Skip new tasks if the queue is not empty. Swift
I have a piece of code that spams long running tasks 5-6 times per second. Each task takes some time to finish. I want to ignore all the other tasks while 1 is being executed. After it finishes a fresh one should take its place.
There are a bunch of tools being used for concurrency in Swift 4.2. What would work the best?
swift macos concurrency swift4
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I have a piece of code that spams long running tasks 5-6 times per second. Each task takes some time to finish. I want to ignore all the other tasks while 1 is being executed. After it finishes a fresh one should take its place.
There are a bunch of tools being used for concurrency in Swift 4.2. What would work the best?
swift macos concurrency swift4
add a comment |
I have a piece of code that spams long running tasks 5-6 times per second. Each task takes some time to finish. I want to ignore all the other tasks while 1 is being executed. After it finishes a fresh one should take its place.
There are a bunch of tools being used for concurrency in Swift 4.2. What would work the best?
swift macos concurrency swift4
I have a piece of code that spams long running tasks 5-6 times per second. Each task takes some time to finish. I want to ignore all the other tasks while 1 is being executed. After it finishes a fresh one should take its place.
There are a bunch of tools being used for concurrency in Swift 4.2. What would work the best?
swift macos concurrency swift4
swift macos concurrency swift4
asked Nov 11 at 20:17
Ruzard
3341725
3341725
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For solving of this problem you can use GCD or Operation. In case that you have describ I would use Operation. Using this approach you can have a bit more user friendly control over Operation that are executing (stoping, cancelling....).
Small example:
let queue = OperationQueue()
queue.maxConcurrentOperationCount = 1
queue.addOperation { print("🤠") }
queue.addOperation { print("🤓") }
queue.addOperation { print("👺") }
In this case operations are executed one by one.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
For solving of this problem you can use GCD or Operation. In case that you have describ I would use Operation. Using this approach you can have a bit more user friendly control over Operation that are executing (stoping, cancelling....).
Small example:
let queue = OperationQueue()
queue.maxConcurrentOperationCount = 1
queue.addOperation { print("🤠") }
queue.addOperation { print("🤓") }
queue.addOperation { print("👺") }
In this case operations are executed one by one.
add a comment |
For solving of this problem you can use GCD or Operation. In case that you have describ I would use Operation. Using this approach you can have a bit more user friendly control over Operation that are executing (stoping, cancelling....).
Small example:
let queue = OperationQueue()
queue.maxConcurrentOperationCount = 1
queue.addOperation { print("🤠") }
queue.addOperation { print("🤓") }
queue.addOperation { print("👺") }
In this case operations are executed one by one.
add a comment |
For solving of this problem you can use GCD or Operation. In case that you have describ I would use Operation. Using this approach you can have a bit more user friendly control over Operation that are executing (stoping, cancelling....).
Small example:
let queue = OperationQueue()
queue.maxConcurrentOperationCount = 1
queue.addOperation { print("🤠") }
queue.addOperation { print("🤓") }
queue.addOperation { print("👺") }
In this case operations are executed one by one.
For solving of this problem you can use GCD or Operation. In case that you have describ I would use Operation. Using this approach you can have a bit more user friendly control over Operation that are executing (stoping, cancelling....).
Small example:
let queue = OperationQueue()
queue.maxConcurrentOperationCount = 1
queue.addOperation { print("🤠") }
queue.addOperation { print("🤓") }
queue.addOperation { print("👺") }
In this case operations are executed one by one.
answered Nov 11 at 22:35
Oleg Gordiichuk
9,57253671
9,57253671
add a comment |
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