Allow JSON fragments with Decodable
import UIKit
class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
//@IBOutlet weak var ingredientText: UILabel!
struct Recipes: Decodable {
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?
private enum CodingKeys: String, CodingKey{
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"
}
}
var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]
@IBOutlet weak var tableView: UITableView!
fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"
guard let url = URL(string: jsonURL) else{return}
URLSession.shared.dataTask(with: url) {(data, _ , err) in
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")
let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell
}
override func viewDidLoad() {
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()
}
}
I am getting the error:
JSON text did not start with array or object and option to allow fragments not set." UserInfo={NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.})))
json swift
add a comment |
import UIKit
class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
//@IBOutlet weak var ingredientText: UILabel!
struct Recipes: Decodable {
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?
private enum CodingKeys: String, CodingKey{
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"
}
}
var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]
@IBOutlet weak var tableView: UITableView!
fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"
guard let url = URL(string: jsonURL) else{return}
URLSession.shared.dataTask(with: url) {(data, _ , err) in
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")
let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell
}
override func viewDidLoad() {
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()
}
}
I am getting the error:
JSON text did not start with array or object and option to allow fragments not set." UserInfo={NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.})))
json swift
Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 '18 at 6:05
Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 '18 at 6:20
add a comment |
import UIKit
class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
//@IBOutlet weak var ingredientText: UILabel!
struct Recipes: Decodable {
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?
private enum CodingKeys: String, CodingKey{
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"
}
}
var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]
@IBOutlet weak var tableView: UITableView!
fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"
guard let url = URL(string: jsonURL) else{return}
URLSession.shared.dataTask(with: url) {(data, _ , err) in
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")
let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell
}
override func viewDidLoad() {
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()
}
}
I am getting the error:
JSON text did not start with array or object and option to allow fragments not set." UserInfo={NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.})))
json swift
import UIKit
class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
//@IBOutlet weak var ingredientText: UILabel!
struct Recipes: Decodable {
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?
private enum CodingKeys: String, CodingKey{
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"
}
}
var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]
@IBOutlet weak var tableView: UITableView!
fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"
guard let url = URL(string: jsonURL) else{return}
URLSession.shared.dataTask(with: url) {(data, _ , err) in
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")
let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell
}
override func viewDidLoad() {
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()
}
}
I am getting the error:
JSON text did not start with array or object and option to allow fragments not set." UserInfo={NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.})))
json swift
json swift
edited Nov 13 '18 at 5:45
rmaddy
240k27315379
240k27315379
asked Nov 13 '18 at 5:30
Jonathan JordanJonathan Jordan
12
12
Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 '18 at 6:05
Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 '18 at 6:20
add a comment |
Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 '18 at 6:05
Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 '18 at 6:20
Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 '18 at 6:05
Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 '18 at 6:05
Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 '18 at 6:20
Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 '18 at 6:20
add a comment |
2 Answers
2
active
oldest
votes
JSONDecoder
doesn't provide any JSONSerialization.ReadingOptions
.
You could make a manual check whether the first byte of the data is an opening square bracket <5b>
or brace <7b>
guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}
However I'd recommend to use the response
parameter to check for status code 200
URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...
Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase
you are encouraged to name the struct members recipeId
, imageUrl
, sourceUrl
etc.
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 '18 at 6:17
If the root object is a dictionary you have to decodeRecipes.self
– vadian
Nov 13 '18 at 7:34
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 '18 at 7:51
In terms ofDecodable
every dictionary is a struct. So you need an extra struct for the root object.
– vadian
Nov 13 '18 at 7:54
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 '18 at 7:56
add a comment |
You want to decode [Recipe]
, that is, an Array
of Recipe
. That mean the first (non-whitespace) character in data
has to be [
(to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data
to a String
and printing it:
print(String(data: data, encoding: .utf8))
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 '18 at 6:43
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
JSONDecoder
doesn't provide any JSONSerialization.ReadingOptions
.
You could make a manual check whether the first byte of the data is an opening square bracket <5b>
or brace <7b>
guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}
However I'd recommend to use the response
parameter to check for status code 200
URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...
Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase
you are encouraged to name the struct members recipeId
, imageUrl
, sourceUrl
etc.
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 '18 at 6:17
If the root object is a dictionary you have to decodeRecipes.self
– vadian
Nov 13 '18 at 7:34
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 '18 at 7:51
In terms ofDecodable
every dictionary is a struct. So you need an extra struct for the root object.
