Tidying up a powershell script












0















So I need help tidying up a script that I have. The purpose of this script is to make 18 different sql files based on the data below 18 different column headers. What my script does now is make 1 sql file based on which column I choose to input via "Read-Host". This is my current script



function get-header
{Read-Host "Type the Column header betwen B-Z for which sql files needs to be created"
}
function get-column
{
Read-Host "Type the Column number"
}

do
{
$val = get-header
}
while(!($val))

do
{$col = get-column
}
while(!($col))

switch ($val)
{
"B"{$column = "1"}
"C"{$column = "2"}
"D"{$column = "3"}
"E"{$column = "4"}
"F"{$column = "5"}
"G"{$column = "6"}
"H"{$column = "7"}
"I"{$column = "8"}
"J"{$column = "9"}
"K"{$column = "10"}
"L"{$column = "11"}
"M"{$column = "12"}
"N"{$column = "13"}
"O"{$column = "14"}
"P"{$column = "15"}
"Q"{$column = "16"}
"R"{$column = "17"}
"S"{$column = "18"}
"T"{$column = "19"}
"U"{$column = "20"}
"V"{$column = "21"}
"W"{$column = "22"}
"X"{$column = "23"}
"Y"{$column = "24"}
"Z"{$column = "25"}
default { $column = 'Unknown' }

}

if ($column -eq 'Unknown')
{
Write-Warning "Not a valid input"
return
}

$csv = Import-Csv "Indices Updates - September 2018.csv" -Header 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26

$date = (Get-Date -Format "MM/dd/yyyy").Replace("-","/")

$sql = @("INSERT INTO benchmark_values(created_at,benchmark_id,date,amount,created_by_username)


foreach($data in $csv)
{

$secondcolumn = [int]$column + 1

$sql += "('$date',$col,'$($data.1)',$($data.$secondcolumn),'BPylla'),"

}


$sql | Out-File "sqldata.sql"


Now I want to get rid of read-host entirely because I dont want to input any values. I also will give an example of what the csv file looks like and what the sql file should look like.



CSV File Image



SQL File Image



So the goal is to produce different sql files from each column of information using the the sql format posted. I already have the template for that in my script now, I just need the script to create all the sql files based on headers and still input the data below the headers in the new sql files. Any help would be greatly appreciated! Thanks!










share|improve this question

























  • It's not clear to me what you are after. Just a hint instead of -Header 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26 simply use -Header @(1..26)

    – LotPings
    Nov 12 '18 at 23:44











  • Also most of your switch could be replaced by calculating $Column=([int][char]$Val.ToUpper())-65

    – LotPings
    Nov 12 '18 at 23:50











  • Does that $column variable give you the column data?

    – Andrew Fortes
    Nov 13 '18 at 3:09






  • 1





    @LotPings: Or, even simpler: -Header (1..26) - @(...) is never needed for expressions you know to be arrays (and is not only inefficient, but always outputs [object], irrespective of the input array type - try @([int] (1..3)).GetType().Name).

    – mklement0
    Nov 13 '18 at 4:08













  • @mklement0 so where and how would you apply that to the current script?

    – Andrew Fortes
    Nov 13 '18 at 16:06
















0















So I need help tidying up a script that I have. The purpose of this script is to make 18 different sql files based on the data below 18 different column headers. What my script does now is make 1 sql file based on which column I choose to input via "Read-Host". This is my current script



function get-header
{Read-Host "Type the Column header betwen B-Z for which sql files needs to be created"
}
function get-column
{
Read-Host "Type the Column number"
}

do
{
$val = get-header
}
while(!($val))

do
{$col = get-column
}
while(!($col))

switch ($val)
{
"B"{$column = "1"}
"C"{$column = "2"}
"D"{$column = "3"}
"E"{$column = "4"}
"F"{$column = "5"}
"G"{$column = "6"}
"H"{$column = "7"}
"I"{$column = "8"}
"J"{$column = "9"}
"K"{$column = "10"}
"L"{$column = "11"}
"M"{$column = "12"}
"N"{$column = "13"}
"O"{$column = "14"}
"P"{$column = "15"}
"Q"{$column = "16"}
"R"{$column = "17"}
"S"{$column = "18"}
"T"{$column = "19"}
"U"{$column = "20"}
"V"{$column = "21"}
"W"{$column = "22"}
"X"{$column = "23"}
"Y"{$column = "24"}
"Z"{$column = "25"}
default { $column = 'Unknown' }

}

if ($column -eq 'Unknown')
{
Write-Warning "Not a valid input"
return
}

$csv = Import-Csv "Indices Updates - September 2018.csv" -Header 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26

$date = (Get-Date -Format "MM/dd/yyyy").Replace("-","/")

$sql = @("INSERT INTO benchmark_values(created_at,benchmark_id,date,amount,created_by_username)


foreach($data in $csv)
{

$secondcolumn = [int]$column + 1

$sql += "('$date',$col,'$($data.1)',$($data.$secondcolumn),'BPylla'),"

}


$sql | Out-File "sqldata.sql"


Now I want to get rid of read-host entirely because I dont want to input any values. I also will give an example of what the csv file looks like and what the sql file should look like.



