Getting syntax errors when creating function
0
I have been spending over 2 hours now trying to google my way to the answer.
I am completely new to SQL and MySQL and I have tried to write the following function:
CREATE FUNCTION fp_spinofffactor (id char(8), startdate date)
RETURNS float
BEGIN
DECLARE spinoffFactor float; (ERROR- EXPECTED A ";")
select spinoffFactor = ISNULL(EXP(SUM(LOG(spinoffFactor))),1)
from(
select case when (prev_price- divs) <= 0 THEN 1
else (prev_price- divs)/prev_price end as spinoffFactor
from (select
divs,
fp_v2.fp_prevUnadjPrice(id, ex_date) as prev_price
from (
select sum(fbd.p_divs_pd) as divs,fbd.p_divs_exdate as ex_date
from fp_v2.fp_basic_dividends fbd
where fbd.fsym_id = id
and fbd.p_divs_s_pd=1
and fbd.p_divs_exdate > startdate
group by fbd.p_divs_exdate ) a ) b ) c;
return spinofffactor; ERROR (Return is not valid at this position)
END ERROR (END IS NOT VALID AT THIS position)
But I get multiple syntax errors. I have written the errors where I get them.
I have a hard time finding information about the syntax rules of MySQL and the workbench.
Can anyone help ?
mysql sql mysql-workbench
asked Nov 13 '18 at 12:01
ChrisChris
649
add a comment |
0
I have been spending over 2 hours now trying to google my way to the answer.
I am completely new to SQL and MySQL and I have tried to write the following function:
CREATE FUNCTION fp_spinofffactor (id char(8), startdate date)
RETURNS float
BEGIN
DECLARE spinoffFactor float; (ERROR- EXPECTED A ";")
select spinoffFactor = ISNULL(EXP(SUM(LOG(spinoffFactor))),1)
from(
select case when (prev_price- divs) <= 0 THEN 1
else (prev_price- divs)/prev_price end as spinoffFactor
from (select
divs,
fp_v2.fp_prevUnadjPrice(id, ex_date) as prev_price
from (
select sum(fbd.p_divs_pd) as divs,fbd.p_divs_exdate as ex_date
from fp_v2.fp_basic_dividends fbd
where fbd.fsym_id = id
and fbd.p_divs_s_pd=1
and fbd.p_divs_exdate > startdate
group by fbd.p_divs_exdate ) a ) b ) c;
return spinofffactor; ERROR (Return is not valid at this position)
END ERROR (END IS NOT VALID AT THIS position)
But I get multiple syntax errors. I have written the errors where I get them.
I have a hard time finding information about the syntax rules of MySQL and the workbench.
Can anyone help ?
mysql sql mysql-workbench
asked Nov 13 '18 at 12:01
ChrisChris
649
add a comment |
0
0
0
I have been spending over 2 hours now trying to google my way to the answer.
I am completely new to SQL and MySQL and I have tried to write the following function:
CREATE FUNCTION fp_spinofffactor (id char(8), startdate date)
RETURNS float
BEGIN
DECLARE spinoffFactor float; (ERROR- EXPECTED A ";")
select spinoffFactor = ISNULL(EXP(SUM(LOG(spinoffFactor))),1)
from(
select case when (prev_price- divs) <= 0 THEN 1
else (prev_price- divs)/prev_price end as spinoffFactor
from (select
divs,
fp_v2.fp_prevUnadjPrice(id, ex_date) as prev_price
from (
select sum(fbd.p_divs_pd) as divs,fbd.p_divs_exdate as ex_date
from fp_v2.fp_basic_dividends fbd
where fbd.fsym_id = id
and fbd.p_divs_s_pd=1
and fbd.p_divs_exdate > startdate
group by fbd.p_divs_exdate ) a ) b ) c;
return spinofffactor; ERROR (Return is not valid at this position)
END ERROR (END IS NOT VALID AT THIS position)
But I get multiple syntax errors. I have written the errors where I get them.
I have a hard time finding information about the syntax rules of MySQL and the workbench.
Can anyone help ?
mysql sql mysql-workbench
asked Nov 13 '18 at 12:01
ChrisChris
649
I have been spending over 2 hours now trying to google my way to the answer.
