Filtering data where one field is above value depending on another field criteria
Not sure how to title this (therefore didn't get lucky when trying to search for an answer), but let's say I've got a table as follows:
Product Quality Source
P1 0.80 Provider1
P1 0.75 Provider2
P1 0.20 Provider3
P1 0.83 Provider4
P1 0.60 Provider5
P2 0.45 Provider1
P2 0.76 Provider2
P2 0.20 Provider3
P2 0.87 Provider4
P3 0.45 Provider1
P3 0.30 Provider2
P3 0.84 Provider4
P3 0.24 Provider5
and I only want to keep products that are either Provider1 or Provider3 or has a higher quality than the best of qualities of that product on Provider1 or Provider3. So I'd like to end up with:
Product Quality Source
P1 0.80 Provider1
P1 0.20 Provider2
P1 0.83 Provider4
P2 0.45 Provider1
P2 0.76 Provider2
P2 0.20 Provider3
P2 0.87 Provider4
P3 0.45 Provider1
P3 0.84 Provider4
I've got quite a bit of data so I'm looking for a smart way to do this.
Brute force would be something like:
select * from mytable m1 where m1.Source = 'Tier1' or m1.Source > (select max(m2.Quality) from mytable m2 where m2.Product = m1.Product and m2.Source = 'Tier1')
Any suggestion?
Thanks
Edit1: I had simplified the problem slightly by omitting that each product could have multiple sources, I've now amended my post.
Using Littlefoot's suggestion:
with inter as
(
select m1.product, m1.quality, m1.source,
(select max(m2.quality) from mytable m2
where m2.product = m1.product
and m2.source in ('Provider1', 'Provider3')
) max_quality
from mytable m1
)
select product, quality, source from inter
where source in ('Provider1', 'Prodiver3')
or quality > max_quality;
I will need to see if that is fast enough when I run the request on the whole table (~hundreds of thousands of rows).
oracle
add a comment |
Not sure how to title this (therefore didn't get lucky when trying to search for an answer), but let's say I've got a table as follows:
Product Quality Source
P1 0.80 Provider1
P1 0.75 Provider2
P1 0.20 Provider3
P1 0.83 Provider4
P1 0.60 Provider5
P2 0.45 Provider1
P2 0.76 Provider2
P2 0.20 Provider3
P2 0.87 Provider4
P3 0.45 Provider1
P3 0.30 Provider2
P3 0.84 Provider4
P3 0.24 Provider5
and I only want to keep products that are either Provider1 or Provider3 or has a higher quality than the best of qualities of that product on Provider1 or Provider3. So I'd like to end up with:
Product Quality Source
P1 0.80 Provider1
P1 0.20 Provider2
P1 0.83 Provider4
P2 0.45 Provider1
P2 0.76 Provider2
P2 0.20 Provider3
P2 0.87 Provider4
P3 0.45 Provider1
P3 0.84 Provider4
I've got quite a bit of data so I'm looking for a smart way to do this.
Brute force would be something like:
select * from mytable m1 where m1.Source = 'Tier1' or m1.Source > (select max(m2.Quality) from mytable m2 where m2.Product = m1.Product and m2.Source = 'Tier1')
Any suggestion?
Thanks
Edit1: I had simplified the problem slightly by omitting that each product could have multiple sources, I've now amended my post.
Using Littlefoot's suggestion:
with inter as
(
select m1.product, m1.quality, m1.source,
(select max(m2.quality) from mytable m2
where m2.product = m1.product
and m2.source in ('Provider1', 'Provider3')
) max_quality
from mytable m1
)
select product, quality, source from inter
where source in ('Provider1', 'Prodiver3')
or quality > max_quality;
I will need to see if that is fast enough when I run the request on the whole table (~hundreds of thousands of rows).
oracle
add a comment |
Not sure how to title this (therefore didn't get lucky when trying to search for an answer), but let's say I've got a table as follows:
Product Quality Source
P1 0.80 Provider1
P1 0.75 Provider2
P1 0.20 Provider3
P1 0.83 Provider4
P1 0.60 Provider5
P2 0.45 Provider1
P2 0.76 Provider2
P2 0.20 Provider3
P2 0.87 Provider4
P3 0.45 Provider1
P3 0.30 Provider2
P3 0.84 Provider4
P3 0.24 Provider5
and I only want to keep products that are either Provider1 or Provider3 or has a higher quality than the best of qualities of that product on Provider1 or Provider3. So I'd like to end up with:
Product Quality Source
P1 0.80 Provider1
P1 0.20 Provider2
P1 0.83 Provider4
P2 0.45 Provider1
P2 0.76 Provider2
P2 0.20 Provider3
P2 0.87 Provider4
P3 0.45 Provider1
P3 0.84 Provider4
I've got quite a bit of data so I'm looking for a smart way to do this.
