How to return mongodb query result with hapi js











up vote
0
down vote

favorite












I've been trying to build APIs with Hapi, started with something simple as returning all users from database:



{
method: 'GET',
path: '/users',
handler: (request, h) => {
var users;
collection.find({}).toArray((err, users) => {
console.log(res)
// I want to return the list of users here
// return users // this one does not work
// return h.response(users) // does not work either
});

return "" // or here
}
}


How can I make this work?










share|improve this question
























  • Are there any errors? Are you using the MongoDB node driver? Is the db connection successful and collection variable declared correctly (pointing to a valid collection)?
    – Bajal
    Nov 11 at 2:32












  • There's no error, the Console.log did show the expected result (an array of users) so I suppose the connection and query are good. Yes, I'm using MongoDB node drive const mongoClient = require('mongodb').MongoClient;
    – tab87vn
    Nov 11 at 13:27










  • Possible duplicate of cursor.toArray() returns a promise instead of array
    – Akrion
    Nov 11 at 22:21















up vote
0
down vote

favorite












I've been trying to build APIs with Hapi, started with something simple as returning all users from database:



{
method: 'GET',
path: '/users',
handler: (request, h) => {
var users;
collection.find({}).toArray((err, users) => {
console.log(res)
// I want to return the list of users here
// return users // this one does not work
// return h.response(users) // does not work either
});

return "" // or here
}
}


How can I make this work?










share|improve this question
























  • Are there any errors? Are you using the MongoDB node driver? Is the db connection successful and collection variable declared correctly (pointing to a valid collection)?
    – Bajal
    Nov 11 at 2:32












  • There's no error, the Console.log did show the expected result (an array of users) so I suppose the connection and query are good. Yes, I'm using MongoDB node drive const mongoClient = require('mongodb').MongoClient;
    – tab87vn
    Nov 11 at 13:27










  • Possible duplicate of cursor.toArray() returns a promise instead of array
    – Akrion
    Nov 11 at 22:21













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I've been trying to build APIs with Hapi, started with something simple as returning all users from database:



{
method: 'GET',
path: '/users',
handler: (request, h) => {
var users;
collection.find({}).toArray((err, users) => {
console.log(res)
// I want to return the list of users here
// return users // this one does not work
// return h.response(users) // does not work either
});

return "" // or here
}
}


How can I make this work?










share|improve this question















I've been trying to build APIs with Hapi, started with something simple as returning all users from database:



{
method: 'GET',
path: '/users',
handler: (request, h) => {
var users;
collection.find({}).toArray((err, users) => {
console.log(res)
// I want to return the list of users here
// return users // this one does not work
// return h.response(users) // does not work either
});

return "" // or here
}
}


How can I make this work?







node.js mongodb api hapijs






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 11 at 0:04









kmdreko

3,46011225




3,46011225










asked Nov 10 at 23:28









tab87vn

10411




10411












  • Are there any errors? Are you using the MongoDB node driver? Is the db connection successful and collection variable declared correctly (pointing to a valid collection)?
    – Bajal
    Nov 11 at 2:32












  • There's no error, the Console.log did show the expected result (an array of users) so I suppose the connection and query are good. Yes, I'm using MongoDB node drive const mongoClient = require('mongodb').MongoClient;
    – tab87vn
    Nov 11 at 13:27










  • Possible duplicate of cursor.toArray() returns a promise instead of array
    – Akrion
    Nov 11 at 22:21


















  • Are there any errors? Are you using the MongoDB node driver? Is the db connection successful and collection variable declared correctly (pointing to a valid collection)?
    – Bajal
    Nov 11 at 2:32












  • There's no error, the Console.log did show the expected result (an array of users) so I suppose the connection and query are good. Yes, I'm using MongoDB node drive const mongoClient = require('mongodb').MongoClient;
    – tab87vn
    Nov 11 at 13:27










  • Possible duplicate of cursor.toArray() returns a promise instead of array
    – Akrion
    Nov 11 at 22:21
















Are there any errors? Are you using the MongoDB node driver? Is the db connection successful and collection variable declared correctly (pointing to a valid collection)?
– Bajal
Nov 11 at 2:32






Are there any errors? Are you using the MongoDB node driver? Is the db connection successful and collection variable declared correctly (pointing to a valid collection)?
– Bajal
Nov 11 at 2:32














There's no error, the Console.log did show the expected result (an array of users) so I suppose the connection and query are good. Yes, I'm using MongoDB node drive const mongoClient = require('mongodb').MongoClient;
– tab87vn
Nov 11 at 13:27




There's no error, the Console.log did show the expected result (an array of users) so I suppose the connection and query are good. Yes, I'm using MongoDB node drive const mongoClient = require('mongodb').MongoClient;
– tab87vn
Nov 11 at 13:27












Possible duplicate of cursor.toArray() returns a promise instead of array
– Akrion
Nov 11 at 22:21




Possible duplicate of cursor.toArray() returns a promise instead of array
– Akrion
Nov 11 at 22:21












1 Answer
1






active

oldest

votes

















up vote
2
down vote



accepted










You could do :



server.route({
method: 'GET',
path: '/',
handler: (request, h) => {
return collection.find({}).toArray()
//return collection.findOne({}) // Or like this, to just return one result
}
});





share|improve this answer





















  • indeed, this works like a charm and it's simpler than I thought.
    – tab87vn
    Nov 12 at 11:16











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














 

draft saved


draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53244432%2fhow-to-return-mongodb-query-result-with-hapi-js%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote



accepted










You could do :



server.route({
method: 'GET',
path: '/',
handler: (request, h) => {
return collection.find({}).toArray()
//return collection.findOne({}) // Or like this, to just return one result
}
});





share|improve this answer





















  • indeed, this works like a charm and it's simpler than I thought.
    – tab87vn
    Nov 12 at 11:16















up vote
2
down vote



accepted










You could do :



server.route({
method: 'GET',
path: '/',
handler: (request, h) => {
return collection.find({}).toArray()
//return collection.findOne({}) // Or like this, to just return one result
}
});





share|improve this answer





















  • indeed, this works like a charm and it's simpler than I thought.
    – tab87vn
    Nov 12 at 11:16













up vote
2
down vote



accepted







up vote
2
down vote



accepted






You could do :



server.route({
method: 'GET',
path: '/',
handler: (request, h) => {
return collection.find({}).toArray()
//return collection.findOne({}) // Or like this, to just return one result
}
});





share|improve this answer












You could do :



server.route({
method: 'GET',
path: '/',
handler: (request, h) => {
return collection.find({}).toArray()
//return collection.findOne({}) // Or like this, to just return one result
}
});






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 11 at 22:56









Bajal

1,97611017




1,97611017












  • indeed, this works like a charm and it's simpler than I thought.
    – tab87vn
    Nov 12 at 11:16


















  • indeed, this works like a charm and it's simpler than I thought.
    – tab87vn
    Nov 12 at 11:16
















indeed, this works like a charm and it's simpler than I thought.
– tab87vn
Nov 12 at 11:16




indeed, this works like a charm and it's simpler than I thought.
– tab87vn
Nov 12 at 11:16


















 

draft saved


draft discarded



















































 


draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53244432%2fhow-to-return-mongodb-query-result-with-hapi-js%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Full-time equivalent

Bicuculline

さくらももこ