Function Argument Packing And Unpacking Python
Currently, I have a function like so:
def my_func(*args):
#prints amount of arguments
print(len(args))
#prints each argument
for arg in args:
print(arg)
I want to put multiple arguments through to this function, but the following doesn't work for me. It gives out a syntax error on the asterisk * after the else.
my_func(
*(1, 2, 3, 4)
if someBool is True
else *(1, 2)
)
The workaround I found puts 1 and 2 in first and then puts 3 and 4 while checking for someBool.
my_func(
1, 2,
3 if someBool is True else None,
4 if someBool is True else None
)
I am fine with the above as my function checks for None but if there is an alternative I would gladly thank them.
python python-3.x function ternary-operator
add a comment |
Currently, I have a function like so:
def my_func(*args):
#prints amount of arguments
print(len(args))
#prints each argument
for arg in args:
print(arg)
I want to put multiple arguments through to this function, but the following doesn't work for me. It gives out a syntax error on the asterisk * after the else.
my_func(
*(1, 2, 3, 4)
if someBool is True
else *(1, 2)
)
The workaround I found puts 1 and 2 in first and then puts 3 and 4 while checking for someBool.
my_func(
1, 2,
3 if someBool is True else None,
4 if someBool is True else None
)
I am fine with the above as my function checks for None but if there is an alternative I would gladly thank them.
python python-3.x function ternary-operator
Why don't you write theif
statement outside the function call?
– SilverSlash
Nov 12 '18 at 2:21
I have a function taking either 2, 4, or any even number of arguments. Making it in one function makes it (for me) easier to check and understand. I would put it outside but I'm more comfortable with the ternary operator. Thanks for the suggestion though :D
– GeeTransit
Nov 12 '18 at 2:30
add a comment |
Currently, I have a function like so:
def my_func(*args):
#prints amount of arguments
print(len(args))
#prints each argument
for arg in args:
print(arg)
I want to put multiple arguments through to this function, but the following doesn't work for me. It gives out a syntax error on the asterisk * after the else.
my_func(
*(1, 2, 3, 4)
if someBool is True
else *(1, 2)
)
The workaround I found puts 1 and 2 in first and then puts 3 and 4 while checking for someBool.
my_func(
1, 2,
3 if someBool is True else None,
4 if someBool is True else None
)
I am fine with the above as my function checks for None but if there is an alternative I would gladly thank them.
python python-3.x function ternary-operator
Currently, I have a function like so:
def my_func(*args):
#prints amount of arguments
print(len(args))
#prints each argument
for arg in args:
print(arg)
I want to put multiple arguments through to this function, but the following doesn't work for me. It gives out a syntax error on the asterisk * after the else.
my_func(
*(1, 2, 3, 4)
if someBool is True
else *(1, 2)
)
The workaround I found puts 1 and 2 in first and then puts 3 and 4 while checking for someBool.
my_func(
1, 2,
3 if someBool is True else None,
4 if someBool is True else None
)
I am fine with the above as my function checks for None but if there is an alternative I would gladly thank them.
python python-3.x function ternary-operator
python python-3.x function ternary-operator
asked Nov 12 '18 at 2:18
GeeTransit
18210
18210
Why don't you write theif
statement outside the function call?
– SilverSlash
Nov 12 '18 at 2:21
I have a function taking either 2, 4, or any even number of arguments. Making it in one function makes it (for me) easier to check and understand. I would put it outside but I'm more comfortable with the ternary operator. Thanks for the suggestion though :D
– GeeTransit
Nov 12 '18 at 2:30
add a comment |
Why don't you write theif
statement outside the function call?