Brute force would be something like:
select * from mytable m1 where m1.Source = 'Tier1' or m1.Source > (select max(m2.Quality) from mytable m2 where m2.Product = m1.Product and m2.Source = 'Tier1')
Any suggestion?
Thanks
Edit1: I had simplified the problem slightly by omitting that each product could have multiple sources, I've now amended my post.
Using Littlefoot's suggestion:
with inter as
(
select m1.product, m1.quality, m1.source,
(select max(m2.quality) from mytable m2
where m2.product = m1.product
and m2.source in ('Provider1', 'Provider3')
) max_quality
from mytable m1
)
select product, quality, source from inter
where source in ('Provider1', 'Prodiver3')
or quality > max_quality;
I will need to see if that is fast enough when I run the request on the whole table (~hundreds of thousands of rows).
oracle
Not sure how to title this (therefore didn't get lucky when trying to search for an answer), but let's say I've got a table as follows:
Product Quality Source
P1 0.80 Provider1
P1 0.75 Provider2
P1 0.20 Provider3
P1 0.83 Provider4
P1 0.60 Provider5
P2 0.45 Provider1
P2 0.76 Provider2
P2 0.20 Provider3
P2 0.87 Provider4
P3 0.45 Provider1
P3 0.30 Provider2
P3 0.84 Provider4
P3 0.24 Provider5
and I only want to keep products that are either Provider1 or Provider3 or has a higher quality than the best of qualities of that product on Provider1 or Provider3. So I'd like to end up with:
Product Quality Source
P1 0.80 Provider1
P1 0.20 Provider2
P1 0.83 Provider4
P2 0.45 Provider1
P2 0.76 Provider2
P2 0.20 Provider3
P2 0.87 Provider4
P3 0.45 Provider1
P3 0.84 Provider4
I've got quite a bit of data so I'm looking for a smart way to do this.
Brute force would be something like:
select * from mytable m1 where m1.Source = 'Tier1' or m1.Source > (select max(m2.Quality) from mytable m2 where m2.Product = m1.Product and m2.Source = 'Tier1')
Any suggestion?
Thanks
Edit1: I had simplified the problem slightly by omitting that each product could have multiple sources, I've now amended my post.
Using Littlefoot's suggestion:
with inter as
(
select m1.product, m1.quality, m1.source,
(select max(m2.quality) from mytable m2
where m2.product = m1.product
and m2.source in ('Provider1', 'Provider3')
) max_quality
from mytable m1
)
select product, quality, source from inter
where source in ('Provider1', 'Prodiver3')
or quality > max_quality;
I will need to see if that is fast enough when I run the request on the whole table (~hundreds of thousands of rows).
oracle
oracle
edited Nov 13 '18 at 9:12
Will1v
asked Nov 12 '18 at 19:48
Will1vWill1v
5018
5018
add a comment |
add a comment |
1 Answer
1
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One option might be
SQL> with test (product, quality, source) as
2 (select 'P1', 0.8, 'Tier1' from dual union all
3 select 'P2', 0.75, 'Tier2' from dual union all
4 select 'P3', 0.2, 'Tier2' from dual union all
5 select 'P4', 0.83, 'Tier2' from dual union all
6 select 'P5', 0.6, 'Tier1' from dual
7 ),
8 inter as
9 (select product, quality, source,
10 (select max(quality) max_qual from test
11 where source = 'Tier1'
12 ) max_qual
13 from test
14 )
15 select product, quality, source
16 From inter
17 where source = 'Tier1'
18 or quality > max_qual;
PR QUALITY SOURC
-- ---------- -----
P1 ,8 Tier1
P4 ,83 Tier2
P5 ,6 Tier1
SQL>
Or:
<snip>
8 inter as
9 (select product, quality, source,
10 max(case when source = 'Tier1' then quality else 0 end) over (order by null) max_qual
11 from test
12 )
13 select product, quality, source
14 from inter
15 where source = 'Tier1'
16 or quality > max_qual;
PR QUALITY SOURC
-- ---------- -----
P1 ,8 Tier1
P4 ,83 Tier2
P5 ,6 Tier1
SQL>
Thanks Littlefoot. I'm not sure I understand the first part. Why : ` with test (product, quality, source) as` ` (select 'P1', 0.8, 'Tier1' from dual union all` ` select 'P2', 0.75, 'Tier2' from dual union all` ` select 'P3', 0.2, 'Tier2' from dual union all` ` select 'P4', 0.83, 'Tier2' from dual union all` ` select 'P5', 0.6, 'Tier1' from dual` ` ),` rather than: ` with test (product, quality, source) as` ` (select product, quality, source from mytable)` (this would make sense because I actually have more than those 3 fields in mytable)
– Will1v
Nov 12 '18 at 20:37
Not sure how to make my comment above readable...