CSV File Image



SQL File Image



So the goal is to produce different sql files from each column of information using the the sql format posted. I already have the template for that in my script now, I just need the script to create all the sql files based on headers and still input the data below the headers in the new sql files. Any help would be greatly appreciated! Thanks!










share|improve this question

























  • It's not clear to me what you are after. Just a hint instead of -Header 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26 simply use -Header @(1..26)

    – LotPings
    Nov 12 '18 at 23:44











  • Also most of your switch could be replaced by calculating $Column=([int][char]$Val.ToUpper())-65

    – LotPings
    Nov 12 '18 at 23:50











  • Does that $column variable give you the column data?

    – Andrew Fortes
    Nov 13 '18 at 3:09






  • 1





    @LotPings: Or, even simpler: -Header (1..26) - @(...) is never needed for expressions you know to be arrays (and is not only inefficient, but always outputs [object], irrespective of the input array type - try @([int] (1..3)).GetType().Name).

    – mklement0
    Nov 13 '18 at 4:08













  • @mklement0 so where and how would you apply that to the current script?

    – Andrew Fortes
    Nov 13 '18 at 16:06














0












0








0








So I need help tidying up a script that I have. The purpose of this script is to make 18 different sql files based on the data below 18 different column headers. What my script does now is make 1 sql file based on which column I choose to input via "Read-Host". This is my current script



function get-header
{Read-Host "Type the Column header betwen B-Z for which sql files needs to be created"
}
function get-column
{
Read-Host "Type the Column number"
}

do
{
$val = get-header
}
while(!($val))

do
{$col = get-column
}
while(!($col))

switch ($val)
{
"B"{$column = "1"}
"C"{$column = "2"}
"D"{$column = "3"}
"E"{$column = "4"}
"F"{$column = "5"}
"G"{$column = "6"}
"H"{$column = "7"}
"I"{$column = "8"}
"J"{$column = "9"}
"K"{$column = "10"}
"L"{$column = "11"}
"M"{$column = "12"}
"N"{$column = "13"}
"O"{$column = "14"}
"P"{$column = "15"}
"Q"{$column = "16"}
"R"{$column = "17"}
"S"{$column = "18"}
"T"{$column = "19"}
"U"{$column = "20"}
"V"{$column = "21"}
"W"{$column = "22"}
"X"{$column = "23"}
"Y"{$column = "24"}
"Z"{$column = "25"}
default { $column = 'Unknown' }

}

if ($column -eq 'Unknown')
{
Write-Warning "Not a valid input"
return
}

$csv = Import-Csv "Indices Updates - September 2018.csv" -Header 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26

$date = (Get-Date -Format "MM/dd/yyyy").Replace("-","/")

$sql = @("INSERT INTO benchmark_values(created_at,benchmark_id,date,amount,created_by_username)


foreach($data in $csv)
{

$secondcolumn = [int]$column + 1

$sql += "('$date',$col,'$($data.1)',$($data.$secondcolumn),'BPylla'),"

}


$sql | Out-File "sqldata.sql"


Now I want to get rid of read-host entirely because I dont want to input any values. I also will give an example of what the csv file looks like and what the sql file should look like.



CSV File Image



SQL File Image



So the goal is to produce different sql files from each column of information using the the sql format posted. I already have the template for that in my script now, I just need the script to create all the sql files based on headers and still input the data below the headers in the new sql files. Any help would be greatly appreciated! Thanks!










share|improve this question
















So I need help tidying up a script that I have. The purpose of this script is to make 18 different sql files based on the data below 18 different column headers. What my script does now is make 1 sql file based on which column I choose to input via "Read-Host". This is my current script



function get-header
{Read-Host "Type the Column header betwen B-Z for which sql files needs to be created"
}
function get-column
{
Read-Host "Type the Column number"
}

do
{
$val = get-header
}
while(!($val))

do
{$col = get-column
}
while(!($col))

switch ($val)
{
"B"{$column = "1"}
"C"{$column = "2"}
"D"{$column = "3"}
"E"{$column = "4"}
"F"{$column = "5"}
"G"{$column = "6"}
"H"{$column = "7"}
"I"{$column = "8"}
"J"{$column = "9"}
"K"{$column = "10"}
"L"{$column = "11"}
"M"{$column = "12"}
"N"{$column = "13"}
"O"{$column = "14"}
"P"{$column = "15"}
"Q"{$column = "16"}
"R"{$column = "17"}
"S"{$column = "18"}
"T"{$column = "19"}
"U"{$column = "20"}
"V"{$column = "21"}
"W"{$column = "22"}
"X"{$column = "23"}
"Y"{$column = "24"}
"Z"{$column = "25"}
default { $column = 'Unknown' }

