Build set using hash-map on C++











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I'm trying to build set using hash-map, but testing system sends me wrong answers. I don't have access to tests, but on my tests code works fine. I don't have any ideas for new tests, maybe you'll have some?
This is my code:



#include <iostream>
#include <fstream>
using namespace std;

int h1(int number) {
number %= 1000003;
return abs(number);
}

int h2(int number) {
number = number % 999991 + 12;
return abs(number);
}

int Insert(int * Hash_table,bool * Deleted,int& number) {
int x = h1(number);
int y = h2(number);
for(int i = 0; i < 1000003;i++) {
if(Hash_table[x] == NULL || Deleted[x]) {
Hash_table[x] = number;
Deleted[x] = false;
break;
}
x = (x + i * y) % 1000003;
}
}

string Exists(int * Hash_table,bool * Deleted,int& number) {
int x = h1(number);
int y = h2(number);
for(int i = 0; i < 1000003;i++) {
if(Hash_table[x] == 0 && number == 0 && !Deleted[x])
return "truen";
if(Hash_table[x] != NULL)
if(Hash_table[x] == number && !Deleted[x] ) {
return "truen";
}
if(Hash_table[x] == NULL || Deleted[x])
return "falsen";

x = (x + i * y) % 1000003;

}

}
int Delete(int * Hash_table,bool * Deleted,int& number){
int x = h1(number);
int y = h2(number);
for(int i = 0; i < 1000003;i++){
if(Hash_table[x] == 0 && number == 0){
Deleted[x] = true;
break;
}
if(Hash_table[x] != NULL) {
if(Hash_table[x] == number) {
Deleted[x] = true;
break;
}

x = (x + i * y) % 1000003;
}
else
return 0;
}
}

int main () {
int Hash_table[1000003];
bool Deleted[1000003];
ifstream input("set.in");
ofstream output("set.out");
string command;
int number;
while(true) {
input >> command;
if(input.eof())
break;
if(command == "insert") {
input >> number;
Insert(Hash_table,Deleted,number);
}
if(command == "delete") {
input >> number;
Delete(Hash_table,Deleted,number);
}
if(command == "exists") {
input >> number;
output << Exists(Hash_table,Deleted,number);
}
}
}


I have to realise such commands as "input","exists" and "delete". I think logic of code is nice, but I'm not sure about hash functions.
Updated: Add if statements for 0 and now h1 and h2 return absolute values.
But now I have problems in 4th test.










share|improve this question




















  • 1




    Welcome to Stack Overflow! Talk us through the sorts of local testing that you've done on your end. If you haven't written any local tests, I'd start there - it's much, much easier to debug things when you can see what the program is doing and how the behavior differs from what you expect than it is to submit code to a black box testing framework and hope that it turns out well.
    – templatetypedef
    Nov 10 at 20:25










  • Okay, for example, code works fine for such test: insert 2 insert 5 insert 3 exists 2 exists 4 insert 2 delete 2 exists 2 Output: true false false
    – Василий Югай
    Nov 10 at 20:29








  • 1




    (1) int Hash_table[1000003]; is seriously dangerous. Stack is small, life is short, allocate dynamically. (2) What about 0? Is it a number? insert 0 then exists 0.
    – n.m.
    Nov 10 at 20:40










  • (1) I know limit of number of input numbers (1000000), that's why I used const value. (2) Yes, with 0 my code doesn't work, it's because of NULL? How can I change if operators without using NULL?
    – Василий Югай
    Nov 10 at 20:51








  • 1




    s/NULL/nullptr/
    – Jesper Juhl
    Nov 10 at 20:55















up vote
0
down vote

favorite












I'm trying to build set using hash-map, but testing system sends me wrong answers. I don't have access to tests, but on my tests code works fine. I don't have any ideas for new tests, maybe you'll have some?
This is my code:



#include <iostream>
#include <fstream>
using namespace std;

int h1(int number) {
number %= 1000003;
return abs(number);
}

int h2(int number) {
number = number % 999991 + 12;
return abs(number);
}

int Insert(int * Hash_table,bool * Deleted,int& number) {
int x = h1(number);
int y = h2(number);
for(int i = 0; i < 1000003;i++) {
if(Hash_table[x] == NULL || Deleted[x]) {
Hash_table[x] = number;
Deleted[x] = false;
break;
}
x = (x + i * y) % 1000003;
}
}

string Exists(int * Hash_table,bool * Deleted,int& number) {
int x = h1(number);
int y = h2(number);
for(int i = 0; i < 1000003;i++) {
if(Hash_table[x] == 0 && number == 0 && !Deleted[x])
return "truen";
if(Hash_table[x] != NULL)
if(Hash_table[x] == number && !Deleted[x] ) {
return "truen";
}
if(Hash_table[x] == NULL || Deleted[x])
return "falsen";

x = (x + i * y) % 1000003;