– Will1v
Nov 12 '18 at 20:41
1
I used CTE (a common-table-expression, the WITH factoring clause) to "simulate" a table. I used list of columns I saw in your example. As you didn't post CREATE TABLE nor INSERT INTO statements, I used CTE to get some data to be able to write a query which will return something. No problem if you have additional columns, if they don't affect the result.
– Littlefoot
Nov 12 '18 at 20:42
Thanks Littlefoot. I’ve edited my post and used your suggestion to try and answer the new version of the problem.
– Will1v
Nov 13 '18 at 9:21
add a comment |
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One option might be
SQL> with test (product, quality, source) as
2 (select 'P1', 0.8, 'Tier1' from dual union all
3 select 'P2', 0.75, 'Tier2' from dual union all
4 select 'P3', 0.2, 'Tier2' from dual union all
5 select 'P4', 0.83, 'Tier2' from dual union all
6 select 'P5', 0.6, 'Tier1' from dual
7 ),
8 inter as
9 (select product, quality, source,
10 (select max(quality) max_qual from test
11 where source = 'Tier1'
12 ) max_qual
13 from test
14 )
15 select product, quality, source
16 From inter
17 where source = 'Tier1'
18 or quality > max_qual;
PR QUALITY SOURC
-- ---------- -----
P1 ,8 Tier1
P4 ,83 Tier2
P5 ,6 Tier1
SQL>
Or:
<snip>
8 inter as
9 (select product, quality, source,
10 max(case when source = 'Tier1' then quality else 0 end) over (order by null) max_qual
11 from test
12 )
13 select product, quality, source
14 from inter
15 where source = 'Tier1'
16 or quality > max_qual;
PR QUALITY SOURC
-- ---------- -----
P1 ,8 Tier1
P4 ,83 Tier2
P5 ,6 Tier1
SQL>
Thanks Littlefoot. I'm not sure I understand the first part. Why : ` with test (product, quality, source) as` ` (select 'P1', 0.8, 'Tier1' from dual union all` ` select 'P2', 0.75, 'Tier2' from dual union all` ` select 'P3', 0.2, 'Tier2' from dual union all` ` select 'P4', 0.83, 'Tier2' from dual union all` ` select 'P5', 0.6, 'Tier1' from dual` ` ),` rather than: ` with test (product, quality, source) as` ` (select product, quality, source from mytable)` (this would make sense because I actually have more than those 3 fields in mytable)
– Will1v
Nov 12 '18 at 20:37
Not sure how to make my comment above readable...
– Will1v
Nov 12 '18 at 20:41
1
I used CTE (a common-table-expression, the WITH factoring clause) to "simulate" a table. I used list of columns I saw in your example. As you didn't post CREATE TABLE nor INSERT INTO statements, I used CTE to get some data to be able to write a query which will return something. No problem if you have additional columns, if they don't affect the result.
– Littlefoot
Nov 12 '18 at 20:42
Thanks Littlefoot. I’ve edited my post and used your suggestion to try and answer the new version of the problem.
– Will1v
Nov 13 '18 at 9:21
add a comment |
One option might be
SQL> with test (product, quality, source) as
2 (select 'P1', 0.8, 'Tier1' from dual union all
3 select 'P2', 0.75, 'Tier2' from dual union all
4 select 'P3', 0.2, 'Tier2' from dual union all
5 select 'P4', 0.83, 'Tier2' from dual union all
6 select 'P5', 0.6, 'Tier1' from dual
7 ),
8 inter as
9 (select product, quality, source,
10 (select max(quality) max_qual from test
11 where source = 'Tier1'
12 ) max_qual
13 from test
14 )
15 select product, quality, source
16 From inter
17 where source = 'Tier1'
18 or quality > max_qual;
PR QUALITY SOURC
-- ---------- -----
P1 ,8 Tier1
P4 ,83 Tier2
P5 ,6 Tier1
SQL>
Or:
<snip>
8 inter as
9 (select product, quality, source,
10 max(case when source = 'Tier1' then quality else 0 end) over (order by null) max_qual
11 from test
12 )
13 select product, quality, source
14 from inter
15 where source = 'Tier1'
16 or quality > max_qual;
PR QUALITY SOURC
-- ---------- -----
P1 ,8 Tier1
P4 ,83 Tier2
P5 ,6 Tier1
SQL>
Thanks Littlefoot. I'm not sure I understand the first part. Why : ` with test (product, quality, source) as` ` (select 'P1', 0.8, 'Tier1' from dual union all` ` select 'P2', 0.75, 'Tier2' from dual union all` ` select 'P3', 0.2, 'Tier2' from dual union all` ` select 'P4', 0.83, 'Tier2' from dual union all` ` select 'P5', 0.6, 'Tier1' from dual` ` ),` rather than: ` with test (product, quality, source) as` ` (select product, quality, source from mytable)` (this would make sense because I actually have more than those 3 fields in mytable)
– Will1v
Nov 12 '18 at 20:37
Not sure how to make my comment above readable...
