Iterated Prisoner's Trilemma












18












$begingroup$


CHALLENGE STATUS: OPEN



Comment, open a PR, or otherwise yell at me if I'm missing your bot.





Prisoner's dilemma ... with three choices. Crazy, huh?



Here's our payoff matrix. Player A on the left, B on the top



A,B| C | N | D
---|---|---|---
C |3,3|4,1|0,5
N |1,4|2,2|3,2
D |5,0|2,3|1,1


The payoff matrix is engineered so that it's best for both players to always cooperate, but you can gain (usually) by choosing Neutral or Defection.



Here's some (competing) example bots.



# turns out if you don't actually have to implement __init__(). TIL!

class AllC:
def round(self, _): return "C"
class AllN:
def round(self, _): return "N"
class AllD:
def round(self, _): return "D"
class RandomBot:
def round(self, _): return random.choice(["C", "N", "D"])

# Actually using an identically-behaving "FastGrudger".
class Grudger:
def __init__(self):
self.history =
def round(self, last):
if(last):
self.history.append(last)
if(self.history.count("D") > 0):
return "D"
return "C"

class TitForTat:
def round(self, last):
if(last == "D"):
return "D"
return "C"


Your bot is a Python3 class. A new instance is created for every game, and round() is called each round, with your opponent's choice from last round (or None, if it's the first round)



There's a 50 rep bounty for the winner in like a month.



Specifics




  • Every bot plays every other bot (1v1), including itself, in [REDACTED] rounds.

  • Standard loopholes disallowed.

  • No messing with anything outside your class or other underhanded shenanigains.

  • You may submit up to five bots.

  • Yes, you can implement handshake.

  • Any response other than C, N, or D will be silently taken as N.

  • Each bot's points from every game they play will be totaled up and compared.


Controller



Check!



Other Languages



I'll throw together an API if anyone needs it.



Scores: 2018-11-27



27 bots, 729 games.

name | avg. score/round
----------------|-------------------
PatternFinder | 3.152
DirichletDice2 | 3.019
EvaluaterBot | 2.971
Ensemble | 2.800
DirichletDice | 2.763
Shifting | 2.737
FastGrudger | 2.632
Nash2 | 2.574
HistoricAverage | 2.552
LastOptimalBot | 2.532
Number6 | 2.531
HandshakeBot | 2.458
OldTitForTat | 2.411
WeightedAverage | 2.403
TitForTat | 2.328
AllD | 2.272
Tetragram | 2.256
Nash | 2.193
Jade | 2.186
Useless | 2.140
RandomBot | 2.018
CopyCat | 1.902
TatForTit | 1.891
NeverCOOP | 1.710
AllC | 1.565
AllN | 1.446
Kevin | 1.322









share|improve this question











$endgroup$








  • 1




    $begingroup$
    How are bots put against each other? I get from the Grudger that there are always two bots against/with each other and the enemy's last choice is passed to the bot. How many rounds are played? And for a game: Does only the result count (i.e. who won) or also the points?
    $endgroup$
    – Black Owl Kai
    Nov 12 '18 at 17:52








  • 1




    $begingroup$
    You would get more entries if you made this language-agnostic, or at least broader. You could have a wrapper python class that spawns a process and sends it text commands to get back text responses.
    $endgroup$
    – Sparr
    Nov 12 '18 at 17:54






  • 1




    $begingroup$
    Done. This was on the sandbox for like a month!
    $endgroup$
    – Blacksilver
    Nov 12 '18 at 17:56








  • 2




    $begingroup$
    If you wrap most of main.py in while len(botlist) > 1: with botlist.remove(lowest_scoring_bot) at the bottom of the loop, you get an elimination tournament with interesting results.
    $endgroup$
    – Sparr
    Nov 13 '18 at 7:39






  • 1




    $begingroup$
    Another version of this someday might pass the entire interaction history rather than just the last move. It doesn't change much although it simplifies user code slightly. But it would allow for extensions, such as noisy communication channels that clarify over time: "Really, a D, even though I've said C four times in a row? No, I didn't say D; what do you take me for? Oh, sorry, can we just forget that round?"
    $endgroup$
    – Scott Sauyet
    Nov 13 '18 at 13:31
















18












$begingroup$


CHALLENGE STATUS: OPEN



Comment, open a PR, or otherwise yell at me if I'm missing your bot.





Prisoner's dilemma ... with three choices. Crazy, huh?



Here's our payoff matrix. Player A on the left, B on the top



A,B| C | N | D
---|---|---|---
C |3,3|4,1|0,5
N |1,4|2,2|3,2
D |5,0|2,3|1,1


The payoff matrix is engineered so that it's best for both players to always cooperate, but you can gain (usually) by choosing Neutral or Defection.



Here's some (competing) example bots.



# turns out if you don't actually have to implement __init__(). TIL!

class AllC:
def round(self, _): return "C"
class AllN:
def round(self, _): return "N"
class AllD:
def round(self, _): return "D"
class RandomBot:
def round(self, _): return random.choice(["C", "N", "D"])

# Actually using an identically-behaving "FastGrudger".
class Grudger:
def __init__(self):
self.history =
def round(self, last):
if(last):
self.history.append(last)
if(self.history.count("D") > 0):
return "D"
return "C"

class TitForTat:
def round(self, last):
if(last == "D"):
return "D"
return "C"


Your bot is a Python3 class. A new instance is created for every game, and round() is called each round, with your opponent's choice from last round (or None, if it's the first round)



There's a 50 rep bounty for the winner in like a month.



Specifics




  • Every bot plays every other bot (1v1), including itself, in [REDACTED] rounds.

  • Standard loopholes disallowed.

  • No messing with anything outside your class or other underhanded shenanigains.

  • You may submit up to five bots.

  • Yes, you can implement handshake.

  • Any response other than C, N, or D will be silently taken as N.

  • Each bot's points from every game they play will be totaled up and compared.


Controller



Check!



Other Languages



I'll throw together an API if anyone needs it.



Scores: 2018-11-27



27 bots, 729 games.

name | avg. score/round
----------------|-------------------
PatternFinder | 3.152
DirichletDice2 | 3.019
EvaluaterBot | 2.971
Ensemble | 2.800
DirichletDice | 2.763
Shifting | 2.737
FastGrudger | 2.632
Nash2 | 2.574
HistoricAverage | 2.552
LastOptimalBot | 2.532
Number6 | 2.531
HandshakeBot | 2.458
OldTitForTat | 2.411
WeightedAverage | 2.403
TitForTat | 2.328
AllD | 2.272
Tetragram | 2.256
Nash | 2.193
Jade | 2.186
Useless | 2.140
RandomBot | 2.018
CopyCat | 1.902
TatForTit | 1.891
NeverCOOP | 1.710
AllC | 1.565
AllN | 1.446
Kevin | 1.322









share|improve this question











$endgroup$








  • 1




    $begingroup$
    How are bots put against each other? I get from the Grudger that there are always two bots against/with each other and the enemy's last choice is passed to the bot. How many rounds are played? And for a game: Does only the result count (i.e. who won) or also the points?
    $endgroup$
    – Black Owl Kai
    Nov 12 '18 at 17:52








  • 1




    $begingroup$
    You would get more entries if you made this language-agnostic, or at least broader. You could have a wrapper python class that spawns a process and sends it text commands to get back text responses.
    $endgroup$
    – Sparr
    Nov 12 '18 at 17:54






  • 1




    $begingroup$
    Done. This was on the sandbox for like a month!
    $endgroup$
    – Blacksilver
    Nov 12 '18 at 17:56








  • 2




    $begingroup$
    If you wrap most of main.py in while len(botlist) > 1: with botlist.remove(lowest_scoring_bot) at the bottom of the loop, you get an elimination tournament with interesting results.
    $endgroup$
    – Sparr
    Nov 13 '18 at 7:39






  • 1




    $begingroup$
    Another version of this someday might pass the entire interaction history rather than just the last move. It doesn't change much although it simplifies user code slightly. But it would allow for extensions, such as noisy communication channels that clarify over time: "Really, a D, even though I've said C four times in a row? No, I didn't say D; what do you take me for? Oh, sorry, can we just forget that round?"
    $endgroup$
    – Scott Sauyet
    Nov 13 '18 at 13:31














18












18








18


5



$begingroup$


CHALLENGE STATUS: OPEN



Comment, open a PR, or otherwise yell at me if I'm missing your bot.





Prisoner's dilemma ... with three choices. Crazy, huh?



Here's our payoff matrix. Player A on the left, B on the top



A,B| C | N | D
---|---|---|---
C |3,3|4,1|0,5
N |1,4|2,2|3,2
D |5,0|2,3|1,1


The payoff matrix is engineered so that it's best for both players to always cooperate, but you can gain (usually) by choosing Neutral or Defection.



Here's some (competing) example bots.



# turns out if you don't actually have to implement __init__(). TIL!

class AllC:
def round(self, _): return "C"
class AllN:
def round(self, _): return "N"
class AllD:
def round(self, _): return "D"
class RandomBot:
def round(self, _): return random.choice(["C", "N", "D"])

# Actually using an identically-behaving "FastGrudger".
class Grudger:
def __init__(self):
self.history =
def round(self, last):
if(last):
self.history.append(last)
if(self.history.count("D") > 0):
return "D"
return "C"

class TitForTat:
def round(self, last):
if(last == "D"):
return "D"
return "C"


Your bot is a Python3 class. A new instance is created for every game, and round() is called each round, with your opponent's choice from last round (or None, if it's the first round)



There's a 50 rep bounty for the winner in like a month.



Specifics




  • Every bot plays every other bot (1v1), including itself, in [REDACTED] rounds.

  • Standard loopholes disallowed.

  • No messing with anything outside your class or other underhanded shenanigains.

  • You may submit up to five bots.

  • Yes, you can implement handshake.

  • Any response other than C, N, or D will be silently taken as N.

  • Each bot's points from every game they play will be totaled up and compared.


Controller



Check!



Other Languages



I'll throw together an API if anyone needs it.



Scores: 2018-11-27



27 bots, 729 games.

name | avg. score/round
----------------|-------------------
PatternFinder | 3.152
DirichletDice2 | 3.019
EvaluaterBot | 2.971
Ensemble | 2.800
DirichletDice | 2.763
Shifting | 2.737
FastGrudger | 2.632
Nash2 | 2.574
HistoricAverage | 2.552
LastOptimalBot | 2.532
Number6 | 2.531
HandshakeBot | 2.458
OldTitForTat | 2.411
WeightedAverage | 2.403
TitForTat | 2.328
AllD | 2.272
Tetragram | 2.256
Nash | 2.193
Jade | 2.186
Useless | 2.140
RandomBot | 2.018
CopyCat | 1.902
TatForTit | 1.891
NeverCOOP | 1.710
AllC | 1.565
AllN | 1.446
Kevin | 1.322









share|improve this question











$endgroup$




CHALLENGE STATUS: OPEN



Comment, open a PR, or otherwise yell at me if I'm missing your bot.





Prisoner's dilemma ... with three choices. Crazy, huh?



Here's our payoff matrix. Player A on the left, B on the top



A,B| C | N | D
---|---|---|---
C |3,3|4,1|0,5
N |1,4|2,2|3,2
D |5,0|2,3|1,1


The payoff matrix is engineered so that it's best for both players to always cooperate, but you can gain (usually) by choosing Neutral or Defection.



Here's some (competing) example bots.



# turns out if you don't actually have to implement __init__(). TIL!

class AllC:
def round(self, _): return "C"
class AllN:
def round(self, _): return "N"
class AllD:
def round(self, _): return "D"
class RandomBot:
def round(self, _): return random.choice(["C", "N", "D"])

# Actually using an identically-behaving "FastGrudger".
class Grudger:
def __init__(self):
self.history =
def round(self, last):
if(last):
self.history.append(last)
if(self.history.count("D") > 0):
return "D"
return "C"

class TitForTat:
def round(self, last):
if(last == "D"):
return "D"
return "C"


Your bot is a Python3 class. A new instance is created for every game, and round() is called each round, with your opponent's choice from last round (or None, if it's the first round)



There's a 50 rep bounty for the winner in like a month.



Specifics




  • Every bot plays every other bot (1v1), including itself, in [REDACTED] rounds.

  • Standard loopholes disallowed.

  • No messing with anything outside your class or other underhanded shenanigains.

  • You may submit up to five bots.

  • Yes, you can implement handshake.

  • Any response other than C, N, or D will be silently taken as N.

  • Each bot's points from every game they play will be totaled up and compared.


Controller



Check!



Other Languages



I'll throw together an API if anyone needs it.



Scores: 2018-11-27



27 bots, 729 games.

name | avg. score/round
----------------|-------------------
PatternFinder | 3.152
DirichletDice2 | 3.019
EvaluaterBot | 2.971
Ensemble | 2.800
DirichletDice | 2.763
Shifting | 2.737
FastGrudger | 2.632
Nash2 | 2.574
HistoricAverage | 2.552
LastOptimalBot | 2.532
Number6 | 2.531
HandshakeBot | 2.458
OldTitForTat | 2.411
WeightedAverage | 2.403
TitForTat | 2.328
AllD | 2.272
Tetragram | 2.256
Nash | 2.193
Jade | 2.186
Useless | 2.140
RandomBot | 2.018
CopyCat | 1.902
TatForTit | 1.891
NeverCOOP | 1.710
AllC | 1.565
AllN | 1.446
Kevin | 1.322






king-of-the-hill python






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 27 '18 at 16:25







Blacksilver

















asked Nov 12 '18 at 17:43









BlacksilverBlacksilver

435314




435314








  • 1




    $begingroup$
    How are bots put against each other? I get from the Grudger that there are always two bots against/with each other and the enemy's last choice is passed to the bot. How many rounds are played? And for a game: Does only the result count (i.e. who won) or also the points?
    $endgroup$
    – Black Owl Kai
    Nov 12 '18 at 17:52








  • 1




    $begingroup$
    You would get more entries if you made this language-agnostic, or at least broader. You could have a wrapper python class that spawns a process and sends it text commands to get back text responses.
    $endgroup$
    – Sparr
    Nov 12 '18 at 17:54






  • 1




    $begingroup$
    Done. This was on the sandbox for like a month!
    $endgroup$
    – Blacksilver
    Nov 12 '18 at 17:56








  • 2




    $begingroup$
    If you wrap most of main.py in while len(botlist) > 1: with botlist.remove(lowest_scoring_bot) at the bottom of the loop, you get an elimination tournament with interesting results.
    $endgroup$
    – Sparr
    Nov 13 '18 at 7:39






  • 1




    $begingroup$
    Another version of this someday might pass the entire interaction history rather than just the last move. It doesn't change much although it simplifies user code slightly. But it would allow for extensions, such as noisy communication channels that clarify over time: "Really, a D, even though I've said C four times in a row? No, I didn't say D; what do you take me for? Oh, sorry, can we just forget that round?"
    $endgroup$
    – Scott Sauyet
    Nov 13 '18 at 13:31














  • 1




    $begingroup$
    How are bots put against each other? I get from the Grudger that there are always two bots against/with each other and the enemy's last choice is passed to the bot. How many rounds are played? And for a game: Does only the result count (i.e. who won) or also the points?
    $endgroup$
    – Black Owl Kai
    Nov 12 '18 at 17:52








  • 1




    $begingroup$
    You would get more entries if you made this language-agnostic, or at least broader. You could have a wrapper python class that spawns a process and sends it text commands to get back text responses.
    $endgroup$
    – Sparr
    Nov 12 '18 at 17:54






  • 1




    $begingroup$
    Done. This was on the sandbox for like a month!
    $endgroup$
    – Blacksilver
    Nov 12 '18 at 17:56








  • 2




    $begingroup$
    If you wrap most of main.py in while len(botlist) > 1: with botlist.remove(lowest_scoring_bot) at the bottom of the loop, you get an elimination tournament with interesting results.
    $endgroup$
    – Sparr
    Nov 13 '18 at 7:39






  • 1




    $begingroup$
    Another version of this someday might pass the entire interaction history rather than just the last move. It doesn't change much although it simplifies user code slightly. But it would allow for extensions, such as noisy communication channels that clarify over time: "Really, a D, even though I've said C four times in a row? No, I didn't say D; what do you take me for? Oh, sorry, can we just forget that round?"
    $endgroup$
    – Scott Sauyet
    Nov 13 '18 at 13:31








1




1




$begingroup$
How are bots put against each other? I get from the Grudger that there are always two bots against/with each other and the enemy's last choice is passed to the bot. How many rounds are played? And for a game: Does only the result count (i.e. who won) or also the points?
$endgroup$
– Black Owl Kai
Nov 12 '18 at 17:52






$begingroup$
How are bots put against each other? I get from the Grudger that there are always two bots against/with each other and the enemy's last choice is passed to the bot. How many rounds are played? And for a game: Does only the result count (i.e. who won) or also the points?
$endgroup$
– Black Owl Kai
Nov 12 '18 at 17:52






1




1




$begingroup$
You would get more entries if you made this language-agnostic, or at least broader. You could have a wrapper python class that spawns a process and sends it text commands to get back text responses.
$endgroup$
– Sparr
Nov 12 '18 at 17:54




$begingroup$
You would get more entries if you made this language-agnostic, or at least broader. You could have a wrapper python class that spawns a process and sends it text commands to get back text responses.
$endgroup$
– Sparr
Nov 12 '18 at 17:54




1




1




$begingroup$
Done. This was on the sandbox for like a month!
$endgroup$
– Blacksilver
Nov 12 '18 at 17:56






$begingroup$
Done. This was on the sandbox for like a month!
$endgroup$
– Blacksilver
Nov 12 '18 at 17:56






2




2




$begingroup$
If you wrap most of main.py in while len(botlist) > 1: with botlist.remove(lowest_scoring_bot) at the bottom of the loop, you get an elimination tournament with interesting results.
$endgroup$
– Sparr
Nov 13 '18 at 7:39




$begingroup$
If you wrap most of main.py in while len(botlist) > 1: with botlist.remove(lowest_scoring_bot) at the bottom of the loop, you get an elimination tournament with interesting results.
$endgroup$
– Sparr
Nov 13 '18 at 7:39




1




1




$begingroup$
Another version of this someday might pass the entire interaction history rather than just the last move. It doesn't change much although it simplifies user code slightly. But it would allow for extensions, such as noisy communication channels that clarify over time: "Really, a D, even though I've said C four times in a row? No, I didn't say D; what do you take me for? Oh, sorry, can we just forget that round?"
$endgroup$
– Scott Sauyet
Nov 13 '18 at 13:31




$begingroup$
Another version of this someday might pass the entire interaction history rather than just the last move. It doesn't change much although it simplifies user code slightly. But it would allow for extensions, such as noisy communication channels that clarify over time: "Really, a D, even though I've said C four times in a row? No, I didn't say D; what do you take me for? Oh, sorry, can we just forget that round?"
$endgroup$
– Scott Sauyet
Nov 13 '18 at 13:31










19 Answers
19






active

oldest

votes


















9












$begingroup$

EvaluaterBot





class EvaluaterBot:
def __init__(self):
self.c2i = {"C":0, "N":1, "D":2}
self.i2c = {0:"C", 1:"N", 2:"D"}
self.history = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
self.last = [None, None]

def round(self, last):
if self.last[0] == None:
ret = 2
else:
# Input the latest enemy action (the reaction to my action 2 rounds ago)
# into the history
self.history[self.last[0]][self.c2i[last]] += 1
# The enemy will react to the last action I did
prediction,_ = max(enumerate(self.history[self.last[1]]), key=lambda l:l[1])
ret = (prediction - 1) % 3
self.last = [self.last[1], ret]
return self.i2c[ret]


Wins against all previously submitted bots except (maybe) the random bot (but it could have an advantage, because it picks D in a draw and D should optimal) and plays a constant draw against themself.






share|improve this answer











$endgroup$













  • $begingroup$
    Yep, beats everything.
    $endgroup$
    – Blacksilver
    Nov 12 '18 at 19:43










  • $begingroup$
    Scratch that, PatternFinder beats it by a bit.
    $endgroup$
    – Blacksilver
    Nov 13 '18 at 14:25



















7












$begingroup$

TatForTit



class TatForTit:
def round(self, last):
if(last == "C"):
return "N"
return "D"


This bot will alternate picking D N D N while TitForTat alternates C D C D, for an average net gain of 3 points per round if I have read the payout matrix correctly. I think this might be optimal against TitForTat. Obviously it could be improved to detect a non-TFT opponent and adopt other strategies, but I was just aiming for the original bounty.






share|improve this answer











$endgroup$





















    6












    $begingroup$

    NashEquilibrium



    This bot has taken a game theory class in college but was lazy and didn't go to the class where they covered iterated games. So he only plays single game mixed nash equilibrium. Turns out 1/5 2/5 2/5 is the mixed NE for the payoffs.



    class NashEquilibrium:
    def round(self, _):
    a = random.random()
    if a <= 0.2:
    return "C"
    elif a <= 0.6:
    return "N"
    else:
    return "D"


    Constant Abusing Nash Equilibrium



    This bot picked up a lesson or two from his lazy brother. His lazy brother's problem was that he didn't take advantage of fixed strategies. This version checks if the opponent is a constant player or titfortat and plays accordingly, else it plays the regular nash equilibrium.



    It's only downside is that it averages 2.2 points per turn playing against itself.



    class NashEquilibrium2:

    def __init__(self):
    self.opphistory = [None, None, None]
    self.titfortatcounter = 0
    self.titfortatflag = 0
    self.mylast = "C"
    self.constantflag = 0
    self.myret = "C"

    def round(self, last):
    self.opphistory.pop(0)
    self.opphistory.append(last)

    # check if its a constant bot, if so exploit
    if self.opphistory.count(self.opphistory[0]) == 3:
    self.constantflag = 1
    if last == "C":
    self.myret = "D"
    elif last == "N":
    self.myret = "C"
    elif last == "D":
    self.myret = "N"

    # check if its a titfortat bot, if so exploit
    # give it 2 chances to see if its titfortat as it might happen randomly
    if self.mylast == "D" and last == "D":
    self.titfortatcounter = self.titfortatcounter + 1

    if self.mylast == "D" and last!= "D":
    self.titfortatcounter = 0

    if self.titfortatcounter >= 3:
    self.titfortatflag = 1

    if self.titfortatflag == 1:
    if last == "C":
    self.myret = "D"
    elif last == "D":
    self.myret = "N"
    elif last == "N":
    # tit for tat doesn't return N, we made a mistake somewhere
    self.titfortatflag = 0
    self.titfortatcounter = 0

    # else play the single game nash equilibrium
    if self.constantflag == 0 and self.titfortatflag == 0:
    a = random.random()
    if a <= 0.2:
    self.myret = "C"
    elif a <= 0.6:
    self.myret = "N"
    else:
    self.myret = "D"


    self.mylast = self.myret
    return self.myret





    share|improve this answer











    $endgroup$









    • 1




      $begingroup$
      NashEquilibrium.round needs to take arguments even if it doesn't use them, so as to fit the expected function prototype.
      $endgroup$
      – Ray
      Nov 13 '18 at 3:18












    • $begingroup$
      Thank you fixed it
      $endgroup$
      – Ofya
      Nov 13 '18 at 3:45










    • $begingroup$
      Little shorter: class NashEquilibrium: def round(self, _): a = random.random() for k, v in [(0.2, "C"), (0.6, "N"), (1, "D")]: if a <= k: return v
      $endgroup$
      – Robert Grant
      Nov 14 '18 at 1:01



















    5












    $begingroup$

    Jade



    class Jade:
    def __init__(self):
    self.dRate = 0.001
    self.nRate = 0.003

    def round(self, last):
    if last == 'D':
    self.dRate *= 1.1
    self.nRate *= 1.2
    elif last == 'N':
    self.dRate *= 1.03
    self.nRate *= 1.05
    self.dRate = min(self.dRate, 1)
    self.nRate = min(self.nRate, 1)

    x = random.random()
    if x > (1 - self.dRate):
    return 'D'
    elif x > (1 - self.nRate):
    return 'N'
    else:
    return 'C'


    Starts out optimistic, but gets progressively more bitter as the opponent refuses to cooperate. Lots of magic constants that could probably be tweaked, but this probably isn't going to do well enough to justify the time.






    share|improve this answer









    $endgroup$





















      5












      $begingroup$

      PatternFinder



      class PatternFinder:
      def __init__(self):
      import collections
      self.size = 10
      self.moves = [None]
      self.other =
      self.patterns = collections.defaultdict(list)
      self.counter_moves = {"C":"D", "N":"C", "D":"N"}
      self.initial_move = "D"
      self.pattern_length_exponent = 1
      self.pattern_age_exponent = 1
      self.debug = False
      def round(self, last):
      self.other.append(last)
      best_pattern_match = None
      best_pattern_score = None
      best_pattern_response = None
      self.debug and print("match so far:",tuple(zip(self.moves,self.other)))
      for turn in range(max(0,len(self.moves)-self.size),len(self.moves)):
      # record patterns ending with the move that just happened
      pattern_full = tuple(zip(self.moves[turn:],self.other[turn:]))
      if len(pattern_full) > 1:
      pattern_trunc = pattern_full[:-1]
      pattern_trunc_result = pattern_full[-1][1]
      self.patterns[pattern_trunc].append([pattern_trunc_result,len(self.moves)-1])
      if pattern_full in self.patterns:
      # we've seen this pattern at least once before
      self.debug and print("I've seen",pattern_full,"before:",self.patterns[pattern_full])
      for [response,turn_num] in self.patterns[pattern_full]:
      score = len(pattern_full) ** self.pattern_length_exponent / (len(self.moves) - turn_num) ** self.pattern_age_exponent
      if best_pattern_score == None or score > best_pattern_score:
      best_pattern_match = pattern_full
      best_pattern_score = score
      best_pattern_response = response
      # this could be much smarter about aggregating previous responses
      if best_pattern_response:
      move = self.counter_moves[best_pattern_response]
      else:
      # fall back to playing nice
      move = "C"
      self.moves.append(move)
      self.debug and print("I choose",move)
      return move


      This bot looks for previous occurrences of the recent game state to see how the opponent responded to those occurrences, with a preference for longer pattern matches and more recent matches, then plays the move that will "beat" the opponent's predicted move. There's a lot of room for it to be smarter with all the data it keeps track of, but I ran out of time to work on it.






      share|improve this answer











      $endgroup$













      • $begingroup$
        When you get the time, mind giving her an optimization pass? It's easily the largest time-sink.
        $endgroup$
        – Blacksilver
        Nov 13 '18 at 3:46






      • 2




        $begingroup$
        @Blacksilver I just reduced the maximum pattern length from 100 to 10. It should run almost instantly now if you're running <200 rounds
        $endgroup$
        – Sparr
        Nov 13 '18 at 5:55








      • 1




        $begingroup$
        Maybe using a highly composite number (i.e., 12) would score better?
        $endgroup$
        – Blacksilver
        Nov 13 '18 at 16:09



















      4












      $begingroup$

      OldTitForTat



      Old school player is too lazy to update for the new rules.



      class OldTitForTat:
      def round(self, last):
      if(last == None)
      return "C"
      if(last == "C"):
      return "C"
      return "D"





      share|improve this answer









      $endgroup$





















        3












        $begingroup$

        NeverCOOP





        class NeverCOOP:
        def round(self, last):
        try:
        if last in "ND":
        return "D"
        else:
        return "N"
        except:
        return "N"


        If the opposing bot defects or is neutral, choose defect. Otherwise if this is the first turn or the opposing bot cooperates, choose neutral. I'm not sure how good this will work...






        share|improve this answer









        $endgroup$













        • $begingroup$
          What's the try/except for?
          $endgroup$
          – Blacksilver
          Nov 12 '18 at 19:09






        • 1




          $begingroup$
          @Blacksilver I'd assume it serves the same purpose as the if(last): in your Grudger bot, detecting whether there was a previous round.
          $endgroup$
          – ETHproductions
          Nov 12 '18 at 19:31










        • $begingroup$
          ahh, I see. None in "ND" errors.
          $endgroup$
          – Blacksilver
          Nov 12 '18 at 19:38










        • $begingroup$
          Because if last and last in "ND": was too complicated?
          $endgroup$
          – immibis
          Nov 12 '18 at 21:29



















        3












        $begingroup$

        LastOptimalBot



        class LastOptimalBot:
        def round(self, last):
        return "N" if last == "D" else ("D" if last == "C" else "C")


        Assumes that the opposing bot will always play the same move again, and chooses the one that has the best payoff against it.



        Averages:



        Me   Opp
        2.6 2 vs TitForTat
        5 0 vs AllC
        4 1 vs AllN
        3 2 vs AllD
        3.5 3.5 vs Random
        3 2 vs Grudger
        2 2 vs LastOptimalBot
        1 3.5 vs TatForTit
        4 1 vs NeverCOOP
        1 4 vs EvaluaterBot
        2.28 2.24 vs NashEquilibrium

        2.91 average overall





        share|improve this answer











        $endgroup$













        • $begingroup$
          oof. Maybe T4T would do better as return last.
          $endgroup$
          – Blacksilver
          Nov 12 '18 at 18:11










        • $begingroup$
          I'd like that! If TitForTat were return last, LOB would go 18-9 over 6 rounds rather than the 13-10 over 5 rounds it's currently getting. I think it's fine as is - don't worry about optimizing the example bots.
          $endgroup$
          – Spitemaster
          Nov 12 '18 at 18:30










        • $begingroup$
          return last would be a better T4T for this challenge, I think
          $endgroup$
          – Sparr
          Nov 12 '18 at 18:43










        • $begingroup$
          Just tried -- the if(last): return last; else: return "C" is worse.
          $endgroup$
          – Blacksilver
          Nov 12 '18 at 18:59










        • $begingroup$
          Right, but as @Sparr was saying, it might be more appropriate. Up to you, I suppose.
          $endgroup$
          – Spitemaster
          Nov 12 '18 at 19:00



















        3












        $begingroup$

        CopyCat



        class CopyCat:
        def round(self, last):
        if last:
        return last
        return "C"


        Copies the opponent's last move.