I am completely new to SQL and MySQL and I have tried to write the following function:
CREATE FUNCTION fp_spinofffactor (id char(8), startdate date)
RETURNS float
BEGIN
DECLARE spinoffFactor float; (ERROR- EXPECTED A ";")
select spinoffFactor = ISNULL(EXP(SUM(LOG(spinoffFactor))),1)
from(
select case when (prev_price- divs) <= 0 THEN 1
else (prev_price- divs)/prev_price end as spinoffFactor
from (select
divs,
fp_v2.fp_prevUnadjPrice(id, ex_date) as prev_price
from (
select sum(fbd.p_divs_pd) as divs,fbd.p_divs_exdate as ex_date
from fp_v2.fp_basic_dividends fbd
where fbd.fsym_id = id
and fbd.p_divs_s_pd=1
and fbd.p_divs_exdate > startdate
group by fbd.p_divs_exdate ) a ) b ) c;
return spinofffactor; ERROR (Return is not valid at this position)
END ERROR (END IS NOT VALID AT THIS position)
But I get multiple syntax errors. I have written the errors where I get them.
I have a hard time finding information about the syntax rules of MySQL and the workbench.
Can anyone help ?
mysql sql mysql-workbench
mysql sql mysql-workbench
asked Nov 13 '18 at 12:01
ChrisChris
649
asked Nov 13 '18 at 12:01
ChrisChris
649
edited Nov 13 '18 at 12:39
Chris
asked Nov 13 '18 at 12:01
ChrisChris
649
asked Nov 13 '18 at 12:01
ChrisChris
649
asked Nov 13 '18 at 12:01
ChrisChris
649
649
add a comment |
add a comment |
1 Answer
1
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oldest
votes
1
You need to provide delimiter in MySql workbench to tell where your code begins and ends.
Assuming your syntax is correct, you can write as below.
DELIMITER $$
CREATE FUNCTION fp_spinofffactor (id char(8), startdate date)
RETURNS float
BEGIN
DECLARE spinoffFactor float;
select spinoffFactor = ISNULL(EXP(SUM(LOG(spinoffFactor))),1)
from(
select case when (prev_price- divs) <= 0 THEN 1
else (prev_price- divs)/prev_price end as spinoffFactor
from (select
divs,
fp_v2.fp_prevUnadjPrice(id, ex_date) as prev_price
from (
select sum(fbd.p_divs_pd) as divs,fbd.p_divs_exdate as ex_date
from fp_v2.fp_basic_dividends fbd
where fbd.fsym_id = id
and fbd.p_divs_s_pd=1
and fbd.p_divs_exdate > startdate
group by fbd.p_divs_exdate ) a ) b ) c;
return spinofffactor;
END$$
DELIMITER ;
You can also, run this from MySQL command prompt and it should work.
answered Nov 13 '18 at 13:02
VikiTVikiT
436
Thanks man. Do you have 5 minutes for private chat? I have a few questions.
– Chris
Nov 13 '18 at 13:09
@Chris, glad it worked. I do not use chat and only try to help, when get time. If you have any specific questions, you can post again and someone will take a look. Have a good day.
– VikiT
Nov 13 '18 at 13:27
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
1
You need to provide delimiter in MySql workbench to tell where your code begins and ends.
Assuming your syntax is correct, you can write as below.
DELIMITER $$
CREATE FUNCTION fp_spinofffactor (id char(8), startdate date)
RETURNS float
BEGIN
DECLARE spinoffFactor float;
select spinoffFactor = ISNULL(EXP(SUM(LOG(spinoffFactor))),1)
from(
select case when (prev_price- divs) <= 0 THEN 1
else (prev_price- divs)/prev_price end as spinoffFactor
from (select
divs,
fp_v2.fp_prevUnadjPrice(id, ex_date) as prev_price
from (
select sum(fbd.p_divs_pd) as divs,fbd.p_divs_exdate as ex_date
from fp_v2.fp_basic_dividends fbd
where fbd.fsym_id = id
and fbd.p_divs_s_pd=1
and fbd.p_divs_exdate > startdate
group by fbd.p_divs_exdate ) a ) b ) c;
return spinofffactor;
END$$
DELIMITER ;
You can also, run this from MySQL command prompt and it should work.
answered Nov 13 '18 at 13:02
VikiTVikiT
436
Thanks man. Do you have 5 minutes for private chat? I have a few questions.
– Chris
Nov 13 '18 at 13:09
@Chris, glad it worked. I do not use chat and only try to help, when get time. If you have any specific questions, you can post again and someone will take a look. Have a good day.
– VikiT
Nov 13 '18 at 13:27
add a comment |
1
You need to provide delimiter in MySql workbench to tell where your code begins and ends.
Assuming your syntax is correct, you can write as below.
