Negate the ^(```) and repeat its element
up vote
1
down vote
favorite
Suppose such a markdown file
In [86]: !cat formatCase.md
Some content in the head
```
>>> '{:20,.2f}'.format(18446744073709551616.0)
'18,446,744,073,709,551,616.00'
```
When formatting an integer, include the comma after the width:
```
>>> '{:20,d}'.format(18446744073709551616)
'18,446,744,073,709,551,616'
```
some content on the foot.
I'd like to add language type to ```
In [88]: c = open("new_format.md").read()
new_c = re.sub(r"```([^`]+)```", r"```python1```",c)
This solution works,
One more step, if there exist situation to make typo error inside ```, one ` or two `` occurs,
then, should replace [^`] with ^(```).
tried alternatively
r"```(^(```))+```"
r"```(?:^(?:```))+```"
r"```((?:^(?:```))+)```"
It does not perform correctly.
How could get it done to consider ^(```) situation.
regex python-3.x
add a comment |
up vote
1
down vote
favorite
Suppose such a markdown file
In [86]: !cat formatCase.md
Some content in the head
```
>>> '{:20,.2f}'.format(18446744073709551616.0)
'18,446,744,073,709,551,616.00'
```
When formatting an integer, include the comma after the width:
```
>>> '{:20,d}'.format(18446744073709551616)
'18,446,744,073,709,551,616'
```
some content on the foot.
I'd like to add language type to ```
In [88]: c = open("new_format.md").read()
new_c = re.sub(r"```([^`]+)```", r"```python1```",c)
This solution works,
One more step, if there exist situation to make typo error inside ```, one ` or two `` occurs,
then, should replace [^`] with ^(```).
tried alternatively
r"```(^(```))+```"
r"```(?:^(?:```))+```"
r"```((?:^(?:```))+)```"
It does not perform correctly.
How could get it done to consider ^(```) situation.
regex python-3.x
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Suppose such a markdown file
In [86]: !cat formatCase.md
Some content in the head
```
>>> '{:20,.2f}'.format(18446744073709551616.0)
'18,446,744,073,709,551,616.00'
```
When formatting an integer, include the comma after the width:
```
>>> '{:20,d}'.format(18446744073709551616)
'18,446,744,073,709,551,616'
```
some content on the foot.
I'd like to add language type to ```
In [88]: c = open("new_format.md").read()
new_c = re.sub(r"```([^`]+)```", r"```python1```",c)
This solution works,
One more step, if there exist situation to make typo error inside ```, one ` or two `` occurs,
then, should replace [^`] with ^(```).
tried alternatively
r"```(^(```))+```"
r"```(?:^(?:```))+```"
r"```((?:^(?:```))+)```"
It does not perform correctly.
How could get it done to consider ^(```) situation.
regex python-3.x
Suppose such a markdown file
In [86]: !cat formatCase.md
Some content in the head
```
>>> '{:20,.2f}'.format(18446744073709551616.0)
'18,446,744,073,709,551,616.00'
```
When formatting an integer, include the comma after the width:
```
>>> '{:20,d}'.format(18446744073709551616)
'18,446,744,073,709,551,616'
```
some content on the foot.
I'd like to add language type to ```
In [88]: c = open("new_format.md").read()
new_c = re.sub(r"```([^`]+)```", r"```python1```",c)
This solution works,
One more step, if there exist situation to make typo error inside ```, one ` or two `` occurs,
then, should replace [^`] with ^(```).
tried alternatively
r"```(^(```))+```"
r"```(?:^(?:```))+```"
r"```((?:^(?:```))+)```"
It does not perform correctly.
How could get it done to consider ^(```) situation.
regex python-3.x
regex python-3.x
edited Nov 11 at 4:29
asked Nov 11 at 3:47
Sawajiri
2029
2029
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
You may use
r'```([^`]*(?:``?(?!`)[^`]*)*)```'
See the regex demo
Details
```
- 3 backticks
([^`]*(?:``?(?!`)[^`]*)*)
- Group 1:
[^`]*
- 0+ chars other than backtick
(?:``?(?!`)[^`]*)*
- zero or more repetitions of
``?(?!`)
- 1 or 2 backticks not followed with another backtick
[^`]*
- 0+ chars other than backtick
```
- 3 backticks
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
You may use
r'```([^`]*(?:``?(?!`)[^`]*)*)```'
See the regex demo
Details
```
- 3 backticks
([^`]*(?:``?(?!`)[^`]*)*)
- Group 1:
[^`]*
- 0+ chars other than backtick
(?:``?(?!`)[^`]*)*
- zero or more repetitions of
``?(?!`)
- 1 or 2 backticks not followed with another backtick
[^`]*
- 0+ chars other than backtick
```
- 3 backticks
add a comment |
up vote
0
down vote
You may use
r'```([^`]*(?:``?(?!`)[^`]*)*)```'
See the regex demo
Details
```
- 3 backticks
([^`]*(?:``?(?!`)[^`]*)*)
- Group 1:
[^`]*
- 0+ chars other than backtick
(?:``?(?!`)[^`]*)*
- zero or more repetitions of
``?(?!`)
- 1 or 2 backticks not followed with another backtick
[^`]*
- 0+ chars other than backtick
```
- 3 backticks
add a comment |
up vote
0
down vote
up vote
0
down vote
You may use
r'```([^`]*(?:``?(?!`)[^`]*)*)```'
See the regex demo
Details
```
- 3 backticks
([^`]*(?:``?(?!`)[^`]*)*)
- Group 1:
[^`]*
- 0+ chars other than backtick
(?:``?(?!`)[^`]*)*
- zero or more repetitions of
``?(?!`)
- 1 or 2 backticks not followed with another backtick
[^`]*
- 0+ chars other than backtick
```
- 3 backticks
You may use
r'```([^`]*(?:``?(?!`)[^`]*)*)```'
See the regex demo
Details
```
- 3 backticks
([^`]*(?:``?(?!`)[^`]*)*)
- Group 1:
[^`]*
- 0+ chars other than backtick
(?:``?(?!`)[^`]*)*
- zero or more repetitions of
``?(?!`)
- 1 or 2 backticks not followed with another backtick
[^`]*
- 0+ chars other than backtick
```
- 3 backticks
answered Nov 11 at 11:33
Wiktor Stribiżew
302k16123197
302k16123197
add a comment |
add a comment |
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