        I don't expect this to do well, but no one had implemented this classic yet.






        share|improve this answer











        $endgroup$





















          3












          $begingroup$

          Ensemble



          This runs an ensemble of related models. The individual models consider different amounts of history, and have the option of either always choosing the move that will optimize the expected payout difference, or will randomly select a move in proportion to expected payout difference.



          Each member of the ensemble then votes on their preferred move. They get a number of votes equal to how much more they've won than the opponent (which means that terrible models will get negative votes). Whichever move wins the vote is then selected.



          (They should probably split their votes among the moves in proportion to how much they favor each, but I don't care enough to do that right now.)



          It beats everything posted so far except EvaluaterBot and PatternFinder. (One-on-one, it beats EvaluaterBot and loses to PatternFinder).



          from collections import defaultdict
          import random
          class Number6:
          class Choices:
          def __init__(self, C = 0, N = 0, D = 0):
          self.C = C
          self.N = N
          self.D = D

          def __init__(self, strategy = "maxExpected", markov_order = 3):
          self.MARKOV_ORDER = markov_order;
          self.my_choices = ""
          self.opponent = defaultdict(lambda: self.Choices())
          self.choice = None # previous choice
          self.payoff = {
          "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
          "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
          "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
          }
          self.total_payoff = 0

          # if random, will choose in proportion to payoff.
          # otherwise, will always choose argmax
          self.strategy = strategy
          # maxExpected: maximize expected relative payoff
          # random: like maxExpected, but it chooses in proportion to E[payoff]
          # argmax: always choose the option that is optimal for expected opponent choice

          def update_opponent_model(self, last):
          for i in range(0, self.MARKOV_ORDER):
          hist = self.my_choices[i:]
          self.opponent[hist].C += ("C" == last)
          self.opponent[hist].N += ("N" == last)
          self.opponent[hist].D += ("D" == last)

          def normalize(self, counts):
          sum = float(counts.C + counts.N + counts.D)
          if 0 == sum:
          return self.Choices(1.0 / 3.0, 1.0 / 3.0, 1.0 / 3.0)
          return self.Choices(
          counts.C / sum, counts.N / sum, counts.D / sum)

          def get_distribution(self):
          for i in range(0, self.MARKOV_ORDER):
          hist = self.my_choices[i:]
          #print "check hist = " + hist
          if hist in self.opponent:
          return self.normalize(self.opponent[hist])

          return self.Choices(1.0 / 3.0, 1.0 / 3.0, 1.0 / 3.0)

          def choose(self, dist):
          payoff = self.Choices()
          # We're interested in *beating the opponent*, not
          # maximizing our score, so we optimize the difference
          payoff.C = (3-3) * dist.C + (4-1) * dist.N + (0-5) * dist.D
          payoff.N = (1-4) * dist.C + (2-2) * dist.N + (3-2) * dist.D
          payoff.D = (5-0) * dist.C + (2-3) * dist.N + (1-1) * dist.D

          # D has slightly better payoff on uniform opponent,
          # so we select it on ties
          if self.strategy == "maxExpected":
          if payoff.C > payoff.N:
          return "C" if payoff.C > payoff.D else "D"
          return "N" if payoff.N > payoff.D else "D"
          elif self.strategy == "randomize":
          payoff = self.normalize(payoff)
          r = random.uniform(0.0, 1.0)
          if (r < payoff.C): return "C"
          return "N" if (r < payoff.N) else "D"
          elif self.strategy == "argMax":
          if dist.C > dist.N:
          return "D" if dist.C > dist.D else "N"
          return "C" if dist.N > dist.D else "N"

          assert(0) #, "I am not a number! I am a free man!")

          def update_history(self):
          self.my_choices += self.choice
          if len(self.my_choices) > self.MARKOV_ORDER:
          assert(len(self.my_choices) == self.MARKOV_ORDER + 1)
          self.my_choices = self.my_choices[1:]

          def round(self, last):
          if last: self.update_opponent_model(last)

          dist = self.get_distribution()
          self.choice = self.choose(dist)
          self.update_history()
          return self.choice

          class Ensemble:
          def __init__(self):
          self.models =
          self.votes =
          self.prev_choice =
          for order in range(0, 6):
          self.models.append(Number6("maxExpected", order))
          self.models.append(Number6("randomize", order))
          #self.models.append(Number6("argMax", order))
          for i in range(0, len(self.models)):
          self.votes.append(0)
          self.prev_choice.append("D")

          self.payoff = {
          "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
          "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
          "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
          }

          def round(self, last):
          if last:
          for i in range(0, len(self.models)):
          self.votes[i] += self.payoff[self.prev_choice[i]][last]

          # vote. Sufficiently terrible models get negative votes
          C = 0
          N = 0
          D = 0
          for i in range(0, len(self.models)):
          choice = self.models[i].round(last)
          if "C" == choice: C += self.votes[i]
          if "N" == choice: N += self.votes[i]
          if "D" == choice: D += self.votes[i]
          self.prev_choice[i] = choice

          if C > D and C > N: return "C"
          elif N > D: return "N"
          else: return "D"


          Test Framework



          In case anyone else finds it useful, here's a test framework for looking at individual matchups. Python2. Just put all the opponents you're interested in in opponents.py, and change the references to Ensemble to your own.



          import sys, inspect
          import opponents
          from ensemble import Ensemble

          def count_payoff(label, them):
          if None == them: return
          me = choices[label]
          payoff = {
          "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
          "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
          "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
          }
          if label not in total_payoff: total_payoff[label] = 0
          total_payoff[label] += payoff[me][them]

          def update_hist(label, choice):
          choices[label] = choice

          opponents = [ x[1] for x
          in inspect.getmembers(sys.modules['opponents'], inspect.isclass)]

          for k in opponents:
          total_payoff = {}

          for j in range(0, 100):
          A = Ensemble()
          B = k()
          choices = {}

          aChoice = None
          bChoice = None
          for i in range(0, 100):
          count_payoff(A.__class__.__name__, bChoice)
          a = A.round(bChoice)
          update_hist(A.__class__.__name__, a)

          count_payoff(B.__class__.__name__, aChoice)
          b = B.round(aChoice)
          update_hist(B.__class__.__name__, b)

          aChoice = a
          bChoice = b
          print total_payoff





          share|improve this answer











          $endgroup$













          • $begingroup$
            The controller is ready, you didn't have to do all that...
            $endgroup$
            – Blacksilver
            Nov 13 '18 at 3:40






          • 1




            $begingroup$
            @Blacksilver I realized that just as I was about to submit. But this one works in versions before 3.6, and gives information about individual matchups that can help identify weak spots, so it wasn't a complete waste of time.
            $endgroup$
            – Ray
            Nov 13 '18 at 3:42










          • $begingroup$
            Fair enough; running now. I'll probably add options to my controller to do similar things.
            $endgroup$
            – Blacksilver
            Nov 13 '18 at 3:45










          • $begingroup$
            "It beats everything posted so far except Ensemble and PatternFinder" I'm honored :)
            $endgroup$
            – Sparr
            Nov 13 '18 at 7:19










          • $begingroup$
            @Sparr Oops. That was supposed to say EvaluaterBot and PatternFinder. But that's when comparing total score against the entire field. PatternFinder remains the only one that beats this in a direct match up.
            $endgroup$
            – Ray
            Nov 13 '18 at 8:04



















          2












          $begingroup$

          Improved Dirichlet Dice



          import random

          class DirichletDice2:
          def __init__(self):

          self.alpha = dict(
          C = {'C' : 1, 'N' : 1, 'D' : 1},
          N = {'C' : 1, 'N' : 1, 'D' : 1},
          D = {'C' : 1, 'N' : 1, 'D' : 1}
          )
          self.myLast = [None, None]
          self.payoff = dict(
          C = { "C": 0, "N": 3, "D": -5 },
          N = { "C": -3, "N": 0, "D": 1 },
          D = { "C": 5, "N": -1, "D": 0 }
          )

          def DirichletDraw(self, key):
          alpha = self.alpha[key].values()
          mu = [random.gammavariate(a,1) for a in alpha]
          mu = [m / sum(mu) for m in mu]
          return mu

          def ExpectedPayoff(self, probs):
          expectedPayoff = {}
          for val in ['C','N','D']:
          payoff = sum([p * v for p,v in zip(probs, self.payoff[val].values())])
          expectedPayoff[val] = payoff
          return expectedPayoff

          def round(self, last):
          if last is None:
          self.myLast[0] = 'D'
          return 'D'

          #update dice corresponding to opponent's last response to my
          #outcome two turns ago
          if self.myLast[1] is not None:
          self.alpha[self.myLast[1]][last] += 1

          #draw probs for my opponent's roll from Dirichlet distribution and then return the optimal response
          mu = self.DirichletDraw(self.myLast[0])
          expectedPayoff = self.ExpectedPayoff(mu)
          res = max(expectedPayoff, key=expectedPayoff.get)

          #update myLast
          self.myLast[1] = self.myLast[0]
          self.myLast[0] = res

          return res


          This is an improved version of Dirichlet Dice. Instead of taking the expected multinomial distribution from the Dirichlet distribution, it draws a Multinomial distribution randomly from the Dirichlet distribution. Then, instead of drawing from the Multinomial and giving the optimal response to that, it gives the optimal expected response to the given Multinomial using the points. So the randomness has essentially been shifted from the Multinomial draw to the Dirichlet draw. Also, the priors are more flat now, to encourage exploration.



          It's "improved" because it now accounts for the points system by giving the best expected value against the probabilities, while maintaining its randomness by drawing the probabilities themselves. Before, I tried simply doing the best expected payoff from the expected probabilities, but that did badly because it just got stuck, and didn't explore enough to update its dice. Also it was more predictable and exploitable.





          Original submission:



          Dirichlet Dice



          import random

          class DirichletDice:
          def __init__(self):

          self.alpha = dict(
          C = {'C' : 2, 'N' : 3, 'D' : 1},
          N = {'C' : 1, 'N' : 2, 'D' : 3},
          D = {'C' : 3, 'N' : 1, 'D' : 2}
          )

          self.Response = {'C' : 'D', 'N' : 'C', 'D' : 'N'}
          self.myLast = [None, None]

          #expected value of the dirichlet distribution given by Alpha
          def MultinomialDraw(self, key):
          alpha = list(self.alpha[key].values())
          probs = [x / sum(alpha) for x in alpha]
          outcome = random.choices(['C','N','D'], weights=probs)[0]
          return outcome

          def round(self, last):
          if last is None:
          self.myLast[0] = 'D'
          return 'D'

          #update dice corresponding to opponent's last response to my
          #outcome two turns ago
          if self.myLast[1] is not None:
          self.alpha[self.myLast[1]][last] += 1

          #predict opponent's move based on my last move
          predict = self.MultinomialDraw(self.myLast[0])
          res = self.Response[predict]

          #update myLast
          self.myLast[1] = self.myLast[0]
          self.myLast[0] = res

          return res


          Basically I'm assuming that the opponent's response to my last output is a multinomial variable (weighted dice), one for each of my outputs, so there's a dice for "C", one for "N", and one for "D". So if my last roll was, for example, a "N" then I roll the "N-dice" to guess what their response would be to my "N". I begin with a Dirichlet prior that assumes that my opponent is somewhat "smart" (more likely to play the one with the best payoff against my last roll, least likely to play the one with the worst payoff). I generate the "expected" Multinomial distribution from the appropriate Dirichlet prior (this is the expected value of the probability distribution over their dice weights). I roll the weighted dice of my last output, and respond with the one with the best payoff against that dice outcome.



          Starting in the third round, I do a Bayesian update of the appropriate Dirichlet prior of my opponent's last response to the thing I played two rounds ago. I'm trying to iteratively learn their dice weightings.



          I could have also simply picked the response with the best "expected" outcome once generating the dice, instead of simply rolling the dice and responding to the outcome. However, I wanted to keep the randomness in, so that my bot is less vulnerable to the ones that try to predict a pattern.






          share|improve this answer











          $endgroup$





















            2












            $begingroup$

            Kevin



            class Kevin:
            def round(self, last):
            return {"C":"N","N":"D","D":"C",None:"N"} [last]


            Picks the worst choice. The worst bot made.



            Useless



            import random

            class Useless:
            def __init__(self):
            self.lastLast = None

            def round(self, last):
            tempLastLast = self.lastLast
            self.lastLast = last

            if(last == "D" and tempLastLast == "N"):
            return "C"
            if(last == "D" and tempLastLast == "C"):
            return "N"

            if(last == "N" and tempLastLast == "D"):
            return "C"
            if(last == "N" and tempLastLast == "C"):
            return "D"

            if(last == "C" and tempLastLast == "D"):
            return "N"
            if(last == "C" and tempLastLast == "N"):
            return "D"

            return random.choice("CND")


            It looks at the last two moves done by the opponent and picks the most not done else it picks something random. There is probably a better way of doing this.






            share|improve this answer











            $endgroup$





















              2












              $begingroup$

              Historic Average



              class HistoricAverage:
              PAYOFFS = {
              "C":{"C":3,"N":1,"D":5},
              "N":{"C":4,"N":2,"D":2},
              "D":{"C":0,"N":3,"D":1}}
              def __init__(self):
              self.payoffsum = {"C":0, "N":0, "D":0}
              def round(this, last):
              if(last != None):
              for x in this.payoffsum:
              this.payoffsum[x] += HistoricAverage.PAYOFFS[last][x]
              return max(this.payoffsum, key=this.payoffsum.get)


              Looks at history and finds the action that would have been best on average. Starts cooperative.






              share|improve this answer











              $endgroup$













              • $begingroup$
                This could run faster if it didn't re-calculate the averages every round.
                $endgroup$
                – Sparr
                Nov 13 '18 at 19:57










              • $begingroup$
                @Sparr true. I edited it so it does now.
                $endgroup$
                – MegaTom
                Nov 14 '18 at 20:19



















              1












              $begingroup$

              Weighted Average



              class WeightedAverageBot:
              def __init__(self):
              self.C_bias = 1/4
              self.N = self.C_bias
              self.D = self.C_bias
              self.prev_weight = 1/2
              def round(self, last):
              if last:
              if last == "C" or last == "N":
              self.D *= self.prev_weight
              if last == "C" or last == "D":
              self.N *= self.prev_weight
              if last == "N":
              self.N = 1 - ((1 - self.N) * self.prev_weight)
              if last == "D":
              self.D = 1 - ((1 - self.D) * self.prev_weight)
              if self.N <= self.C_bias and self.D <= self.C_bias:
              return "D"
              if self.N > self.D:
              return "C"
              return "N"


              The opponent's behavior is modeled as a right triangle with corners for C N D at 0,0 0,1 1,0 respectively. Each opponent move shifts the point within that triangle toward that corner, and we play to beat the move indicated by the point (with C being given an adjustably small slice of the triangle). In theory I wanted this to have a longer memory with more weight to previous moves, but in practice the current meta favors bots that change quickly, so this devolves into an approximation of LastOptimalBot against most enemies. Posting for posterity; maybe someone will be inspired.






              share|improve this answer









              $endgroup$





















                1












                $begingroup$

                Tetragram



                import itertools

                class Tetragram:
                def __init__(self):
                self.history = {x: ['C'] for x in itertools.product('CND', repeat=4)}
                self.theirs =
                self.previous = None

                def round(self, last):
                if self.previous is not None and len(self.previous) == 4:
                self.history[self.previous].append(last)
                if last is not None:
                self.theirs = (self.theirs + [last])[-3:]

                if self.previous is not None and len(self.previous) == 4:
                expected = random.choice(self.history[self.previous])
                if expected == 'C':
                choice = 'C'
                elif expected == 'N':
                choice = 'C'
                else:
                choice = 'N'
                else:
                choice = 'C'

                self.previous = tuple(self.theirs + [choice])
                return choice


                Try to find a pattern in the opponent's moves, assuming they're also watching our last move.






                share|improve this answer









                $endgroup$





















                  1












                  $begingroup$

                  Handshake



                  class HandshakeBot:
                  def __init__(self):
                  self.handshake_length = 4
                  self.handshake = ["N","N","C","D"]
                  while len(self.handshake) < self.handshake_length:
                  self.handshake *= 2
                  self.handshake = self.handshake[:self.handshake_length]
                  self.opp_hand =
                  self.friendly = None
                  def round(self, last):
                  if last:
                  if self.friendly == None:
                  # still trying to handshake
                  self.opp_hand.append(last)
                  if self.opp_hand[-1] != self.handshake[len(self.opp_hand)-1]:
                  self.friendly = False
                  return "D"
                  if len(self.opp_hand) == len(self.handshake):
                  self.friendly = True
                  return "C"
                  return self.handshake[len(self.opp_hand)]
                  elif self.friendly == True:
                  # successful handshake and continued cooperation
                  if last == "C":
                  return "C"
                  self.friendly = False
                  return "D"
                  else:
                  # failed handshake or abandoned cooperation
                  return "N" if last == "D" else ("D" if last == "C" else "C")
                  return self.handshake[0]


                  Recognizes when it's playing against itself, then cooperates. Otherwise mimics LastOptimalBot which seems like the best one-line strategy. Performs worse than LastOptimalBot, by an amount inversely proportional to the number of rounds. Obviously would do better if there were more copies of it in the field *cough**wink*.






                  share|improve this answer









                  $endgroup$













                  • $begingroup$
                    Just submit a few clones that have different non-handshake behavior.
                    $endgroup$
                    – Blacksilver
                    Nov 13 '18 at 22:52










                  • $begingroup$
                    That seems exploit-y. I could submit one such clone for every simple behavior represented here.
                    $endgroup$
                    – Sparr
                    Nov 14 '18 at 0:12










                  • $begingroup$
                    I've added an extra clause saying that you can only submit max five bots.
                    $endgroup$
                    – Blacksilver
                    Nov 14 '18 at 2:14



















                  1












                  $begingroup$

                  ShiftingOptimalBot



                  class ShiftingOptimalBot:
                  def __init__(self):
                  # wins, draws, losses
                  self.history = [0,0,0]
                  self.lastMove = None
                  self.state = 0
                  def round(self, last):
                  if last == None:
                  self.lastMove = "C"
                  return self.lastMove
                  if last == self.lastMove:
                  self.history[1] += 1
                  elif (last == "C" and self.lastMove == "D") or (last == "D" and self.lastMove == "N") or (last == "N" and self.lastMove == "C"):
                  self.history[0] += 1
                  else:
                  self.history[2] += 1

                  if self.history[0] + 1 < self.history[2] or self.history[2] > 5:
                  self.state = (self.state + 1) % 3
                  self.history = [0,0,0]
                  if self.history[1] > self.history[0] + self.history[2] + 2:
                  self.state = (self.state + 2) % 3
                  self.history = [0,0,0]

                  if self.state == 0:
                  self.lastMove = "N" if last == "D" else ("D" if last == "C" else "C")
                  elif self.state == 1:
                  self.lastMove = last
                  else:
                  self.lastMove = "C" if last == "D" else ("N" if last == "C" else "D")
                  return self.lastMove


                  This bot uses LastOptimalBot's algorithm as long as it's winning. If the other bot starts predicting it, however, it will start playing whichever move its opponent played last (which is the move that beats the move that would beat LastOptimalBot). It cycles through simple transpositions of those algorithms as long as it continues to lose (or when it gets bored by drawing a lot).



                  Honestly, I'm surprised that LastOptimalBot is sitting in 5th as I post this. I'm fairly certain this will do better, assuming that I wrote this python correctly.






                  share|improve this answer











                  $endgroup$





















                    0












                    $begingroup$

                    HandshakePatternMatch



                    from .patternfinder import PatternFinder
                    import collections

                    class HandshakePatternMatch:
                    def __init__(self):
                    self.moves = [None]
                    self.other =
                    self.handshake = [None,"N","C","C","D","N"]
                    self.friendly = None
                    self.pattern = PatternFinder()
                    def round(self, last):
                    self.other.append(last)
                    if last:
                    if len(self.other) < len(self.handshake):
                    # still trying to handshake
                    if self.friendly == False or self.other[-1] != self.handshake[-1]:
                    self.friendly = False
                    else:
                    self.friendly = True
                    move = self.handshake[len(self.other)]
                    self.pattern.round(last)
                    elif self.friendly == True:
                    # successful handshake and continued cooperation
                    move = self.pattern.round(last)
                    if last == "C":
                    move = "C"
                    elif last == self.handshake[-1] and self.moves[-1] == self.handshake[-1]:
                    move = "C"
                    else:
                    self.friendly = False
                    else:
                    # failed handshake or abandoned cooperation
                    move = self.pattern.round(last)
                    else:
                    move = self.handshake[1]
                    self.pattern.round(last)
                    self.moves.append(move)
                    return move


                    Why pattern match yourself? Handshake and cooperate away.






                    share|improve this answer









                    $endgroup$













                    • $begingroup$
                      import PatternFinder is cheating in my books.
                      $endgroup$
                      – Blacksilver
                      Nov 17 '18 at 2:30










                    • $begingroup$
                      @Blacksilver It gets done all the time in KOTH. It's no different than copying the code in an existing answer and using it. Robot Roulette: High stakes robot gambling had it happening all over the place to the point that bots would detect if their code was being called by an opponent and sabotage the return.
                      $endgroup$
                      – Draco18s
                      Nov 17 '18 at 2:36












                    • $begingroup$
                      Alright then. TIL.
                      $endgroup$
                      – Blacksilver
                      Nov 17 '18 at 2:37










                    • $begingroup$
                      I'll do the crunching tomorrow.
                      $endgroup$
                      – Blacksilver
                      Nov 17 '18 at 2:38










                    • $begingroup$
                      Here's a perfect example of using other bots' code. Usually it comes down to "that guy worked out some tricky math, I want his results under these conditions." (My own entry did that to pretty good effect; UpYours was more scatter-shot in its approach).
                      $endgroup$
                      – Draco18s
                      Nov 17 '18 at 2:41





















                    0












                    $begingroup$

                    Hardcoded



                    class Hardcoded:
                    sequence = "DNCNNDDCNDDDCCDNNNNDDCNNDDCDCNNNDNDDCNNDDNDDCDNCCNNDNNDDCNNDDCDCNNNDNCDNDNDDNCNDDCDNNDCNNDDCDCNNDNNDDCDNDDCCNNNDNNDDCNNDDNDCDNCNDDCDNNDDCCNDNNDDCNNNDCDNDDCNNNNDNDDCDNCDCNNDNNDDCDNDDCCNNNDNDDCNNNDNDCDCDNNDCNNDNDDCDNCNNDDCNDNNDDCDNNDCDNDNCDDCNNNDNDNCNDDCDNDDCCNNNNDNDDCNNDDCNNDDCDCNNDNNDDCDNDDCCNDNNDDCNNNDCDNNDNDDCCNNNDNDDNCDCDNNDCNNDNDDCNNDDCDNCNNDDCDNNDCDNDNCDDCNDNNDDCNNNDDCDNCNNDNNDDCNNDDNNDCDNCNDDCNNDCDNNDDCNNDDNCDCNNDNDNDDCDNCDCNNNDNDDCDCNNDNNDDCDNDDCCNNNDNNDDCNDNDNCDDCDCNNNNDNDDCDNCNDDCDNNDDCNNNDNDDCDNCNNDCNNDNDDNCDCDNNNDDCNNDDCNNDDNNDCDNCNDDCNNDDNDCDNNDNDDCCNCDNNDCNNDDNDDCNCDNNDCDNNNDDCNNDDCDCDNNDDCNDNCNNDNNDNDNDDCDNCDCNNNDNDDCDNCNNDDCDNNDCNNDDCNNDDCDCDNNDDCNDNCNNNDDCDNNDCDNDNCNNDNDDNNDNDCDDCCNNNDDCNDNDNCDDCDCNNNDNNDDCNDCDNDDCNNNNDNDDCCNDNNDDCDCNNNDNDDNDDCDNCCNNDNNDDCNNDDCDCNNDNNDDCNNDDNCNDDNNDCDNCNDDCNNDDNDCDNNDNDDCCNCDNNDCNNDNDDCNNDDNCDCDNNDCNNDNDDCDCDNNNNDDCNNDDNDCCNNDDNDDCNCDNNDCNNDDNDDCDNCNDDCNNNNDCDNNDDCNDNDDCDNCNNDCDNNDCNNDNDDNCDCNNDNDDCDNDDCCNNNNDNDDCNNDDCDCNNDNNDDCDCDNNDDC"
                    def __init__(self):
                    self.round_num = -1
                    def round(self,_):
                    self.round_num += 1
                    return Hardcoded.sequence[self.round_num % 1000]


                    Just plays a hardcoded sequence of moves optimized to beat some of the top deterministic bots.






                    share|improve this answer











                    $endgroup$












                      protected by Community Nov 18 '18 at 18:02



                      Thank you for your interest in this question.
                      Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).



                      Would you like to answer one of these unanswered questions instead?














                      19 Answers
                      19






                      active

                      oldest

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                      19 Answers
                      19






                      active

                      oldest

                      votes









                      active

                      oldest

                      votes






                      active

                      oldest

                      votes









                      9












                      $begingroup$

                      EvaluaterBot





                      class EvaluaterBot:
                      def __init__(self):
                      self.c2i = {"C":0, "N":1, "D":2}
                      self.i2c = {0:"C", 1:"N", 2:"D"}
                      self.history = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
                      self.last = [None, None]

                      def round(self, last):
                      if self.last[0] == None:
                      ret = 2
                      else:
                      # Input the latest enemy action (the reaction to my action 2 rounds ago)
                      # into the history
                      self.history[self.last[0]][self.c2i[last]] += 1
                      # The enemy will react to the last action I did
                      prediction,_ = max(enumerate(self.history[self.last[1]]), key=lambda l:l[1])
                      ret = (prediction - 1) % 3
                      self.last = [self.last[1], ret]
                      return self.i2c[ret]


                      Wins against all previously submitted bots except (maybe) the random bot (but it could have an advantage, because it picks D in a draw and D should optimal) and plays a constant draw against themself.






                      share|improve this answer











                      $endgroup$













                      • $begingroup$
                        Yep, beats everything.
                        $endgroup$
                        – Blacksilver
                        Nov 12 '18 at 19:43










                      • $begingroup$
                        Scratch that, PatternFinder beats it by a bit.
                        $endgroup$
                        – Blacksilver
                        Nov 13 '18 at 14:25
















                      9












                      $begingroup$

                      EvaluaterBot





                      class EvaluaterBot:
                      def __init__(self):
                      self.c2i = {"C":0, "N":1, "D":2}
                      self.i2c = {0:"C", 1:"N", 2:"D"}
                      self.history = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
                      self.last = [None, None]

                      def round(self, last):
                      if self.last[0] == None:
                      ret = 2
                      else:
                      # Input the latest enemy action (the reaction to my action 2 rounds ago)
                      # into the history
                      self.history[self.last[0]][self.c2i[last]] += 1
                      # The enemy will react to the last action I did
                      prediction,_ = max(enumerate(self.history[self.last[1]]), key=lambda l:l[1])
                      ret = (prediction - 1) % 3
                      self.last = [self.last[1], ret]
                      return self.i2c[ret]


                      Wins against all previously submitted bots except (maybe) the random bot (but it could have an advantage, because it picks D in a draw and D should optimal) and plays a constant draw against themself.






                      share|improve this answer











                      $endgroup$













                      • $begingroup$
                        Yep, beats everything.
                        $endgroup$
                        – Blacksilver
                        Nov 12 '18 at 19:43










                      • $begingroup$
                        Scratch that, PatternFinder beats it by a bit.
                        $endgroup$
                        – Blacksilver
                        Nov 13 '18 at 14:25














                      9












                      9








                      9





                      $begingroup$

                      EvaluaterBot





                      class EvaluaterBot:
                      def __init__(self):
                      self.c2i = {"C":0, "N":1, "D":2}
                      self.i2c = {0:"C", 1:"N", 2:"D"}
                      self.history = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
                      self.last = [None, None]

                      def round(self, last):
                      if self.last[0] == None:
                      ret = 2
                      else:
                      # Input the latest enemy action (the reaction to my action 2 rounds ago)
                      # into the history
                      self.history[self.last[0]][self.c2i[last]] += 1
                      # The enemy will react to the last action I did
                      prediction,_ = max(enumerate(self.history[self.last[1]]), key=lambda l:l[1])
                      ret = (prediction - 1) % 3
                      self.last = [self.last[1], ret]
                      return self.i2c[ret]


                      Wins against all previously submitted bots except (maybe) the random bot (but it could have an advantage, because it picks D in a draw and D should optimal) and plays a constant draw against themself.






                      share|improve this answer











                      $endgroup$



                      EvaluaterBot





                      class EvaluaterBot:
                      def __init__(self):
                      self.c2i = {"C":0, "N":1, "D":2}
                      self.i2c = {0:"C", 1:"N", 2:"D"}
                      self.history = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
                      self.last = [None, None]

                      def round(self, last):
                      if self.last[0] == None:
                      ret = 2
                      else:
                      # Input the latest enemy action (the reaction to my action 2 rounds ago)
                      # into the history
                      self.history[self.last[0]][self.c2i[last]] += 1
                      # The enemy will react to the last action I did
                      prediction,_ = max(enumerate(self.history[self.last[1]]), key=lambda l:l[1])
                      ret = (prediction - 1) % 3
                      self.last = [self.last[1], ret]
                      return self.i2c[ret]


                      Wins against all previously submitted bots except (maybe) the random bot (but it could have an advantage, because it picks D in a draw and D should optimal) and plays a constant draw against themself.







