summing 2 arrays to third array
i'm trying to make a program for my college task. it's about summing 2 arrays and the output into third array. but there's an error ArrayOutOfBoundsException but idk where's the error.
here's my source code
Scanner sc = new Scanner(System.in);
int arr1 = new int[3];
int arr2 = new int[3];
int i, j, k;
for(i = 0; i < 3; i++) {
System.out.print("Masukkan array pertama ke-" + i + ": ");
arr1[i] = sc.nextInt();
}
for(j = 0; j < 3; j++) {
System.out.print("Masukkan array kedua ke-" + j + ": ");
arr2[j] = sc.nextInt();
}
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
the expected is like this
arr1 = {1, 2, 3, 4}
arr2 = {1, 2, 3, 4}
arr3 = {2, 4, 6, 8}
java
add a comment |
i'm trying to make a program for my college task. it's about summing 2 arrays and the output into third array. but there's an error ArrayOutOfBoundsException but idk where's the error.
here's my source code
Scanner sc = new Scanner(System.in);
int arr1 = new int[3];
int arr2 = new int[3];
int i, j, k;
for(i = 0; i < 3; i++) {
System.out.print("Masukkan array pertama ke-" + i + ": ");
arr1[i] = sc.nextInt();
}
for(j = 0; j < 3; j++) {
System.out.print("Masukkan array kedua ke-" + j + ": ");
arr2[j] = sc.nextInt();
}
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
the expected is like this
arr1 = {1, 2, 3, 4}
arr2 = {1, 2, 3, 4}
arr3 = {2, 4, 6, 8}
java
arr3
is created on each loop iteration (which doesn't make sense) and surrounding for-loop has wrong conditional expression.
– Michael Butscher
Nov 13 '18 at 12:12
for(k = 0; k < 4; k++)
is probably your issue. Shouldn't that bek < 3
?
– OldCurmudgeon
Nov 13 '18 at 12:21
add a comment |
i'm trying to make a program for my college task. it's about summing 2 arrays and the output into third array. but there's an error ArrayOutOfBoundsException but idk where's the error.
here's my source code
Scanner sc = new Scanner(System.in);
int arr1 = new int[3];
int arr2 = new int[3];
int i, j, k;
for(i = 0; i < 3; i++) {
System.out.print("Masukkan array pertama ke-" + i + ": ");
arr1[i] = sc.nextInt();
}
for(j = 0; j < 3; j++) {
System.out.print("Masukkan array kedua ke-" + j + ": ");
arr2[j] = sc.nextInt();
}
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
the expected is like this
arr1 = {1, 2, 3, 4}
arr2 = {1, 2, 3, 4}
arr3 = {2, 4, 6, 8}
java
i'm trying to make a program for my college task. it's about summing 2 arrays and the output into third array. but there's an error ArrayOutOfBoundsException but idk where's the error.
here's my source code
Scanner sc = new Scanner(System.in);
int arr1 = new int[3];
int arr2 = new int[3];
int i, j, k;
for(i = 0; i < 3; i++) {
System.out.print("Masukkan array pertama ke-" + i + ": ");
arr1[i] = sc.nextInt();
}
for(j = 0; j < 3; j++) {
System.out.print("Masukkan array kedua ke-" + j + ": ");
arr2[j] = sc.nextInt();
}
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
the expected is like this
arr1 = {1, 2, 3, 4}
arr2 = {1, 2, 3, 4}
arr3 = {2, 4, 6, 8}
java
java
edited Nov 13 '18 at 12:29
Suraj Rao
23k85770
23k85770
asked Nov 13 '18 at 12:10
Rizky Putra Pradhana BudimanRizky Putra Pradhana Budiman
11
11
arr3
is created on each loop iteration (which doesn't make sense) and surrounding for-loop has wrong conditional expression.
– Michael Butscher
Nov 13 '18 at 12:12
for(k = 0; k < 4; k++)
is probably your issue. Shouldn't that bek < 3
?
– OldCurmudgeon
Nov 13 '18 at 12:21
add a comment |
arr3
is created on each loop iteration (which doesn't make sense) and surrounding for-loop has wrong conditional expression.
– Michael Butscher
Nov 13 '18 at 12:12
for(k = 0; k < 4; k++)
is probably your issue. Shouldn't that bek < 3
?