DELIMITER $$
CREATE FUNCTION fp_spinofffactor (id char(8), startdate date)
RETURNS float
BEGIN
DECLARE spinoffFactor float;
select spinoffFactor = ISNULL(EXP(SUM(LOG(spinoffFactor))),1)
from(
select case when (prev_price- divs) <= 0 THEN 1
else (prev_price- divs)/prev_price end as spinoffFactor
from (select
divs,
fp_v2.fp_prevUnadjPrice(id, ex_date) as prev_price
from (
select sum(fbd.p_divs_pd) as divs,fbd.p_divs_exdate as ex_date
from fp_v2.fp_basic_dividends fbd
where fbd.fsym_id = id
and fbd.p_divs_s_pd=1
and fbd.p_divs_exdate > startdate
group by fbd.p_divs_exdate ) a ) b ) c;
return spinofffactor;
END$$
DELIMITER ;
You can also, run this from MySQL command prompt and it should work.
answered Nov 13 '18 at 13:02
VikiTVikiT
436
Thanks man. Do you have 5 minutes for private chat? I have a few questions.
– Chris
Nov 13 '18 at 13:09
@Chris, glad it worked. I do not use chat and only try to help, when get time. If you have any specific questions, you can post again and someone will take a look. Have a good day.
– VikiT
Nov 13 '18 at 13:27
add a comment |
1
1
1
You need to provide delimiter in MySql workbench to tell where your code begins and ends.
Assuming your syntax is correct, you can write as below.
DELIMITER $$
CREATE FUNCTION fp_spinofffactor (id char(8), startdate date)
RETURNS float
BEGIN
DECLARE spinoffFactor float;
select spinoffFactor = ISNULL(EXP(SUM(LOG(spinoffFactor))),1)
from(
select case when (prev_price- divs) <= 0 THEN 1
else (prev_price- divs)/prev_price end as spinoffFactor
from (select
divs,
fp_v2.fp_prevUnadjPrice(id, ex_date) as prev_price
from (
select sum(fbd.p_divs_pd) as divs,fbd.p_divs_exdate as ex_date
from fp_v2.fp_basic_dividends fbd
where fbd.fsym_id = id
and fbd.p_divs_s_pd=1
and fbd.p_divs_exdate > startdate
group by fbd.p_divs_exdate ) a ) b ) c;
return spinofffactor;
END$$
DELIMITER ;
You can also, run this from MySQL command prompt and it should work.
answered Nov 13 '18 at 13:02
VikiTVikiT
436
You need to provide delimiter in MySql workbench to tell where your code begins and ends.
Assuming your syntax is correct, you can write as below.
DELIMITER $$
CREATE FUNCTION fp_spinofffactor (id char(8), startdate date)
RETURNS float
BEGIN
DECLARE spinoffFactor float;
select spinoffFactor = ISNULL(EXP(SUM(LOG(spinoffFactor))),1)
from(
select case when (prev_price- divs) <= 0 THEN 1
else (prev_price- divs)/prev_price end as spinoffFactor
from (select
divs,
fp_v2.fp_prevUnadjPrice(id, ex_date) as prev_price
from (
select sum(fbd.p_divs_pd) as divs,fbd.p_divs_exdate as ex_date
from fp_v2.fp_basic_dividends fbd
where fbd.fsym_id = id
and fbd.p_divs_s_pd=1
and fbd.p_divs_exdate > startdate
group by fbd.p_divs_exdate ) a ) b ) c;
return spinofffactor;
END$$
DELIMITER ;
You can also, run this from MySQL command prompt and it should work.
answered Nov 13 '18 at 13:02
VikiTVikiT
436
answered Nov 13 '18 at 13:02
VikiTVikiT
436
answered Nov 13 '18 at 13:02
VikiTVikiT
436
answered Nov 13 '18 at 13:02
VikiTVikiT
436
436
Thanks man. Do you have 5 minutes for private chat? I have a few questions.
– Chris
Nov 13 '18 at 13:09
@Chris, glad it worked. I do not use chat and only try to help, when get time. If you have any specific questions, you can post again and someone will take a look. Have a good day.
– VikiT
Nov 13 '18 at 13:27
add a comment |
Thanks man. Do you have 5 minutes for private chat? I have a few questions.
– Chris
Nov 13 '18 at 13:09
@Chris, glad it worked. I do not use chat and only try to help, when get time. If you have any specific questions, you can post again and someone will take a look. Have a good day.
– VikiT
Nov 13 '18 at 13:27
Thanks man. Do you have 5 minutes for private chat? I have a few questions.
– Chris
Nov 13 '18 at 13:09
Thanks man. Do you have 5 minutes for private chat? I have a few questions.
– Chris
Nov 13 '18 at 13:09
@Chris, glad it worked. I do not use chat and only try to help, when get time. If you have any specific questions, you can post again and someone will take a look. Have a good day.
– VikiT
Nov 13 '18 at 13:27
@Chris, glad it worked. I do not use chat and only try to help, when get time. If you have any specific questions, you can post again and someone will take a look. Have a good day.
– VikiT
Nov 13 '18 at 13:27
add a comment |
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