                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited Nov 12 '18 at 19:31

























                      answered Nov 12 '18 at 19:24









                      Black Owl KaiBlack Owl Kai

                      5807




                      5807












                      • $begingroup$
                        Yep, beats everything.
                        $endgroup$
                        – Blacksilver
                        Nov 12 '18 at 19:43










                      • $begingroup$
                        Scratch that, PatternFinder beats it by a bit.
                        $endgroup$
                        – Blacksilver
                        Nov 13 '18 at 14:25


















                      • $begingroup$
                        Yep, beats everything.
                        $endgroup$
                        – Blacksilver
                        Nov 12 '18 at 19:43










                      • $begingroup$
                        Scratch that, PatternFinder beats it by a bit.
                        $endgroup$
                        – Blacksilver
                        Nov 13 '18 at 14:25
















                      $begingroup$
                      Yep, beats everything.
                      $endgroup$
                      – Blacksilver
                      Nov 12 '18 at 19:43




                      $begingroup$
                      Yep, beats everything.
                      $endgroup$
                      – Blacksilver
                      Nov 12 '18 at 19:43












                      $begingroup$
                      Scratch that, PatternFinder beats it by a bit.
                      $endgroup$
                      – Blacksilver
                      Nov 13 '18 at 14:25




                      $begingroup$
                      Scratch that, PatternFinder beats it by a bit.
                      $endgroup$
                      – Blacksilver
                      Nov 13 '18 at 14:25











                      7












                      $begingroup$

                      TatForTit



                      class TatForTit:
                      def round(self, last):
                      if(last == "C"):
                      return "N"
                      return "D"


                      This bot will alternate picking D N D N while TitForTat alternates C D C D, for an average net gain of 3 points per round if I have read the payout matrix correctly. I think this might be optimal against TitForTat. Obviously it could be improved to detect a non-TFT opponent and adopt other strategies, but I was just aiming for the original bounty.






                      share|improve this answer











                      $endgroup$


















                        7












                        $begingroup$

                        TatForTit



                        class TatForTit:
                        def round(self, last):
                        if(last == "C"):
                        return "N"
                        return "D"


                        This bot will alternate picking D N D N while TitForTat alternates C D C D, for an average net gain of 3 points per round if I have read the payout matrix correctly. I think this might be optimal against TitForTat. Obviously it could be improved to detect a non-TFT opponent and adopt other strategies, but I was just aiming for the original bounty.






                        share|improve this answer











                        $endgroup$
















                          7












                          7








                          7





                          $begingroup$

                          TatForTit



                          class TatForTit:
                          def round(self, last):
                          if(last == "C"):
                          return "N"
                          return "D"


                          This bot will alternate picking D N D N while TitForTat alternates C D C D, for an average net gain of 3 points per round if I have read the payout matrix correctly. I think this might be optimal against TitForTat. Obviously it could be improved to detect a non-TFT opponent and adopt other strategies, but I was just aiming for the original bounty.






                          share|improve this answer











                          $endgroup$



                          TatForTit



                          class TatForTit:
                          def round(self, last):
                          if(last == "C"):
                          return "N"
                          return "D"


                          This bot will alternate picking D N D N while TitForTat alternates C D C D, for an average net gain of 3 points per round if I have read the payout matrix correctly. I think this might be optimal against TitForTat. Obviously it could be improved to detect a non-TFT opponent and adopt other strategies, but I was just aiming for the original bounty.







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Nov 13 '18 at 7:20

























                          answered Nov 12 '18 at 18:04









                          SparrSparr

                          5,0881633




                          5,0881633























                              6












                              $begingroup$

                              NashEquilibrium



                              This bot has taken a game theory class in college but was lazy and didn't go to the class where they covered iterated games. So he only plays single game mixed nash equilibrium. Turns out 1/5 2/5 2/5 is the mixed NE for the payoffs.



                              class NashEquilibrium:
                              def round(self, _):
                              a = random.random()
                              if a <= 0.2:
                              return "C"
                              elif a <= 0.6:
                              return "N"
                              else:
                              return "D"


                              Constant Abusing Nash Equilibrium



                              This bot picked up a lesson or two from his lazy brother. His lazy brother's problem was that he didn't take advantage of fixed strategies. This version checks if the opponent is a constant player or titfortat and plays accordingly, else it plays the regular nash equilibrium.



                              It's only downside is that it averages 2.2 points per turn playing against itself.



                              class NashEquilibrium2:

                              def __init__(self):
                              self.opphistory = [None, None, None]
                              self.titfortatcounter = 0
                              self.titfortatflag = 0
                              self.mylast = "C"
                              self.constantflag = 0
                              self.myret = "C"

                              def round(self, last):
                              self.opphistory.pop(0)
                              self.opphistory.append(last)

                              # check if its a constant bot, if so exploit
                              if self.opphistory.count(self.opphistory[0]) == 3:
                              self.constantflag = 1
                              if last == "C":
                              self.myret = "D"
                              elif last == "N":
                              self.myret = "C"
                              elif last == "D":
                              self.myret = "N"

                              # check if its a titfortat bot, if so exploit
                              # give it 2 chances to see if its titfortat as it might happen randomly
                              if self.mylast == "D" and last == "D":
                              self.titfortatcounter = self.titfortatcounter + 1

                              if self.mylast == "D" and last!= "D":
                              self.titfortatcounter = 0

                              if self.titfortatcounter >= 3:
                              self.titfortatflag = 1

                              if self.titfortatflag == 1:
                              if last == "C":
                              self.myret = "D"
                              elif last == "D":
                              self.myret = "N"
                              elif last == "N":
                              # tit for tat doesn't return N, we made a mistake somewhere
                              self.titfortatflag = 0
                              self.titfortatcounter = 0

                              # else play the single game nash equilibrium
                              if self.constantflag == 0 and self.titfortatflag == 0:
                              a = random.random()
                              if a <= 0.2:
                              self.myret = "C"
                              elif a <= 0.6:
                              self.myret = "N"
                              else:
                              self.myret = "D"


                              self.mylast = self.myret
                              return self.myret





                              share|improve this answer











                              $endgroup$









                              • 1




                                $begingroup$
                                NashEquilibrium.round needs to take arguments even if it doesn't use them, so as to fit the expected function prototype.
                                $endgroup$
                                – Ray
                                Nov 13 '18 at 3:18












                              • $begingroup$
                                Thank you fixed it
                                $endgroup$
                                – Ofya
                                Nov 13 '18 at 3:45










                              • $begingroup$
                                Little shorter: class NashEquilibrium: def round(self, _): a = random.random() for k, v in [(0.2, "C"), (0.6, "N"), (1, "D")]: if a <= k: return v
                                $endgroup$
                                – Robert Grant
                                Nov 14 '18 at 1:01
















                              6












                              $begingroup$

                              NashEquilibrium



                              This bot has taken a game theory class in college but was lazy and didn't go to the class where they covered iterated games. So he only plays single game mixed nash equilibrium. Turns out 1/5 2/5 2/5 is the mixed NE for the payoffs.



                              class NashEquilibrium:
                              def round(self, _):
                              a = random.random()
                              if a <= 0.2:
                              return "C"
                              elif a <= 0.6:
                              return "N"
                              else:
                              return "D"


                              Constant Abusing Nash Equilibrium



                              This bot picked up a lesson or two from his lazy brother. His lazy brother's problem was that he didn't take advantage of fixed strategies. This version checks if the opponent is a constant player or titfortat and plays accordingly, else it plays the regular nash equilibrium.



                              It's only downside is that it averages 2.2 points per turn playing against itself.



                              class NashEquilibrium2:

                              def __init__(self):
                              self.opphistory = [None, None, None]
                              self.titfortatcounter = 0
                              self.titfortatflag = 0
                              self.mylast = "C"
                              self.constantflag = 0
                              self.myret = "C"

                              def round(self, last):
                              self.opphistory.pop(0)
                              self.opphistory.append(last)

                              # check if its a constant bot, if so exploit
                              if self.opphistory.count(self.opphistory[0]) == 3:
                              self.constantflag = 1
                              if last == "C":
                              self.myret = "D"
                              elif last == "N":
                              self.myret = "C"
                              elif last == "D":
                              self.myret = "N"

                              # check if its a titfortat bot, if so exploit
                              # give it 2 chances to see if its titfortat as it might happen randomly
                              if self.mylast == "D" and last == "D":
                              self.titfortatcounter = self.titfortatcounter + 1

                              if self.mylast == "D" and last!= "D":
                              self.titfortatcounter = 0

                              if self.titfortatcounter >= 3:
                              self.titfortatflag = 1

                              if self.titfortatflag == 1:
                              if last == "C":
                              self.myret = "D"
                              elif last == "D":
                              self.myret = "N"
                              elif last == "N":
                              # tit for tat doesn't return N, we made a mistake somewhere
                              self.titfortatflag = 0
                              self.titfortatcounter = 0

                              # else play the single game nash equilibrium
                              if self.constantflag == 0 and self.titfortatflag == 0:
                              a = random.random()
                              if a <= 0.2:
                              self.myret = "C"
                              elif a <= 0.6:
                              self.myret = "N"
                              else:
                              self.myret = "D"


                              self.mylast = self.myret
                              return self.myret





                              share|improve this answer











                              $endgroup$









                              • 1




                                $begingroup$
                                NashEquilibrium.round needs to take arguments even if it doesn't use them, so as to fit the expected function prototype.
                                $endgroup$
                                – Ray
                                Nov 13 '18 at 3:18












                              • $begingroup$
                                Thank you fixed it
                                $endgroup$
                                – Ofya
                                Nov 13 '18 at 3:45










                              • $begingroup$
                                Little shorter: class NashEquilibrium: def round(self, _): a = random.random() for k, v in [(0.2, "C"), (0.6, "N"), (1, "D")]: if a <= k: return v
                                $endgroup$
                                – Robert Grant
                                Nov 14 '18 at 1:01














                              6












                              6








                              6





                              $begingroup$

                              NashEquilibrium



                              This bot has taken a game theory class in college but was lazy and didn't go to the class where they covered iterated games. So he only plays single game mixed nash equilibrium. Turns out 1/5 2/5 2/5 is the mixed NE for the payoffs.



                              class NashEquilibrium:
                              def round(self, _):
                              a = random.random()
                              if a <= 0.2:
                              return "C"
                              elif a <= 0.6:
                              return "N"
                              else:
                              return "D"


                              Constant Abusing Nash Equilibrium



                              This bot picked up a lesson or two from his lazy brother. His lazy brother's problem was that he didn't take advantage of fixed strategies. This version checks if the opponent is a constant player or titfortat and plays accordingly, else it plays the regular nash equilibrium.



                              It's only downside is that it averages 2.2 points per turn playing against itself.



                              class NashEquilibrium2:

                              def __init__(self):
                              self.opphistory = [None, None, None]
                              self.titfortatcounter = 0
                              self.titfortatflag = 0
                              self.mylast = "C"
                              self.constantflag = 0
                              self.myret = "C"

                              def round(self, last):
                              self.opphistory.pop(0)
                              self.opphistory.append(last)

                              # check if its a constant bot, if so exploit
                              if self.opphistory.count(self.opphistory[0]) == 3:
                              self.constantflag = 1
                              if last == "C":
                              self.myret = "D"
                              elif last == "N":
                              self.myret = "C"
                              elif last == "D":
                              self.myret = "N"

                              # check if its a titfortat bot, if so exploit
                              # give it 2 chances to see if its titfortat as it might happen randomly
                              if self.mylast == "D" and last == "D":
                              self.titfortatcounter = self.titfortatcounter + 1

                              if self.mylast == "D" and last!= "D":
                              self.titfortatcounter = 0

                              if self.titfortatcounter >= 3:
                              self.titfortatflag = 1

                              if self.titfortatflag == 1:
                              if last == "C":
                              self.myret = "D"
                              elif last == "D":
                              self.myret = "N"
                              elif last == "N":
                              # tit for tat doesn't return N, we made a mistake somewhere
                              self.titfortatflag = 0
                              self.titfortatcounter = 0

                              # else play the single game nash equilibrium
                              if self.constantflag == 0 and self.titfortatflag == 0:
                              a = random.random()
                              if a <= 0.2:
                              self.myret = "C"
                              elif a <= 0.6:
                              self.myret = "N"
                              else:
                              self.myret = "D"


                              self.mylast = self.myret
                              return self.myret





                              share|improve this answer











                              $endgroup$



                              NashEquilibrium



                              This bot has taken a game theory class in college but was lazy and didn't go to the class where they covered iterated games. So he only plays single game mixed nash equilibrium. Turns out 1/5 2/5 2/5 is the mixed NE for the payoffs.



                              class NashEquilibrium:
                              def round(self, _):
                              a = random.random()
                              if a <= 0.2:
                              return "C"
                              elif a <= 0.6:
                              return "N"
                              else:
                              return "D"


                              Constant Abusing Nash Equilibrium



                              This bot picked up a lesson or two from his lazy brother. His lazy brother's problem was that he didn't take advantage of fixed strategies. This version checks if the opponent is a constant player or titfortat and plays accordingly, else it plays the regular nash equilibrium.



                              It's only downside is that it averages 2.2 points per turn playing against itself.



                              class NashEquilibrium2:

                              def __init__(self):
                              self.opphistory = [None, None, None]
                              self.titfortatcounter = 0
                              self.titfortatflag = 0
                              self.mylast = "C"
                              self.constantflag = 0
                              self.myret = "C"

                              def round(self, last):
                              self.opphistory.pop(0)
                              self.opphistory.append(last)

                              # check if its a constant bot, if so exploit
                              if self.opphistory.count(self.opphistory[0]) == 3:
                              self.constantflag = 1
                              if last == "C":
                              self.myret = "D"
                              elif last == "N":
                              self.myret = "C"
                              elif last == "D":
                              self.myret = "N"

                              # check if its a titfortat bot, if so exploit
                              # give it 2 chances to see if its titfortat as it might happen randomly
                              if self.mylast == "D" and last == "D":
                              self.titfortatcounter = self.titfortatcounter + 1

                              if self.mylast == "D" and last!= "D":
                              self.titfortatcounter = 0

                              if self.titfortatcounter >= 3:
                              self.titfortatflag = 1

                              if self.titfortatflag == 1:
                              if last == "C":
                              self.myret = "D"
                              elif last == "D":
                              self.myret = "N"
                              elif last == "N":
                              # tit for tat doesn't return N, we made a mistake somewhere
                              self.titfortatflag = 0
                              self.titfortatcounter = 0

                              # else play the single game nash equilibrium
                              if self.constantflag == 0 and self.titfortatflag == 0:
                              a = random.random()
                              if a <= 0.2:
                              self.myret = "C"
                              elif a <= 0.6:
                              self.myret = "N"
                              else:
                              self.myret = "D"


                              self.mylast = self.myret
                              return self.myret






                              share|improve this answer














                              share|improve this answer



                              share|improve this answer








                              edited Nov 13 '18 at 3:44









                              Blacksilver

                              435314




                              435314










                              answered Nov 12 '18 at 21:28









                              OfyaOfya

                              1716




                              1716








                              • 1




                                $begingroup$
                                NashEquilibrium.round needs to take arguments even if it doesn't use them, so as to fit the expected function prototype.
                                $endgroup$
                                – Ray
                                Nov 13 '18 at 3:18












                              • $begingroup$
                                Thank you fixed it
                                $endgroup$
                                – Ofya
                                Nov 13 '18 at 3:45










                              • $begingroup$
                                Little shorter: class NashEquilibrium: def round(self, _): a = random.random() for k, v in [(0.2, "C"), (0.6, "N"), (1, "D")]: if a <= k: return v
                                $endgroup$
                                – Robert Grant
                                Nov 14 '18 at 1:01














                              • 1




                                $begingroup$
                                NashEquilibrium.round needs to take arguments even if it doesn't use them, so as to fit the expected function prototype.
                                $endgroup$
                                – Ray
                                Nov 13 '18 at 3:18












                              • $begingroup$
                                Thank you fixed it
                                $endgroup$
                                – Ofya
                                Nov 13 '18 at 3:45










                              • $begingroup$
                                Little shorter: class NashEquilibrium: def round(self, _): a = random.random() for k, v in [(0.2, "C"), (0.6, "N"), (1, "D")]: if a <= k: return v
                                $endgroup$
                                – Robert Grant
                                Nov 14 '18 at 1:01








                              1




                              1




                              $begingroup$
                              NashEquilibrium.round needs to take arguments even if it doesn't use them, so as to fit the expected function prototype.
                              $endgroup$
                              – Ray
                              Nov 13 '18 at 3:18






                              $begingroup$
                              NashEquilibrium.round needs to take arguments even if it doesn't use them, so as to fit the expected function prototype.
                              $endgroup$
                              – Ray
                              Nov 13 '18 at 3:18














                              $begingroup$
                              Thank you fixed it
                              $endgroup$
                              – Ofya
                              Nov 13 '18 at 3:45




                              $begingroup$
                              Thank you fixed it
                              $endgroup$
                              – Ofya
                              Nov 13 '18 at 3:45












                              $begingroup$
                              Little shorter: class NashEquilibrium: def round(self, _): a = random.random() for k, v in [(0.2, "C"), (0.6, "N"), (1, "D")]: if a <= k: return v
                              $endgroup$
                              – Robert Grant
                              Nov 14 '18 at 1:01




                              $begingroup$
                              Little shorter: class NashEquilibrium: def round(self, _): a = random.random() for k, v in [(0.2, "C"), (0.6, "N"), (1, "D")]: if a <= k: return v
                              $endgroup$
                              – Robert Grant
                              Nov 14 '18 at 1:01











                              5












                              $begingroup$

                              Jade



                              class Jade:
                              def __init__(self):
                              self.dRate = 0.001
                              self.nRate = 0.003

                              def round(self, last):
                              if last == 'D':
                              self.dRate *= 1.1
                              self.nRate *= 1.2
                              elif last == 'N':
                              self.dRate *= 1.03
                              self.nRate *= 1.05
                              self.dRate = min(self.dRate, 1)
                              self.nRate = min(self.nRate, 1)

                              x = random.random()
                              if x > (1 - self.dRate):
                              return 'D'
                              elif x > (1 - self.nRate):
                              return 'N'
                              else:
                              return 'C'


                              Starts out optimistic, but gets progressively more bitter as the opponent refuses to cooperate. Lots of magic constants that could probably be tweaked, but this probably isn't going to do well enough to justify the time.






                              share|improve this answer









                              $endgroup$


















                                5












                                $begingroup$

                                Jade



                                class Jade:
                                def __init__(self):
                                self.dRate = 0.001
                                self.nRate = 0.003

                                def round(self, last):
                                if last == 'D':
                                self.dRate *= 1.1
                                self.nRate *= 1.2
                                elif last == 'N':
                                self.dRate *= 1.03
                                self.nRate *= 1.05
                                self.dRate = min(self.dRate, 1)
                                self.nRate = min(self.nRate, 1)

                                x = random.random()
                                if x > (1 - self.dRate):
                                return 'D'
                                elif x > (1 - self.nRate):
                                return 'N'
                                else:
                                return 'C'


                                Starts out optimistic, but gets progressively more bitter as the opponent refuses to cooperate. Lots of magic constants that could probably be tweaked, but this probably isn't going to do well enough to justify the time.






                                share|improve this answer









                                $endgroup$
















                                  5












                                  5








                                  5





                                  $begingroup$

                                  Jade



                                  class Jade:
                                  def __init__(self):
                                  self.dRate = 0.001
                                  self.nRate = 0.003

                                  def round(self, last):
                                  if last == 'D':
                                  self.dRate *= 1.1
                                  self.nRate *= 1.2
                                  elif last == 'N':
                                  self.dRate *= 1.03
                                  self.nRate *= 1.05
                                  self.dRate = min(self.dRate, 1)
                                  self.nRate = min(self.nRate, 1)

                                  x = random.random()
                                  if x > (1 - self.dRate):
                                  return 'D'
                                  elif x > (1 - self.nRate):
                                  return 'N'
                                  else:
                                  return 'C'


                                  Starts out optimistic, but gets progressively more bitter as the opponent refuses to cooperate. Lots of magic constants that could probably be tweaked, but this probably isn't going to do well enough to justify the time.






                                  share|improve this answer









                                  $endgroup$



                                  Jade



                                  class Jade:
                                  def __init__(self):
                                  self.dRate = 0.001
                                  self.nRate = 0.003

                                  def round(self, last):
                                  if last == 'D':
                                  self.dRate *= 1.1
                                  self.nRate *= 1.2
                                  elif last == 'N':
                                  self.dRate *= 1.03
                                  self.nRate *= 1.05
                                  self.dRate = min(self.dRate, 1)
                                  self.nRate = min(self.nRate, 1)

                                  x = random.random()
                                  if x > (1 - self.dRate):
                                  return 'D'
                                  elif x > (1 - self.nRate):
                                  return 'N'
                                  else:
                                  return 'C'


                                  Starts out optimistic, but gets progressively more bitter as the opponent refuses to cooperate. Lots of magic constants that could probably be tweaked, but this probably isn't going to do well enough to justify the time.







                                  share|improve this answer












                                  share|improve this answer



                                  share|improve this answer










                                  answered Nov 12 '18 at 20:56









                                  MnemonicMnemonic

                                  4,6951730




                                  4,6951730























                                      5












                                      $begingroup$

                                      PatternFinder



                                      class PatternFinder:
                                      def __init__(self):
                                      import collections
                                      self.size = 10
                                      self.moves = [None]
                                      self.other =
                                      self.patterns = collections.defaultdict(list)
                                      self.counter_moves = {"C":"D", "N":"C", "D":"N"}
                                      self.initial_move = "D"
                                      self.pattern_length_exponent = 1
                                      self.pattern_age_exponent = 1
                                      self.debug = False
                                      def round(self, last):
                                      self.other.append(last)
                                      best_pattern_match = None
                                      best_pattern_score = None
                                      best_pattern_response = None
                                      self.debug and print("match so far:",tuple(zip(self.moves,self.other)))
                                      for turn in range(max(0,len(self.moves)-self.size),len(self.moves)):
                                      # record patterns ending with the move that just happened
                                      pattern_full = tuple(zip(self.moves[turn:],self.other[turn:]))
                                      if len(pattern_full) > 1:
                                      pattern_trunc = pattern_full[:-1]
                                      pattern_trunc_result = pattern_full[-1][1]
                                      self.patterns[pattern_trunc].append([pattern_trunc_result,len(self.moves)-1])
                                      if pattern_full in self.patterns:
                                      # we've seen this pattern at least once before
                                      self.debug and print("I've seen",pattern_full,"before:",self.patterns[pattern_full])
                                      for [response,turn_num] in self.patterns[pattern_full]:
                                      score = len(pattern_full) ** self.pattern_length_exponent / (len(self.moves) - turn_num) ** self.pattern_age_exponent
                                      if best_pattern_score == None or score > best_pattern_score:
                                      best_pattern_match = pattern_full
                                      best_pattern_score = score
                                      best_pattern_response = response
                                      # this could be much smarter about aggregating previous responses
                                      if best_pattern_response:
                                      move = self.counter_moves[best_pattern_response]
                                      else:
                                      # fall back to playing nice
                                      move = "C"
                                      self.moves.append(move)
                                      self.debug and print("I choose",move)
                                      return move


                                      This bot looks for previous occurrences of the recent game state to see how the opponent responded to those occurrences, with a preference for longer pattern matches and more recent matches, then plays the move that will "beat" the opponent's predicted move. There's a lot of room for it to be smarter with all the data it keeps track of, but I ran out of time to work on it.






                                      share|improve this answer











                                      $endgroup$













                                      • $begingroup$
                                        When you get the time, mind giving her an optimization pass? It's easily the largest time-sink.
                                        $endgroup$
                                        – Blacksilver
                                        Nov 13 '18 at 3:46






                                      • 2




                                        $begingroup$
                                        @Blacksilver I just reduced the maximum pattern length from 100 to 10. It should run almost instantly now if you're running <200 rounds
                                        $endgroup$
                                        – Sparr
                                        Nov 13 '18 at 5:55








                                      • 1




                                        $begingroup$
                                        Maybe using a highly composite number (i.e., 12) would score better?
                                        $endgroup$
                                        – Blacksilver
                                        Nov 13 '18 at 16:09
















                                      5












                                      $begingroup$

                                      PatternFinder



                                      class PatternFinder:
                                      def __init__(self):
                                      import collections
                                      self.size = 10
                                      self.moves = [None]
                                      self.other =
                                      self.patterns = collections.defaultdict(list)
                                      self.counter_moves = {"C":"D", "N":"C", "D":"N"}
                                      self.initial_move = "D"
                                      self.pattern_length_exponent = 1
                                      self.pattern_age_exponent = 1
                                      self.debug = False
                                      def round(self, last):
                                      self.other.append(last)
                                      best_pattern_match = None
                                      best_pattern_score = None
                                      best_pattern_response = None
                                      self.debug and print("match so far:",tuple(zip(self.moves,self.other)))
                                      for turn in range(max(0,len(self.moves)-self.size),len(self.moves)):
                                      # record patterns ending with the move that just happened
                                      pattern_full = tuple(zip(self.moves[turn:],self.other[turn:]))
                                      if len(pattern_full) > 1:
                                      pattern_trunc = pattern_full[:-1]
                                      pattern_trunc_result = pattern_full[-1][1]
                                      self.patterns[pattern_trunc].append([pattern_trunc_result,len(self.moves)-1])
                                      if pattern_full in self.patterns:
                                      # we've seen this pattern at least once before
                                      self.debug and print("I've seen",pattern_full,"before:",self.patterns[pattern_full])
                                      for [response,turn_num] in self.patterns[pattern_full]:
                                      score = len(pattern_full) ** self.pattern_length_exponent / (len(self.moves) - turn_num) ** self.pattern_age_exponent
                                      if best_pattern_score == None or score > best_pattern_score:
                                      best_pattern_match = pattern_full
                                      best_pattern_score = score
                                      best_pattern_response = response
                                      # this could be much smarter about aggregating previous responses
                                      if best_pattern_response:
                                      move = self.counter_moves[best_pattern_response]
                                      else:
                                      # fall back to playing nice
                                      move = "C"
                                      self.moves.append(move)
                                      self.debug and print("I choose",move)
                                      return move


                                      This bot looks for previous occurrences of the recent game state to see how the opponent responded to those occurrences, with a preference for longer pattern matches and more recent matches, then plays the move that will "beat" the opponent's predicted move. There's a lot of room for it to be smarter with all the data it keeps track of, but I ran out of time to work on it.






                                      share|improve this answer











                                      $endgroup$













                                      • $begingroup$
                                        When you get the time, mind giving her an optimization pass? It's easily the largest time-sink.
                                        $endgroup$
                                        – Blacksilver
                                        Nov 13 '18 at 3:46






                                      • 2




                                        $begingroup$
                                        @Blacksilver I just reduced the maximum pattern length from 100 to 10. It should run almost instantly now if you're running <200 rounds
                                        $endgroup$
                                        – Sparr
                                        Nov 13 '18 at 5:55








                                      • 1




                                        $begingroup$
                                        Maybe using a highly composite number (i.e., 12) would score better?
                                        $endgroup$
                                        – Blacksilver
                                        Nov 13 '18 at 16:09














                                      5












                                      5








                                      5





                                      $begingroup$

                                      PatternFinder



                                      class PatternFinder:
                                      def __init__(self):
                                      import collections
                                      self.size = 10
                                      self.moves = [None]
                                      self.other =
                                      self.patterns = collections.defaultdict(list)
                                      self.counter_moves = {"C":"D", "N":"C", "D":"N"}
                                      self.initial_move = "D"
                                      self.pattern_length_exponent = 1
                                      self.pattern_age_exponent = 1
                                      self.debug = False
                                      def round(self, last):
                                      self.other.append(last)
                                      best_pattern_match = None
                                      best_pattern_score = None
                                      best_pattern_response = None
                                      self.debug and print("match so far:",tuple(zip(self.moves,self.other)))
                                      for turn in range(max(0,len(self.moves)-self.size),len(self.moves)):
                                      # record patterns ending with the move that just happened
                                      pattern_full = tuple(zip(self.moves[turn:],self.other[turn:]))
                                      if len(pattern_full) > 1:
                                      pattern_trunc = pattern_full[:-1]
                                      pattern_trunc_result = pattern_full[-1][1]
                                      self.patterns[pattern_trunc].append([pattern_trunc_result,len(self.moves)-1])
                                      if pattern_full in self.patterns:
                                      # we've seen this pattern at least once before
                                      self.debug and print("I've seen",pattern_full,"before:",self.patterns[pattern_full])
                                      for [response,turn_num] in self.patterns[pattern_full]:
                                      score = len(pattern_full) ** self.pattern_length_exponent / (len(self.moves) - turn_num) ** self.pattern_age_exponent
                                      if best_pattern_score == None or score > best_pattern_score:
                                      best_pattern_match = pattern_full
                                      best_pattern_score = score
                                      best_pattern_response = response
                                      # this could be much smarter about aggregating previous responses
                                      if best_pattern_response:
                                      move = self.counter_moves[best_pattern_response]
                                      else:
                                      # fall back to playing nice
                                      move = "C"
                                      self.moves.append(move)
                                      self.debug and print("I choose",move)
                                      return move


                                      This bot looks for previous occurrences of the recent game state to see how the opponent responded to those occurrences, with a preference for longer pattern matches and more recent matches, then plays the move that will "beat" the opponent's predicted move. There's a lot of room for it to be smarter with all the data it keeps track of, but I ran out of time to work on it.