}

}
int Delete(int * Hash_table,bool * Deleted,int& number){
int x = h1(number);
int y = h2(number);
for(int i = 0; i < 1000003;i++){
if(Hash_table[x] == 0 && number == 0){
Deleted[x] = true;
break;
}
if(Hash_table[x] != NULL) {
if(Hash_table[x] == number) {
Deleted[x] = true;
break;
}

x = (x + i * y) % 1000003;
}
else
return 0;
}
}

int main () {
int Hash_table[1000003];
bool Deleted[1000003];
ifstream input("set.in");
ofstream output("set.out");
string command;
int number;
while(true) {
input >> command;
if(input.eof())
break;
if(command == "insert") {
input >> number;
Insert(Hash_table,Deleted,number);
}
if(command == "delete") {
input >> number;
Delete(Hash_table,Deleted,number);
}
if(command == "exists") {
input >> number;
output << Exists(Hash_table,Deleted,number);
}
}
}


I have to realise such commands as "input","exists" and "delete". I think logic of code is nice, but I'm not sure about hash functions.
Updated: Add if statements for 0 and now h1 and h2 return absolute values.
But now I have problems in 4th test.










share|improve this question




















  • 1




    Welcome to Stack Overflow! Talk us through the sorts of local testing that you've done on your end. If you haven't written any local tests, I'd start there - it's much, much easier to debug things when you can see what the program is doing and how the behavior differs from what you expect than it is to submit code to a black box testing framework and hope that it turns out well.
    – templatetypedef
    Nov 10 at 20:25










  • Okay, for example, code works fine for such test: insert 2 insert 5 insert 3 exists 2 exists 4 insert 2 delete 2 exists 2 Output: true false false
    – Василий Югай
    Nov 10 at 20:29








  • 1




    (1) int Hash_table[1000003]; is seriously dangerous. Stack is small, life is short, allocate dynamically. (2) What about 0? Is it a number? insert 0 then exists 0.
    – n.m.
    Nov 10 at 20:40










  • (1) I know limit of number of input numbers (1000000), that's why I used const value. (2) Yes, with 0 my code doesn't work, it's because of NULL? How can I change if operators without using NULL?
    – Василий Югай
    Nov 10 at 20:51








  • 1




    s/NULL/nullptr/
    – Jesper Juhl
    Nov 10 at 20:55













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I'm trying to build set using hash-map, but testing system sends me wrong answers. I don't have access to tests, but on my tests code works fine. I don't have any ideas for new tests, maybe you'll have some?
This is my code:



#include <iostream>
#include <fstream>
using namespace std;

int h1(int number) {
number %= 1000003;
return abs(number);
}

int h2(int number) {
number = number % 999991 + 12;
return abs(number);
}

int Insert(int * Hash_table,bool * Deleted,int& number) {
int x = h1(number);
int y = h2(number);
for(int i = 0; i < 1000003;i++) {
if(Hash_table[x] == NULL || Deleted[x]) {
Hash_table[x] = number;
Deleted[x] = false;
break;
}
x = (x + i * y) % 1000003;
}
}

string Exists(int * Hash_table,bool * Deleted,int& number) {
int x = h1(number);
int y = h2(number);
for(int i = 0; i < 1000003;i++) {
if(Hash_table[x] == 0 && number == 0 && !Deleted[x])
return "truen";
if(Hash_table[x] != NULL)
if(Hash_table[x] == number && !Deleted[x] ) {
return "truen";
}
if(Hash_table[x] == NULL || Deleted[x])
return "falsen";

x = (x + i * y) % 1000003;

}

}
int Delete(int * Hash_table,bool * Deleted,int& number){
int x = h1(number);
int y = h2(number);
for(int i = 0; i < 1000003;i++){
if(Hash_table[x] == 0 && number == 0){
Deleted[x] = true;
break;
}
if(Hash_table[x] != NULL) {
if(Hash_table[x] == number) {
Deleted[x] = true;
break;
}

x = (x + i * y) % 1000003;
}
else
return 0;
}
}

int main () {
int Hash_table[1000003];
bool Deleted[1000003];
ifstream input("set.in");
ofstream output("set.out");
string command;
int number;
while(true) {
input >> command;
if(input.eof())
break;
if(command == "insert") {
input >> number;
Insert(Hash_table,Deleted,number);
}
if(command == "delete") {
input >> number;
Delete(Hash_table,Deleted,number);
}
if(command == "exists") {
input >> number;
output << Exists(Hash_table,Deleted,number);
}
}
}


I have to realise such commands as "input","exists" and "delete". I think logic of code is nice, but I'm not sure about hash functions.
Updated: Add if statements for 0 and now h1 and h2 return absolute values.
But now I have problems in 4th test.










