Spring Data JPA Specification with MayToMany relation
0
I'm trying to use Specification to build a search criteria with Spring Data JPA.
I have 2 entities
@Entity
public class User {
@Id
private Long userId;
@ManyToMany
@JoinColumn(name="locationId")
@JsonIgnore
private List<Location> locations;
//getters and setters
And Location
public class Location {
@Id
private long locationId;
@ManyToMany(fetch = FetchType.LAZY, cascade = { CascadeType.PERSIST, CascadeType.REMOVE, CascadeType.DETACH,
CascadeType.REFRESH }, mappedBy = "locations")
@JsonIgnore
private List<User> users;
//getters and setters
Now I would like to find all users with a given list of locations, so I'm trying to build the predicate.
My problem is getting the relation table between the 2 entities... I'm trying in this way
Root<Location> second = query.from(Location.class);
Expression<Collection<Root>> userLocations = second.get("users");
return builder.and(builder.isMember(root, userLocations));
This is the sql query i need
select distinct * from User u
join User_Location ul on u.userId = ul.`users_userId`
where ul.`locations_locationId` in (1,2,3...)
The main difficult for me is telling Spring to use the relation table User_Location which is not an entity...
But I indeed miss something...
java jpa spring-data-jpa many-to-many criteria-api
asked Nov 12 '18 at 21:45
besmartbesmart
65722455
add a comment |
0
I'm trying to use Specification to build a search criteria with Spring Data JPA.
I have 2 entities
@Entity
public class User {
@Id
private Long userId;
@ManyToMany
@JoinColumn(name="locationId")
@JsonIgnore
private List<Location> locations;
//getters and setters
And Location
public class Location {
@Id
private long locationId;
@ManyToMany(fetch = FetchType.LAZY, cascade = { CascadeType.PERSIST, CascadeType.REMOVE, CascadeType.DETACH,
CascadeType.REFRESH }, mappedBy = "locations")
@JsonIgnore
private List<User> users;
//getters and setters
Now I would like to find all users with a given list of locations, so I'm trying to build the predicate.
My problem is getting the relation table between the 2 entities... I'm trying in this way
Root<Location> second = query.from(Location.class);
Expression<Collection<Root>> userLocations = second.get("users");
return builder.and(builder.isMember(root, userLocations));
This is the sql query i need
select distinct * from User u
join User_Location ul on u.userId = ul.`users_userId`
where ul.`locations_locationId` in (1,2,3...)
The main difficult for me is telling Spring to use the relation table User_Location which is not an entity...
But I indeed miss something...
java jpa spring-data-jpa many-to-many criteria-api
asked Nov 12 '18 at 21:45
besmartbesmart
65722455
You can break down a bidirectional Many-to-Many relationship to two One-To-Many relationships. The config can be found here.
– huytmb
Nov 13 '18 at 8:52
1
You don't need to use the join table in your query. Simply do "select distrinct u from User u where u.locations in (l1, l2, l3, …)" In criteriaBuilder the class is a "Join" class, so Join<User, Location> locations = root.join("locations)" if I remember correctly. Then "query.where( builder.in(locations, locationList))". Something along those lines.
– K.Nicholas
Nov 13 '18 at 20:00
thanks, this works perfectly
– besmart
Nov 14 '18 at 13:01
add a comment |
0
0
0
I'm trying to use Specification to build a search criteria with Spring Data JPA.
I have 2 entities
@Entity
public class User {
@Id
private Long userId;
@ManyToMany
@JoinColumn(name="locationId")
@JsonIgnore
private List<Location> locations;
//getters and setters
And Location
public class Location {
@Id
private long locationId;
@ManyToMany(fetch = FetchType.LAZY, cascade = { CascadeType.PERSIST, CascadeType.REMOVE, CascadeType.DETACH,
CascadeType.REFRESH }, mappedBy = "locations")
@JsonIgnore
private List<User> users;
//getters and setters
Now I would like to find all users with a given list of locations, so I'm trying to build the predicate.
My problem is getting the relation table between the 2 entities... I'm trying in this way
Root<Location> second = query.from(Location.class);
Expression<Collection<Root>> userLocations = second.get("users");
return builder.and(builder.isMember(root, userLocations));
This is the sql query i need
select distinct * from User u
join User_Location ul on u.userId = ul.`users_userId`
where ul.`locations_locationId` in (1,2,3...)
The main difficult for me is telling Spring to use the relation table User_Location which is not an entity...
But I indeed miss something...
java jpa spring-data-jpa many-to-many criteria-api
asked Nov 12 '18 at 21:45
besmartbesmart
65722455
I'm trying to use Specification to build a search criteria with Spring Data JPA.