                                      share|improve this answer











                                      $endgroup$



                                      PatternFinder



                                      class PatternFinder:
                                      def __init__(self):
                                      import collections
                                      self.size = 10
                                      self.moves = [None]
                                      self.other =
                                      self.patterns = collections.defaultdict(list)
                                      self.counter_moves = {"C":"D", "N":"C", "D":"N"}
                                      self.initial_move = "D"
                                      self.pattern_length_exponent = 1
                                      self.pattern_age_exponent = 1
                                      self.debug = False
                                      def round(self, last):
                                      self.other.append(last)
                                      best_pattern_match = None
                                      best_pattern_score = None
                                      best_pattern_response = None
                                      self.debug and print("match so far:",tuple(zip(self.moves,self.other)))
                                      for turn in range(max(0,len(self.moves)-self.size),len(self.moves)):
                                      # record patterns ending with the move that just happened
                                      pattern_full = tuple(zip(self.moves[turn:],self.other[turn:]))
                                      if len(pattern_full) > 1:
                                      pattern_trunc = pattern_full[:-1]
                                      pattern_trunc_result = pattern_full[-1][1]
                                      self.patterns[pattern_trunc].append([pattern_trunc_result,len(self.moves)-1])
                                      if pattern_full in self.patterns:
                                      # we've seen this pattern at least once before
                                      self.debug and print("I've seen",pattern_full,"before:",self.patterns[pattern_full])
                                      for [response,turn_num] in self.patterns[pattern_full]:
                                      score = len(pattern_full) ** self.pattern_length_exponent / (len(self.moves) - turn_num) ** self.pattern_age_exponent
                                      if best_pattern_score == None or score > best_pattern_score:
                                      best_pattern_match = pattern_full
                                      best_pattern_score = score
                                      best_pattern_response = response
                                      # this could be much smarter about aggregating previous responses
                                      if best_pattern_response:
                                      move = self.counter_moves[best_pattern_response]
                                      else:
                                      # fall back to playing nice
                                      move = "C"
                                      self.moves.append(move)
                                      self.debug and print("I choose",move)
                                      return move


                                      This bot looks for previous occurrences of the recent game state to see how the opponent responded to those occurrences, with a preference for longer pattern matches and more recent matches, then plays the move that will "beat" the opponent's predicted move. There's a lot of room for it to be smarter with all the data it keeps track of, but I ran out of time to work on it.







                                      share|improve this answer














                                      share|improve this answer



                                      share|improve this answer








                                      edited Nov 13 '18 at 5:54

























                                      answered Nov 12 '18 at 23:56









                                      SparrSparr

                                      5,0881633




                                      5,0881633












                                      • $begingroup$
                                        When you get the time, mind giving her an optimization pass? It's easily the largest time-sink.
                                        $endgroup$
                                        – Blacksilver
                                        Nov 13 '18 at 3:46






                                      • 2




                                        $begingroup$
                                        @Blacksilver I just reduced the maximum pattern length from 100 to 10. It should run almost instantly now if you're running <200 rounds
                                        $endgroup$
                                        – Sparr
                                        Nov 13 '18 at 5:55








                                      • 1




                                        $begingroup$
                                        Maybe using a highly composite number (i.e., 12) would score better?
                                        $endgroup$
                                        – Blacksilver
                                        Nov 13 '18 at 16:09


















                                      • $begingroup$
                                        When you get the time, mind giving her an optimization pass? It's easily the largest time-sink.
                                        $endgroup$
                                        – Blacksilver
                                        Nov 13 '18 at 3:46






                                      • 2




                                        $begingroup$
                                        @Blacksilver I just reduced the maximum pattern length from 100 to 10. It should run almost instantly now if you're running <200 rounds
                                        $endgroup$
                                        – Sparr
                                        Nov 13 '18 at 5:55








                                      • 1




                                        $begingroup$
                                        Maybe using a highly composite number (i.e., 12) would score better?
                                        $endgroup$
                                        – Blacksilver
                                        Nov 13 '18 at 16:09
















                                      $begingroup$
                                      When you get the time, mind giving her an optimization pass? It's easily the largest time-sink.
                                      $endgroup$
                                      – Blacksilver
                                      Nov 13 '18 at 3:46




                                      $begingroup$
                                      When you get the time, mind giving her an optimization pass? It's easily the largest time-sink.
                                      $endgroup$
                                      – Blacksilver
                                      Nov 13 '18 at 3:46




                                      2




                                      2




                                      $begingroup$
                                      @Blacksilver I just reduced the maximum pattern length from 100 to 10. It should run almost instantly now if you're running <200 rounds
                                      $endgroup$
                                      – Sparr
                                      Nov 13 '18 at 5:55






                                      $begingroup$
                                      @Blacksilver I just reduced the maximum pattern length from 100 to 10. It should run almost instantly now if you're running <200 rounds
                                      $endgroup$
                                      – Sparr
                                      Nov 13 '18 at 5:55






                                      1




                                      1




                                      $begingroup$
                                      Maybe using a highly composite number (i.e., 12) would score better?
                                      $endgroup$
                                      – Blacksilver
                                      Nov 13 '18 at 16:09




                                      $begingroup$
                                      Maybe using a highly composite number (i.e., 12) would score better?
                                      $endgroup$
                                      – Blacksilver
                                      Nov 13 '18 at 16:09











                                      4












                                      $begingroup$

                                      OldTitForTat



                                      Old school player is too lazy to update for the new rules.



                                      class OldTitForTat:
                                      def round(self, last):
                                      if(last == None)
                                      return "C"
                                      if(last == "C"):
                                      return "C"
                                      return "D"





                                      share|improve this answer









                                      $endgroup$


















                                        4












                                        $begingroup$

                                        OldTitForTat



                                        Old school player is too lazy to update for the new rules.



                                        class OldTitForTat:
                                        def round(self, last):
                                        if(last == None)
                                        return "C"
                                        if(last == "C"):
                                        return "C"
                                        return "D"





                                        share|improve this answer









                                        $endgroup$
















                                          4












                                          4








                                          4





                                          $begingroup$

                                          OldTitForTat



                                          Old school player is too lazy to update for the new rules.



                                          class OldTitForTat:
                                          def round(self, last):
                                          if(last == None)
                                          return "C"
                                          if(last == "C"):
                                          return "C"
                                          return "D"





                                          share|improve this answer









                                          $endgroup$



                                          OldTitForTat



                                          Old school player is too lazy to update for the new rules.



                                          class OldTitForTat:
                                          def round(self, last):
                                          if(last == None)
                                          return "C"
                                          if(last == "C"):
                                          return "C"
                                          return "D"






                                          share|improve this answer












                                          share|improve this answer



                                          share|improve this answer










                                          answered Nov 12 '18 at 21:53









                                          JoshuaJoshua

                                          2,3921018




                                          2,3921018























                                              3












                                              $begingroup$

                                              NeverCOOP





                                              class NeverCOOP:
                                              def round(self, last):
                                              try:
                                              if last in "ND":
                                              return "D"
                                              else:
                                              return "N"
                                              except:
                                              return "N"


                                              If the opposing bot defects or is neutral, choose defect. Otherwise if this is the first turn or the opposing bot cooperates, choose neutral. I'm not sure how good this will work...






                                              share|improve this answer









                                              $endgroup$













                                              • $begingroup$
                                                What's the try/except for?
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 19:09






                                              • 1




                                                $begingroup$
                                                @Blacksilver I'd assume it serves the same purpose as the if(last): in your Grudger bot, detecting whether there was a previous round.
                                                $endgroup$
                                                – ETHproductions
                                                Nov 12 '18 at 19:31










                                              • $begingroup$
                                                ahh, I see. None in "ND" errors.
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 19:38










                                              • $begingroup$
                                                Because if last and last in "ND": was too complicated?
                                                $endgroup$
                                                – immibis
                                                Nov 12 '18 at 21:29
















                                              3












                                              $begingroup$

                                              NeverCOOP





                                              class NeverCOOP:
                                              def round(self, last):
                                              try:
                                              if last in "ND":
                                              return "D"
                                              else:
                                              return "N"
                                              except:
                                              return "N"


                                              If the opposing bot defects or is neutral, choose defect. Otherwise if this is the first turn or the opposing bot cooperates, choose neutral. I'm not sure how good this will work...






                                              share|improve this answer









                                              $endgroup$













                                              • $begingroup$
                                                What's the try/except for?
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 19:09






                                              • 1




                                                $begingroup$
                                                @Blacksilver I'd assume it serves the same purpose as the if(last): in your Grudger bot, detecting whether there was a previous round.
                                                $endgroup$
                                                – ETHproductions
                                                Nov 12 '18 at 19:31










                                              • $begingroup$
                                                ahh, I see. None in "ND" errors.
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 19:38










                                              • $begingroup$
                                                Because if last and last in "ND": was too complicated?
                                                $endgroup$
                                                – immibis
                                                Nov 12 '18 at 21:29














                                              3












                                              3








                                              3





                                              $begingroup$

                                              NeverCOOP





                                              class NeverCOOP:
                                              def round(self, last):
                                              try:
                                              if last in "ND":
                                              return "D"
                                              else:
                                              return "N"
                                              except:
                                              return "N"


                                              If the opposing bot defects or is neutral, choose defect. Otherwise if this is the first turn or the opposing bot cooperates, choose neutral. I'm not sure how good this will work...






                                              share|improve this answer









                                              $endgroup$



                                              NeverCOOP





                                              class NeverCOOP:
                                              def round(self, last):
                                              try:
                                              if last in "ND":
                                              return "D"
                                              else:
                                              return "N"
                                              except:
                                              return "N"


                                              If the opposing bot defects or is neutral, choose defect. Otherwise if this is the first turn or the opposing bot cooperates, choose neutral. I'm not sure how good this will work...







                                              share|improve this answer












                                              share|improve this answer



                                              share|improve this answer










                                              answered Nov 12 '18 at 18:17









                                              glietzglietz

                                              816




                                              816












                                              • $begingroup$
                                                What's the try/except for?
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 19:09






                                              • 1




                                                $begingroup$
                                                @Blacksilver I'd assume it serves the same purpose as the if(last): in your Grudger bot, detecting whether there was a previous round.
                                                $endgroup$
                                                – ETHproductions
                                                Nov 12 '18 at 19:31










                                              • $begingroup$
                                                ahh, I see. None in "ND" errors.
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 19:38










                                              • $begingroup$
                                                Because if last and last in "ND": was too complicated?
                                                $endgroup$
                                                – immibis
                                                Nov 12 '18 at 21:29


















                                              • $begingroup$
                                                What's the try/except for?
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 19:09






                                              • 1




                                                $begingroup$
                                                @Blacksilver I'd assume it serves the same purpose as the if(last): in your Grudger bot, detecting whether there was a previous round.
                                                $endgroup$
                                                – ETHproductions
                                                Nov 12 '18 at 19:31










                                              • $begingroup$
                                                ahh, I see. None in "ND" errors.
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 19:38










                                              • $begingroup$
                                                Because if last and last in "ND": was too complicated?
                                                $endgroup$
                                                – immibis
                                                Nov 12 '18 at 21:29
















                                              $begingroup$
                                              What's the try/except for?
                                              $endgroup$
                                              – Blacksilver
                                              Nov 12 '18 at 19:09




                                              $begingroup$
                                              What's the try/except for?
                                              $endgroup$
                                              – Blacksilver
                                              Nov 12 '18 at 19:09




                                              1




                                              1




                                              $begingroup$
                                              @Blacksilver I'd assume it serves the same purpose as the if(last): in your Grudger bot, detecting whether there was a previous round.
                                              $endgroup$
                                              – ETHproductions
                                              Nov 12 '18 at 19:31




                                              $begingroup$
                                              @Blacksilver I'd assume it serves the same purpose as the if(last): in your Grudger bot, detecting whether there was a previous round.
                                              $endgroup$
                                              – ETHproductions
                                              Nov 12 '18 at 19:31












                                              $begingroup$
                                              ahh, I see. None in "ND" errors.
                                              $endgroup$
                                              – Blacksilver
                                              Nov 12 '18 at 19:38




                                              $begingroup$
                                              ahh, I see. None in "ND" errors.
                                              $endgroup$
                                              – Blacksilver
                                              Nov 12 '18 at 19:38












                                              $begingroup$
                                              Because if last and last in "ND": was too complicated?
                                              $endgroup$
                                              – immibis
                                              Nov 12 '18 at 21:29




                                              $begingroup$
                                              Because if last and last in "ND": was too complicated?
                                              $endgroup$
                                              – immibis
                                              Nov 12 '18 at 21:29











                                              3












                                              $begingroup$

                                              LastOptimalBot



                                              class LastOptimalBot:
                                              def round(self, last):
                                              return "N" if last == "D" else ("D" if last == "C" else "C")


                                              Assumes that the opposing bot will always play the same move again, and chooses the one that has the best payoff against it.



                                              Averages:



                                              Me   Opp
                                              2.6 2 vs TitForTat
                                              5 0 vs AllC
                                              4 1 vs AllN
                                              3 2 vs AllD
                                              3.5 3.5 vs Random
                                              3 2 vs Grudger
                                              2 2 vs LastOptimalBot
                                              1 3.5 vs TatForTit
                                              4 1 vs NeverCOOP
                                              1 4 vs EvaluaterBot
                                              2.28 2.24 vs NashEquilibrium

                                              2.91 average overall





                                              share|improve this answer











                                              $endgroup$













                                              • $begingroup$
                                                oof. Maybe T4T would do better as return last.
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 18:11










                                              • $begingroup$
                                                I'd like that! If TitForTat were return last, LOB would go 18-9 over 6 rounds rather than the 13-10 over 5 rounds it's currently getting. I think it's fine as is - don't worry about optimizing the example bots.
                                                $endgroup$
                                                – Spitemaster
                                                Nov 12 '18 at 18:30










                                              • $begingroup$
                                                return last would be a better T4T for this challenge, I think
                                                $endgroup$
                                                – Sparr
                                                Nov 12 '18 at 18:43










                                              • $begingroup$
                                                Just tried -- the if(last): return last; else: return "C" is worse.
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 18:59










                                              • $begingroup$
                                                Right, but as @Sparr was saying, it might be more appropriate. Up to you, I suppose.
                                                $endgroup$
                                                – Spitemaster
                                                Nov 12 '18 at 19:00
















                                              3












                                              $begingroup$

                                              LastOptimalBot



                                              class LastOptimalBot:
                                              def round(self, last):
                                              return "N" if last == "D" else ("D" if last == "C" else "C")


                                              Assumes that the opposing bot will always play the same move again, and chooses the one that has the best payoff against it.



                                              Averages:



                                              Me   Opp
                                              2.6 2 vs TitForTat
                                              5 0 vs AllC
                                              4 1 vs AllN
                                              3 2 vs AllD
                                              3.5 3.5 vs Random
                                              3 2 vs Grudger
                                              2 2 vs LastOptimalBot
                                              1 3.5 vs TatForTit
                                              4 1 vs NeverCOOP
                                              1 4 vs EvaluaterBot
                                              2.28 2.24 vs NashEquilibrium

                                              2.91 average overall





                                              share|improve this answer











                                              $endgroup$













                                              • $begingroup$
                                                oof. Maybe T4T would do better as return last.
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 18:11










                                              • $begingroup$
                                                I'd like that! If TitForTat were return last, LOB would go 18-9 over 6 rounds rather than the 13-10 over 5 rounds it's currently getting. I think it's fine as is - don't worry about optimizing the example bots.
                                                $endgroup$
                                                – Spitemaster
                                                Nov 12 '18 at 18:30










                                              • $begingroup$
                                                return last would be a better T4T for this challenge, I think
                                                $endgroup$
                                                – Sparr
                                                Nov 12 '18 at 18:43










                                              • $begingroup$
                                                Just tried -- the if(last): return last; else: return "C" is worse.
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 18:59










                                              • $begingroup$
                                                Right, but as @Sparr was saying, it might be more appropriate. Up to you, I suppose.
                                                $endgroup$
                                                – Spitemaster
                                                Nov 12 '18 at 19:00














                                              3












                                              3








                                              3





                                              $begingroup$

                                              LastOptimalBot



                                              class LastOptimalBot:
                                              def round(self, last):
                                              return "N" if last == "D" else ("D" if last == "C" else "C")


                                              Assumes that the opposing bot will always play the same move again, and chooses the one that has the best payoff against it.



                                              Averages:



                                              Me   Opp
                                              2.6 2 vs TitForTat
                                              5 0 vs AllC
                                              4 1 vs AllN
                                              3 2 vs AllD
                                              3.5 3.5 vs Random
                                              3 2 vs Grudger
                                              2 2 vs LastOptimalBot
                                              1 3.5 vs TatForTit
                                              4 1 vs NeverCOOP
                                              1 4 vs EvaluaterBot
                                              2.28 2.24 vs NashEquilibrium

                                              2.91 average overall





                                              share|improve this answer











                                              $endgroup$



                                              LastOptimalBot



                                              class LastOptimalBot:
                                              def round(self, last):
                                              return "N" if last == "D" else ("D" if last == "C" else "C")


                                              Assumes that the opposing bot will always play the same move again, and chooses the one that has the best payoff against it.



                                              Averages:



                                              Me   Opp
                                              2.6 2 vs TitForTat
                                              5 0 vs AllC
                                              4 1 vs AllN
                                              3 2 vs AllD
                                              3.5 3.5 vs Random
                                              3 2 vs Grudger
                                              2 2 vs LastOptimalBot
                                              1 3.5 vs TatForTit
                                              4 1 vs NeverCOOP
                                              1 4 vs EvaluaterBot
                                              2.28 2.24 vs NashEquilibrium

                                              2.91 average overall






                                              share|improve this answer














                                              share|improve this answer



                                              share|improve this answer








                                              edited Nov 12 '18 at 22:43

























                                              answered Nov 12 '18 at 18:05









                                              SpitemasterSpitemaster

                                              3736




                                              3736












                                              • $begingroup$
                                                oof. Maybe T4T would do better as return last.
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 18:11










                                              • $begingroup$
                                                I'd like that! If TitForTat were return last, LOB would go 18-9 over 6 rounds rather than the 13-10 over 5 rounds it's currently getting. I think it's fine as is - don't worry about optimizing the example bots.
                                                $endgroup$
                                                – Spitemaster
                                                Nov 12 '18 at 18:30










                                              • $begingroup$
                                                return last would be a better T4T for this challenge, I think
                                                $endgroup$
                                                – Sparr
                                                Nov 12 '18 at 18:43










                                              • $begingroup$
                                                Just tried -- the if(last): return last; else: return "C" is worse.
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 18:59










                                              • $begingroup$
                                                Right, but as @Sparr was saying, it might be more appropriate. Up to you, I suppose.
                                                $endgroup$
                                                – Spitemaster
                                                Nov 12 '18 at 19:00


















                                              • $begingroup$
                                                oof. Maybe T4T would do better as return last.
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 18:11










                                              • $begingroup$
                                                I'd like that! If TitForTat were return last, LOB would go 18-9 over 6 rounds rather than the 13-10 over 5 rounds it's currently getting. I think it's fine as is - don't worry about optimizing the example bots.
                                                $endgroup$
                                                – Spitemaster
                                                Nov 12 '18 at 18:30










                                              • $begingroup$
                                                return last would be a better T4T for this challenge, I think
                                                $endgroup$
                                                – Sparr
                                                Nov 12 '18 at 18:43










                                              • $begingroup$
                                                Just tried -- the if(last): return last; else: return "C" is worse.
                                                $endgroup$
                                                – Blacksilver
                                                Nov 12 '18 at 18:59










                                              • $begingroup$
                                                Right, but as @Sparr was saying, it might be more appropriate. Up to you, I suppose.
                                                $endgroup$
                                                – Spitemaster
                                                Nov 12 '18 at 19:00
















                                              $begingroup$
                                              oof. Maybe T4T would do better as return last.
                                              $endgroup$
                                              – Blacksilver
                                              Nov 12 '18 at 18:11




                                              $begingroup$
                                              oof. Maybe T4T would do better as return last.
                                              $endgroup$
                                              – Blacksilver
                                              Nov 12 '18 at 18:11












                                              $begingroup$
                                              I'd like that! If TitForTat were return last, LOB would go 18-9 over 6 rounds rather than the 13-10 over 5 rounds it's currently getting. I think it's fine as is - don't worry about optimizing the example bots.
                                              $endgroup$
                                              – Spitemaster
                                              Nov 12 '18 at 18:30




                                              $begingroup$
                                              I'd like that! If TitForTat were return last, LOB would go 18-9 over 6 rounds rather than the 13-10 over 5 rounds it's currently getting. I think it's fine as is - don't worry about optimizing the example bots.
                                              $endgroup$
                                              – Spitemaster
                                              Nov 12 '18 at 18:30












                                              $begingroup$
                                              return last would be a better T4T for this challenge, I think
                                              $endgroup$
                                              – Sparr
                                              Nov 12 '18 at 18:43




                                              $begingroup$
                                              return last would be a better T4T for this challenge, I think
                                              $endgroup$
                                              – Sparr
                                              Nov 12 '18 at 18:43












                                              $begingroup$
                                              Just tried -- the if(last): return last; else: return "C" is worse.
                                              $endgroup$
                                              – Blacksilver
                                              Nov 12 '18 at 18:59




                                              $begingroup$
                                              Just tried -- the if(last): return last; else: return "C" is worse.
                                              $endgroup$
                                              – Blacksilver
                                              Nov 12 '18 at 18:59












                                              $begingroup$
                                              Right, but as @Sparr was saying, it might be more appropriate. Up to you, I suppose.
                                              $endgroup$
                                              – Spitemaster
                                              Nov 12 '18 at 19:00




                                              $begingroup$
                                              Right, but as @Sparr was saying, it might be more appropriate. Up to you, I suppose.
                                              $endgroup$
                                              – Spitemaster
                                              Nov 12 '18 at 19:00











                                              3












                                              $begingroup$

                                              CopyCat



                                              class CopyCat:
                                              def round(self, last):
                                              if last:
                                              return last
                                              return "C"


                                              Copies the opponent's last move.

                                              I don't expect this to do well, but no one had implemented this classic yet.






                                              share|improve this answer











                                              $endgroup$


















                                                3












                                                $begingroup$

                                                CopyCat



                                                class CopyCat:
                                                def round(self, last):
                                                if last:
                                                return last
                                                return "C"


                                                Copies the opponent's last move.

                                                I don't expect this to do well, but no one had implemented this classic yet.






                                                share|improve this answer











                                                $endgroup$
















                                                  3












                                                  3








                                                  3





                                                  $begingroup$

                                                  CopyCat



                                                  class CopyCat:
                                                  def round(self, last):
                                                  if last:
                                                  return last
                                                  return "C"


                                                  Copies the opponent's last move.

                                                  I don't expect this to do well, but no one had implemented this classic yet.






                                                  share|improve this answer











                                                  $endgroup$



                                                  CopyCat



                                                  class CopyCat:
                                                  def round(self, last):
                                                  if last:
                                                  return last
                                                  return "C"


                                                  Copies the opponent's last move.

                                                  I don't expect this to do well, but no one had implemented this classic yet.







                                                  share|improve this answer














                                                  share|improve this answer



                                                  share|improve this answer








                                                  edited Nov 13 '18 at 3:38









                                                  Blacksilver

                                                  435314




                                                  435314










                                                  answered Nov 13 '18 at 2:46









                                                  MannerPotsMannerPots

                                                  313




                                                  313























                                                      3












                                                      $begingroup$

                                                      Ensemble



                                                      This runs an ensemble of related models. The individual models consider different amounts of history, and have the option of either always choosing the move that will optimize the expected payout difference, or will randomly select a move in proportion to expected payout difference.



                                                      Each member of the ensemble then votes on their preferred move. They get a number of votes equal to how much more they've won than the opponent (which means that terrible models will get negative votes). Whichever move wins the vote is then selected.



                                                      (They should probably split their votes among the moves in proportion to how much they favor each, but I don't care enough to do that right now.)



                                                      It beats everything posted so far except EvaluaterBot and PatternFinder. (One-on-one, it beats EvaluaterBot and loses to PatternFinder).



                                                      from collections import defaultdict
                                                      import random
                                                      class Number6:
                                                      class Choices:
                                                      def __init__(self, C = 0, N = 0, D = 0):
                                                      self.C = C
                                                      self.N = N
                                                      self.D = D

                                                      def __init__(self, strategy = "maxExpected", markov_order = 3):
                                                      self.MARKOV_ORDER = markov_order;
                                                      self.my_choices = ""
                                                      self.opponent = defaultdict(lambda: self.Choices())
                                                      self.choice = None # previous choice
                                                      self.payoff = {
                                                      "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
                                                      "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
                                                      "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
                                                      }
                                                      self.total_payoff = 0

                                                      # if random, will choose in proportion to payoff.
                                                      # otherwise, will always choose argmax
                                                      self.strategy = strategy
                                                      # maxExpected: maximize expected relative payoff
                                                      # random: like maxExpected, but it chooses in proportion to E[payoff]
                                                      # argmax: always choose the option that is optimal for expected opponent choice

                                                      def update_opponent_model(self, last):
                                                      for i in range(0, self.MARKOV_ORDER):
                                                      hist = self.my_choices[i:]
                                                      self.opponent[hist].C += ("C" == last)
                                                      self.opponent[hist].N += ("N" == last)
                                                      self.opponent[hist].D += ("D" == last)

                                                      def normalize(self, counts):
                                                      sum = float(counts.C + counts.N + counts.D)
                                                      if 0 == sum:
                                                      return self.Choices(1.0 / 3.0, 1.0 / 3.0, 1.0 / 3.0)
                                                      return self.Choices(
                                                      counts.C / sum, counts.N / sum, counts.D / sum)

                                                      def get_distribution(self):
                                                      for i in range(0, self.MARKOV_ORDER):
                                                      hist = self.my_choices[i:]
                                                      #print "check hist = " + hist
                                                      if hist in self.opponent:
                                                      return self.normalize(self.opponent[hist])

                                                      return self.Choices(1.0 / 3.0, 1.0 / 3.0, 1.0 / 3.0)

                                                      def choose(self, dist):
                                                      payoff = self.Choices()
                                                      # We're interested in *beating the opponent*, not
                                                      # maximizing our score, so we optimize the difference
                                                      payoff.C = (3-3) * dist.C + (4-1) * dist.N + (0-5) * dist.D
                                                      payoff.N = (1-4) * dist.C + (2-2) * dist.N + (3-2) * dist.D
                                                      payoff.D = (5-0) * dist.C + (2-3) * dist.N + (1-1) * dist.D

                                                      # D has slightly better payoff on uniform opponent,
                                                      # so we select it on ties
                                                      if self.strategy == "maxExpected":
                                                      if payoff.C > payoff.N:
                                                      return "C" if payoff.C > payoff.D else "D"
                                                      return "N" if payoff.N > payoff.D else "D"
                                                      elif self.strategy == "randomize":
                                                      payoff = self.normalize(payoff)
                                                      r = random.uniform(0.0, 1.0)
                                                      if (r < payoff.C): return "C"
                                                      return "N" if (r < payoff.N) else "D"
                                                      elif self.strategy == "argMax":
                                                      if dist.C > dist.N:
                                                      return "D" if dist.C > dist.D else "N"
                                                      return "C" if dist.N > dist.D else "N"

                                                      assert(0) #, "I am not a number! I am a free man!")

                                                      def update_history(self):
                                                      self.my_choices += self.choice
                                                      if len(self.my_choices) > self.MARKOV_ORDER:
                                                      assert(len(self.my_choices) == self.MARKOV_ORDER + 1)
                                                      self.my_choices = self.my_choices[1:]

                                                      def round(self, last):
                                                      if last: self.update_opponent_model(last)

                                                      dist = self.get_distribution()
                                                      self.choice = self.choose(dist)
                                                      self.update_history()
                                                      return self.choice

                                                      class Ensemble:
                                                      def __init__(self):
                                                      self.models =
                                                      self.votes =
                                                      self.prev_choice =
                                                      for order in range(0, 6):
                                                      self.models.append(Number6("maxExpected", order))
                                                      self.models.append(Number6("randomize", order))
                                                      #self.models.append(Number6("argMax", order))
                                                      for i in range(0, len(self.models)):
                                                      self.votes.append(0)
                                                      self.prev_choice.append("D")

                                                      self.payoff = {
                                                      "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
                                                      "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
                                                      "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
                                                      }

                                                      def round(self, last):
                                                      if last:
                                                      for i in range(0, len(self.models)):
                                                      self.votes[i] += self.payoff[self.prev_choice[i]][last]

                                                      # vote. Sufficiently terrible models get negative votes
                                                      C = 0
                                                      N = 0
                                                      D = 0
                                                      for i in range(0, len(self.models)):
                                                      choice = self.models[i].round(last)
                                                      if "C" == choice: C += self.votes[i]
                                                      if "N" == choice: N += self.votes[i]
                                                      if "D" == choice: D += self.votes[i]
                                                      self.prev_choice[i] = choice

                                                      if C > D and C > N: return "C"
                                                      elif N > D: return "N"
                                                      else: return "D"


                                                      Test Framework



                                                      In case anyone else finds it useful, here's a test framework for looking at individual matchups. Python2. Just put all the opponents you're interested in in opponents.py, and change the references to Ensemble to your own.



