C print a generic type vector
up vote
2
down vote
favorite
Hi I'm trying to create a function that takes a void* pointer as parameter and print all element of the vector using printf
the declaration of the function is:
void print_vec(void *vec,int dime_se,int dime,char *format);
and implementation is:
void print_vec(void *vec,int dime_se,int dime,char *format){
for(int i=0;i<dime;i++)
printf(format,*(vec+dime_se*i));
}
the problem is that when i compile the compiler returns:
error: invalid use of void expression printf(format,*(vec+dime_se*i));
So the question there is a way to do this task without make this?
void print_vec(void *vec,int dime_se,int dime,char *format){
for(int i=0;i<dime;i++)
switch(format[1]){
case 'c':
printf(format,*((char*)(vec+dime_se*i)));
break;
case 'd':
printf(format,*((unsigned int*)(vec+dime_se*i)));
break;
case 's':
printf(format,*((char**)(vec+dime_se*i)));
break;
case 'i':
printf(format,*((int*)(vec+dime_se*i)));
break;
case 'f':
printf(format,*((float*)(vec+dime_se*i)));
break;
default:
break;
}
}
c vector printf
add a comment |
up vote
2
down vote
favorite
Hi I'm trying to create a function that takes a void* pointer as parameter and print all element of the vector using printf
the declaration of the function is:
void print_vec(void *vec,int dime_se,int dime,char *format);
and implementation is:
void print_vec(void *vec,int dime_se,int dime,char *format){
for(int i=0;i<dime;i++)
printf(format,*(vec+dime_se*i));
}
the problem is that when i compile the compiler returns:
error: invalid use of void expression printf(format,*(vec+dime_se*i));
So the question there is a way to do this task without make this?
void print_vec(void *vec,int dime_se,int dime,char *format){
for(int i=0;i<dime;i++)
switch(format[1]){
case 'c':
printf(format,*((char*)(vec+dime_se*i)));
break;
case 'd':
printf(format,*((unsigned int*)(vec+dime_se*i)));
break;
case 's':
printf(format,*((char**)(vec+dime_se*i)));
break;
case 'i':
printf(format,*((int*)(vec+dime_se*i)));
break;
case 'f':
printf(format,*((float*)(vec+dime_se*i)));
break;
default:
break;
}
}
c vector printf
1
no. C have not generic types. to callprintf
with valid arguments compiler need extra information about size of arguments. in your example you useint
,char
,float
andchar*
and they can have any size depends on your machine
– kerrytazi
yesterday
1
Pointer math onvoid*
is not portable.(unsigned int*)(vec+dime_se*i)
-->((unsigned int*)vec + i)
– chux
yesterday
1
Why use'd'
withunsigned
?'d'
goes withint
.'u'
goes withunsigned
.
– chux
yesterday
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
Hi I'm trying to create a function that takes a void* pointer as parameter and print all element of the vector using printf
the declaration of the function is:
void print_vec(void *vec,int dime_se,int dime,char *format);
and implementation is:
void print_vec(void *vec,int dime_se,int dime,char *format){
for(int i=0;i<dime;i++)
printf(format,*(vec+dime_se*i));
}
the problem is that when i compile the compiler returns:
error: invalid use of void expression printf(format,*(vec+dime_se*i));
So the question there is a way to do this task without make this?
void print_vec(void *vec,int dime_se,int dime,char *format){
for(int i=0;i<dime;i++)
switch(format[1]){
case 'c':
printf(format,*((char*)(vec+dime_se*i)));
break;
case 'd':
printf(format,*((unsigned int*)(vec+dime_se*i)));
break;
case 's':
printf(format,*((char**)(vec+dime_se*i)));
break;
case 'i':
printf(format,*((int*)(vec+dime_se*i)));
break;
case 'f':
printf(format,*((float*)(vec+dime_se*i)));
break;
default:
break;
}
}
c vector printf
Hi I'm trying to create a function that takes a void* pointer as parameter and print all element of the vector using printf
the declaration of the function is:
void print_vec(void *vec,int dime_se,int dime,char *format);
and implementation is:
void print_vec(void *vec,int dime_se,int dime,char *format){
for(int i=0;i<dime;i++)
printf(format,*(vec+dime_se*i));
}
the problem is that when i compile the compiler returns:
error: invalid use of void expression printf(format,*(vec+dime_se*i));
So the question there is a way to do this task without make this?