– Will1v
Nov 12 '18 at 20:41
1
I used CTE (a common-table-expression, the WITH factoring clause) to "simulate" a table. I used list of columns I saw in your example. As you didn't post CREATE TABLE nor INSERT INTO statements, I used CTE to get some data to be able to write a query which will return something. No problem if you have additional columns, if they don't affect the result.
– Littlefoot
Nov 12 '18 at 20:42
Thanks Littlefoot. I’ve edited my post and used your suggestion to try and answer the new version of the problem.
– Will1v
Nov 13 '18 at 9:21
add a comment |
One option might be
SQL> with test (product, quality, source) as
2 (select 'P1', 0.8, 'Tier1' from dual union all
3 select 'P2', 0.75, 'Tier2' from dual union all
4 select 'P3', 0.2, 'Tier2' from dual union all
5 select 'P4', 0.83, 'Tier2' from dual union all
6 select 'P5', 0.6, 'Tier1' from dual
7 ),
8 inter as
9 (select product, quality, source,
10 (select max(quality) max_qual from test
11 where source = 'Tier1'
12 ) max_qual
13 from test
14 )
15 select product, quality, source
16 From inter
17 where source = 'Tier1'
18 or quality > max_qual;
PR QUALITY SOURC
-- ---------- -----
P1 ,8 Tier1
P4 ,83 Tier2
P5 ,6 Tier1
SQL>
Or:
<snip>
8 inter as
9 (select product, quality, source,
10 max(case when source = 'Tier1' then quality else 0 end) over (order by null) max_qual
11 from test
12 )
13 select product, quality, source
14 from inter
15 where source = 'Tier1'
16 or quality > max_qual;
PR QUALITY SOURC
-- ---------- -----
P1 ,8 Tier1
P4 ,83 Tier2
P5 ,6 Tier1
SQL>
One option might be
SQL> with test (product, quality, source) as
2 (select 'P1', 0.8, 'Tier1' from dual union all
3 select 'P2', 0.75, 'Tier2' from dual union all
4 select 'P3', 0.2, 'Tier2' from dual union all
5 select 'P4', 0.83, 'Tier2' from dual union all
6 select 'P5', 0.6, 'Tier1' from dual
7 ),
8 inter as
9 (select product, quality, source,
10 (select max(quality) max_qual from test
11 where source = 'Tier1'
12 ) max_qual
13 from test
14 )
15 select product, quality, source
16 From inter
17 where source = 'Tier1'
18 or quality > max_qual;
PR QUALITY SOURC
-- ---------- -----
P1 ,8 Tier1
P4 ,83 Tier2
P5 ,6 Tier1
SQL>
Or:
<snip>
8 inter as
9 (select product, quality, source,
10 max(case when source = 'Tier1' then quality else 0 end) over (order by null) max_qual
11 from test
12 )
13 select product, quality, source
14 from inter
15 where source = 'Tier1'
16 or quality > max_qual;
PR QUALITY SOURC
-- ---------- -----
P1 ,8 Tier1
P4 ,83 Tier2
P5 ,6 Tier1
SQL>
answered Nov 12 '18 at 19:53
LittlefootLittlefoot
20.8k71433
20.8k71433
Thanks Littlefoot. I'm not sure I understand the first part. Why : ` with test (product, quality, source) as` ` (select 'P1', 0.8, 'Tier1' from dual union all` ` select 'P2', 0.75, 'Tier2' from dual union all` ` select 'P3', 0.2, 'Tier2' from dual union all` ` select 'P4', 0.83, 'Tier2' from dual union all` ` select 'P5', 0.6, 'Tier1' from dual` ` ),` rather than: ` with test (product, quality, source) as` ` (select product, quality, source from mytable)` (this would make sense because I actually have more than those 3 fields in mytable)
– Will1v
Nov 12 '18 at 20:37
Not sure how to make my comment above readable...