                                                      import sys, inspect
                                                      import opponents
                                                      from ensemble import Ensemble

                                                      def count_payoff(label, them):
                                                      if None == them: return
                                                      me = choices[label]
                                                      payoff = {
                                                      "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
                                                      "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
                                                      "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
                                                      }
                                                      if label not in total_payoff: total_payoff[label] = 0
                                                      total_payoff[label] += payoff[me][them]

                                                      def update_hist(label, choice):
                                                      choices[label] = choice

                                                      opponents = [ x[1] for x
                                                      in inspect.getmembers(sys.modules['opponents'], inspect.isclass)]

                                                      for k in opponents:
                                                      total_payoff = {}

                                                      for j in range(0, 100):
                                                      A = Ensemble()
                                                      B = k()
                                                      choices = {}

                                                      aChoice = None
                                                      bChoice = None
                                                      for i in range(0, 100):
                                                      count_payoff(A.__class__.__name__, bChoice)
                                                      a = A.round(bChoice)
                                                      update_hist(A.__class__.__name__, a)

                                                      count_payoff(B.__class__.__name__, aChoice)
                                                      b = B.round(aChoice)
                                                      update_hist(B.__class__.__name__, b)

                                                      aChoice = a
                                                      bChoice = b
                                                      print total_payoff





                                                      share|improve this answer











                                                      $endgroup$













                                                      • $begingroup$
                                                        The controller is ready, you didn't have to do all that...
                                                        $endgroup$
                                                        – Blacksilver
                                                        Nov 13 '18 at 3:40






                                                      • 1




                                                        $begingroup$
                                                        @Blacksilver I realized that just as I was about to submit. But this one works in versions before 3.6, and gives information about individual matchups that can help identify weak spots, so it wasn't a complete waste of time.
                                                        $endgroup$
                                                        – Ray
                                                        Nov 13 '18 at 3:42










                                                      • $begingroup$
                                                        Fair enough; running now. I'll probably add options to my controller to do similar things.
                                                        $endgroup$
                                                        – Blacksilver
                                                        Nov 13 '18 at 3:45










                                                      • $begingroup$
                                                        "It beats everything posted so far except Ensemble and PatternFinder" I'm honored :)
                                                        $endgroup$
                                                        – Sparr
                                                        Nov 13 '18 at 7:19










                                                      • $begingroup$
                                                        @Sparr Oops. That was supposed to say EvaluaterBot and PatternFinder. But that's when comparing total score against the entire field. PatternFinder remains the only one that beats this in a direct match up.
                                                        $endgroup$
                                                        – Ray
                                                        Nov 13 '18 at 8:04
















                                                      3












                                                      $begingroup$

                                                      Ensemble



                                                      This runs an ensemble of related models. The individual models consider different amounts of history, and have the option of either always choosing the move that will optimize the expected payout difference, or will randomly select a move in proportion to expected payout difference.



                                                      Each member of the ensemble then votes on their preferred move. They get a number of votes equal to how much more they've won than the opponent (which means that terrible models will get negative votes). Whichever move wins the vote is then selected.



                                                      (They should probably split their votes among the moves in proportion to how much they favor each, but I don't care enough to do that right now.)



                                                      It beats everything posted so far except EvaluaterBot and PatternFinder. (One-on-one, it beats EvaluaterBot and loses to PatternFinder).



                                                      from collections import defaultdict
                                                      import random
                                                      class Number6:
                                                      class Choices:
                                                      def __init__(self, C = 0, N = 0, D = 0):
                                                      self.C = C
                                                      self.N = N
                                                      self.D = D

                                                      def __init__(self, strategy = "maxExpected", markov_order = 3):
                                                      self.MARKOV_ORDER = markov_order;
                                                      self.my_choices = ""
                                                      self.opponent = defaultdict(lambda: self.Choices())
                                                      self.choice = None # previous choice
                                                      self.payoff = {
                                                      "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
                                                      "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
                                                      "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
                                                      }
                                                      self.total_payoff = 0

                                                      # if random, will choose in proportion to payoff.
                                                      # otherwise, will always choose argmax
                                                      self.strategy = strategy
                                                      # maxExpected: maximize expected relative payoff
                                                      # random: like maxExpected, but it chooses in proportion to E[payoff]
                                                      # argmax: always choose the option that is optimal for expected opponent choice

                                                      def update_opponent_model(self, last):
                                                      for i in range(0, self.MARKOV_ORDER):
                                                      hist = self.my_choices[i:]
                                                      self.opponent[hist].C += ("C" == last)
                                                      self.opponent[hist].N += ("N" == last)
                                                      self.opponent[hist].D += ("D" == last)

                                                      def normalize(self, counts):
                                                      sum = float(counts.C + counts.N + counts.D)
                                                      if 0 == sum:
                                                      return self.Choices(1.0 / 3.0, 1.0 / 3.0, 1.0 / 3.0)
                                                      return self.Choices(
                                                      counts.C / sum, counts.N / sum, counts.D / sum)

                                                      def get_distribution(self):
                                                      for i in range(0, self.MARKOV_ORDER):
                                                      hist = self.my_choices[i:]
                                                      #print "check hist = " + hist
                                                      if hist in self.opponent:
                                                      return self.normalize(self.opponent[hist])

                                                      return self.Choices(1.0 / 3.0, 1.0 / 3.0, 1.0 / 3.0)

                                                      def choose(self, dist):
                                                      payoff = self.Choices()
                                                      # We're interested in *beating the opponent*, not
                                                      # maximizing our score, so we optimize the difference
                                                      payoff.C = (3-3) * dist.C + (4-1) * dist.N + (0-5) * dist.D
                                                      payoff.N = (1-4) * dist.C + (2-2) * dist.N + (3-2) * dist.D
                                                      payoff.D = (5-0) * dist.C + (2-3) * dist.N + (1-1) * dist.D

                                                      # D has slightly better payoff on uniform opponent,
                                                      # so we select it on ties
                                                      if self.strategy == "maxExpected":
                                                      if payoff.C > payoff.N:
                                                      return "C" if payoff.C > payoff.D else "D"
                                                      return "N" if payoff.N > payoff.D else "D"
                                                      elif self.strategy == "randomize":
                                                      payoff = self.normalize(payoff)
                                                      r = random.uniform(0.0, 1.0)
                                                      if (r < payoff.C): return "C"
                                                      return "N" if (r < payoff.N) else "D"
                                                      elif self.strategy == "argMax":
                                                      if dist.C > dist.N:
                                                      return "D" if dist.C > dist.D else "N"
                                                      return "C" if dist.N > dist.D else "N"

                                                      assert(0) #, "I am not a number! I am a free man!")

                                                      def update_history(self):
                                                      self.my_choices += self.choice
                                                      if len(self.my_choices) > self.MARKOV_ORDER:
                                                      assert(len(self.my_choices) == self.MARKOV_ORDER + 1)
                                                      self.my_choices = self.my_choices[1:]

                                                      def round(self, last):
                                                      if last: self.update_opponent_model(last)

                                                      dist = self.get_distribution()
                                                      self.choice = self.choose(dist)
                                                      self.update_history()
                                                      return self.choice

                                                      class Ensemble:
                                                      def __init__(self):
                                                      self.models =
                                                      self.votes =
                                                      self.prev_choice =
                                                      for order in range(0, 6):
                                                      self.models.append(Number6("maxExpected", order))
                                                      self.models.append(Number6("randomize", order))
                                                      #self.models.append(Number6("argMax", order))
                                                      for i in range(0, len(self.models)):
                                                      self.votes.append(0)
                                                      self.prev_choice.append("D")

                                                      self.payoff = {
                                                      "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
                                                      "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
                                                      "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
                                                      }

                                                      def round(self, last):
                                                      if last:
                                                      for i in range(0, len(self.models)):
                                                      self.votes[i] += self.payoff[self.prev_choice[i]][last]

                                                      # vote. Sufficiently terrible models get negative votes
                                                      C = 0
                                                      N = 0
                                                      D = 0
                                                      for i in range(0, len(self.models)):
                                                      choice = self.models[i].round(last)
                                                      if "C" == choice: C += self.votes[i]
                                                      if "N" == choice: N += self.votes[i]
                                                      if "D" == choice: D += self.votes[i]
                                                      self.prev_choice[i] = choice

                                                      if C > D and C > N: return "C"
                                                      elif N > D: return "N"
                                                      else: return "D"


                                                      Test Framework



                                                      In case anyone else finds it useful, here's a test framework for looking at individual matchups. Python2. Just put all the opponents you're interested in in opponents.py, and change the references to Ensemble to your own.



                                                      import sys, inspect
                                                      import opponents
                                                      from ensemble import Ensemble

                                                      def count_payoff(label, them):
                                                      if None == them: return
                                                      me = choices[label]
                                                      payoff = {
                                                      "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
                                                      "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
                                                      "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
                                                      }
                                                      if label not in total_payoff: total_payoff[label] = 0
                                                      total_payoff[label] += payoff[me][them]

                                                      def update_hist(label, choice):
                                                      choices[label] = choice

                                                      opponents = [ x[1] for x
                                                      in inspect.getmembers(sys.modules['opponents'], inspect.isclass)]

                                                      for k in opponents:
                                                      total_payoff = {}

                                                      for j in range(0, 100):
                                                      A = Ensemble()
                                                      B = k()
                                                      choices = {}

                                                      aChoice = None
                                                      bChoice = None
                                                      for i in range(0, 100):
                                                      count_payoff(A.__class__.__name__, bChoice)
                                                      a = A.round(bChoice)
                                                      update_hist(A.__class__.__name__, a)

                                                      count_payoff(B.__class__.__name__, aChoice)
                                                      b = B.round(aChoice)
                                                      update_hist(B.__class__.__name__, b)

                                                      aChoice = a
                                                      bChoice = b
                                                      print total_payoff





                                                      share|improve this answer











                                                      $endgroup$













                                                      • $begingroup$
                                                        The controller is ready, you didn't have to do all that...
                                                        $endgroup$
                                                        – Blacksilver
                                                        Nov 13 '18 at 3:40






                                                      • 1




                                                        $begingroup$
                                                        @Blacksilver I realized that just as I was about to submit. But this one works in versions before 3.6, and gives information about individual matchups that can help identify weak spots, so it wasn't a complete waste of time.
                                                        $endgroup$
                                                        – Ray
                                                        Nov 13 '18 at 3:42










                                                      • $begingroup$
                                                        Fair enough; running now. I'll probably add options to my controller to do similar things.
                                                        $endgroup$
                                                        – Blacksilver
                                                        Nov 13 '18 at 3:45










                                                      • $begingroup$
                                                        "It beats everything posted so far except Ensemble and PatternFinder" I'm honored :)
                                                        $endgroup$
                                                        – Sparr
                                                        Nov 13 '18 at 7:19










                                                      • $begingroup$
                                                        @Sparr Oops. That was supposed to say EvaluaterBot and PatternFinder. But that's when comparing total score against the entire field. PatternFinder remains the only one that beats this in a direct match up.
                                                        $endgroup$
                                                        – Ray
                                                        Nov 13 '18 at 8:04














                                                      3












                                                      3








                                                      3





                                                      $begingroup$

                                                      Ensemble



                                                      This runs an ensemble of related models. The individual models consider different amounts of history, and have the option of either always choosing the move that will optimize the expected payout difference, or will randomly select a move in proportion to expected payout difference.



                                                      Each member of the ensemble then votes on their preferred move. They get a number of votes equal to how much more they've won than the opponent (which means that terrible models will get negative votes). Whichever move wins the vote is then selected.



                                                      (They should probably split their votes among the moves in proportion to how much they favor each, but I don't care enough to do that right now.)



                                                      It beats everything posted so far except EvaluaterBot and PatternFinder. (One-on-one, it beats EvaluaterBot and loses to PatternFinder).



                                                      from collections import defaultdict
                                                      import random
                                                      class Number6:
                                                      class Choices:
                                                      def __init__(self, C = 0, N = 0, D = 0):
                                                      self.C = C
                                                      self.N = N
                                                      self.D = D

                                                      def __init__(self, strategy = "maxExpected", markov_order = 3):
                                                      self.MARKOV_ORDER = markov_order;
                                                      self.my_choices = ""
                                                      self.opponent = defaultdict(lambda: self.Choices())
                                                      self.choice = None # previous choice
                                                      self.payoff = {
                                                      "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
                                                      "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
                                                      "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
                                                      }
                                                      self.total_payoff = 0

                                                      # if random, will choose in proportion to payoff.
                                                      # otherwise, will always choose argmax
                                                      self.strategy = strategy
                                                      # maxExpected: maximize expected relative payoff
                                                      # random: like maxExpected, but it chooses in proportion to E[payoff]
                                                      # argmax: always choose the option that is optimal for expected opponent choice

                                                      def update_opponent_model(self, last):
                                                      for i in range(0, self.MARKOV_ORDER):
                                                      hist = self.my_choices[i:]
                                                      self.opponent[hist].C += ("C" == last)
                                                      self.opponent[hist].N += ("N" == last)
                                                      self.opponent[hist].D += ("D" == last)

                                                      def normalize(self, counts):
                                                      sum = float(counts.C + counts.N + counts.D)
                                                      if 0 == sum:
                                                      return self.Choices(1.0 / 3.0, 1.0 / 3.0, 1.0 / 3.0)
                                                      return self.Choices(
                                                      counts.C / sum, counts.N / sum, counts.D / sum)

                                                      def get_distribution(self):
                                                      for i in range(0, self.MARKOV_ORDER):
                                                      hist = self.my_choices[i:]
                                                      #print "check hist = " + hist
                                                      if hist in self.opponent:
                                                      return self.normalize(self.opponent[hist])

                                                      return self.Choices(1.0 / 3.0, 1.0 / 3.0, 1.0 / 3.0)

                                                      def choose(self, dist):
                                                      payoff = self.Choices()
                                                      # We're interested in *beating the opponent*, not
                                                      # maximizing our score, so we optimize the difference
                                                      payoff.C = (3-3) * dist.C + (4-1) * dist.N + (0-5) * dist.D
                                                      payoff.N = (1-4) * dist.C + (2-2) * dist.N + (3-2) * dist.D
                                                      payoff.D = (5-0) * dist.C + (2-3) * dist.N + (1-1) * dist.D

                                                      # D has slightly better payoff on uniform opponent,
                                                      # so we select it on ties
                                                      if self.strategy == "maxExpected":
                                                      if payoff.C > payoff.N:
                                                      return "C" if payoff.C > payoff.D else "D"
                                                      return "N" if payoff.N > payoff.D else "D"
                                                      elif self.strategy == "randomize":
                                                      payoff = self.normalize(payoff)
                                                      r = random.uniform(0.0, 1.0)
                                                      if (r < payoff.C): return "C"
                                                      return "N" if (r < payoff.N) else "D"
                                                      elif self.strategy == "argMax":
                                                      if dist.C > dist.N:
                                                      return "D" if dist.C > dist.D else "N"
                                                      return "C" if dist.N > dist.D else "N"

                                                      assert(0) #, "I am not a number! I am a free man!")

                                                      def update_history(self):
                                                      self.my_choices += self.choice
                                                      if len(self.my_choices) > self.MARKOV_ORDER:
                                                      assert(len(self.my_choices) == self.MARKOV_ORDER + 1)
                                                      self.my_choices = self.my_choices[1:]

                                                      def round(self, last):
                                                      if last: self.update_opponent_model(last)

                                                      dist = self.get_distribution()
                                                      self.choice = self.choose(dist)
                                                      self.update_history()
                                                      return self.choice

                                                      class Ensemble:
                                                      def __init__(self):
                                                      self.models =
                                                      self.votes =
                                                      self.prev_choice =
                                                      for order in range(0, 6):
                                                      self.models.append(Number6("maxExpected", order))
                                                      self.models.append(Number6("randomize", order))
                                                      #self.models.append(Number6("argMax", order))
                                                      for i in range(0, len(self.models)):
                                                      self.votes.append(0)
                                                      self.prev_choice.append("D")

                                                      self.payoff = {
                                                      "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
                                                      "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
                                                      "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
                                                      }

                                                      def round(self, last):
                                                      if last:
                                                      for i in range(0, len(self.models)):
                                                      self.votes[i] += self.payoff[self.prev_choice[i]][last]

                                                      # vote. Sufficiently terrible models get negative votes
                                                      C = 0
                                                      N = 0
                                                      D = 0
                                                      for i in range(0, len(self.models)):
                                                      choice = self.models[i].round(last)
                                                      if "C" == choice: C += self.votes[i]
                                                      if "N" == choice: N += self.votes[i]
                                                      if "D" == choice: D += self.votes[i]
                                                      self.prev_choice[i] = choice

                                                      if C > D and C > N: return "C"
                                                      elif N > D: return "N"
                                                      else: return "D"


                                                      Test Framework



                                                      In case anyone else finds it useful, here's a test framework for looking at individual matchups. Python2. Just put all the opponents you're interested in in opponents.py, and change the references to Ensemble to your own.



                                                      import sys, inspect
                                                      import opponents
                                                      from ensemble import Ensemble

                                                      def count_payoff(label, them):
                                                      if None == them: return
                                                      me = choices[label]
                                                      payoff = {
                                                      "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
                                                      "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
                                                      "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
                                                      }
                                                      if label not in total_payoff: total_payoff[label] = 0
                                                      total_payoff[label] += payoff[me][them]

                                                      def update_hist(label, choice):
                                                      choices[label] = choice

                                                      opponents = [ x[1] for x
                                                      in inspect.getmembers(sys.modules['opponents'], inspect.isclass)]

                                                      for k in opponents:
                                                      total_payoff = {}

                                                      for j in range(0, 100):
                                                      A = Ensemble()
                                                      B = k()
                                                      choices = {}

                                                      aChoice = None
                                                      bChoice = None
                                                      for i in range(0, 100):
                                                      count_payoff(A.__class__.__name__, bChoice)
                                                      a = A.round(bChoice)
                                                      update_hist(A.__class__.__name__, a)

                                                      count_payoff(B.__class__.__name__, aChoice)
                                                      b = B.round(aChoice)
                                                      update_hist(B.__class__.__name__, b)

                                                      aChoice = a
                                                      bChoice = b
                                                      print total_payoff





                                                      share|improve this answer











                                                      $endgroup$



                                                      Ensemble



                                                      This runs an ensemble of related models. The individual models consider different amounts of history, and have the option of either always choosing the move that will optimize the expected payout difference, or will randomly select a move in proportion to expected payout difference.



                                                      Each member of the ensemble then votes on their preferred move. They get a number of votes equal to how much more they've won than the opponent (which means that terrible models will get negative votes). Whichever move wins the vote is then selected.



                                                      (They should probably split their votes among the moves in proportion to how much they favor each, but I don't care enough to do that right now.)



                                                      It beats everything posted so far except EvaluaterBot and PatternFinder. (One-on-one, it beats EvaluaterBot and loses to PatternFinder).



                                                      from collections import defaultdict
                                                      import random
                                                      class Number6:
                                                      class Choices:
                                                      def __init__(self, C = 0, N = 0, D = 0):
                                                      self.C = C
                                                      self.N = N
                                                      self.D = D

                                                      def __init__(self, strategy = "maxExpected", markov_order = 3):
                                                      self.MARKOV_ORDER = markov_order;
                                                      self.my_choices = ""
                                                      self.opponent = defaultdict(lambda: self.Choices())
                                                      self.choice = None # previous choice
                                                      self.payoff = {
                                                      "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
                                                      "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
                                                      "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
                                                      }
                                                      self.total_payoff = 0

                                                      # if random, will choose in proportion to payoff.
                                                      # otherwise, will always choose argmax
                                                      self.strategy = strategy
                                                      # maxExpected: maximize expected relative payoff
                                                      # random: like maxExpected, but it chooses in proportion to E[payoff]
                                                      # argmax: always choose the option that is optimal for expected opponent choice

                                                      def update_opponent_model(self, last):
                                                      for i in range(0, self.MARKOV_ORDER):
                                                      hist = self.my_choices[i:]
                                                      self.opponent[hist].C += ("C" == last)
                                                      self.opponent[hist].N += ("N" == last)
                                                      self.opponent[hist].D += ("D" == last)

                                                      def normalize(self, counts):
                                                      sum = float(counts.C + counts.N + counts.D)
                                                      if 0 == sum:
                                                      return self.Choices(1.0 / 3.0, 1.0 / 3.0, 1.0 / 3.0)
                                                      return self.Choices(
                                                      counts.C / sum, counts.N / sum, counts.D / sum)

                                                      def get_distribution(self):
                                                      for i in range(0, self.MARKOV_ORDER):
                                                      hist = self.my_choices[i:]
                                                      #print "check hist = " + hist
                                                      if hist in self.opponent:
                                                      return self.normalize(self.opponent[hist])

                                                      return self.Choices(1.0 / 3.0, 1.0 / 3.0, 1.0 / 3.0)

                                                      def choose(self, dist):
                                                      payoff = self.Choices()
                                                      # We're interested in *beating the opponent*, not
                                                      # maximizing our score, so we optimize the difference
                                                      payoff.C = (3-3) * dist.C + (4-1) * dist.N + (0-5) * dist.D
                                                      payoff.N = (1-4) * dist.C + (2-2) * dist.N + (3-2) * dist.D
                                                      payoff.D = (5-0) * dist.C + (2-3) * dist.N + (1-1) * dist.D

                                                      # D has slightly better payoff on uniform opponent,
                                                      # so we select it on ties
                                                      if self.strategy == "maxExpected":
                                                      if payoff.C > payoff.N:
                                                      return "C" if payoff.C > payoff.D else "D"
                                                      return "N" if payoff.N > payoff.D else "D"
                                                      elif self.strategy == "randomize":
                                                      payoff = self.normalize(payoff)
                                                      r = random.uniform(0.0, 1.0)
                                                      if (r < payoff.C): return "C"
                                                      return "N" if (r < payoff.N) else "D"
                                                      elif self.strategy == "argMax":
                                                      if dist.C > dist.N:
                                                      return "D" if dist.C > dist.D else "N"
                                                      return "C" if dist.N > dist.D else "N"

                                                      assert(0) #, "I am not a number! I am a free man!")

                                                      def update_history(self):
                                                      self.my_choices += self.choice
                                                      if len(self.my_choices) > self.MARKOV_ORDER:
                                                      assert(len(self.my_choices) == self.MARKOV_ORDER + 1)
                                                      self.my_choices = self.my_choices[1:]

                                                      def round(self, last):
                                                      if last: self.update_opponent_model(last)

                                                      dist = self.get_distribution()
                                                      self.choice = self.choose(dist)
                                                      self.update_history()
                                                      return self.choice

                                                      class Ensemble:
                                                      def __init__(self):
                                                      self.models =
                                                      self.votes =
                                                      self.prev_choice =
                                                      for order in range(0, 6):
                                                      self.models.append(Number6("maxExpected", order))
                                                      self.models.append(Number6("randomize", order))
                                                      #self.models.append(Number6("argMax", order))
                                                      for i in range(0, len(self.models)):
                                                      self.votes.append(0)
                                                      self.prev_choice.append("D")

                                                      self.payoff = {
                                                      "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
                                                      "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
                                                      "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
                                                      }

                                                      def round(self, last):
                                                      if last:
                                                      for i in range(0, len(self.models)):
                                                      self.votes[i] += self.payoff[self.prev_choice[i]][last]

                                                      # vote. Sufficiently terrible models get negative votes
                                                      C = 0
                                                      N = 0
                                                      D = 0
                                                      for i in range(0, len(self.models)):
                                                      choice = self.models[i].round(last)
                                                      if "C" == choice: C += self.votes[i]
                                                      if "N" == choice: N += self.votes[i]
                                                      if "D" == choice: D += self.votes[i]
                                                      self.prev_choice[i] = choice

                                                      if C > D and C > N: return "C"
                                                      elif N > D: return "N"
                                                      else: return "D"


                                                      Test Framework



                                                      In case anyone else finds it useful, here's a test framework for looking at individual matchups. Python2. Just put all the opponents you're interested in in opponents.py, and change the references to Ensemble to your own.



                                                      import sys, inspect
                                                      import opponents
                                                      from ensemble import Ensemble

                                                      def count_payoff(label, them):
                                                      if None == them: return
                                                      me = choices[label]
                                                      payoff = {
                                                      "C": { "C": 3-3, "N": 4-1, "D": 0-5 },
                                                      "N": { "C": 1-4, "N": 2-2, "D": 3-2 },
                                                      "D": { "C": 5-0, "N": 2-3, "D": 1-1 },
                                                      }
                                                      if label not in total_payoff: total_payoff[label] = 0
                                                      total_payoff[label] += payoff[me][them]

                                                      def update_hist(label, choice):
                                                      choices[label] = choice

                                                      opponents = [ x[1] for x
                                                      in inspect.getmembers(sys.modules['opponents'], inspect.isclass)]

                                                      for k in opponents:
                                                      total_payoff = {}

                                                      for j in range(0, 100):
                                                      A = Ensemble()
                                                      B = k()
                                                      choices = {}

                                                      aChoice = None
                                                      bChoice = None
                                                      for i in range(0, 100):
                                                      count_payoff(A.__class__.__name__, bChoice)
                                                      a = A.round(bChoice)
                                                      update_hist(A.__class__.__name__, a)

                                                      count_payoff(B.__class__.__name__, aChoice)
                                                      b = B.round(aChoice)
                                                      update_hist(B.__class__.__name__, b)

                                                      aChoice = a
                                                      bChoice = b
                                                      print total_payoff






                                                      share|improve this answer














                                                      share|improve this answer



                                                      share|improve this answer








                                                      edited Nov 13 '18 at 7:59

























                                                      answered Nov 13 '18 at 3:39









                                                      RayRay

                                                      1,448511




                                                      1,448511












                                                      • $begingroup$
                                                        The controller is ready, you didn't have to do all that...
                                                        $endgroup$
                                                        – Blacksilver
                                                        Nov 13 '18 at 3:40






                                                      • 1




                                                        $begingroup$
                                                        @Blacksilver I realized that just as I was about to submit. But this one works in versions before 3.6, and gives information about individual matchups that can help identify weak spots, so it wasn't a complete waste of time.
                                                        $endgroup$
                                                        – Ray
                                                        Nov 13 '18 at 3:42










                                                      • $begingroup$
                                                        Fair enough; running now. I'll probably add options to my controller to do similar things.
                                                        $endgroup$
                                                        – Blacksilver
                                                        Nov 13 '18 at 3:45










                                                      • $begingroup$
                                                        "It beats everything posted so far except Ensemble and PatternFinder" I'm honored :)
                                                        $endgroup$
                                                        – Sparr
                                                        Nov 13 '18 at 7:19










                                                      • $begingroup$
                                                        @Sparr Oops. That was supposed to say EvaluaterBot and PatternFinder. But that's when comparing total score against the entire field. PatternFinder remains the only one that beats this in a direct match up.
                                                        $endgroup$
                                                        – Ray
                                                        Nov 13 '18 at 8:04


















                                                      • $begingroup$
                                                        The controller is ready, you didn't have to do all that...
                                                        $endgroup$
                                                        – Blacksilver
                                                        Nov 13 '18 at 3:40






                                                      • 1




                                                        $begingroup$
                                                        @Blacksilver I realized that just as I was about to submit. But this one works in versions before 3.6, and gives information about individual matchups that can help identify weak spots, so it wasn't a complete waste of time.
                                                        $endgroup$
                                                        – Ray
                                                        Nov 13 '18 at 3:42










                                                      • $begingroup$
                                                        Fair enough; running now. I'll probably add options to my controller to do similar things.
                                                        $endgroup$
                                                        – Blacksilver
                                                        Nov 13 '18 at 3:45










                                                      • $begingroup$
                                                        "It beats everything posted so far except Ensemble and PatternFinder" I'm honored :)
                                                        $endgroup$
                                                        – Sparr
                                                        Nov 13 '18 at 7:19










                                                      • $begingroup$
                                                        @Sparr Oops. That was supposed to say EvaluaterBot and PatternFinder. But that's when comparing total score against the entire field. PatternFinder remains the only one that beats this in a direct match up.
                                                        $endgroup$
                                                        – Ray
                                                        Nov 13 '18 at 8:04
















                                                      $begingroup$
                                                      The controller is ready, you didn't have to do all that...
                                                      $endgroup$
                                                      – Blacksilver
                                                      Nov 13 '18 at 3:40




                                                      $begingroup$
                                                      The controller is ready, you didn't have to do all that...
                                                      $endgroup$
                                                      – Blacksilver
                                                      Nov 13 '18 at 3:40




                                                      1




                                                      1




                                                      $begingroup$
                                                      @Blacksilver I realized that just as I was about to submit. But this one works in versions before 3.6, and gives information about individual matchups that can help identify weak spots, so it wasn't a complete waste of time.
                                                      $endgroup$
                                                      – Ray
                                                      Nov 13 '18 at 3:42




                                                      $begingroup$
                                                      @Blacksilver I realized that just as I was about to submit. But this one works in versions before 3.6, and gives information about individual matchups that can help identify weak spots, so it wasn't a complete waste of time.
                                                      $endgroup$
                                                      – Ray
                                                      Nov 13 '18 at 3:42












                                                      $begingroup$
                                                      Fair enough; running now. I'll probably add options to my controller to do similar things.
                                                      $endgroup$
                                                      – Blacksilver
                                                      Nov 13 '18 at 3:45




                                                      $begingroup$
                                                      Fair enough; running now. I'll probably add options to my controller to do similar things.
                                                      $endgroup$
                                                      – Blacksilver
                                                      Nov 13 '18 at 3:45












                                                      $begingroup$
                                                      "It beats everything posted so far except Ensemble and PatternFinder" I'm honored :)
                                                      $endgroup$
                                                      – Sparr
                                                      Nov 13 '18 at 7:19




                                                      $begingroup$
                                                      "It beats everything posted so far except Ensemble and PatternFinder" I'm honored :)
                                                      $endgroup$
                                                      – Sparr
                                                      Nov 13 '18 at 7:19












                                                      $begingroup$
                                                      @Sparr Oops. That was supposed to say EvaluaterBot and PatternFinder. But that's when comparing total score against the entire field. PatternFinder remains the only one that beats this in a direct match up.
                                                      $endgroup$
                                                      – Ray
                                                      Nov 13 '18 at 8:04




                                                      $begingroup$
                                                      @Sparr Oops. That was supposed to say EvaluaterBot and PatternFinder. But that's when comparing total score against the entire field. PatternFinder remains the only one that beats this in a direct match up.
                                                      $endgroup$
                                                      – Ray
                                                      Nov 13 '18 at 8:04











                                                      2












                                                      $begingroup$

                                                      Improved Dirichlet Dice



                                                      import random

                                                      class DirichletDice2:
                                                      def __init__(self):

                                                      self.alpha = dict(
                                                      C = {'C' : 1, 'N' : 1, 'D' : 1},
                                                      N = {'C' : 1, 'N' : 1, 'D' : 1},
                                                      D = {'C' : 1, 'N' : 1, 'D' : 1}
                                                      )
                                                      self.myLast = [None, None]
                                                      self.payoff = dict(
                                                      C = { "C": 0, "N": 3, "D": -5 },
                                                      N = { "C": -3, "N": 0, "D": 1 },
                                                      D = { "C": 5, "N": -1, "D": 0 }
                                                      )

                                                      def DirichletDraw(self, key):
                                                      alpha = self.alpha[key].values()
                                                      mu = [random.gammavariate(a,1) for a in alpha]
                                                      mu = [m / sum(mu) for m in mu]
                                                      return mu

                                                      def ExpectedPayoff(self, probs):
                                                      expectedPayoff = {}
                                                      for val in ['C','N','D']:
                                                      payoff = sum([p * v for p,v in zip(probs, self.payoff[val].values())])
                                                      expectedPayoff[val] = payoff
                                                      return expectedPayoff

                                                      def round(self, last):
                                                      if last is None:
                                                      self.myLast[0] = 'D'
                                                      return 'D'

                                                      #update dice corresponding to opponent's last response to my
                                                      #outcome two turns ago
                                                      if self.myLast[1] is not None:
                                                      self.alpha[self.myLast[1]][last] += 1

                                                      #draw probs for my opponent's roll from Dirichlet distribution and then return the optimal response
                                                      mu = self.DirichletDraw(self.myLast[0])
                                                      expectedPayoff = self.ExpectedPayoff(mu)
                                                      res = max(expectedPayoff, key=expectedPayoff.get)

                                                      #update myLast
                                                      self.myLast[1] = self.myLast[0]
                                                      self.myLast[0] = res

                                                      return res


                                                      This is an improved version of Dirichlet Dice. Instead of taking the expected multinomial distribution from the Dirichlet distribution, it draws a Multinomial distribution randomly from the Dirichlet distribution. Then, instead of drawing from the Multinomial and giving the optimal response to that, it gives the optimal expected response to the given Multinomial using the points. So the randomness has essentially been shifted from the Multinomial draw to the Dirichlet draw. Also, the priors are more flat now, to encourage exploration.