void print_vec(void *vec,int dime_se,int dime,char *format){
for(int i=0;i<dime;i++)
switch(format[1]){
case 'c':
printf(format,*((char*)(vec+dime_se*i)));
break;
case 'd':
printf(format,*((unsigned int*)(vec+dime_se*i)));
break;
case 's':
printf(format,*((char**)(vec+dime_se*i)));
break;
case 'i':
printf(format,*((int*)(vec+dime_se*i)));
break;
case 'f':
printf(format,*((float*)(vec+dime_se*i)));
break;
default:
break;
}
}
c vector printf
c vector printf
asked yesterday
P.Carlino
394114
394114
1
no. C have not generic types. to callprintf
with valid arguments compiler need extra information about size of arguments. in your example you useint
,char
,float
andchar*
and they can have any size depends on your machine
– kerrytazi
yesterday
1
Pointer math onvoid*
is not portable.(unsigned int*)(vec+dime_se*i)
-->((unsigned int*)vec + i)
– chux
yesterday
1
Why use'd'
withunsigned
?'d'
goes withint
.'u'
goes withunsigned
.
– chux
yesterday
add a comment |
1
no. C have not generic types. to callprintf
with valid arguments compiler need extra information about size of arguments. in your example you useint
,char
,float
andchar*
and they can have any size depends on your machine
– kerrytazi
yesterday
1
Pointer math onvoid*
is not portable.(unsigned int*)(vec+dime_se*i)
-->((unsigned int*)vec + i)
– chux
yesterday
1
Why use'd'
withunsigned
?'d'
goes withint
.'u'
goes withunsigned
.
– chux
yesterday
1
1
no. C have not generic types. to call
printf
with valid arguments compiler need extra information about size of arguments. in your example you use int
, char
, float
and char*
and they can have any size depends on your machine– kerrytazi
yesterday
no. C have not generic types. to call
printf
with valid arguments compiler need extra information about size of arguments. in your example you use int
, char
, float
and char*
and they can have any size depends on your machine– kerrytazi
yesterday
1
1
Pointer math on
void*
is not portable. (unsigned int*)(vec+dime_se*i)
--> ((unsigned int*)vec + i)
– chux
yesterday
Pointer math on
void*
is not portable. (unsigned int*)(vec+dime_se*i)
--> ((unsigned int*)vec + i)
– chux
yesterday
1
1
Why use
'd'
with unsigned
? 'd'
goes with int
. 'u'
goes with unsigned
.– chux
yesterday
Why use
'd'
with unsigned
? 'd'
goes with int
. 'u'
goes with unsigned
.– chux
yesterday
add a comment |
1 Answer
1
active
oldest
votes
up vote
4
down vote
accepted
You don't need the dime_se
param. The size is more or less implicit in the format character.
Also, if you cast to the right pointer type you can let C do the scaling instead of doing it
manually:
#include <stddef.h>
#include <stdio.h>
void print_vec(void const*vec,size_t dime,char const*format)
{
for(size_t i=0;i<dime;i++)
switch(format[1]){
#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i])
X('c',char);
X('d',unsigned);
X('s',char*);
X('i',int);
X('f',float);
break;default: return;
#undef X
}
}
I said more or less because type promotion kind of blurs the line. %f
could well mean you've got a double
instead of a float
.
If you want to use a dime_se
parameter to disambiguate that case, you can:
break;case 'f':
if(sizeof(double)==dime_se)
printf(format,((double*)vec)[i]);
else {
assert(sizeof(float)==dime_se);
printf(format,((float*)vec)[i]);
}
but I'm not sure if a print_vec
function like that is a good idea.
Note this answer will only work if your format string always start with a simple type like %d. If you want the function to do fancier printing like fixed number of decimals "%.02f", or print an entire message for each item in the vector, you would need a more complex parsing logic to rely on the format string for typing.