– OldCurmudgeon
Nov 13 '18 at 12:21
arr3
is created on each loop iteration (which doesn't make sense) and surrounding for-loop has wrong conditional expression.– Michael Butscher
Nov 13 '18 at 12:12
arr3
is created on each loop iteration (which doesn't make sense) and surrounding for-loop has wrong conditional expression.– Michael Butscher
Nov 13 '18 at 12:12
for(k = 0; k < 4; k++)
is probably your issue. Shouldn't that be k < 3
?– OldCurmudgeon
Nov 13 '18 at 12:21
for(k = 0; k < 4; k++)
is probably your issue. Shouldn't that be k < 3
?– OldCurmudgeon
Nov 13 '18 at 12:21
add a comment |
3 Answers
3
active
oldest
votes
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
two major mistakes here. You do k < 4
, while you should do k < 3
Also, you shouldn't re-create the array each iteration. Try this:
int arr3 = new int[3];
for(k = 0; k < 3; k++) {
arr3[k] = arr1[k] + arr2[k]; // i and j don't make sense here.
}
Printing the arrays, you can do after this.
thank you, silly me for doing such a simple mistake!
– Rizky Putra Pradhana Budiman
Nov 13 '18 at 12:31
add a comment |
Based on your expected output, your array size should be 4 instead of 3. Your code should look like this
int arr1 = new int[4];
int arr2 = new int[4];
Your code received an ArrayOutOfBoundsException because the k in your 3rd for loop should be 3 instead of 4 since your k should be less than your array size which is 3. One thing to mention is that instead of hard-coding your array size, it is a better practice to assign a variable to store the size of the array so that you will not need to keep track of the size. Or you can just do this every time you use a for loop:
k < array.length
add a comment |
The problem is the input length is 3 and the output length is 4.
Scanner sc = new Scanner(System.in);
int arr1 = new int[3];
int arr2 = new int[3];
int i, j, k;
//Changed 3 below to 4
for(i = 0; i < 4; i++) {
System.out.print("Masukkan array pertama ke-" + i + ": ");
arr1[i] = sc.nextInt();
}
//Changed 3 below to 4;
for(j = 0; j < 4; j++) {
System.out.print("Masukkan array kedua ke-" + j + ": ");
arr2[j] = sc.nextInt();
}
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
1
this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements
– Stultuske
Nov 13 '18 at 12:23
Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.
– Jolaosho batmat
Nov 13 '18 at 12:35
int arr1 = new int[3]; int arr2 = new int[3];
– Stultuske
Nov 13 '18 at 14:20
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
two major mistakes here. You do k < 4
, while you should do k < 3
Also, you shouldn't re-create the array each iteration. Try this:
int arr3 = new int[3];
for(k = 0; k < 3; k++) {
arr3[k] = arr1[k] + arr2[k]; // i and j don't make sense here.
}
Printing the arrays, you can do after this.
thank you, silly me for doing such a simple mistake!
– Rizky Putra Pradhana Budiman
Nov 13 '18 at 12:31
add a comment |
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
two major mistakes here. You do k < 4
, while you should do k < 3
Also, you shouldn't re-create the array each iteration. Try this:
int arr3 = new int[3];
for(k = 0; k < 3; k++) {
arr3[k] = arr1[k] + arr2[k]; // i and j don't make sense here.
}
Printing the arrays, you can do after this.
thank you, silly me for doing such a simple mistake!
– Rizky Putra Pradhana Budiman
Nov 13 '18 at 12:31
add a comment |
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
two major mistakes here. You do k < 4
, while you should do k < 3
Also, you shouldn't re-create the array each iteration. Try this:
int arr3 = new int[3];
for(k = 0; k < 3; k++) {
arr3[k] = arr1[k] + arr2[k]; // i and j don't make sense here.
}
Printing the arrays, you can do after this.
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
two major mistakes here. You do k < 4
, while you should do k < 3
Also, you shouldn't re-create the array each iteration. Try this:
int arr3 = new int[3];
for(k = 0; k < 3; k++) {
arr3[k] = arr1[k] + arr2[k]; // i and j don't make sense here.
}
Printing the arrays, you can do after this.
edited Nov 13 '18 at 12:23
answered Nov 13 '18 at 12:12
StultuskeStultuske
6,21111626
6,21111626
thank you, silly me for doing such a simple mistake!
– Rizky Putra Pradhana Budiman
Nov 13 '18 at 12:31
add a comment |
thank you, silly me for doing such a simple mistake!
– Rizky Putra Pradhana Budiman
Nov 13 '18 at 12:31
thank you, silly me for doing such a simple mistake!
– Rizky Putra Pradhana Budiman
Nov 13 '18 at 12:31
thank you, silly me for doing such a simple mistake!