– SilverSlash
Nov 12 '18 at 2:21
I have a function taking either 2, 4, or any even number of arguments. Making it in one function makes it (for me) easier to check and understand. I would put it outside but I'm more comfortable with the ternary operator. Thanks for the suggestion though :D
– GeeTransit
Nov 12 '18 at 2:30
Why don't you write the
if
statement outside the function call?– SilverSlash
Nov 12 '18 at 2:21
Why don't you write the
if
statement outside the function call?– SilverSlash
Nov 12 '18 at 2:21
I have a function taking either 2, 4, or any even number of arguments. Making it in one function makes it (for me) easier to check and understand. I would put it outside but I'm more comfortable with the ternary operator. Thanks for the suggestion though :D
– GeeTransit
Nov 12 '18 at 2:30
I have a function taking either 2, 4, or any even number of arguments. Making it in one function makes it (for me) easier to check and understand. I would put it outside but I'm more comfortable with the ternary operator. Thanks for the suggestion though :D
– GeeTransit
Nov 12 '18 at 2:30
add a comment |
2 Answers
2
active
oldest
votes
Move the *
to outside the ... if ... else ...
:
my_func(
*((1, 2, 3, 4)
if someBool is True
else (1, 2))
)
add a comment |
You need an extra set of parenthesis. Also, you don't need to say is True
to check if a Boolean is "truthy" in python, making it: my_func(*((1, 2, 3, 4) if someBool else (1, 2)))
.
Theis True
was included since I wanted to prevent some possible confusion. I'll omit it next time :)
– GeeTransit
Nov 12 '18 at 2:33
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Move the *
to outside the ... if ... else ...
:
my_func(
*((1, 2, 3, 4)
if someBool is True
else (1, 2))
)
add a comment |
Move the *
to outside the ... if ... else ...
:
my_func(
*((1, 2, 3, 4)
if someBool is True
else (1, 2))
)
add a comment |
Move the *
to outside the ... if ... else ...
:
my_func(
*((1, 2, 3, 4)
if someBool is True
else (1, 2))
)
Move the *
to outside the ... if ... else ...
:
my_func(
*((1, 2, 3, 4)
if someBool is True
else (1, 2))
)
answered Nov 12 '18 at 2:23
jwodder
32.8k35283
32.8k35283
add a comment |
add a comment |
You need an extra set of parenthesis. Also, you don't need to say is True
to check if a Boolean is "truthy" in python, making it: my_func(*((1, 2, 3, 4) if someBool else (1, 2)))
.
Theis True
was included since I wanted to prevent some possible confusion. I'll omit it next time :)
– GeeTransit
Nov 12 '18 at 2:33
add a comment |
You need an extra set of parenthesis. Also, you don't need to say is True
to check if a Boolean is "truthy" in python, making it: my_func(*((1, 2, 3, 4) if someBool else (1, 2)))
.
Theis True
was included since I wanted to prevent some possible confusion. I'll omit it next time :)
– GeeTransit
Nov 12 '18 at 2:33
add a comment |
You need an extra set of parenthesis. Also, you don't need to say is True
to check if a Boolean is "truthy" in python, making it: my_func(*((1, 2, 3, 4) if someBool else (1, 2)))
.
You need an extra set of parenthesis. Also, you don't need to say is True
to check if a Boolean is "truthy" in python, making it: my_func(*((1, 2, 3, 4) if someBool else (1, 2)))
.
answered Nov 12 '18 at 2:23
soundstripe
48138
48138
Theis True
was included since I wanted to prevent some possible confusion. I'll omit it next time :)
– GeeTransit
Nov 12 '18 at 2:33
add a comment |
Theis True
was included since I wanted to prevent some possible confusion. I'll omit it next time :)
– GeeTransit
Nov 12 '18 at 2:33
The
is True
was included since I wanted to prevent some possible confusion. I'll omit it next time :)– GeeTransit
Nov 12 '18 at 2:33
The
is True
was included since I wanted to prevent some possible confusion. I'll omit it next time :)– GeeTransit
Nov 12 '18 at 2:33
add a comment |
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Why don't you write the
if
statement outside the function call?– SilverSlash
Nov 12 '18 at 2:21
I have a function taking either 2, 4, or any even number of arguments. Making it in one function makes it (for me) easier to check and understand. I would put it outside but I'm more comfortable with the ternary operator. Thanks for the suggestion though :D
– GeeTransit
Nov 12 '18 at 2:30