– Lev M.
yesterday
1
@chux Missed that. Thanks.
– PSkocik
yesterday
As coded, printing any'f'
returns right after printing (drop through) . Curious: why#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i])
and not#define X(Char,Tp) case Char: printf(format,((Tp*)vec)[i]); break
?
– chux
yesterday
@chux It's just how I write my switches if they contain mostly "breaking-cases". It doesn't matter with the macro, but in normal C code, if I see eachcase
preceded bybreak;
it'll make one that isn't stand out more easily than if thebreak
were at the end of what follows thecase
. It helps me quickly catch accidental fall-through. I think it's pretty neat that the C grammar allows me to symmetrically start even the firstcase
withbreak
even though thebreak
part is basically dead code there.
– PSkocik
yesterday
Hmmm, If you valuebreak
at the beginning, perhaps then#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i]); break
to avoid the earlier coding oops that caused a "accidental fall-through".
– chux
yesterday
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
accepted
You don't need the dime_se
param. The size is more or less implicit in the format character.
Also, if you cast to the right pointer type you can let C do the scaling instead of doing it
manually:
#include <stddef.h>
#include <stdio.h>
void print_vec(void const*vec,size_t dime,char const*format)
{
for(size_t i=0;i<dime;i++)
switch(format[1]){
#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i])
X('c',char);
X('d',unsigned);
X('s',char*);
X('i',int);
X('f',float);
break;default: return;
#undef X
}
}
I said more or less because type promotion kind of blurs the line. %f
could well mean you've got a double
instead of a float
.
If you want to use a dime_se
parameter to disambiguate that case, you can:
break;case 'f':
if(sizeof(double)==dime_se)
printf(format,((double*)vec)[i]);
else {
assert(sizeof(float)==dime_se);
printf(format,((float*)vec)[i]);
}
but I'm not sure if a print_vec
function like that is a good idea.
Note this answer will only work if your format string always start with a simple type like %d. If you want the function to do fancier printing like fixed number of decimals "%.02f", or print an entire message for each item in the vector, you would need a more complex parsing logic to rely on the format string for typing.
– Lev M.
yesterday
1
@chux Missed that. Thanks.
– PSkocik
yesterday
As coded, printing any'f'
returns right after printing (drop through) . Curious: why#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i])
and not#define X(Char,Tp) case Char: printf(format,((Tp*)vec)[i]); break
?
– chux
yesterday
@chux It's just how I write my switches if they contain mostly "breaking-cases". It doesn't matter with the macro, but in normal C code, if I see eachcase
preceded bybreak;
it'll make one that isn't stand out more easily than if thebreak
were at the end of what follows thecase
. It helps me quickly catch accidental fall-through. I think it's pretty neat that the C grammar allows me to symmetrically start even the firstcase
withbreak
even though thebreak
part is basically dead code there.
– PSkocik
yesterday
Hmmm, If you valuebreak
at the beginning, perhaps then#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i]); break
to avoid the earlier coding oops that caused a "accidental fall-through".
– chux
yesterday
add a comment |
up vote
4
down vote
accepted
You don't need the dime_se
param. The size is more or less implicit in the format character.
Also, if you cast to the right pointer type you can let C do the scaling instead of doing it
manually:
#include <stddef.h>
#include <stdio.h>
void print_vec(void const*vec,size_t dime,char const*format)
{
for(size_t i=0;i<dime;i++)
switch(format[1]){
#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i])
X('c',char);
X('d',unsigned);
X('s',char*);
X('i',int);
X('f',float);
break;default: return;
#undef X
}
}
I said more or less because type promotion kind of blurs the line. %f
could well mean you've got a double
instead of a float
.
If you want to use a dime_se
parameter to disambiguate that case, you can:
break;case 'f':
if(sizeof(double)==dime_se)
printf(format,((double*)vec)[i]);
else {
assert(sizeof(float)==dime_se);
printf(format,((float*)vec)[i]);
}
but I'm not sure if a print_vec
function like that is a good idea.