I have 2 entities
@Entity
public class User {
@Id
private Long userId;
@ManyToMany
@JoinColumn(name="locationId")
@JsonIgnore
private List<Location> locations;
//getters and setters
And Location
public class Location {
@Id
private long locationId;
@ManyToMany(fetch = FetchType.LAZY, cascade = { CascadeType.PERSIST, CascadeType.REMOVE, CascadeType.DETACH,
CascadeType.REFRESH }, mappedBy = "locations")
@JsonIgnore
private List<User> users;
//getters and setters
Now I would like to find all users with a given list of locations, so I'm trying to build the predicate.
My problem is getting the relation table between the 2 entities... I'm trying in this way
Root<Location> second = query.from(Location.class);
Expression<Collection<Root>> userLocations = second.get("users");
return builder.and(builder.isMember(root, userLocations));
This is the sql query i need
select distinct * from User u
join User_Location ul on u.userId = ul.`users_userId`
where ul.`locations_locationId` in (1,2,3...)
The main difficult for me is telling Spring to use the relation table User_Location which is not an entity...
But I indeed miss something...
java jpa spring-data-jpa many-to-many criteria-api
java jpa spring-data-jpa many-to-many criteria-api
asked Nov 12 '18 at 21:45
besmartbesmart
65722455
asked Nov 12 '18 at 21:45
besmartbesmart
65722455
edited Nov 13 '18 at 8:28
besmart
asked Nov 12 '18 at 21:45
besmartbesmart
65722455
asked Nov 12 '18 at 21:45
besmartbesmart
65722455
asked Nov 12 '18 at 21:45
besmartbesmart
65722455
65722455
You can break down a bidirectional Many-to-Many relationship to two One-To-Many relationships. The config can be found here.
– huytmb
Nov 13 '18 at 8:52
1
You don't need to use the join table in your query. Simply do "select distrinct u from User u where u.locations in (l1, l2, l3, …)" In criteriaBuilder the class is a "Join" class, so Join<User, Location> locations = root.join("locations)" if I remember correctly. Then "query.where( builder.in(locations, locationList))". Something along those lines.
– K.Nicholas
Nov 13 '18 at 20:00
thanks, this works perfectly
– besmart
Nov 14 '18 at 13:01
add a comment |
You can break down a bidirectional Many-to-Many relationship to two One-To-Many relationships. The config can be found here.
– huytmb
Nov 13 '18 at 8:52
1
You don't need to use the join table in your query. Simply do "select distrinct u from User u where u.locations in (l1, l2, l3, …)" In criteriaBuilder the class is a "Join" class, so Join<User, Location> locations = root.join("locations)" if I remember correctly. Then "query.where( builder.in(locations, locationList))". Something along those lines.
– K.Nicholas
Nov 13 '18 at 20:00
thanks, this works perfectly
– besmart
Nov 14 '18 at 13:01
You can break down a bidirectional Many-to-Many relationship to two One-To-Many relationships. The config can be found here.
– huytmb
Nov 13 '18 at 8:52
You can break down a bidirectional Many-to-Many relationship to two One-To-Many relationships. The config can be found here.
– huytmb
Nov 13 '18 at 8:52
1
1
You don't need to use the join table in your query. Simply do "select distrinct u from User u where u.locations in (l1, l2, l3, …)" In criteriaBuilder the class is a "Join" class, so Join<User, Location> locations = root.join("locations)" if I remember correctly. Then "query.where( builder.in(locations, locationList))". Something along those lines.
– K.Nicholas
Nov 13 '18 at 20:00
You don't need to use the join table in your query. Simply do "select distrinct u from User u where u.locations in (l1, l2, l3, …)" In criteriaBuilder the class is a "Join" class, so Join<User, Location> locations = root.join("locations)" if I remember correctly. Then "query.where( builder.in(locations, locationList))". Something along those lines.
– K.Nicholas
Nov 13 '18 at 20:00
thanks, this works perfectly
– besmart
Nov 14 '18 at 13:01
thanks, this works perfectly
– besmart
Nov 14 '18 at 13:01
add a comment |
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You can break down a bidirectional Many-to-Many relationship to two One-To-Many relationships. The config can be found here.
– huytmb
Nov 13 '18 at 8:52
1
You don't need to use the join table in your query. Simply do "select distrinct u from User u where u.locations in (l1, l2, l3, …)" In criteriaBuilder the class is a "Join" class, so Join<User, Location> locations = root.join("locations)" if I remember correctly. Then "query.where( builder.in(locations, locationList))". Something along those lines.
– K.Nicholas
Nov 13 '18 at 20:00
thanks, this works perfectly
– besmart
Nov 14 '18 at 13:01