11 at 23:23




On a side note... if re/rt/ra etc... are the real characters... it looks like your arguments to replace are the wrong way around anyway...
– Jon Clements
Nov 11 at 23:23












1 Answer
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You might want to take a look at translate. Your code would probably look something like



text = text.translate(str.maketrans('abcd...', ''.join([ra, rb, rc, rd...]))








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    You might want to take a look at translate. Your code would probably look something like



    text = text.translate(str.maketrans('abcd...', ''.join([ra, rb, rc, rd...]))








    share|improve this answer


























      1














      You might want to take a look at translate. Your code would probably look something like



      text = text.translate(str.maketrans('abcd...', ''.join([ra, rb, rc, rd...]))








      share|improve this answer
























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        You might want to take a look at translate. Your code would probably look something like



        text = text.translate(str.maketrans('abcd...', ''.join([ra, rb, rc, rd...]))








        share|improve this answer












        You might want to take a look at translate. Your code would probably look something like



        text = text.translate(str.maketrans('abcd...', ''.join([ra, rb, rc, rd...]))









        share|improve this answer












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        answered Nov 11 at 22:51









        MegaBluejay

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