Note this answer will only work if your format string always start with a simple type like %d. If you want the function to do fancier printing like fixed number of decimals "%.02f", or print an entire message for each item in the vector, you would need a more complex parsing logic to rely on the format string for typing.
– Lev M.
yesterday
1
@chux Missed that. Thanks.
– PSkocik
yesterday
As coded, printing any'f'
returns right after printing (drop through) . Curious: why#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i])
and not#define X(Char,Tp) case Char: printf(format,((Tp*)vec)[i]); break
?
– chux
yesterday
@chux It's just how I write my switches if they contain mostly "breaking-cases". It doesn't matter with the macro, but in normal C code, if I see eachcase
preceded bybreak;
it'll make one that isn't stand out more easily than if thebreak
were at the end of what follows thecase
. It helps me quickly catch accidental fall-through. I think it's pretty neat that the C grammar allows me to symmetrically start even the firstcase
withbreak
even though thebreak
part is basically dead code there.
– PSkocik
yesterday
Hmmm, If you valuebreak
at the beginning, perhaps then#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i]); break
to avoid the earlier coding oops that caused a "accidental fall-through".
– chux
yesterday
add a comment |
up vote
4
down vote
accepted
up vote
4
down vote
accepted
You don't need the dime_se
param. The size is more or less implicit in the format character.
Also, if you cast to the right pointer type you can let C do the scaling instead of doing it
manually:
#include <stddef.h>
#include <stdio.h>
void print_vec(void const*vec,size_t dime,char const*format)
{
for(size_t i=0;i<dime;i++)
switch(format[1]){
#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i])
X('c',char);
X('d',unsigned);
X('s',char*);
X('i',int);
X('f',float);
break;default: return;
#undef X
}
}
I said more or less because type promotion kind of blurs the line. %f
could well mean you've got a double
instead of a float
.
If you want to use a dime_se
parameter to disambiguate that case, you can:
break;case 'f':
if(sizeof(double)==dime_se)
printf(format,((double*)vec)[i]);
else {
assert(sizeof(float)==dime_se);
printf(format,((float*)vec)[i]);
}
but I'm not sure if a print_vec
function like that is a good idea.
You don't need the dime_se
param. The size is more or less implicit in the format character.
Also, if you cast to the right pointer type you can let C do the scaling instead of doing it
manually:
#include <stddef.h>
#include <stdio.h>
void print_vec(void const*vec,size_t dime,char const*format)
{
for(size_t i=0;i<dime;i++)
switch(format[1]){
#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i])
X('c',char);
X('d',unsigned);
X('s',char*);
X('i',int);
X('f',float);
break;default: return;
#undef X
}
}
I said more or less because type promotion kind of blurs the line. %f
could well mean you've got a double
instead of a float
.
If you want to use a dime_se
parameter to disambiguate that case, you can:
break;case 'f':
if(sizeof(double)==dime_se)
printf(format,((double*)vec)[i]);
else {
assert(sizeof(float)==dime_se);
printf(format,((float*)vec)[i]);
}
but I'm not sure if a print_vec
function like that is a good idea.
edited yesterday
answered yesterday
PSkocik
30.1k54267
30.1k54267
Note this answer will only work if your format string always start with a simple type like %d. If you want the function to do fancier printing like fixed number of decimals "%.02f", or print an entire message for each item in the vector, you would need a more complex parsing logic to rely on the format string for typing.
– Lev M.
yesterday
1
@chux Missed that. Thanks.
– PSkocik
yesterday
As coded, printing any'f'
returns right after printing (drop through) . Curious: why#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i])
and not#define X(Char,Tp) case Char: printf(format,((Tp*)vec)[i]); break
?
– chux
yesterday
@chux It's just how I write my switches if they contain mostly "breaking-cases". It doesn't matter with the macro, but in normal C code, if I see eachcase
preceded bybreak;
it'll make one that isn't stand out more easily than if thebreak
were at the end of what follows thecase
. It helps me quickly catch accidental fall-through. I think it's pretty neat that the C grammar allows me to symmetrically start even the firstcase
withbreak
even though thebreak
part is basically dead code there.