– vadian
Nov 13 '18 at 7:54
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 '18 at 7:56
add a comment |
JSONDecoder
doesn't provide any JSONSerialization.ReadingOptions
.
You could make a manual check whether the first byte of the data is an opening square bracket <5b>
or brace <7b>
guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}
However I'd recommend to use the response
parameter to check for status code 200
URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...
Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase
you are encouraged to name the struct members recipeId
, imageUrl
, sourceUrl
etc.
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 '18 at 6:17
If the root object is a dictionary you have to decodeRecipes.self
– vadian
Nov 13 '18 at 7:34
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 '18 at 7:51
In terms ofDecodable
every dictionary is a struct. So you need an extra struct for the root object.
– vadian
Nov 13 '18 at 7:54
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 '18 at 7:56
add a comment |
JSONDecoder
doesn't provide any JSONSerialization.ReadingOptions
.
You could make a manual check whether the first byte of the data is an opening square bracket <5b>
or brace <7b>
guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}
However I'd recommend to use the response
parameter to check for status code 200
URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...
Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase
you are encouraged to name the struct members recipeId
, imageUrl
, sourceUrl
etc.
JSONDecoder
doesn't provide any JSONSerialization.ReadingOptions
.
You could make a manual check whether the first byte of the data is an opening square bracket <5b>
or brace <7b>
guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}
However I'd recommend to use the response
parameter to check for status code 200
URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...
Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase
you are encouraged to name the struct members recipeId
, imageUrl
, sourceUrl
etc.
edited Nov 13 '18 at 6:12
answered Nov 13 '18 at 5:59
vadianvadian
146k13157175
146k13157175
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 '18 at 6:17
If the root object is a dictionary you have to decodeRecipes.self
– vadian
Nov 13 '18 at 7:34
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 '18 at 7:51
In terms ofDecodable
every dictionary is a struct. So you need an extra struct for the root object.
– vadian
Nov 13 '18 at 7:54
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 '18 at 7:56
add a comment |
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 '18 at 6:17
If the root object is a dictionary you have to decodeRecipes.self
– vadian
Nov 13 '18 at 7:34
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 '18 at 7:51
In terms ofDecodable
every dictionary is a struct. So you need an extra struct for the root object.
– vadian
Nov 13 '18 at 7:54
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 '18 at 7:56
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 '18 at 6:17
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 '18 at 6:17
If the root object is a dictionary you have to decode
Recipes.self
– vadian
Nov 13 '18 at 7:34
If the root object is a dictionary you have to decode
Recipes.self
– vadian
Nov 13 '18 at 7:34
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 '18 at 7:51
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 '18 at 7:51
In terms of
Decodable
every dictionary is a struct. So you need an extra struct for the root object.– vadian
Nov 13 '18 at 7:54
In terms of
Decodable
every dictionary is a struct. So you need an extra struct for the root object.– vadian
Nov 13 '18 at 7:54
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 '18 at 7:56
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 '18 at 7:56
add a comment |
You want to decode [Recipe]
, that is, an Array
of Recipe
. That mean the first (non-whitespace) character in data
has to be [
(to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data
to a String
and printing it:
print(String(data: data, encoding: .utf8))
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 '18 at 6:43
add a comment |
You want to decode [Recipe]
, that is, an Array
of Recipe
. That mean the first (non-whitespace) character in data
has to be [
(to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data
to a String
and printing it:
print(String(data: data, encoding: .utf8))
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 '18 at 6:43
add a comment |
You want to decode [Recipe]
, that is, an Array
of Recipe
. That mean the first (non-whitespace) character in data
has to be [
(to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data
to a String
and printing it:
print(String(data: data, encoding: .utf8))
You want to decode [Recipe]
, that is, an Array
of Recipe
. That mean the first (non-whitespace) character in data
has to be [
(to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data
to a String
and printing it:
print(String(data: data, encoding: .utf8))
answered Nov 13 '18 at 6:04
rob mayoffrob mayoff
292k41591640
292k41591640
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 '18 at 6:43
add a comment |
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 '18 at 6:43
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 '18 at 6:43
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 '18 at 6:43
add a comment |
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Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 '18 at 6:05
Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 '18 at 6:20