share|improve this question















I'm trying to build set using hash-map, but testing system sends me wrong answers. I don't have access to tests, but on my tests code works fine. I don't have any ideas for new tests, maybe you'll have some?
This is my code:



#include <iostream>
#include <fstream>
using namespace std;

int h1(int number) {
number %= 1000003;
return abs(number);
}

int h2(int number) {
number = number % 999991 + 12;
return abs(number);
}

int Insert(int * Hash_table,bool * Deleted,int& number) {
int x = h1(number);
int y = h2(number);
for(int i = 0; i < 1000003;i++) {
if(Hash_table[x] == NULL || Deleted[x]) {
Hash_table[x] = number;
Deleted[x] = false;
break;
}
x = (x + i * y) % 1000003;
}
}

string Exists(int * Hash_table,bool * Deleted,int& number) {
int x = h1(number);
int y = h2(number);
for(int i = 0; i < 1000003;i++) {
if(Hash_table[x] == 0 && number == 0 && !Deleted[x])
return "truen";
if(Hash_table[x] != NULL)
if(Hash_table[x] == number && !Deleted[x] ) {
return "truen";
}
if(Hash_table[x] == NULL || Deleted[x])
return "falsen";

x = (x + i * y) % 1000003;

}

}
int Delete(int * Hash_table,bool * Deleted,int& number){
int x = h1(number);
int y = h2(number);
for(int i = 0; i < 1000003;i++){
if(Hash_table[x] == 0 && number == 0){
Deleted[x] = true;
break;
}
if(Hash_table[x] != NULL) {
if(Hash_table[x] == number) {
Deleted[x] = true;
break;
}

x = (x + i * y) % 1000003;
}
else
return 0;
}
}

int main () {
int Hash_table[1000003];
bool Deleted[1000003];
ifstream input("set.in");
ofstream output("set.out");
string command;
int number;
while(true) {
input >> command;
if(input.eof())
break;
if(command == "insert") {
input >> number;
Insert(Hash_table,Deleted,number);
}
if(command == "delete") {
input >> number;
Delete(Hash_table,Deleted,number);
}
if(command == "exists") {
input >> number;
output << Exists(Hash_table,Deleted,number);
}
}
}


I have to realise such commands as "input","exists" and "delete". I think logic of code is nice, but I'm not sure about hash functions.
Updated: Add if statements for 0 and now h1 and h2 return absolute values.
But now I have problems in 4th test.







c++ algorithm hashmap






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 11 at 20:49

























asked Nov 10 at 20:19









Василий Югай

42




42








  • 1




    Welcome to Stack Overflow! Talk us through the sorts of local testing that you've done on your end. If you haven't written any local tests, I'd start there - it's much, much easier to debug things when you can see what the program is doing and how the behavior differs from what you expect than it is to submit code to a black box testing framework and hope that it turns out well.
    – templatetypedef
    Nov 10 at 20:25










  • Okay, for example, code works fine for such test: insert 2 insert 5 insert 3 exists 2 exists 4 insert 2 delete 2 exists 2 Output: true false false
    – Василий Югай
    Nov 10 at 20:29








  • 1




    (1) int Hash_table[1000003]; is seriously dangerous. Stack is small, life is short, allocate dynamically. (2) What about 0? Is it a number? insert 0 then exists 0.
    – n.m.
    Nov 10 at 20:40










  • (1) I know limit of number of input numbers (1000000), that's why I used const value. (2) Yes, with 0 my code doesn't work, it's because of NULL? How can I change if operators without using NULL?
    – Василий Югай
    Nov 10 at 20:51








  • 1




    s/NULL/nullptr/
    – Jesper Juhl
    Nov 10 at 20:55














  • 1




    Welcome to Stack Overflow! Talk us through the sorts of local testing that you've done on your end. If you haven't written any local tests, I'd start there - it's much, much easier to debug things when you can see what the program is doing and how the behavior differs from what you expect than it is to submit code to a black box testing framework and hope that it turns out well.
    – templatetypedef
    Nov 10 at 20:25










  • Okay, for example, code works fine for such test: insert 2 insert 5 insert 3 exists 2 exists 4 insert 2 delete 2 exists 2 Output: true false false
    – Василий Югай
    Nov 10 at 20:29








  • 1




    (1) int Hash_table[1000003]; is seriously dangerous. Stack is small, life is short, allocate dynamically. (2) What about 0? Is it a number? insert 0 then exists 0.
    – n.m.
    Nov 10 at 20:40










  • (1) I know limit of number of input numbers (1000000), that's why I used const value. (2) Yes, with 0 my code doesn't work, it's because of NULL? How can I change if operators without using NULL?
    – Василий Югай
    Nov 10 at 20:51