                                                      It's "improved" because it now accounts for the points system by giving the best expected value against the probabilities, while maintaining its randomness by drawing the probabilities themselves. Before, I tried simply doing the best expected payoff from the expected probabilities, but that did badly because it just got stuck, and didn't explore enough to update its dice. Also it was more predictable and exploitable.





                                                      Original submission:



                                                      Dirichlet Dice



                                                      import random

                                                      class DirichletDice:
                                                      def __init__(self):

                                                      self.alpha = dict(
                                                      C = {'C' : 2, 'N' : 3, 'D' : 1},
                                                      N = {'C' : 1, 'N' : 2, 'D' : 3},
                                                      D = {'C' : 3, 'N' : 1, 'D' : 2}
                                                      )

                                                      self.Response = {'C' : 'D', 'N' : 'C', 'D' : 'N'}
                                                      self.myLast = [None, None]

                                                      #expected value of the dirichlet distribution given by Alpha
                                                      def MultinomialDraw(self, key):
                                                      alpha = list(self.alpha[key].values())
                                                      probs = [x / sum(alpha) for x in alpha]
                                                      outcome = random.choices(['C','N','D'], weights=probs)[0]
                                                      return outcome

                                                      def round(self, last):
                                                      if last is None:
                                                      self.myLast[0] = 'D'
                                                      return 'D'

                                                      #update dice corresponding to opponent's last response to my
                                                      #outcome two turns ago
                                                      if self.myLast[1] is not None:
                                                      self.alpha[self.myLast[1]][last] += 1

                                                      #predict opponent's move based on my last move
                                                      predict = self.MultinomialDraw(self.myLast[0])
                                                      res = self.Response[predict]

                                                      #update myLast
                                                      self.myLast[1] = self.myLast[0]
                                                      self.myLast[0] = res

                                                      return res


                                                      Basically I'm assuming that the opponent's response to my last output is a multinomial variable (weighted dice), one for each of my outputs, so there's a dice for "C", one for "N", and one for "D". So if my last roll was, for example, a "N" then I roll the "N-dice" to guess what their response would be to my "N". I begin with a Dirichlet prior that assumes that my opponent is somewhat "smart" (more likely to play the one with the best payoff against my last roll, least likely to play the one with the worst payoff). I generate the "expected" Multinomial distribution from the appropriate Dirichlet prior (this is the expected value of the probability distribution over their dice weights). I roll the weighted dice of my last output, and respond with the one with the best payoff against that dice outcome.



                                                      Starting in the third round, I do a Bayesian update of the appropriate Dirichlet prior of my opponent's last response to the thing I played two rounds ago. I'm trying to iteratively learn their dice weightings.



                                                      I could have also simply picked the response with the best "expected" outcome once generating the dice, instead of simply rolling the dice and responding to the outcome. However, I wanted to keep the randomness in, so that my bot is less vulnerable to the ones that try to predict a pattern.






                                                      share|improve this answer











                                                      $endgroup$


















                                                        2












                                                        $begingroup$

                                                        Improved Dirichlet Dice



                                                        import random

                                                        class DirichletDice2:
                                                        def __init__(self):

                                                        self.alpha = dict(
                                                        C = {'C' : 1, 'N' : 1, 'D' : 1},
                                                        N = {'C' : 1, 'N' : 1, 'D' : 1},
                                                        D = {'C' : 1, 'N' : 1, 'D' : 1}
                                                        )
                                                        self.myLast = [None, None]
                                                        self.payoff = dict(
                                                        C = { "C": 0, "N": 3, "D": -5 },
                                                        N = { "C": -3, "N": 0, "D": 1 },
                                                        D = { "C": 5, "N": -1, "D": 0 }
                                                        )

                                                        def DirichletDraw(self, key):
                                                        alpha = self.alpha[key].values()
                                                        mu = [random.gammavariate(a,1) for a in alpha]
                                                        mu = [m / sum(mu) for m in mu]
                                                        return mu

                                                        def ExpectedPayoff(self, probs):
                                                        expectedPayoff = {}
                                                        for val in ['C','N','D']:
                                                        payoff = sum([p * v for p,v in zip(probs, self.payoff[val].values())])
                                                        expectedPayoff[val] = payoff
                                                        return expectedPayoff

                                                        def round(self, last):
                                                        if last is None:
                                                        self.myLast[0] = 'D'
                                                        return 'D'

                                                        #update dice corresponding to opponent's last response to my
                                                        #outcome two turns ago
                                                        if self.myLast[1] is not None:
                                                        self.alpha[self.myLast[1]][last] += 1

                                                        #draw probs for my opponent's roll from Dirichlet distribution and then return the optimal response
                                                        mu = self.DirichletDraw(self.myLast[0])
                                                        expectedPayoff = self.ExpectedPayoff(mu)
                                                        res = max(expectedPayoff, key=expectedPayoff.get)

                                                        #update myLast
                                                        self.myLast[1] = self.myLast[0]
                                                        self.myLast[0] = res

                                                        return res


                                                        This is an improved version of Dirichlet Dice. Instead of taking the expected multinomial distribution from the Dirichlet distribution, it draws a Multinomial distribution randomly from the Dirichlet distribution. Then, instead of drawing from the Multinomial and giving the optimal response to that, it gives the optimal expected response to the given Multinomial using the points. So the randomness has essentially been shifted from the Multinomial draw to the Dirichlet draw. Also, the priors are more flat now, to encourage exploration.



                                                        It's "improved" because it now accounts for the points system by giving the best expected value against the probabilities, while maintaining its randomness by drawing the probabilities themselves. Before, I tried simply doing the best expected payoff from the expected probabilities, but that did badly because it just got stuck, and didn't explore enough to update its dice. Also it was more predictable and exploitable.





                                                        Original submission:



                                                        Dirichlet Dice



                                                        import random

                                                        class DirichletDice:
                                                        def __init__(self):

                                                        self.alpha = dict(
                                                        C = {'C' : 2, 'N' : 3, 'D' : 1},
                                                        N = {'C' : 1, 'N' : 2, 'D' : 3},
                                                        D = {'C' : 3, 'N' : 1, 'D' : 2}
                                                        )

                                                        self.Response = {'C' : 'D', 'N' : 'C', 'D' : 'N'}
                                                        self.myLast = [None, None]

                                                        #expected value of the dirichlet distribution given by Alpha
                                                        def MultinomialDraw(self, key):
                                                        alpha = list(self.alpha[key].values())
                                                        probs = [x / sum(alpha) for x in alpha]
                                                        outcome = random.choices(['C','N','D'], weights=probs)[0]
                                                        return outcome

                                                        def round(self, last):
                                                        if last is None:
                                                        self.myLast[0] = 'D'
                                                        return 'D'

                                                        #update dice corresponding to opponent's last response to my
                                                        #outcome two turns ago
                                                        if self.myLast[1] is not None:
                                                        self.alpha[self.myLast[1]][last] += 1

                                                        #predict opponent's move based on my last move
                                                        predict = self.MultinomialDraw(self.myLast[0])
                                                        res = self.Response[predict]

                                                        #update myLast
                                                        self.myLast[1] = self.myLast[0]
                                                        self.myLast[0] = res

                                                        return res


                                                        Basically I'm assuming that the opponent's response to my last output is a multinomial variable (weighted dice), one for each of my outputs, so there's a dice for "C", one for "N", and one for "D". So if my last roll was, for example, a "N" then I roll the "N-dice" to guess what their response would be to my "N". I begin with a Dirichlet prior that assumes that my opponent is somewhat "smart" (more likely to play the one with the best payoff against my last roll, least likely to play the one with the worst payoff). I generate the "expected" Multinomial distribution from the appropriate Dirichlet prior (this is the expected value of the probability distribution over their dice weights). I roll the weighted dice of my last output, and respond with the one with the best payoff against that dice outcome.



                                                        Starting in the third round, I do a Bayesian update of the appropriate Dirichlet prior of my opponent's last response to the thing I played two rounds ago. I'm trying to iteratively learn their dice weightings.



                                                        I could have also simply picked the response with the best "expected" outcome once generating the dice, instead of simply rolling the dice and responding to the outcome. However, I wanted to keep the randomness in, so that my bot is less vulnerable to the ones that try to predict a pattern.






                                                        share|improve this answer











                                                        $endgroup$
















                                                          2












                                                          2








                                                          2





                                                          $begingroup$

                                                          Improved Dirichlet Dice



                                                          import random

                                                          class DirichletDice2:
                                                          def __init__(self):

                                                          self.alpha = dict(
                                                          C = {'C' : 1, 'N' : 1, 'D' : 1},
                                                          N = {'C' : 1, 'N' : 1, 'D' : 1},
                                                          D = {'C' : 1, 'N' : 1, 'D' : 1}
                                                          )
                                                          self.myLast = [None, None]
                                                          self.payoff = dict(
                                                          C = { "C": 0, "N": 3, "D": -5 },
                                                          N = { "C": -3, "N": 0, "D": 1 },
                                                          D = { "C": 5, "N": -1, "D": 0 }
                                                          )

                                                          def DirichletDraw(self, key):
                                                          alpha = self.alpha[key].values()
                                                          mu = [random.gammavariate(a,1) for a in alpha]
                                                          mu = [m / sum(mu) for m in mu]
                                                          return mu

                                                          def ExpectedPayoff(self, probs):
                                                          expectedPayoff = {}
                                                          for val in ['C','N','D']:
                                                          payoff = sum([p * v for p,v in zip(probs, self.payoff[val].values())])
                                                          expectedPayoff[val] = payoff
                                                          return expectedPayoff

                                                          def round(self, last):
                                                          if last is None:
                                                          self.myLast[0] = 'D'
                                                          return 'D'

                                                          #update dice corresponding to opponent's last response to my
                                                          #outcome two turns ago
                                                          if self.myLast[1] is not None:
                                                          self.alpha[self.myLast[1]][last] += 1

                                                          #draw probs for my opponent's roll from Dirichlet distribution and then return the optimal response
                                                          mu = self.DirichletDraw(self.myLast[0])
                                                          expectedPayoff = self.ExpectedPayoff(mu)
                                                          res = max(expectedPayoff, key=expectedPayoff.get)

                                                          #update myLast
                                                          self.myLast[1] = self.myLast[0]
                                                          self.myLast[0] = res

                                                          return res


                                                          This is an improved version of Dirichlet Dice. Instead of taking the expected multinomial distribution from the Dirichlet distribution, it draws a Multinomial distribution randomly from the Dirichlet distribution. Then, instead of drawing from the Multinomial and giving the optimal response to that, it gives the optimal expected response to the given Multinomial using the points. So the randomness has essentially been shifted from the Multinomial draw to the Dirichlet draw. Also, the priors are more flat now, to encourage exploration.



                                                          It's "improved" because it now accounts for the points system by giving the best expected value against the probabilities, while maintaining its randomness by drawing the probabilities themselves. Before, I tried simply doing the best expected payoff from the expected probabilities, but that did badly because it just got stuck, and didn't explore enough to update its dice. Also it was more predictable and exploitable.





                                                          Original submission:



                                                          Dirichlet Dice



                                                          import random

                                                          class DirichletDice:
                                                          def __init__(self):

                                                          self.alpha = dict(
                                                          C = {'C' : 2, 'N' : 3, 'D' : 1},
                                                          N = {'C' : 1, 'N' : 2, 'D' : 3},
                                                          D = {'C' : 3, 'N' : 1, 'D' : 2}
                                                          )

                                                          self.Response = {'C' : 'D', 'N' : 'C', 'D' : 'N'}
                                                          self.myLast = [None, None]

                                                          #expected value of the dirichlet distribution given by Alpha
                                                          def MultinomialDraw(self, key):
                                                          alpha = list(self.alpha[key].values())
                                                          probs = [x / sum(alpha) for x in alpha]
                                                          outcome = random.choices(['C','N','D'], weights=probs)[0]
                                                          return outcome

                                                          def round(self, last):
                                                          if last is None:
                                                          self.myLast[0] = 'D'
                                                          return 'D'

                                                          #update dice corresponding to opponent's last response to my
                                                          #outcome two turns ago
                                                          if self.myLast[1] is not None:
                                                          self.alpha[self.myLast[1]][last] += 1

                                                          #predict opponent's move based on my last move
                                                          predict = self.MultinomialDraw(self.myLast[0])
                                                          res = self.Response[predict]

                                                          #update myLast
                                                          self.myLast[1] = self.myLast[0]
                                                          self.myLast[0] = res

                                                          return res


                                                          Basically I'm assuming that the opponent's response to my last output is a multinomial variable (weighted dice), one for each of my outputs, so there's a dice for "C", one for "N", and one for "D". So if my last roll was, for example, a "N" then I roll the "N-dice" to guess what their response would be to my "N". I begin with a Dirichlet prior that assumes that my opponent is somewhat "smart" (more likely to play the one with the best payoff against my last roll, least likely to play the one with the worst payoff). I generate the "expected" Multinomial distribution from the appropriate Dirichlet prior (this is the expected value of the probability distribution over their dice weights). I roll the weighted dice of my last output, and respond with the one with the best payoff against that dice outcome.



                                                          Starting in the third round, I do a Bayesian update of the appropriate Dirichlet prior of my opponent's last response to the thing I played two rounds ago. I'm trying to iteratively learn their dice weightings.



                                                          I could have also simply picked the response with the best "expected" outcome once generating the dice, instead of simply rolling the dice and responding to the outcome. However, I wanted to keep the randomness in, so that my bot is less vulnerable to the ones that try to predict a pattern.






                                                          share|improve this answer











                                                          $endgroup$



                                                          Improved Dirichlet Dice



                                                          import random

                                                          class DirichletDice2:
                                                          def __init__(self):

                                                          self.alpha = dict(
                                                          C = {'C' : 1, 'N' : 1, 'D' : 1},
                                                          N = {'C' : 1, 'N' : 1, 'D' : 1},
                                                          D = {'C' : 1, 'N' : 1, 'D' : 1}
                                                          )
                                                          self.myLast = [None, None]
                                                          self.payoff = dict(
                                                          C = { "C": 0, "N": 3, "D": -5 },
                                                          N = { "C": -3, "N": 0, "D": 1 },
                                                          D = { "C": 5, "N": -1, "D": 0 }
                                                          )

                                                          def DirichletDraw(self, key):
                                                          alpha = self.alpha[key].values()
                                                          mu = [random.gammavariate(a,1) for a in alpha]
                                                          mu = [m / sum(mu) for m in mu]
                                                          return mu

                                                          def ExpectedPayoff(self, probs):
                                                          expectedPayoff = {}
                                                          for val in ['C','N','D']:
                                                          payoff = sum([p * v for p,v in zip(probs, self.payoff[val].values())])
                                                          expectedPayoff[val] = payoff
                                                          return expectedPayoff

                                                          def round(self, last):
                                                          if last is None:
                                                          self.myLast[0] = 'D'
                                                          return 'D'

                                                          #update dice corresponding to opponent's last response to my
                                                          #outcome two turns ago
                                                          if self.myLast[1] is not None:
                                                          self.alpha[self.myLast[1]][last] += 1

                                                          #draw probs for my opponent's roll from Dirichlet distribution and then return the optimal response
                                                          mu = self.DirichletDraw(self.myLast[0])
                                                          expectedPayoff = self.ExpectedPayoff(mu)
                                                          res = max(expectedPayoff, key=expectedPayoff.get)

                                                          #update myLast
                                                          self.myLast[1] = self.myLast[0]
                                                          self.myLast[0] = res

                                                          return res


                                                          This is an improved version of Dirichlet Dice. Instead of taking the expected multinomial distribution from the Dirichlet distribution, it draws a Multinomial distribution randomly from the Dirichlet distribution. Then, instead of drawing from the Multinomial and giving the optimal response to that, it gives the optimal expected response to the given Multinomial using the points. So the randomness has essentially been shifted from the Multinomial draw to the Dirichlet draw. Also, the priors are more flat now, to encourage exploration.



                                                          It's "improved" because it now accounts for the points system by giving the best expected value against the probabilities, while maintaining its randomness by drawing the probabilities themselves. Before, I tried simply doing the best expected payoff from the expected probabilities, but that did badly because it just got stuck, and didn't explore enough to update its dice. Also it was more predictable and exploitable.





                                                          Original submission:



                                                          Dirichlet Dice



                                                          import random

                                                          class DirichletDice:
                                                          def __init__(self):

                                                          self.alpha = dict(
                                                          C = {'C' : 2, 'N' : 3, 'D' : 1},
                                                          N = {'C' : 1, 'N' : 2, 'D' : 3},
                                                          D = {'C' : 3, 'N' : 1, 'D' : 2}
                                                          )

                                                          self.Response = {'C' : 'D', 'N' : 'C', 'D' : 'N'}
                                                          self.myLast = [None, None]

                                                          #expected value of the dirichlet distribution given by Alpha
                                                          def MultinomialDraw(self, key):
                                                          alpha = list(self.alpha[key].values())
                                                          probs = [x / sum(alpha) for x in alpha]
                                                          outcome = random.choices(['C','N','D'], weights=probs)[0]
                                                          return outcome

                                                          def round(self, last):
                                                          if last is None:
                                                          self.myLast[0] = 'D'
                                                          return 'D'

                                                          #update dice corresponding to opponent's last response to my
                                                          #outcome two turns ago
                                                          if self.myLast[1] is not None:
                                                          self.alpha[self.myLast[1]][last] += 1

                                                          #predict opponent's move based on my last move
                                                          predict = self.MultinomialDraw(self.myLast[0])
                                                          res = self.Response[predict]

                                                          #update myLast
                                                          self.myLast[1] = self.myLast[0]
                                                          self.myLast[0] = res

                                                          return res


                                                          Basically I'm assuming that the opponent's response to my last output is a multinomial variable (weighted dice), one for each of my outputs, so there's a dice for "C", one for "N", and one for "D". So if my last roll was, for example, a "N" then I roll the "N-dice" to guess what their response would be to my "N". I begin with a Dirichlet prior that assumes that my opponent is somewhat "smart" (more likely to play the one with the best payoff against my last roll, least likely to play the one with the worst payoff). I generate the "expected" Multinomial distribution from the appropriate Dirichlet prior (this is the expected value of the probability distribution over their dice weights). I roll the weighted dice of my last output, and respond with the one with the best payoff against that dice outcome.



                                                          Starting in the third round, I do a Bayesian update of the appropriate Dirichlet prior of my opponent's last response to the thing I played two rounds ago. I'm trying to iteratively learn their dice weightings.



                                                          I could have also simply picked the response with the best "expected" outcome once generating the dice, instead of simply rolling the dice and responding to the outcome. However, I wanted to keep the randomness in, so that my bot is less vulnerable to the ones that try to predict a pattern.







                                                          share|improve this answer














                                                          share|improve this answer



                                                          share|improve this answer








                                                          edited Nov 14 '18 at 17:44

























                                                          answered Nov 13 '18 at 19:12









                                                          BridgeburnersBridgeburners

                                                          1212




                                                          1212























                                                              2












                                                              $begingroup$

                                                              Kevin



                                                              class Kevin:
                                                              def round(self, last):
                                                              return {"C":"N","N":"D","D":"C",None:"N"} [last]


                                                              Picks the worst choice. The worst bot made.



                                                              Useless



                                                              import random

                                                              class Useless:
                                                              def __init__(self):
                                                              self.lastLast = None

                                                              def round(self, last):
                                                              tempLastLast = self.lastLast
                                                              self.lastLast = last

                                                              if(last == "D" and tempLastLast == "N"):
                                                              return "C"
                                                              if(last == "D" and tempLastLast == "C"):
                                                              return "N"

                                                              if(last == "N" and tempLastLast == "D"):
                                                              return "C"
                                                              if(last == "N" and tempLastLast == "C"):
                                                              return "D"

                                                              if(last == "C" and tempLastLast == "D"):
                                                              return "N"
                                                              if(last == "C" and tempLastLast == "N"):
                                                              return "D"

                                                              return random.choice("CND")


                                                              It looks at the last two moves done by the opponent and picks the most not done else it picks something random. There is probably a better way of doing this.






                                                              share|improve this answer











                                                              $endgroup$


















                                                                2












                                                                $begingroup$

                                                                Kevin



                                                                class Kevin:
                                                                def round(self, last):
                                                                return {"C":"N","N":"D","D":"C",None:"N"} [last]


                                                                Picks the worst choice. The worst bot made.



                                                                Useless



                                                                import random

                                                                class Useless:
                                                                def __init__(self):
                                                                self.lastLast = None

                                                                def round(self, last):
                                                                tempLastLast = self.lastLast
                                                                self.lastLast = last

                                                                if(last == "D" and tempLastLast == "N"):
                                                                return "C"
                                                                if(last == "D" and tempLastLast == "C"):
                                                                return "N"

                                                                if(last == "N" and tempLastLast == "D"):
                                                                return "C"
                                                                if(last == "N" and tempLastLast == "C"):
                                                                return "D"

                                                                if(last == "C" and tempLastLast == "D"):
                                                                return "N"
                                                                if(last == "C" and tempLastLast == "N"):
                                                                return "D"

                                                                return random.choice("CND")


                                                                It looks at the last two moves done by the opponent and picks the most not done else it picks something random. There is probably a better way of doing this.






                                                                share|improve this answer











                                                                $endgroup$
















                                                                  2












                                                                  2








                                                                  2





                                                                  $begingroup$

                                                                  Kevin



                                                                  class Kevin:
                                                                  def round(self, last):
                                                                  return {"C":"N","N":"D","D":"C",None:"N"} [last]


                                                                  Picks the worst choice. The worst bot made.



                                                                  Useless



                                                                  import random

                                                                  class Useless:
                                                                  def __init__(self):
                                                                  self.lastLast = None

                                                                  def round(self, last):
                                                                  tempLastLast = self.lastLast
                                                                  self.lastLast = last

                                                                  if(last == "D" and tempLastLast == "N"):
                                                                  return "C"
                                                                  if(last == "D" and tempLastLast == "C"):
                                                                  return "N"

                                                                  if(last == "N" and tempLastLast == "D"):
                                                                  return "C"
                                                                  if(last == "N" and tempLastLast == "C"):
                                                                  return "D"

                                                                  if(last == "C" and tempLastLast == "D"):
                                                                  return "N"
                                                                  if(last == "C" and tempLastLast == "N"):
                                                                  return "D"

                                                                  return random.choice("CND")


                                                                  It looks at the last two moves done by the opponent and picks the most not done else it picks something random. There is probably a better way of doing this.






                                                                  share|improve this answer











                                                                  $endgroup$



                                                                  Kevin



                                                                  class Kevin:
                                                                  def round(self, last):
                                                                  return {"C":"N","N":"D","D":"C",None:"N"} [last]


                                                                  Picks the worst choice. The worst bot made.



                                                                  Useless



                                                                  import random

                                                                  class Useless:
                                                                  def __init__(self):
                                                                  self.lastLast = None

                                                                  def round(self, last):
                                                                  tempLastLast = self.lastLast
                                                                  self.lastLast = last

                                                                  if(last == "D" and tempLastLast == "N"):
                                                                  return "C"
                                                                  if(last == "D" and tempLastLast == "C"):
                                                                  return "N"

                                                                  if(last == "N" and tempLastLast == "D"):
                                                                  return "C"
                                                                  if(last == "N" and tempLastLast == "C"):
                                                                  return "D"

                                                                  if(last == "C" and tempLastLast == "D"):
                                                                  return "N"
                                                                  if(last == "C" and tempLastLast == "N"):
                                                                  return "D"

                                                                  return random.choice("CND")


                                                                  It looks at the last two moves done by the opponent and picks the most not done else it picks something random. There is probably a better way of doing this.







                                                                  share|improve this answer














                                                                  share|improve this answer



                                                                  share|improve this answer








                                                                  edited Nov 14 '18 at 18:55

























                                                                  answered Nov 14 '18 at 18:20









                                                                  Link1JLink1J

                                                                  192




                                                                  192























                                                                      2












                                                                      $begingroup$

                                                                      Historic Average



                                                                      class HistoricAverage:
                                                                      PAYOFFS = {
                                                                      "C":{"C":3,"N":1,"D":5},
                                                                      "N":{"C":4,"N":2,"D":2},
                                                                      "D":{"C":0,"N":3,"D":1}}
                                                                      def __init__(self):
                                                                      self.payoffsum = {"C":0, "N":0, "D":0}
                                                                      def round(this, last):
                                                                      if(last != None):
                                                                      for x in this.payoffsum:
                                                                      this.payoffsum[x] += HistoricAverage.PAYOFFS[last][x]
                                                                      return max(this.payoffsum, key=this.payoffsum.get)


                                                                      Looks at history and finds the action that would have been best on average. Starts cooperative.






                                                                      share|improve this answer











                                                                      $endgroup$













                                                                      • $begingroup$
                                                                        This could run faster if it didn't re-calculate the averages every round.
                                                                        $endgroup$
                                                                        – Sparr
                                                                        Nov 13 '18 at 19:57










                                                                      • $begingroup$
                                                                        @Sparr true. I edited it so it does now.
                                                                        $endgroup$
                                                                        – MegaTom
                                                                        Nov 14 '18 at 20:19
















                                                                      2












                                                                      $begingroup$

                                                                      Historic Average



                                                                      class HistoricAverage:
                                                                      PAYOFFS = {
                                                                      "C":{"C":3,"N":1,"D":5},
                                                                      "N":{"C":4,"N":2,"D":2},
                                                                      "D":{"C":0,"N":3,"D":1}}
                                                                      def __init__(self):
                                                                      self.payoffsum = {"C":0, "N":0, "D":0}
                                                                      def round(this, last):
                                                                      if(last != None):
                                                                      for x in this.payoffsum:
                                                                      this.payoffsum[x] += HistoricAverage.PAYOFFS[last][x]
                                                                      return max(this.payoffsum, key=this.payoffsum.get)


                                                                      Looks at history and finds the action that would have been best on average. Starts cooperative.






                                                                      share|improve this answer











                                                                      $endgroup$













                                                                      • $begingroup$
                                                                        This could run faster if it didn't re-calculate the averages every round.
                                                                        $endgroup$
                                                                        – Sparr
                                                                        Nov 13 '18 at 19:57










                                                                      • $begingroup$
                                                                        @Sparr true. I edited it so it does now.
                                                                        $endgroup$
                                                                        – MegaTom
                                                                        Nov 14 '18 at 20:19














                                                                      2












                                                                      2








                                                                      2





                                                                      $begingroup$

                                                                      Historic Average



                                                                      class HistoricAverage:
                                                                      PAYOFFS = {
                                                                      "C":{"C":3,"N":1,"D":5},
                                                                      "N":{"C":4,"N":2,"D":2},
                                                                      "D":{"C":0,"N":3,"D":1}}
                                                                      def __init__(self):
                                                                      self.payoffsum = {"C":0, "N":0, "D":0}
                                                                      def round(this, last):
                                                                      if(last != None):
                                                                      for x in this.payoffsum:
                                                                      this.payoffsum[x] += HistoricAverage.PAYOFFS[last][x]
                                                                      return max(this.payoffsum, key=this.payoffsum.get)


                                                                      Looks at history and finds the action that would have been best on average. Starts cooperative.






                                                                      share|improve this answer











                                                                      $endgroup$



                                                                      Historic Average



                                                                      class HistoricAverage:
                                                                      PAYOFFS = {
                                                                      "C":{"C":3,"N":1,"D":5},
                                                                      "N":{"C":4,"N":2,"D":2},
                                                                      "D":{"C":0,"N":3,"D":1}}
                                                                      def __init__(self):
                                                                      self.payoffsum = {"C":0, "N":0, "D":0}
                                                                      def round(this, last):
                                                                      if(last != None):
                                                                      for x in this.payoffsum:
                                                                      this.payoffsum[x] += HistoricAverage.PAYOFFS[last][x]
                                                                      return max(this.payoffsum, key=this.payoffsum.get)


                                                                      Looks at history and finds the action that would have been best on average. Starts cooperative.