– Will1v
Nov 12 '18 at 20:41
1
I used CTE (a common-table-expression, the WITH factoring clause) to "simulate" a table. I used list of columns I saw in your example. As you didn't post CREATE TABLE nor INSERT INTO statements, I used CTE to get some data to be able to write a query which will return something. No problem if you have additional columns, if they don't affect the result.
– Littlefoot
Nov 12 '18 at 20:42
Thanks Littlefoot. I’ve edited my post and used your suggestion to try and answer the new version of the problem.
– Will1v
Nov 13 '18 at 9:21
add a comment |
Thanks Littlefoot. I'm not sure I understand the first part. Why : ` with test (product, quality, source) as` ` (select 'P1', 0.8, 'Tier1' from dual union all` ` select 'P2', 0.75, 'Tier2' from dual union all` ` select 'P3', 0.2, 'Tier2' from dual union all` ` select 'P4', 0.83, 'Tier2' from dual union all` ` select 'P5', 0.6, 'Tier1' from dual` ` ),` rather than: ` with test (product, quality, source) as` ` (select product, quality, source from mytable)` (this would make sense because I actually have more than those 3 fields in mytable)
– Will1v
Nov 12 '18 at 20:37
Not sure how to make my comment above readable...
– Will1v
Nov 12 '18 at 20:41
1
I used CTE (a common-table-expression, the WITH factoring clause) to "simulate" a table. I used list of columns I saw in your example. As you didn't post CREATE TABLE nor INSERT INTO statements, I used CTE to get some data to be able to write a query which will return something. No problem if you have additional columns, if they don't affect the result.
– Littlefoot
Nov 12 '18 at 20:42
Thanks Littlefoot. I’ve edited my post and used your suggestion to try and answer the new version of the problem.
– Will1v
Nov 13 '18 at 9:21
Thanks Littlefoot. I'm not sure I understand the first part. Why : ` with test (product, quality, source) as` ` (select 'P1', 0.8, 'Tier1' from dual union all` ` select 'P2', 0.75, 'Tier2' from dual union all` ` select 'P3', 0.2, 'Tier2' from dual union all` ` select 'P4', 0.83, 'Tier2' from dual union all` ` select 'P5', 0.6, 'Tier1' from dual` ` ),` rather than: ` with test (product, quality, source) as` ` (select product, quality, source from mytable)` (this would make sense because I actually have more than those 3 fields in mytable)
– Will1v
Nov 12 '18 at 20:37
Thanks Littlefoot. I'm not sure I understand the first part. Why : ` with test (product, quality, source) as` ` (select 'P1', 0.8, 'Tier1' from dual union all` ` select 'P2', 0.75, 'Tier2' from dual union all` ` select 'P3', 0.2, 'Tier2' from dual union all` ` select 'P4', 0.83, 'Tier2' from dual union all` ` select 'P5', 0.6, 'Tier1' from dual` ` ),` rather than: ` with test (product, quality, source) as` ` (select product, quality, source from mytable)` (this would make sense because I actually have more than those 3 fields in mytable)
– Will1v
Nov 12 '18 at 20:37
Not sure how to make my comment above readable...
– Will1v
Nov 12 '18 at 20:41
Not sure how to make my comment above readable...
– Will1v
Nov 12 '18 at 20:41
1
1
I used CTE (a common-table-expression, the WITH factoring clause) to "simulate" a table. I used list of columns I saw in your example. As you didn't post CREATE TABLE nor INSERT INTO statements, I used CTE to get some data to be able to write a query which will return something. No problem if you have additional columns, if they don't affect the result.
– Littlefoot
Nov 12 '18 at 20:42
I used CTE (a common-table-expression, the WITH factoring clause) to "simulate" a table. I used list of columns I saw in your example. As you didn't post CREATE TABLE nor INSERT INTO statements, I used CTE to get some data to be able to write a query which will return something. No problem if you have additional columns, if they don't affect the result.
– Littlefoot
Nov 12 '18 at 20:42
Thanks Littlefoot. I’ve edited my post and used your suggestion to try and answer the new version of the problem.
– Will1v
Nov 13 '18 at 9:21
Thanks Littlefoot. I’ve edited my post and used your suggestion to try and answer the new version of the problem.
– Will1v
Nov 13 '18 at 9:21
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StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown