argparse, python3, can't use parsed file as file
up vote
1
down vote
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So I need to parse .txt file as argument to my script. And then split it by lines, turn it into list and then print it.
parser = argparse.ArgumentParser()
parser.add_argument('textA', type=argparse.FileType('r'), nargs=1, default='textA.txt')
args = parser.parse_args()
textA = args.textA.read().split('n')
print(textA)
So but it's ending up with AttributeError: 'list' object has no attribute 'read' in console
I think I just don't know how to parse file proparly
Sorry about my english grammar
python-3.x argparse
asked Nov 11 at 11:12
Pavel Konstantinov
62
add a comment |
up vote
1
down vote
favorite
So I need to parse .txt file as argument to my script. And then split it by lines, turn it into list and then print it.
parser = argparse.ArgumentParser()
parser.add_argument('textA', type=argparse.FileType('r'), nargs=1, default='textA.txt')
args = parser.parse_args()
textA = args.textA.read().split('n')
print(textA)
So but it's ending up with AttributeError: 'list' object has no attribute 'read' in console
I think I just don't know how to parse file proparly
Sorry about my english grammar
python-3.x argparse
asked Nov 11 at 11:12
Pavel Konstantinov
62
Include aprint(args)in your debugging code so you have clear idea of what the parser produced. That would show you that it produced a one element list, not just an opened file.
– hpaulj
Nov 11 at 17:39
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
So I need to parse .txt file as argument to my script. And then split it by lines, turn it into list and then print it.
parser = argparse.ArgumentParser()
parser.add_argument('textA', type=argparse.FileType('r'), nargs=1, default='textA.txt')
args = parser.parse_args()
textA = args.textA.read().split('n')
print(textA)
So but it's ending up with AttributeError: 'list' object has no attribute 'read' in console
I think I just don't know how to parse file proparly
Sorry about my english grammar
python-3.x argparse
asked Nov 11 at 11:12
Pavel Konstantinov
62
So I need to parse .txt file as argument to my script. And then split it by lines, turn it into list and then print it.
parser = argparse.ArgumentParser()
parser.add_argument('textA', type=argparse.FileType('r'), nargs=1, default='textA.txt')
args = parser.parse_args()
textA = args.textA.read().split('n')
print(textA)
So but it's ending up with AttributeError: 'list' object has no attribute 'read' in console
I think I just don't know how to parse file proparly
Sorry about my english grammar
python-3.x argparse
python-3.x argparse
asked Nov 11 at 11:12
Pavel Konstantinov
62
asked Nov 11 at 11:12
Pavel Konstantinov
62
asked Nov 11 at 11:12
Pavel Konstantinov
62
asked Nov 11 at 11:12
Pavel Konstantinov
62
asked Nov 11 at 11:12
Pavel Konstantinov
62
62
Include aprint(args)in your debugging code so you have clear idea of what the parser produced. That would show you that it produced a one element list, not just an opened file.
– hpaulj
Nov 11 at 17:39
add a comment |
Include aprint(args)in your debugging code so you have clear idea of what the parser produced. That would show you that it produced a one element list, not just an opened file.
– hpaulj
Nov 11 at 17:39
Include a
print(args) in your debugging code so you have clear idea of what the parser produced. That would show you that it produced a one element list, not just an opened file.– hpaulj
Nov 11 at 17:39
Include a
print(args) in your debugging code so you have clear idea of what the parser produced. That would show you that it produced a one element list, not just an opened file.– hpaulj
Nov 11 at 17:39
add a comment |
1 Answer
1
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oldest
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1
down vote
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The narg parameter is the cause of the problem.
This is the documentation that explains the usage of this parameter
https://docs.python.org/3/library/argparse.html?highlight=argparse#nargs
- If you wish this arg to be optional and defaults to 'textA.txt', you should use
nargs="?"in this case. - If you wish to make this a mandatory field, change
args.textA.read()toargs.textA[0].read()and leavenargs=1as is
answered Nov 11 at 11:23
Eternal_flame-AD
3126
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
The narg parameter is the cause of the problem.
This is the documentation that explains the usage of this parameter
https://docs.python.org/3/library/argparse.html?highlight=argparse#nargs
- If you wish this arg to be optional and defaults to 'textA.txt', you should use
nargs="?"in this case. - If you wish to make this a mandatory field, change
args.textA.read()toargs.textA[0].read()and leavenargs=1as is
answered Nov 11 at 11:23
Eternal_flame-AD
3126
add a comment |
up vote
1
down vote
accepted
The narg parameter is the cause of the problem.
This is the documentation that explains the usage of this parameter
https://docs.python.org/3/library/argparse.html?highlight=argparse#nargs
- If you wish this arg to be optional and defaults to 'textA.txt', you should use
nargs="?"in this case. - If you wish to make this a mandatory field, change
args.textA.read()toargs.textA[0].read()and leavenargs=1as is
answered Nov 11 at 11:23
Eternal_flame-AD
3126
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
The narg parameter is the cause of the problem.
This is the documentation that explains the usage of this parameter
https://docs.python.org/3/library/argparse.html?highlight=argparse#nargs
- If you wish this arg to be optional and defaults to 'textA.txt', you should use
nargs="?"in this case. - If you wish to make this a mandatory field, change
args.textA.read()toargs.textA[0].read()and leavenargs=1as is
answered Nov 11 at 11:23
Eternal_flame-AD
3126
The narg parameter is the cause of the problem.
This is the documentation that explains the usage of this parameter
https://docs.python.org/3/library/argparse.html?highlight=argparse#nargs
- If you wish this arg to be optional and defaults to 'textA.txt', you should use
nargs="?"in this case. - If you wish to make this a mandatory field, change
args.textA.read()toargs.textA[0].read()and leavenargs=1as is
answered Nov 11 at 11:23
Eternal_flame-AD
3126
answered Nov 11 at 11:23
Eternal_flame-AD
3126
answered Nov 11 at 11:23
Eternal_flame-AD
3126
answered Nov 11 at 11:23
Eternal_flame-AD
3126
3126
add a comment |
add a comment |
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Include a
print(args)in your debugging code so you have clear idea of what the parser produced. That would show you that it produced a one element list, not just an opened file.– hpaulj
Nov 11 at 17:39