– PSkocik
yesterday
Hmmm, If you valuebreak
at the beginning, perhaps then#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i]); break
to avoid the earlier coding oops that caused a "accidental fall-through".
– chux
yesterday
add a comment |
Note this answer will only work if your format string always start with a simple type like %d. If you want the function to do fancier printing like fixed number of decimals "%.02f", or print an entire message for each item in the vector, you would need a more complex parsing logic to rely on the format string for typing.
– Lev M.
yesterday
1
@chux Missed that. Thanks.
– PSkocik
yesterday
As coded, printing any'f'
returns right after printing (drop through) . Curious: why#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i])
and not#define X(Char,Tp) case Char: printf(format,((Tp*)vec)[i]); break
?
– chux
yesterday
@chux It's just how I write my switches if they contain mostly "breaking-cases". It doesn't matter with the macro, but in normal C code, if I see eachcase
preceded bybreak;
it'll make one that isn't stand out more easily than if thebreak
were at the end of what follows thecase
. It helps me quickly catch accidental fall-through. I think it's pretty neat that the C grammar allows me to symmetrically start even the firstcase
withbreak
even though thebreak
part is basically dead code there.
– PSkocik
yesterday
Hmmm, If you valuebreak
at the beginning, perhaps then#define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i]); break
to avoid the earlier coding oops that caused a "accidental fall-through".
– chux
yesterday
Note this answer will only work if your format string always start with a simple type like %d. If you want the function to do fancier printing like fixed number of decimals "%.02f", or print an entire message for each item in the vector, you would need a more complex parsing logic to rely on the format string for typing.
– Lev M.
yesterday
Note this answer will only work if your format string always start with a simple type like %d. If you want the function to do fancier printing like fixed number of decimals "%.02f", or print an entire message for each item in the vector, you would need a more complex parsing logic to rely on the format string for typing.
– Lev M.
yesterday
1
1
@chux Missed that. Thanks.
– PSkocik
yesterday
@chux Missed that. Thanks.
– PSkocik
yesterday
As coded, printing any
'f'
returns right after printing (drop through) . Curious: why #define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i])
and not #define X(Char,Tp) case Char: printf(format,((Tp*)vec)[i]); break
?– chux
yesterday
As coded, printing any
'f'
returns right after printing (drop through) . Curious: why #define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i])
and not #define X(Char,Tp) case Char: printf(format,((Tp*)vec)[i]); break
?– chux
yesterday
@chux It's just how I write my switches if they contain mostly "breaking-cases". It doesn't matter with the macro, but in normal C code, if I see each
case
preceded by break;
it'll make one that isn't stand out more easily than if the break
were at the end of what follows the case
. It helps me quickly catch accidental fall-through. I think it's pretty neat that the C grammar allows me to symmetrically start even the first case
with break
even though the break
part is basically dead code there.– PSkocik
yesterday
@chux It's just how I write my switches if they contain mostly "breaking-cases". It doesn't matter with the macro, but in normal C code, if I see each
case
preceded by break;
it'll make one that isn't stand out more easily than if the break
were at the end of what follows the case
. It helps me quickly catch accidental fall-through. I think it's pretty neat that the C grammar allows me to symmetrically start even the first case
with break
even though the break
part is basically dead code there.– PSkocik
yesterday
Hmmm, If you value
break
at the beginning, perhaps then #define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i]); break
to avoid the earlier coding oops that caused a "accidental fall-through".– chux
yesterday
Hmmm, If you value
break
at the beginning, perhaps then #define X(Char,Tp) break;case Char: printf(format,((Tp*)vec)[i]); break
to avoid the earlier coding oops that caused a "accidental fall-through".– chux
yesterday
add a comment |
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1
no. C have not generic types. to call
printf
with valid arguments compiler need extra information about size of arguments. in your example you useint
,char
,float
andchar*
and they can have any size depends on your machine– kerrytazi
yesterday
1
Pointer math on
void*
is not portable.(unsigned int*)(vec+dime_se*i)
-->((unsigned int*)vec + i)
– chux
yesterday
1
Why use
'd'
withunsigned
?'d'
goes withint
.'u'
goes withunsigned
.– chux
yesterday