}

if ($column -eq 'Unknown')
{
Write-Warning "Not a valid input"
return
}

$csv = Import-Csv "Indices Updates - September 2018.csv" -Header 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26

$date = (Get-Date -Format "MM/dd/yyyy").Replace("-","/")

$sql = @("INSERT INTO benchmark_values(created_at,benchmark_id,date,amount,created_by_username)


foreach($data in $csv)
{

$secondcolumn = [int]$column + 1

$sql += "('$date',$col,'$($data.1)',$($data.$secondcolumn),'BPylla'),"

}


$sql | Out-File "sqldata.sql"


Now I want to get rid of read-host entirely because I dont want to input any values. I also will give an example of what the csv file looks like and what the sql file should look like.



CSV File Image



SQL File Image



So the goal is to produce different sql files from each column of information using the the sql format posted. I already have the template for that in my script now, I just need the script to create all the sql files based on headers and still input the data below the headers in the new sql files. Any help would be greatly appreciated! Thanks!







powershell






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 '18 at 22:30









mklement0

128k20241270




128k20241270










asked Nov 12 '18 at 21:55









Andrew FortesAndrew Fortes

1




1













  • It's not clear to me what you are after. Just a hint instead of -Header 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26 simply use -Header @(1..26)

    – LotPings
    Nov 12 '18 at 23:44











  • Also most of your switch could be replaced by calculating $Column=([int][char]$Val.ToUpper())-65

    – LotPings
    Nov 12 '18 at 23:50











  • Does that $column variable give you the column data?

    – Andrew Fortes
    Nov 13 '18 at 3:09






  • 1





    @LotPings: Or, even simpler: -Header (1..26) - @(...) is never needed for expressions you know to be arrays (and is not only inefficient, but always outputs [object], irrespective of the input array type - try @([int] (1..3)).GetType().Name).

    – mklement0
    Nov 13 '18 at 4:08













  • @mklement0 so where and how would you apply that to the current script?

    – Andrew Fortes
    Nov 13 '18 at 16:06



















  • It's not clear to me what you are after. Just a hint instead of -Header 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26 simply use -Header @(1..26)

    – LotPings
    Nov 12 '18 at 23:44











  • Also most of your switch could be replaced by calculating $Column=([int][char]$Val.ToUpper())-65

    – LotPings
    Nov 12 '18 at 23:50











  • Does that $column variable give you the column data?

    – Andrew Fortes
    Nov 13 '18 at 3:09






  • 1





    @LotPings: Or, even simpler: -Header (1..26) - @(...) is never needed for expressions you know to be arrays (and is not only inefficient, but always outputs [object], irrespective of the input array type - try @([int] (1..3)).GetType().Name).

    – mklement0
    Nov 13 '18 at 4:08













  • @mklement0 so where and how would you apply that to the current script?

    – Andrew Fortes
    Nov 13 '18 at 16:06

















It's not clear to me what you are after. Just a hint instead of -Header 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26 simply use -Header @(1..26)

– LotPings
Nov 12 '18 at 23:44





It's not clear to me what you are after. Just a hint instead of -Header 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26 simply use -Header @(1..26)

– LotPings
Nov 12 '18 at 23:44













Also most of your switch could be replaced by calculating $Column=([int][char]$Val.ToUpper())-65

– LotPings
Nov 12 '18 at 23:50





Also most of your switch could be replaced by calculating $Column=([int][char]$Val.ToUpper())-65

– LotPings
Nov 12 '18 at 23:50













Does that $column variable give you the column data?

– Andrew Fortes
Nov 13 '18 at 3:09





Does that $column variable give you the column data?

– Andrew Fortes
Nov 13 '18 at 3:09




1




1





@LotPings: Or, even simpler: -Header (1..26) - @(...) is never needed for expressions you know to be arrays (and is not only inefficient, but always outputs [object], irrespective of the input array type - try @([int] (1..3)).GetType().Name).

– mklement0
Nov 13 '18 at 4:08







@LotPings: Or, even simpler: -Header (1..26) - @(...) is never needed for expressions you know to be arrays (and is not only inefficient, but always outputs [object], irrespective of the input array type - try @([int] (1..3)).GetType().Name).

– mklement0
Nov 13 '18 at 4:08















@mklement0 so where and how would you apply that to the current script?

– Andrew Fortes
Nov 13 '18 at 16:06





@mklement0 so where and how would you apply that to the current script?

– Andrew Fortes
Nov 13 '18 at 16:06












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