  • 1




    s/NULL/nullptr/
    – Jesper Juhl
    Nov 10 at 20:55








1




1




Welcome to Stack Overflow! Talk us through the sorts of local testing that you've done on your end. If you haven't written any local tests, I'd start there - it's much, much easier to debug things when you can see what the program is doing and how the behavior differs from what you expect than it is to submit code to a black box testing framework and hope that it turns out well.
– templatetypedef
Nov 10 at 20:25




Welcome to Stack Overflow! Talk us through the sorts of local testing that you've done on your end. If you haven't written any local tests, I'd start there - it's much, much easier to debug things when you can see what the program is doing and how the behavior differs from what you expect than it is to submit code to a black box testing framework and hope that it turns out well.
– templatetypedef
Nov 10 at 20:25












Okay, for example, code works fine for such test: insert 2 insert 5 insert 3 exists 2 exists 4 insert 2 delete 2 exists 2 Output: true false false
– Василий Югай
Nov 10 at 20:29






Okay, for example, code works fine for such test: insert 2 insert 5 insert 3 exists 2 exists 4 insert 2 delete 2 exists 2 Output: true false false
– Василий Югай
Nov 10 at 20:29






1




1




(1) int Hash_table[1000003]; is seriously dangerous. Stack is small, life is short, allocate dynamically. (2) What about 0? Is it a number? insert 0 then exists 0.
– n.m.
Nov 10 at 20:40




(1) int Hash_table[1000003]; is seriously dangerous. Stack is small, life is short, allocate dynamically. (2) What about 0? Is it a number? insert 0 then exists 0.
– n.m.
Nov 10 at 20:40












(1) I know limit of number of input numbers (1000000), that's why I used const value. (2) Yes, with 0 my code doesn't work, it's because of NULL? How can I change if operators without using NULL?
– Василий Югай
Nov 10 at 20:51






(1) I know limit of number of input numbers (1000000), that's why I used const value. (2) Yes, with 0 my code doesn't work, it's because of NULL? How can I change if operators without using NULL?
– Василий Югай
Nov 10 at 20:51






1




1




s/NULL/nullptr/
– Jesper Juhl
Nov 10 at 20:55




s/NULL/nullptr/
– Jesper Juhl
Nov 10 at 20:55












1 Answer
1






active

oldest

votes

















up vote
0
down vote



accepted










int h1(int number) {
number %= 1000003;
return number;
}

int h2(int number) {
number = number % 99991 + 1;
return number;
}


Abouve function will give negative output for negative number. That will cause runtime error for Hash_table[x]. See below:



int h1(int number) {
number = (number%1000003 + 1000003) % 1000003;
return number;
}

int h2(int number) {
number = (number % 99991 + 99991) % 99991 + 1;
return number;
}





share|improve this answer





















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    up vote
    0
    down vote



    accepted










    int h1(int number) {
    number %= 1000003;
    return number;
    }

    int h2(int number) {
    number = number % 99991 + 1;
    return number;
    }


    Abouve function will give negative output for negative number. That will cause runtime error for Hash_table[x]. See below:



    int h1(int number) {
    number = (number%1000003 + 1000003) % 1000003;
    return number;
    }

    int h2(int number) {
    number = (number % 99991 + 99991) % 99991 + 1;
    return number;
    }





    share|improve this answer

























      up vote
      0
      down vote



      accepted










      int h1(int number) {
      number %= 1000003;
      return number;
      }

      int h2(int number) {
      number = number % 99991 + 1;
      return number;
      }


      Abouve function will give negative output for negative number. That will cause runtime error for Hash_table[x]. See below:



      int h1(int number) {
      number = (number%1000003 + 1000003) % 1000003;
      return number;
      }

      int h2(int number) {
      number = (number % 99991 + 99991) % 99991 + 1;
      return number;
      }





      share|improve this answer























        up vote
        0
        down vote



        accepted







        up vote
        0
        down vote



        accepted






        int h1(int number) {
        number %= 1000003;
        return number;
        }

        int h2(int number) {
        number = number % 99991 + 1;
        return number;
        }


        Abouve function will give negative output for negative number. That will cause runtime error for Hash_table[x]. See below:



        int h1(int number) {
        number = (number%1000003 + 1000003) % 1000003;
        return number;
        }

        int h2(int number) {
        number = (number % 99991 + 99991) % 99991 + 1;
        return number;
        }





        share|improve this answer












        int h1(int number) {
        number %= 1000003;
        return number;
        }

        int h2(int number) {
        number = number % 99991 + 1;
        return number;
        }


        Abouve function will give negative output for negative number. That will cause runtime error for Hash_table[x]. See below:



        int h1(int number) {
        number = (number%1000003 + 1000003) % 1000003;
        return number;
        }

        int h2(int number) {
        number = (number % 99991 + 99991) % 99991 + 1;
        return number;
        }






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 11 at 7:25









        nightfury1204

        1,30748




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