                                                                      share|improve this answer














                                                                      share|improve this answer



                                                                      share|improve this answer








                                                                      edited Dec 4 '18 at 15:00

























                                                                      answered Nov 12 '18 at 23:33









                                                                      MegaTomMegaTom

                                                                      3,4721324




                                                                      3,4721324












                                                                      • $begingroup$
                                                                        This could run faster if it didn't re-calculate the averages every round.
                                                                        $endgroup$
                                                                        – Sparr
                                                                        Nov 13 '18 at 19:57










                                                                      • $begingroup$
                                                                        @Sparr true. I edited it so it does now.
                                                                        $endgroup$
                                                                        – MegaTom
                                                                        Nov 14 '18 at 20:19


















                                                                      • $begingroup$
                                                                        This could run faster if it didn't re-calculate the averages every round.
                                                                        $endgroup$
                                                                        – Sparr
                                                                        Nov 13 '18 at 19:57










                                                                      • $begingroup$
                                                                        @Sparr true. I edited it so it does now.
                                                                        $endgroup$
                                                                        – MegaTom
                                                                        Nov 14 '18 at 20:19
















                                                                      $begingroup$
                                                                      This could run faster if it didn't re-calculate the averages every round.
                                                                      $endgroup$
                                                                      – Sparr
                                                                      Nov 13 '18 at 19:57




                                                                      $begingroup$
                                                                      This could run faster if it didn't re-calculate the averages every round.
                                                                      $endgroup$
                                                                      – Sparr
                                                                      Nov 13 '18 at 19:57












                                                                      $begingroup$
                                                                      @Sparr true. I edited it so it does now.
                                                                      $endgroup$
                                                                      – MegaTom
                                                                      Nov 14 '18 at 20:19




                                                                      $begingroup$
                                                                      @Sparr true. I edited it so it does now.
                                                                      $endgroup$
                                                                      – MegaTom
                                                                      Nov 14 '18 at 20:19











                                                                      1












                                                                      $begingroup$

                                                                      Weighted Average



                                                                      class WeightedAverageBot:
                                                                      def __init__(self):
                                                                      self.C_bias = 1/4
                                                                      self.N = self.C_bias
                                                                      self.D = self.C_bias
                                                                      self.prev_weight = 1/2
                                                                      def round(self, last):
                                                                      if last:
                                                                      if last == "C" or last == "N":
                                                                      self.D *= self.prev_weight
                                                                      if last == "C" or last == "D":
                                                                      self.N *= self.prev_weight
                                                                      if last == "N":
                                                                      self.N = 1 - ((1 - self.N) * self.prev_weight)
                                                                      if last == "D":
                                                                      self.D = 1 - ((1 - self.D) * self.prev_weight)
                                                                      if self.N <= self.C_bias and self.D <= self.C_bias:
                                                                      return "D"
                                                                      if self.N > self.D:
                                                                      return "C"
                                                                      return "N"


                                                                      The opponent's behavior is modeled as a right triangle with corners for C N D at 0,0 0,1 1,0 respectively. Each opponent move shifts the point within that triangle toward that corner, and we play to beat the move indicated by the point (with C being given an adjustably small slice of the triangle). In theory I wanted this to have a longer memory with more weight to previous moves, but in practice the current meta favors bots that change quickly, so this devolves into an approximation of LastOptimalBot against most enemies. Posting for posterity; maybe someone will be inspired.






                                                                      share|improve this answer









                                                                      $endgroup$


















                                                                        1












                                                                        $begingroup$

                                                                        Weighted Average



                                                                        class WeightedAverageBot:
                                                                        def __init__(self):
                                                                        self.C_bias = 1/4
                                                                        self.N = self.C_bias
                                                                        self.D = self.C_bias
                                                                        self.prev_weight = 1/2
                                                                        def round(self, last):
                                                                        if last:
                                                                        if last == "C" or last == "N":
                                                                        self.D *= self.prev_weight
                                                                        if last == "C" or last == "D":
                                                                        self.N *= self.prev_weight
                                                                        if last == "N":
                                                                        self.N = 1 - ((1 - self.N) * self.prev_weight)
                                                                        if last == "D":
                                                                        self.D = 1 - ((1 - self.D) * self.prev_weight)
                                                                        if self.N <= self.C_bias and self.D <= self.C_bias:
                                                                        return "D"
                                                                        if self.N > self.D:
                                                                        return "C"
                                                                        return "N"


                                                                        The opponent's behavior is modeled as a right triangle with corners for C N D at 0,0 0,1 1,0 respectively. Each opponent move shifts the point within that triangle toward that corner, and we play to beat the move indicated by the point (with C being given an adjustably small slice of the triangle). In theory I wanted this to have a longer memory with more weight to previous moves, but in practice the current meta favors bots that change quickly, so this devolves into an approximation of LastOptimalBot against most enemies. Posting for posterity; maybe someone will be inspired.






                                                                        share|improve this answer









                                                                        $endgroup$
















                                                                          1












                                                                          1








                                                                          1





                                                                          $begingroup$

                                                                          Weighted Average



                                                                          class WeightedAverageBot:
                                                                          def __init__(self):
                                                                          self.C_bias = 1/4
                                                                          self.N = self.C_bias
                                                                          self.D = self.C_bias
                                                                          self.prev_weight = 1/2
                                                                          def round(self, last):
                                                                          if last:
                                                                          if last == "C" or last == "N":
                                                                          self.D *= self.prev_weight
                                                                          if last == "C" or last == "D":
                                                                          self.N *= self.prev_weight
                                                                          if last == "N":
                                                                          self.N = 1 - ((1 - self.N) * self.prev_weight)
                                                                          if last == "D":
                                                                          self.D = 1 - ((1 - self.D) * self.prev_weight)
                                                                          if self.N <= self.C_bias and self.D <= self.C_bias:
                                                                          return "D"
                                                                          if self.N > self.D:
                                                                          return "C"
                                                                          return "N"


                                                                          The opponent's behavior is modeled as a right triangle with corners for C N D at 0,0 0,1 1,0 respectively. Each opponent move shifts the point within that triangle toward that corner, and we play to beat the move indicated by the point (with C being given an adjustably small slice of the triangle). In theory I wanted this to have a longer memory with more weight to previous moves, but in practice the current meta favors bots that change quickly, so this devolves into an approximation of LastOptimalBot against most enemies. Posting for posterity; maybe someone will be inspired.






                                                                          share|improve this answer









                                                                          $endgroup$



                                                                          Weighted Average



                                                                          class WeightedAverageBot:
                                                                          def __init__(self):
                                                                          self.C_bias = 1/4
                                                                          self.N = self.C_bias
                                                                          self.D = self.C_bias
                                                                          self.prev_weight = 1/2
                                                                          def round(self, last):
                                                                          if last:
                                                                          if last == "C" or last == "N":
                                                                          self.D *= self.prev_weight
                                                                          if last == "C" or last == "D":
                                                                          self.N *= self.prev_weight
                                                                          if last == "N":
                                                                          self.N = 1 - ((1 - self.N) * self.prev_weight)
                                                                          if last == "D":
                                                                          self.D = 1 - ((1 - self.D) * self.prev_weight)
                                                                          if self.N <= self.C_bias and self.D <= self.C_bias:
                                                                          return "D"
                                                                          if self.N > self.D:
                                                                          return "C"
                                                                          return "N"


                                                                          The opponent's behavior is modeled as a right triangle with corners for C N D at 0,0 0,1 1,0 respectively. Each opponent move shifts the point within that triangle toward that corner, and we play to beat the move indicated by the point (with C being given an adjustably small slice of the triangle). In theory I wanted this to have a longer memory with more weight to previous moves, but in practice the current meta favors bots that change quickly, so this devolves into an approximation of LastOptimalBot against most enemies. Posting for posterity; maybe someone will be inspired.







                                                                          share|improve this answer












                                                                          share|improve this answer



                                                                          share|improve this answer










                                                                          answered Nov 13 '18 at 8:56









                                                                          SparrSparr

                                                                          5,0881633




                                                                          5,0881633























                                                                              1












                                                                              $begingroup$

                                                                              Tetragram



                                                                              import itertools

                                                                              class Tetragram:
                                                                              def __init__(self):
                                                                              self.history = {x: ['C'] for x in itertools.product('CND', repeat=4)}
                                                                              self.theirs =
                                                                              self.previous = None

                                                                              def round(self, last):
                                                                              if self.previous is not None and len(self.previous) == 4:
                                                                              self.history[self.previous].append(last)
                                                                              if last is not None:
                                                                              self.theirs = (self.theirs + [last])[-3:]

                                                                              if self.previous is not None and len(self.previous) == 4:
                                                                              expected = random.choice(self.history[self.previous])
                                                                              if expected == 'C':
                                                                              choice = 'C'
                                                                              elif expected == 'N':
                                                                              choice = 'C'
                                                                              else:
                                                                              choice = 'N'
                                                                              else:
                                                                              choice = 'C'

                                                                              self.previous = tuple(self.theirs + [choice])
                                                                              return choice


                                                                              Try to find a pattern in the opponent's moves, assuming they're also watching our last move.






                                                                              share|improve this answer









                                                                              $endgroup$


















                                                                                1












                                                                                $begingroup$

                                                                                Tetragram



                                                                                import itertools

                                                                                class Tetragram:
                                                                                def __init__(self):
                                                                                self.history = {x: ['C'] for x in itertools.product('CND', repeat=4)}
                                                                                self.theirs =
                                                                                self.previous = None

                                                                                def round(self, last):
                                                                                if self.previous is not None and len(self.previous) == 4:
                                                                                self.history[self.previous].append(last)
                                                                                if last is not None:
                                                                                self.theirs = (self.theirs + [last])[-3:]

                                                                                if self.previous is not None and len(self.previous) == 4:
                                                                                expected = random.choice(self.history[self.previous])
                                                                                if expected == 'C':
                                                                                choice = 'C'
                                                                                elif expected == 'N':
                                                                                choice = 'C'
                                                                                else:
                                                                                choice = 'N'
                                                                                else:
                                                                                choice = 'C'

                                                                                self.previous = tuple(self.theirs + [choice])
                                                                                return choice


                                                                                Try to find a pattern in the opponent's moves, assuming they're also watching our last move.






                                                                                share|improve this answer









                                                                                $endgroup$
















                                                                                  1












                                                                                  1








                                                                                  1





                                                                                  $begingroup$

                                                                                  Tetragram



                                                                                  import itertools

                                                                                  class Tetragram:
                                                                                  def __init__(self):
                                                                                  self.history = {x: ['C'] for x in itertools.product('CND', repeat=4)}
                                                                                  self.theirs =
                                                                                  self.previous = None

                                                                                  def round(self, last):
                                                                                  if self.previous is not None and len(self.previous) == 4:
                                                                                  self.history[self.previous].append(last)
                                                                                  if last is not None:
                                                                                  self.theirs = (self.theirs + [last])[-3:]

                                                                                  if self.previous is not None and len(self.previous) == 4:
                                                                                  expected = random.choice(self.history[self.previous])
                                                                                  if expected == 'C':
                                                                                  choice = 'C'
                                                                                  elif expected == 'N':
                                                                                  choice = 'C'
                                                                                  else:
                                                                                  choice = 'N'
                                                                                  else:
                                                                                  choice = 'C'

                                                                                  self.previous = tuple(self.theirs + [choice])
                                                                                  return choice


                                                                                  Try to find a pattern in the opponent's moves, assuming they're also watching our last move.






                                                                                  share|improve this answer









                                                                                  $endgroup$



                                                                                  Tetragram



                                                                                  import itertools

                                                                                  class Tetragram:
                                                                                  def __init__(self):
                                                                                  self.history = {x: ['C'] for x in itertools.product('CND', repeat=4)}
                                                                                  self.theirs =
                                                                                  self.previous = None

                                                                                  def round(self, last):
                                                                                  if self.previous is not None and len(self.previous) == 4:
                                                                                  self.history[self.previous].append(last)
                                                                                  if last is not None:
                                                                                  self.theirs = (self.theirs + [last])[-3:]

                                                                                  if self.previous is not None and len(self.previous) == 4:
                                                                                  expected = random.choice(self.history[self.previous])
                                                                                  if expected == 'C':
                                                                                  choice = 'C'
                                                                                  elif expected == 'N':
                                                                                  choice = 'C'
                                                                                  else:
                                                                                  choice = 'N'
                                                                                  else:
                                                                                  choice = 'C'

                                                                                  self.previous = tuple(self.theirs + [choice])
                                                                                  return choice


                                                                                  Try to find a pattern in the opponent's moves, assuming they're also watching our last move.







                                                                                  share|improve this answer












                                                                                  share|improve this answer



                                                                                  share|improve this answer










                                                                                  answered Nov 13 '18 at 19:09









                                                                                  MnemonicMnemonic

                                                                                  4,6951730




                                                                                  4,6951730























                                                                                      1












                                                                                      $begingroup$

                                                                                      Handshake



                                                                                      class HandshakeBot:
                                                                                      def __init__(self):
                                                                                      self.handshake_length = 4
                                                                                      self.handshake = ["N","N","C","D"]
                                                                                      while len(self.handshake) < self.handshake_length:
                                                                                      self.handshake *= 2
                                                                                      self.handshake = self.handshake[:self.handshake_length]
                                                                                      self.opp_hand =
                                                                                      self.friendly = None
                                                                                      def round(self, last):
                                                                                      if last:
                                                                                      if self.friendly == None:
                                                                                      # still trying to handshake
                                                                                      self.opp_hand.append(last)
                                                                                      if self.opp_hand[-1] != self.handshake[len(self.opp_hand)-1]:
                                                                                      self.friendly = False
                                                                                      return "D"
                                                                                      if len(self.opp_hand) == len(self.handshake):
                                                                                      self.friendly = True
                                                                                      return "C"
                                                                                      return self.handshake[len(self.opp_hand)]
                                                                                      elif self.friendly == True:
                                                                                      # successful handshake and continued cooperation
                                                                                      if last == "C":
                                                                                      return "C"
                                                                                      self.friendly = False
                                                                                      return "D"
                                                                                      else:
                                                                                      # failed handshake or abandoned cooperation
                                                                                      return "N" if last == "D" else ("D" if last == "C" else "C")
                                                                                      return self.handshake[0]


                                                                                      Recognizes when it's playing against itself, then cooperates. Otherwise mimics LastOptimalBot which seems like the best one-line strategy. Performs worse than LastOptimalBot, by an amount inversely proportional to the number of rounds. Obviously would do better if there were more copies of it in the field *cough**wink*.






                                                                                      share|improve this answer









                                                                                      $endgroup$













                                                                                      • $begingroup$
                                                                                        Just submit a few clones that have different non-handshake behavior.
                                                                                        $endgroup$
                                                                                        – Blacksilver
                                                                                        Nov 13 '18 at 22:52










                                                                                      • $begingroup$
                                                                                        That seems exploit-y. I could submit one such clone for every simple behavior represented here.
                                                                                        $endgroup$
                                                                                        – Sparr
                                                                                        Nov 14 '18 at 0:12










                                                                                      • $begingroup$
                                                                                        I've added an extra clause saying that you can only submit max five bots.
                                                                                        $endgroup$
                                                                                        – Blacksilver
                                                                                        Nov 14 '18 at 2:14
















                                                                                      1












                                                                                      $begingroup$

                                                                                      Handshake



                                                                                      class HandshakeBot:
                                                                                      def __init__(self):
                                                                                      self.handshake_length = 4
                                                                                      self.handshake = ["N","N","C","D"]
                                                                                      while len(self.handshake) < self.handshake_length:
                                                                                      self.handshake *= 2
                                                                                      self.handshake = self.handshake[:self.handshake_length]
                                                                                      self.opp_hand =
                                                                                      self.friendly = None
                                                                                      def round(self, last):
                                                                                      if last:
                                                                                      if self.friendly == None:
                                                                                      # still trying to handshake
                                                                                      self.opp_hand.append(last)
                                                                                      if self.opp_hand[-1] != self.handshake[len(self.opp_hand)-1]:
                                                                                      self.friendly = False
                                                                                      return "D"
                                                                                      if len(self.opp_hand) == len(self.handshake):
                                                                                      self.friendly = True
                                                                                      return "C"
                                                                                      return self.handshake[len(self.opp_hand)]
                                                                                      elif self.friendly == True:
                                                                                      # successful handshake and continued cooperation
                                                                                      if last == "C":
                                                                                      return "C"
                                                                                      self.friendly = False
                                                                                      return "D"
                                                                                      else:
                                                                                      # failed handshake or abandoned cooperation
                                                                                      return "N" if last == "D" else ("D" if last == "C" else "C")
                                                                                      return self.handshake[0]


                                                                                      Recognizes when it's playing against itself, then cooperates. Otherwise mimics LastOptimalBot which seems like the best one-line strategy. Performs worse than LastOptimalBot, by an amount inversely proportional to the number of rounds. Obviously would do better if there were more copies of it in the field *cough**wink*.






                                                                                      share|improve this answer









                                                                                      $endgroup$













                                                                                      • $begingroup$
                                                                                        Just submit a few clones that have different non-handshake behavior.
                                                                                        $endgroup$
                                                                                        – Blacksilver
                                                                                        Nov 13 '18 at 22:52










                                                                                      • $begingroup$
                                                                                        That seems exploit-y. I could submit one such clone for every simple behavior represented here.
                                                                                        $endgroup$
                                                                                        – Sparr
                                                                                        Nov 14 '18 at 0:12










                                                                                      • $begingroup$
                                                                                        I've added an extra clause saying that you can only submit max five bots.
                                                                                        $endgroup$
                                                                                        – Blacksilver
                                                                                        Nov 14 '18 at 2:14














                                                                                      1












                                                                                      1








                                                                                      1





                                                                                      $begingroup$

                                                                                      Handshake



                                                                                      class HandshakeBot:
                                                                                      def __init__(self):
                                                                                      self.handshake_length = 4
                                                                                      self.handshake = ["N","N","C","D"]
                                                                                      while len(self.handshake) < self.handshake_length:
                                                                                      self.handshake *= 2
                                                                                      self.handshake = self.handshake[:self.handshake_length]
                                                                                      self.opp_hand =
                                                                                      self.friendly = None
                                                                                      def round(self, last):
                                                                                      if last:
                                                                                      if self.friendly == None:
                                                                                      # still trying to handshake
                                                                                      self.opp_hand.append(last)
                                                                                      if self.opp_hand[-1] != self.handshake[len(self.opp_hand)-1]:
                                                                                      self.friendly = False
                                                                                      return "D"
                                                                                      if len(self.opp_hand) == len(self.handshake):
                                                                                      self.friendly = True
                                                                                      return "C"
                                                                                      return self.handshake[len(self.opp_hand)]
                                                                                      elif self.friendly == True:
                                                                                      # successful handshake and continued cooperation
                                                                                      if last == "C":
                                                                                      return "C"
                                                                                      self.friendly = False
                                                                                      return "D"
                                                                                      else:
                                                                                      # failed handshake or abandoned cooperation
                                                                                      return "N" if last == "D" else ("D" if last == "C" else "C")
                                                                                      return self.handshake[0]


                                                                                      Recognizes when it's playing against itself, then cooperates. Otherwise mimics LastOptimalBot which seems like the best one-line strategy. Performs worse than LastOptimalBot, by an amount inversely proportional to the number of rounds. Obviously would do better if there were more copies of it in the field *cough**wink*.






                                                                                      share|improve this answer









                                                                                      $endgroup$



                                                                                      Handshake



                                                                                      class HandshakeBot:
                                                                                      def __init__(self):
                                                                                      self.handshake_length = 4
                                                                                      self.handshake = ["N","N","C","D"]
                                                                                      while len(self.handshake) < self.handshake_length:
                                                                                      self.handshake *= 2
                                                                                      self.handshake = self.handshake[:self.handshake_length]
                                                                                      self.opp_hand =
                                                                                      self.friendly = None
                                                                                      def round(self, last):
                                                                                      if last:
                                                                                      if self.friendly == None:
                                                                                      # still trying to handshake
                                                                                      self.opp_hand.append(last)
                                                                                      if self.opp_hand[-1] != self.handshake[len(self.opp_hand)-1]:
                                                                                      self.friendly = False
                                                                                      return "D"
                                                                                      if len(self.opp_hand) == len(self.handshake):
                                                                                      self.friendly = True
                                                                                      return "C"
                                                                                      return self.handshake[len(self.opp_hand)]
                                                                                      elif self.friendly == True:
                                                                                      # successful handshake and continued cooperation
                                                                                      if last == "C":
                                                                                      return "C"
                                                                                      self.friendly = False
                                                                                      return "D"
                                                                                      else:
                                                                                      # failed handshake or abandoned cooperation
                                                                                      return "N" if last == "D" else ("D" if last == "C" else "C")
                                                                                      return self.handshake[0]


                                                                                      Recognizes when it's playing against itself, then cooperates. Otherwise mimics LastOptimalBot which seems like the best one-line strategy. Performs worse than LastOptimalBot, by an amount inversely proportional to the number of rounds. Obviously would do better if there were more copies of it in the field *cough**wink*.







                                                                                      share|improve this answer












                                                                                      share|improve this answer



                                                                                      share|improve this answer










                                                                                      answered Nov 13 '18 at 20:00









                                                                                      SparrSparr

                                                                                      5,0881633




                                                                                      5,0881633












                                                                                      • $begingroup$
                                                                                        Just submit a few clones that have different non-handshake behavior.
                                                                                        $endgroup$
                                                                                        – Blacksilver
                                                                                        Nov 13 '18 at 22:52










                                                                                      • $begingroup$
                                                                                        That seems exploit-y. I could submit one such clone for every simple behavior represented here.
                                                                                        $endgroup$
                                                                                        – Sparr
                                                                                        Nov 14 '18 at 0:12










                                                                                      • $begingroup$
                                                                                        I've added an extra clause saying that you can only submit max five bots.
                                                                                        $endgroup$
                                                                                        – Blacksilver
                                                                                        Nov 14 '18 at 2:14


















                                                                                      • $begingroup$
                                                                                        Just submit a few clones that have different non-handshake behavior.
                                                                                        $endgroup$
                                                                                        – Blacksilver
                                                                                        Nov 13 '18 at 22:52










                                                                                      • $begingroup$
                                                                                        That seems exploit-y. I could submit one such clone for every simple behavior represented here.
                                                                                        $endgroup$
                                                                                        – Sparr
                                                                                        Nov 14 '18 at 0:12










                                                                                      • $begingroup$
                                                                                        I've added an extra clause saying that you can only submit max five bots.
                                                                                        $endgroup$
                                                                                        – Blacksilver
                                                                                        Nov 14 '18 at 2:14
















                                                                                      $begingroup$
                                                                                      Just submit a few clones that have different non-handshake behavior.
                                                                                      $endgroup$
                                                                                      – Blacksilver
                                                                                      Nov 13 '18 at 22:52




                                                                                      $begingroup$
                                                                                      Just submit a few clones that have different non-handshake behavior.
                                                                                      $endgroup$
                                                                                      – Blacksilver
                                                                                      Nov 13 '18 at 22:52












                                                                                      $begingroup$
                                                                                      That seems exploit-y. I could submit one such clone for every simple behavior represented here.
                                                                                      $endgroup$
                                                                                      – Sparr
                                                                                      Nov 14 '18 at 0:12




                                                                                      $begingroup$
                                                                                      That seems exploit-y. I could submit one such clone for every simple behavior represented here.
                                                                                      $endgroup$
                                                                                      – Sparr
                                                                                      Nov 14 '18 at 0:12












                                                                                      $begingroup$
                                                                                      I've added an extra clause saying that you can only submit max five bots.
                                                                                      $endgroup$
                                                                                      – Blacksilver
                                                                                      Nov 14 '18 at 2:14




                                                                                      $begingroup$
                                                                                      I've added an extra clause saying that you can only submit max five bots.
                                                                                      $endgroup$
                                                                                      – Blacksilver
                                                                                      Nov 14 '18 at 2:14











                                                                                      1












                                                                                      $begingroup$

                                                                                      ShiftingOptimalBot



                                                                                      class ShiftingOptimalBot:
                                                                                      def __init__(self):
                                                                                      # wins, draws, losses
                                                                                      self.history = [0,0,0]
                                                                                      self.lastMove = None
                                                                                      self.state = 0
                                                                                      def round(self, last):
                                                                                      if last == None:
                                                                                      self.lastMove = "C"
                                                                                      return self.lastMove
                                                                                      if last == self.lastMove:
                                                                                      self.history[1] += 1
                                                                                      elif (last == "C" and self.lastMove == "D") or (last == "D" and self.lastMove == "N") or (last == "N" and self.lastMove == "C"):
                                                                                      self.history[0] += 1
                                                                                      else:
                                                                                      self.history[2] += 1

                                                                                      if self.history[0] + 1 < self.history[2] or self.history[2] > 5:
                                                                                      self.state = (self.state + 1) % 3
                                                                                      self.history = [0,0,0]
                                                                                      if self.history[1] > self.history[0] + self.history[2] + 2:
                                                                                      self.state = (self.state + 2) % 3
                                                                                      self.history = [0,0,0]

                                                                                      if self.state == 0:
                                                                                      self.lastMove = "N" if last == "D" else ("D" if last == "C" else "C")
                                                                                      elif self.state == 1:
                                                                                      self.lastMove = last
                                                                                      else:
                                                                                      self.lastMove = "C" if last == "D" else ("N" if last == "C" else "D")
                                                                                      return self.lastMove


                                                                                      This bot uses LastOptimalBot's algorithm as long as it's winning. If the other bot starts predicting it, however, it will start playing whichever move its opponent played last (which is the move that beats the move that would beat LastOptimalBot). It cycles through simple transpositions of those algorithms as long as it continues to lose (or when it gets bored by drawing a lot).



                                                                                      Honestly, I'm surprised that LastOptimalBot is sitting in 5th as I post this. I'm fairly certain this will do better, assuming that I wrote this python correctly.






                                                                                      share|improve this answer











                                                                                      $endgroup$


















                                                                                        1












                                                                                        $begingroup$

                                                                                        ShiftingOptimalBot



                                                                                        class ShiftingOptimalBot:
                                                                                        def __init__(self):
                                                                                        # wins, draws, losses
                                                                                        self.history = [0,0,0]
                                                                                        self.lastMove = None
                                                                                        self.state = 0
                                                                                        def round(self, last):
                                                                                        if last == None:
                                                                                        self.lastMove = "C"
                                                                                        return self.lastMove
                                                                                        if last == self.lastMove:
                                                                                        self.history[1] += 1
                                                                                        elif (last == "C" and self.lastMove == "D") or (last == "D" and self.lastMove == "N") or (last == "N" and self.lastMove == "C"):
                                                                                        self.history[0] += 1
                                                                                        else:
                                                                                        self.history[2] += 1

                                                                                        if self.history[0] + 1 < self.history[2] or self.history[2] > 5:
                                                                                        self.state = (self.state + 1) % 3
                                                                                        self.history = [0,0,0]
                                                                                        if self.history[1] > self.history[0] + self.history[2] + 2:
                                                                                        self.state = (self.state + 2) % 3
                                                                                        self.history = [0,0,0]

                                                                                        if self.state == 0:
                                                                                        self.lastMove = "N" if last == "D" else ("D" if last == "C" else "C")
                                                                                        elif self.state == 1:
                                                                                        self.lastMove = last
                                                                                        else:
                                                                                        self.lastMove = "C" if last == "D" else ("N" if last == "C" else "D")
                                                                                        return self.lastMove


                                                                                        This bot uses LastOptimalBot's algorithm as long as it's winning. If the other bot starts predicting it, however, it will start playing whichever move its opponent played last (which is the move that beats the move that would beat LastOptimalBot). It cycles through simple transpositions of those algorithms as long as it continues to lose (or when it gets bored by drawing a lot).



                                                                                        Honestly, I'm surprised that LastOptimalBot is sitting in 5th as I post this. I'm fairly certain this will do better, assuming that I wrote this python correctly.






                                                                                        share|improve this answer











                                                                                        $endgroup$
















                                                                                          1












                                                                                          1








                                                                                          1





                                                                                          $begingroup$

                                                                                          ShiftingOptimalBot



                                                                                          class ShiftingOptimalBot:
                                                                                          def __init__(self):
                                                                                          # wins, draws, losses
                                                                                          self.history = [0,0,0]
                                                                                          self.lastMove = None
                                                                                          self.state = 0
                                                                                          def round(self, last):
                                                                                          if last == None:
                                                                                          self.lastMove = "C"
                                                                                          return self.lastMove
                                                                                          if last == self.lastMove:
                                                                                          self.history[1] += 1
                                                                                          elif (last == "C" and self.lastMove == "D") or (last == "D" and self.lastMove == "N") or (last == "N" and self.lastMove == "C"):
                                                                                          self.history[0] += 1
                                                                                          else:
                                                                                          self.history[2] += 1

                                                                                          if self.history[0] + 1 < self.history[2] or self.history[2] > 5:
                                                                                          self.state = (self.state + 1) % 3
                                                                                          self.history = [0,0,0]
                                                                                          if self.history[1] > self.history[0] + self.history[2] + 2:
                                                                                          self.state = (self.state + 2) % 3
                                                                                          self.history = [0,0,0]

                                                                                          if self.state == 0:
                                                                                          self.lastMove = "N" if last == "D" else ("D" if last == "C" else "C")
                                                                                          elif self.state == 1:
                                                                                          self.lastMove = last
                                                                                          else:
                                                                                          self.lastMove = "C" if last == "D" else ("N" if last == "C" else "D")
                                                                                          return self.lastMove


                                                                                          This bot uses LastOptimalBot's algorithm as long as it's winning. If the other bot starts predicting it, however, it will start playing whichever move its opponent played last (which is the move that beats the move that would beat LastOptimalBot). It cycles through simple transpositions of those algorithms as long as it continues to lose (or when it gets bored by drawing a lot).



                                                                                          Honestly, I'm surprised that LastOptimalBot is sitting in 5th as I post this. I'm fairly certain this will do better, assuming that I wrote this python correctly.






                                                                                          share|improve this answer











                                                                                          $endgroup$



                                                                                          ShiftingOptimalBot



                                                                                          class ShiftingOptimalBot:
                                                                                          def __init__(self):
                                                                                          # wins, draws, losses
                                                                                          self.history = [0,0,0]
                                                                                          self.lastMove = None
                                                                                          self.state = 0
                                                                                          def round(self, last):
                                                                                          if last == None:
                                                                                          self.lastMove = "C"
                                                                                          return self.lastMove
                                                                                          if last == self.lastMove:
                                                                                          self.history[1] += 1
                                                                                          elif (last == "C" and self.lastMove == "D") or (last == "D" and self.lastMove == "N") or (last == "N" and self.lastMove == "C"):
                                                                                          self.history[0] += 1
                                                                                          else:
                                                                                          self.history[2] += 1

                                                                                          if self.history[0] + 1 < self.history[2] or self.history[2] > 5:
                                                                                          self.state = (self.state + 1) % 3
                                                                                          self.history = [0,0,0]
                                                                                          if self.history[1] > self.history[0] + self.history[2] + 2:
                                                                                          self.state = (self.state + 2) % 3
                                                                                          self.history = [0,0,0]

                                                                                          if self.state == 0:
                                                                                          self.lastMove = "N" if last == "D" else ("D" if last == "C" else "C")
                                                                                          elif self.state == 1:
                                                                                          self.lastMove = last
                                                                                          else:
                                                                                          self.lastMove = "C" if last == "D" else ("N" if last == "C" else "D")
                                                                                          return self.lastMove


                                                                                          This bot uses LastOptimalBot's algorithm as long as it's winning. If the other bot starts predicting it, however, it will start playing whichever move its opponent played last (which is the move that beats the move that would beat LastOptimalBot). It cycles through simple transpositions of those algorithms as long as it continues to lose (or when it gets bored by drawing a lot).



                                                                                          Honestly, I'm surprised that LastOptimalBot is sitting in 5th as I post this. I'm fairly certain this will do better, assuming that I wrote this python correctly.







                                                                                          share|improve this answer














                                                                                          share|improve this answer



                                                                                          share|improve this answer








                                                                                          edited Nov 14 '18 at 18:29









                                                                                          Blacksilver

                                                                                          435314




                                                                                          435314










                                                                                          answered Nov 14 '18 at 16:04









                                                                                          SpitemasterSpitemaster

                                                                                          3736




                                                                                          3736























                                                                                              0












                                                                                              $begingroup$

                                                                                              HandshakePatternMatch



                                                                                              from .patternfinder import PatternFinder
                                                                                              import collections

                                                                                              class HandshakePatternMatch:
                                                                                              def __init__(self):
                                                                                              self.moves = [None]
                                                                                              self.other =
                                                                                              self.handshake = [None,"N","C","C","D","N"]
                                                                                              self.friendly = None
                                                                                              self.pattern = PatternFinder()
                                                                                              def round(self, last):
                                                                                              self.other.append(last)
                                                                                              if last:
                                                                                              if len(self.other) < len(self.handshake):
                                                                                              # still trying to handshake
                                                                                              if self.friendly == False or self.other[-1] != self.handshake[-1]:
                                                                                              self.friendly = False
                                                                                              else:
                                                                                              self.friendly = True
                                                                                              move = self.handshake[len(self.other)]
                                                                                              self.pattern.round(last)
                                                                                              elif self.friendly == True:
                                                                                              # successful handshake and continued cooperation
                                                                                              move = self.pattern.round(last)
                                                                                              if last == "C":
                                                                                              move = "C"
                                                                                              elif last == self.handshake[-1] and self.moves[-1] == self.handshake[-1]:
                                                                                              move = "C"
                                                                                              else:
                                                                                              self.friendly = False
                                                                                              else:
                                                                                              # failed handshake or abandoned cooperation
                                                                                              move = self.pattern.round(last)
                                                                                              else:
                                                                                              move = self.handshake[1]
                                                                                              self.pattern.round(last)
                                                                                              self.moves.append(move)
                                                                                              return move


                                                                                              Why pattern match yourself? Handshake and cooperate away.






                                                                                              share|improve this answer









                                                                                              $endgroup$













                                                                                              • $begingroup$
                                                                                                import PatternFinder is cheating in my books.
                                                                                                $endgroup$
                                                                                                – Blacksilver
                                                                                                Nov 17 '18 at 2:30










                                                                                              • $begingroup$
                                                                                                @Blacksilver It gets done all the time in KOTH. It's no different than copying the code in an existing answer and using it. Robot Roulette: High stakes robot gambling had it happening all over the place to the point that bots would detect if their code was being called by an opponent and sabotage the return.
                                                                                                $endgroup$
                                                                                                – Draco18s
                                                                                                Nov 17 '18 at 2:36












                                                                                              • $begingroup$
                                                                                                Alright then. TIL.
                                                                                                $endgroup$
                                                                                                – Blacksilver
                                                                                                Nov 17 '18 at 2:37










                                                                                              • $begingroup$
                                                                                                I'll do the crunching tomorrow.
                                                                                                $endgroup$
                                                                                                – Blacksilver
                                                                                                Nov 17 '18 at 2:38










                                                                                              • $begingroup$
                                                                                                Here's a perfect example of using other bots' code. Usually it comes down to "that guy worked out some tricky math, I want his results under these conditions." (My own entry did that to pretty good effect; UpYours was more scatter-shot in its approach).
                                                                                                $endgroup$
                                                                                                – Draco18s
                                                                                                Nov 17 '18 at 2:41


















                                                                                              0












                                                                                              $begingroup$

                                                                                              HandshakePatternMatch



                                                                                              from .patternfinder import PatternFinder
                                                                                              import collections

                                                                                              class HandshakePatternMatch:
                                                                                              def __init__(self):
                                                                                              self.moves = [None]
                                                                                              self.other =
                                                                                              self.handshake = [None,"N","C","C","D","N"]
                                                                                              self.friendly = None
                                                                                              self.pattern = PatternFinder()
                                                                                              def round(self, last):
                                                                                              self.other.append(last)
                                                                                              if last:
                                                                                              if len(self.other) < len(self.handshake):
                                                                                              # still trying to handshake
                                                                                              if self.friendly == False or self.other[-1] != self.handshake[-1]:
                                                                                              self.friendly = False
                                                                                              else:
                                                                                              self.friendly = True
                                                                                              move = self.handshake[len(self.other)]
                                                                                              self.pattern.round(last)
                                                                                              elif self.friendly == True:
                                                                                              # successful handshake and continued cooperation
                                                                                              move = self.pattern.round(last)
                                                                                              if last == "C":
                                                                                              move = "C"
                                                                                              elif last == self.handshake[-1] and self.moves[-1] == self.handshake[-1]:
                                                                                              move = "C"
                                                                                              else:
                                                                                              self.friendly = False
                                                                                              else:
                                                                                              # failed handshake or abandoned cooperation
                                                                                              move = self.pattern.round(last)
                                                                                              else:
                                                                                              move = self.handshake[1]
                                                                                              self.pattern.round(last)
                                                                                              self.moves.append(move)
                                                                                              return move


                                                                                              Why pattern match yourself? Handshake and cooperate away.






                                                                                              share|improve this answer









                                                                                              $endgroup$













                                                                                              • $begingroup$
                                                                                                import PatternFinder is cheating in my books.
                                                                                                $endgroup$
                                                                                                – Blacksilver
                                                                                                Nov 17 '18 at 2:30










                                                                                              • $begingroup$
                                                                                                @Blacksilver It gets done all the time in KOTH. It's no different than copying the code in an existing answer and using it. Robot Roulette: High stakes robot gambling had it happening all over the place to the point that bots would detect if their code was being called by an opponent and sabotage the return.
                                                                                                $endgroup$
                                                                                                – Draco18s
                                                                                                Nov 17 '18 at 2:36












                                                                                              • $begingroup$
                                                                                                Alright then. TIL.
                                                                                                $endgroup$
                                                                                                – Blacksilver
                                                                                                Nov 17 '18 at 2:37










                                                                                              • $begingroup$
                                                                                                I'll do the crunching tomorrow.
                                                                                                $endgroup$
                                                                                                – Blacksilver
                                                                                                Nov 17 '18 at 2:38










                                                                                              • $begingroup$
                                                                                                Here's a perfect example of using other bots' code. Usually it comes down to "that guy worked out some tricky math, I want his results under these conditions." (My own entry did that to pretty good effect; UpYours was more scatter-shot in its approach).
                                                                                                $endgroup$
                                                                                                – Draco18s
                                                                                                Nov 17 '18 at 2:41
















                                                                                              0












                                                                                              0








                                                                                              0





                                                                                              $begingroup$

                                                                                              HandshakePatternMatch



                                                                                              from .patternfinder import PatternFinder
                                                                                              import collections

                                                                                              class HandshakePatternMatch:
                                                                                              def __init__(self):
                                                                                              self.moves = [None]
                                                                                              self.other =
                                                                                              self.handshake = [None,"N","C","C","D","N"]
                                                                                              self.friendly = None
                                                                                              self.pattern = PatternFinder()
                                                                                              def round(self, last):
                                                                                              self.other.append(last)
                                                                                              if last:
                                                                                              if len(self.other) < len(self.handshake):
                                                                                              # still trying to handshake
                                                                                              if self.friendly == False or self.other[-1] != self.handshake[-1]:
                                                                                              self.friendly = False
                                                                                              else:
                                                                                              self.friendly = True
                                                                                              move = self.handshake[len(self.other)]
                                                                                              self.pattern.round(last)
                                                                                              elif self.friendly == True:
                                                                                              # successful handshake and continued cooperation
                                                                                              move = self.pattern.round(last)
                                                                                              if last == "C":
                                                                                              move = "C"
                                                                                              elif last == self.handshake[-1] and self.moves[-1] == self.handshake[-1]:
                                                                                              move = "C"
                                                                                              else:
                                                                                              self.friendly = False
                                                                                              else:
                                                                                              # failed handshake or abandoned cooperation
                                                                                              move = self.pattern.round(last)
                                                                                              else:
                                                                                              move = self.handshake[1]
                                                                                              self.pattern.round(last)
                                                                                              self.moves.append(move)
                                                                                              return move


                                                                                              Why pattern match yourself? Handshake and cooperate away.






                                                                                              share|improve this answer









                                                                                              $endgroup$



                                                                                              HandshakePatternMatch



                                                                                              from .patternfinder import PatternFinder
                                                                                              import collections

                                                                                              class HandshakePatternMatch:
                                                                                              def __init__(self):
                                                                                              self.moves = [None]
                                                                                              self.other =
                                                                                              self.handshake = [None,"N","C","C","D","N"]
                                                                                              self.friendly = None
                                                                                              self.pattern = PatternFinder()
                                                                                              def round(self, last):
                                                                                              self.other.append(last)
                                                                                              if last:
                                                                                              if len(self.other) < len(self.handshake):
                                                                                              # still trying to handshake
                                                                                              if self.friendly == False or self.other[-1] != self.handshake[-1]:
                                                                                              self.friendly = False
                                                                                              else:
                                                                                              self.friendly = True
                                                                                              move = self.handshake[len(self.other)]
                                                                                              self.pattern.round(last)
                                                                                              elif self.friendly == True:
                                                                                              # successful handshake and continued cooperation
                                                                                              move = self.pattern.round(last)
                                                                                              if last == "C":
                                                                                              move = "C"
                                                                                              elif last == self.handshake[-1] and self.moves[-1] == self.handshake[-1]:
                                                                                              move = "C"
                                                                                              else:
                                                                                              self.friendly = False
                                                                                              else:
                                                                                              # failed handshake or abandoned cooperation
                                                                                              move = self.pattern.round(last)
                                                                                              else:
                                                                                              move = self.handshake[1]
                                                                                              self.pattern.round(last)
                                                                                              self.moves.append(move)
                                                                                              return move


                                                                                              Why pattern match yourself? Handshake and cooperate away.







                                                                                              share|improve this answer












                                                                                              share|improve this answer



                                                                                              share|improve this answer










                                                                                              answered Nov 17 '18 at 2:13









                                                                                              Draco18sDraco18s

                                                                                              1,261619




                                                                                              1,261619












                                                                                              • $begingroup$
                                                                                                import PatternFinder is cheating in my books.
                                                                                                $endgroup$
                                                                                                – Blacksilver
                                                                                                Nov 17 '18 at 2:30










                                                                                              • $begingroup$
                                                                                                @Blacksilver It gets done all the time in KOTH. It's no different than copying the code in an existing answer and using it. Robot Roulette: High stakes robot gambling had it happening all over the place to the point that bots would detect if their code was being called by an opponent and sabotage the return.
                                                                                                $endgroup$
                                                                                                – Draco18s
                                                                                                Nov 17 '18 at 2:36












                                                                                              • $begingroup$
                                                                                                Alright then. TIL.
                                                                                                $endgroup$
                                                                                                – Blacksilver
                                                                                                Nov 17 '18 at 2:37










                                                                                              • $begingroup$
                                                                                                I'll do the crunching tomorrow.
                                                                                                $endgroup$
                                                                                                – Blacksilver
                                                                                                Nov 17 '18 at 2:38










                                                                                              • $begingroup$
                                                                                                Here's a perfect example of using other bots' code. Usually it comes down to "that guy worked out some tricky math, I want his results under these conditions." (My own entry did that to pretty good effect; UpYours was more scatter-shot in its approach).
                                                                                                $endgroup$
                                                                                                – Draco18s
                                                                                                Nov 17 '18 at 2:41




















                                                                                              • $begingroup$
                                                                                                import PatternFinder is cheating in my books.
                                                                                                $endgroup$
                                                                                                – Blacksilver
                                                                                                Nov 17 '18 at 2:30










                                                                                              • $begingroup$
                                                                                                @Blacksilver It gets done all the time in KOTH. It's no different than copying the code in an existing answer and using it. Robot Roulette: High stakes robot gambling had it happening all over the place to the point that bots would detect if their code was being called by an opponent and sabotage the return.
                                                                                                $endgroup$
                                                                                                – Draco18s
                                                                                                Nov 17 '18 at 2:36












                                                                                              • $begingroup$
                                                                                                Alright then. TIL.
                                                                                                $endgroup$
                                                                                                – Blacksilver
                                                                                                Nov 17 '18 at 2:37










                                                                                              • $begingroup$
                                                                                                I'll do the crunching tomorrow.
                                                                                                $endgroup$
                                                                                                – Blacksilver
                                                                                                Nov 17 '18 at 2:38










                                                                                              • $begingroup$
                                                                                                Here's a perfect example of using other bots' code. Usually it comes down to "that guy worked out some tricky math, I want his results under these conditions." (My own entry did that to pretty good effect; UpYours was more scatter-shot in its approach).
                                                                                                $endgroup$
                                                                                                – Draco18s
                                                                                                Nov 17 '18 at 2:41


















                                                                                              $begingroup$
                                                                                              import PatternFinder is cheating in my books.
                                                                                              $endgroup$
                                                                                              – Blacksilver
                                                                                              Nov 17 '18 at 2:30




                                                                                              $begingroup$
                                                                                              import PatternFinder is cheating in my books.
                                                                                              $endgroup$
                                                                                              – Blacksilver
                                                                                              Nov 17 '18 at 2:30












                                                                                              $begingroup$
                                                                                              @Blacksilver It gets done all the time in KOTH. It's no different than copying the code in an existing answer and using it. Robot Roulette: High stakes robot gambling had it happening all over the place to the point that bots would detect if their code was being called by an opponent and sabotage the return.
                                                                                              $endgroup$
                                                                                              – Draco18s
                                                                                              Nov 17 '18 at 2:36






                                                                                              $begingroup$
                                                                                              @Blacksilver It gets done all the time in KOTH. It's no different than copying the code in an existing answer and using it. Robot Roulette: High stakes robot gambling had it happening all over the place to the point that bots would detect if their code was being called by an opponent and sabotage the return.
                                                                                              $endgroup$
                                                                                              – Draco18s
                                                                                              Nov 17 '18 at 2:36














                                                                                              $begingroup$
                                                                                              Alright then. TIL.
                                                                                              $endgroup$
                                                                                              – Blacksilver
                                                                                              Nov 17 '18 at 2:37




                                                                                              $begingroup$
                                                                                              Alright then. TIL.
                                                                                              $endgroup$
                                                                                              – Blacksilver
                                                                                              Nov 17 '18 at 2:37












                                                                                              $begingroup$
                                                                                              I'll do the crunching tomorrow.
                                                                                              $endgroup$
                                                                                              – Blacksilver
                                                                                              Nov 17 '18 at 2:38




                                                                                              $begingroup$
                                                                                              I'll do the crunching tomorrow.
                                                                                              $endgroup$
                                                                                              – Blacksilver
                                                                                              Nov 17 '18 at 2:38












                                                                                              $begingroup$
                                                                                              Here's a perfect example of using other bots' code. Usually it comes down to "that guy worked out some tricky math, I want his results under these conditions." (My own entry did that to pretty good effect; UpYours was more scatter-shot in its approach).
                                                                                              $endgroup$
                                                                                              – Draco18s
                                                                                              Nov 17 '18 at 2:41






                                                                                              $begingroup$
                                                                                              Here's a perfect example of using other bots' code. Usually it comes down to "that guy worked out some tricky math, I want his results under these conditions." (My own entry did that to pretty good effect; UpYours was more scatter-shot in its approach).
                                                                                              $endgroup$
                                                                                              – Draco18s
                                                                                              Nov 17 '18 at 2:41













                                                                                              0












                                                                                              $begingroup$

                                                                                              Hardcoded



                                                                                              class Hardcoded:
                                                                                              sequence = "DNCNNDDCNDDDCCDNNNNDDCNNDDCDCNNNDNDDCNNDDNDDCDNCCNNDNNDDCNNDDCDCNNNDNCDNDNDDNCNDDCDNNDCNNDDCDCNNDNNDDCDNDDCCNNNDNNDDCNNDDNDCDNCNDDCDNNDDCCNDNNDDCNNNDCDNDDCNNNNDNDDCDNCDCNNDNNDDCDNDDCCNNNDNDDCNNNDNDCDCDNNDCNNDNDDCDNCNNDDCNDNNDDCDNNDCDNDNCDDCNNNDNDNCNDDCDNDDCCNNNNDNDDCNNDDCNNDDCDCNNDNNDDCDNDDCCNDNNDDCNNNDCDNNDNDDCCNNNDNDDNCDCDNNDCNNDNDDCNNDDCDNCNNDDCDNNDCDNDNCDDCNDNNDDCNNNDDCDNCNNDNNDDCNNDDNNDCDNCNDDCNNDCDNNDDCNNDDNCDCNNDNDNDDCDNCDCNNNDNDDCDCNNDNNDDCDNDDCCNNNDNNDDCNDNDNCDDCDCNNNNDNDDCDNCNDDCDNNDDCNNNDNDDCDNCNNDCNNDNDDNCDCDNNNDDCNNDDCNNDDNNDCDNCNDDCNNDDNDCDNNDNDDCCNCDNNDCNNDDNDDCNCDNNDCDNNNDDCNNDDCDCDNNDDCNDNCNNDNNDNDNDDCDNCDCNNNDNDDCDNCNNDDCDNNDCNNDDCNNDDCDCDNNDDCNDNCNNNDDCDNNDCDNDNCNNDNDDNNDNDCDDCCNNNDDCNDNDNCDDCDCNNNDNNDDCNDCDNDDCNNNNDNDDCCNDNNDDCDCNNNDNDDNDDCDNCCNNDNNDDCNNDDCDCNNDNNDDCNNDDNCNDDNNDCDNCNDDCNNDDNDCDNNDNDDCCNCDNNDCNNDNDDCNNDDNCDCDNNDCNNDNDDCDCDNNNNDDCNNDDNDCCNNDDNDDCNCDNNDCNNDDNDDCDNCNDDCNNNNDCDNNDDCNDNDDCDNCNNDCDNNDCNNDNDDNCDCNNDNDDCDNDDCCNNNNDNDDCNNDDCDCNNDNNDDCDCDNNDDC"
                                                                                              def __init__(self):
                                                                                              self.round_num = -1
                                                                                              def round(self,_):
                                                                                              self.round_num += 1
                                                                                              return Hardcoded.sequence[self.round_num % 1000]


                                                                                              Just plays a hardcoded sequence of moves optimized to beat some of the top deterministic bots.






                                                                                              share|improve this answer











                                                                                              $endgroup$


















                                                                                                0












                                                                                                $begingroup$

                                                                                                Hardcoded



                                                                                                class Hardcoded:
                                                                                                sequence = "DNCNNDDCNDDDCCDNNNNDDCNNDDCDCNNNDNDDCNNDDNDDCDNCCNNDNNDDCNNDDCDCNNNDNCDNDNDDNCNDDCDNNDCNNDDCDCNNDNNDDCDNDDCCNNNDNNDDCNNDDNDCDNCNDDCDNNDDCCNDNNDDCNNNDCDNDDCNNNNDNDDCDNCDCNNDNNDDCDNDDCCNNNDNDDCNNNDNDCDCDNNDCNNDNDDCDNCNNDDCNDNNDDCDNNDCDNDNCDDCNNNDNDNCNDDCDNDDCCNNNNDNDDCNNDDCNNDDCDCNNDNNDDCDNDDCCNDNNDDCNNNDCDNNDNDDCCNNNDNDDNCDCDNNDCNNDNDDCNNDDCDNCNNDDCDNNDCDNDNCDDCNDNNDDCNNNDDCDNCNNDNNDDCNNDDNNDCDNCNDDCNNDCDNNDDCNNDDNCDCNNDNDNDDCDNCDCNNNDNDDCDCNNDNNDDCDNDDCCNNNDNNDDCNDNDNCDDCDCNNNNDNDDCDNCNDDCDNNDDCNNNDNDDCDNCNNDCNNDNDDNCDCDNNNDDCNNDDCNNDDNNDCDNCNDDCNNDDNDCDNNDNDDCCNCDNNDCNNDDNDDCNCDNNDCDNNNDDCNNDDCDCDNNDDCNDNCNNDNNDNDNDDCDNCDCNNNDNDDCDNCNNDDCDNNDCNNDDCNNDDCDCDNNDDCNDNCNNNDDCDNNDCDNDNCNNDNDDNNDNDCDDCCNNNDDCNDNDNCDDCDCNNNDNNDDCNDCDNDDCNNNNDNDDCCNDNNDDCDCNNNDNDDNDDCDNCCNNDNNDDCNNDDCDCNNDNNDDCNNDDNCNDDNNDCDNCNDDCNNDDNDCDNNDNDDCCNCDNNDCNNDNDDCNNDDNCDCDNNDCNNDNDDCDCDNNNNDDCNNDDNDCCNNDDNDDCNCDNNDCNNDDNDDCDNCNDDCNNNNDCDNNDDCNDNDDCDNCNNDCDNNDCNNDNDDNCDCNNDNDDCDNDDCCNNNNDNDDCNNDDCDCNNDNNDDCDCDNNDDC"
                                                                                                def __init__(self):
                                                                                                self.round_num = -1
                                                                                                def round(self,_):
                                                                                                self.round_num += 1
                                                                                                return Hardcoded.sequence[self.round_num % 1000]


                                                                                                Just plays a hardcoded sequence of moves optimized to beat some of the top deterministic bots.






                                                                                                share|improve this answer











                                                                                                $endgroup$
















                                                                                                  0












                                                                                                  0








                                                                                                  0





                                                                                                  $begingroup$

                                                                                                  Hardcoded



                                                                                                  class Hardcoded:
                                                                                                  sequence = "DNCNNDDCNDDDCCDNNNNDDCNNDDCDCNNNDNDDCNNDDNDDCDNCCNNDNNDDCNNDDCDCNNNDNCDNDNDDNCNDDCDNNDCNNDDCDCNNDNNDDCDNDDCCNNNDNNDDCNNDDNDCDNCNDDCDNNDDCCNDNNDDCNNNDCDNDDCNNNNDNDDCDNCDCNNDNNDDCDNDDCCNNNDNDDCNNNDNDCDCDNNDCNNDNDDCDNCNNDDCNDNNDDCDNNDCDNDNCDDCNNNDNDNCNDDCDNDDCCNNNNDNDDCNNDDCNNDDCDCNNDNNDDCDNDDCCNDNNDDCNNNDCDNNDNDDCCNNNDNDDNCDCDNNDCNNDNDDCNNDDCDNCNNDDCDNNDCDNDNCDDCNDNNDDCNNNDDCDNCNNDNNDDCNNDDNNDCDNCNDDCNNDCDNNDDCNNDDNCDCNNDNDNDDCDNCDCNNNDNDDCDCNNDNNDDCDNDDCCNNNDNNDDCNDNDNCDDCDCNNNNDNDDCDNCNDDCDNNDDCNNNDNDDCDNCNNDCNNDNDDNCDCDNNNDDCNNDDCNNDDNNDCDNCNDDCNNDDNDCDNNDNDDCCNCDNNDCNNDDNDDCNCDNNDCDNNNDDCNNDDCDCDNNDDCNDNCNNDNNDNDNDDCDNCDCNNNDNDDCDNCNNDDCDNNDCNNDDCNNDDCDCDNNDDCNDNCNNNDDCDNNDCDNDNCNNDNDDNNDNDCDDCCNNNDDCNDNDNCDDCDCNNNDNNDDCNDCDNDDCNNNNDNDDCCNDNNDDCDCNNNDNDDNDDCDNCCNNDNNDDCNNDDCDCNNDNNDDCNNDDNCNDDNNDCDNCNDDCNNDDNDCDNNDNDDCCNCDNNDCNNDNDDCNNDDNCDCDNNDCNNDNDDCDCDNNNNDDCNNDDNDCCNNDDNDDCNCDNNDCNNDDNDDCDNCNDDCNNNNDCDNNDDCNDNDDCDNCNNDCDNNDCNNDNDDNCDCNNDNDDCDNDDCCNNNNDNDDCNNDDCDCNNDNNDDCDCDNNDDC"
                                                                                                  def __init__(self):
                                                                                                  self.round_num = -1
                                                                                                  def round(self,_):
                                                                                                  self.round_num += 1
                                                                                                  return Hardcoded.sequence[self.round_num % 1000]


                                                                                                  Just plays a hardcoded sequence of moves optimized to beat some of the top deterministic bots.






                                                                                                  share|improve this answer











                                                                                                  $endgroup$



                                                                                                  Hardcoded



                                                                                                  class Hardcoded:
                                                                                                  sequence = "DNCNNDDCNDDDCCDNNNNDDCNNDDCDCNNNDNDDCNNDDNDDCDNCCNNDNNDDCNNDDCDCNNNDNCDNDNDDNCNDDCDNNDCNNDDCDCNNDNNDDCDNDDCCNNNDNNDDCNNDDNDCDNCNDDCDNNDDCCNDNNDDCNNNDCDNDDCNNNNDNDDCDNCDCNNDNNDDCDNDDCCNNNDNDDCNNNDNDCDCDNNDCNNDNDDCDNCNNDDCNDNNDDCDNNDCDNDNCDDCNNNDNDNCNDDCDNDDCCNNNNDNDDCNNDDCNNDDCDCNNDNNDDCDNDDCCNDNNDDCNNNDCDNNDNDDCCNNNDNDDNCDCDNNDCNNDNDDCNNDDCDNCNNDDCDNNDCDNDNCDDCNDNNDDCNNNDDCDNCNNDNNDDCNNDDNNDCDNCNDDCNNDCDNNDDCNNDDNCDCNNDNDNDDCDNCDCNNNDNDDCDCNNDNNDDCDNDDCCNNNDNNDDCNDNDNCDDCDCNNNNDNDDCDNCNDDCDNNDDCNNNDNDDCDNCNNDCNNDNDDNCDCDNNNDDCNNDDCNNDDNNDCDNCNDDCNNDDNDCDNNDNDDCCNCDNNDCNNDDNDDCNCDNNDCDNNNDDCNNDDCDCDNNDDCNDNCNNDNNDNDNDDCDNCDCNNNDNDDCDNCNNDDCDNNDCNNDDCNNDDCDCDNNDDCNDNCNNNDDCDNNDCDNDNCNNDNDDNNDNDCDDCCNNNDDCNDNDNCDDCDCNNNDNNDDCNDCDNDDCNNNNDNDDCCNDNNDDCDCNNNDNDDNDDCDNCCNNDNNDDCNNDDCDCNNDNNDDCNNDDNCNDDNNDCDNCNDDCNNDDNDCDNNDNDDCCNCDNNDCNNDNDDCNNDDNCDCDNNDCNNDNDDCDCDNNNNDDCNNDDNDCCNNDDNDDCNCDNNDCNNDDNDDCDNCNDDCNNNNDCDNNDDCNDNDDCDNCNNDCDNNDCNNDNDDNCDCNNDNDDCDNDDCCNNNNDNDDCNNDDCDCNNDNNDDCDCDNNDDC"
                                                                                                  def __init__(self):
                                                                                                  self.round_num = -1
                                                                                                  def round(self,_):
                                                                                                  self.round_num += 1
                                                                                                  return Hardcoded.sequence[self.round_num % 1000]


                                                                                                  Just plays a hardcoded sequence of moves optimized to beat some of the top deterministic bots.







                                                                                                  share|improve this answer














                                                                                                  share|improve this answer



                                                                                                  share|improve this answer








                                                                                                  edited Dec 4 '18 at 14:59

























                                                                                                  answered Dec 4 '18 at 4:37









                                                                                                  MegaTomMegaTom

                                                                                                  3,4721324




                                                                                                  3,4721324

















                                                                                                      protected by Community Nov 18 '18 at 18:02



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