– Rizky Putra Pradhana Budiman
Nov 13 '18 at 12:31
add a comment |
Based on your expected output, your array size should be 4 instead of 3. Your code should look like this
int arr1 = new int[4];
int arr2 = new int[4];
Your code received an ArrayOutOfBoundsException because the k in your 3rd for loop should be 3 instead of 4 since your k should be less than your array size which is 3. One thing to mention is that instead of hard-coding your array size, it is a better practice to assign a variable to store the size of the array so that you will not need to keep track of the size. Or you can just do this every time you use a for loop:
k < array.length
add a comment |
Based on your expected output, your array size should be 4 instead of 3. Your code should look like this
int arr1 = new int[4];
int arr2 = new int[4];
Your code received an ArrayOutOfBoundsException because the k in your 3rd for loop should be 3 instead of 4 since your k should be less than your array size which is 3. One thing to mention is that instead of hard-coding your array size, it is a better practice to assign a variable to store the size of the array so that you will not need to keep track of the size. Or you can just do this every time you use a for loop:
k < array.length
add a comment |
Based on your expected output, your array size should be 4 instead of 3. Your code should look like this
int arr1 = new int[4];
int arr2 = new int[4];
Your code received an ArrayOutOfBoundsException because the k in your 3rd for loop should be 3 instead of 4 since your k should be less than your array size which is 3. One thing to mention is that instead of hard-coding your array size, it is a better practice to assign a variable to store the size of the array so that you will not need to keep track of the size. Or you can just do this every time you use a for loop:
k < array.length
Based on your expected output, your array size should be 4 instead of 3. Your code should look like this
int arr1 = new int[4];
int arr2 = new int[4];
Your code received an ArrayOutOfBoundsException because the k in your 3rd for loop should be 3 instead of 4 since your k should be less than your array size which is 3. One thing to mention is that instead of hard-coding your array size, it is a better practice to assign a variable to store the size of the array so that you will not need to keep track of the size. Or you can just do this every time you use a for loop:
k < array.length
answered Nov 13 '18 at 23:25
siang swee kongsiang swee kong
663
663
add a comment |
add a comment |
The problem is the input length is 3 and the output length is 4.
Scanner sc = new Scanner(System.in);
int arr1 = new int[3];
int arr2 = new int[3];
int i, j, k;
//Changed 3 below to 4
for(i = 0; i < 4; i++) {
System.out.print("Masukkan array pertama ke-" + i + ": ");
arr1[i] = sc.nextInt();
}
//Changed 3 below to 4;
for(j = 0; j < 4; j++) {
System.out.print("Masukkan array kedua ke-" + j + ": ");
arr2[j] = sc.nextInt();
}
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
1
this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements
– Stultuske
Nov 13 '18 at 12:23
Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.
– Jolaosho batmat
Nov 13 '18 at 12:35
int arr1 = new int[3]; int arr2 = new int[3];
– Stultuske
Nov 13 '18 at 14:20
add a comment |
The problem is the input length is 3 and the output length is 4.
Scanner sc = new Scanner(System.in);
int arr1 = new int[3];
int arr2 = new int[3];
int i, j, k;
//Changed 3 below to 4
for(i = 0; i < 4; i++) {
System.out.print("Masukkan array pertama ke-" + i + ": ");
arr1[i] = sc.nextInt();
}
//Changed 3 below to 4;
for(j = 0; j < 4; j++) {
System.out.print("Masukkan array kedua ke-" + j + ": ");
arr2[j] = sc.nextInt();
}
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
1
this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements
– Stultuske
Nov 13 '18 at 12:23
Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.
– Jolaosho batmat
Nov 13 '18 at 12:35
int arr1 = new int[3]; int arr2 = new int[3];
– Stultuske
Nov 13 '18 at 14:20
add a comment |
The problem is the input length is 3 and the output length is 4.
Scanner sc = new Scanner(System.in);
int arr1 = new int[3];
int arr2 = new int[3];
int i, j, k;
//Changed 3 below to 4
for(i = 0; i < 4; i++) {
System.out.print("Masukkan array pertama ke-" + i + ": ");
arr1[i] = sc.nextInt();
}
//Changed 3 below to 4;
for(j = 0; j < 4; j++) {
System.out.print("Masukkan array kedua ke-" + j + ": ");
arr2[j] = sc.nextInt();
}
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
The problem is the input length is 3 and the output length is 4.
Scanner sc = new Scanner(System.in);
int arr1 = new int[3];
int arr2 = new int[3];
int i, j, k;
//Changed 3 below to 4
for(i = 0; i < 4; i++) {
System.out.print("Masukkan array pertama ke-" + i + ": ");
arr1[i] = sc.nextInt();
}
//Changed 3 below to 4;
for(j = 0; j < 4; j++) {
System.out.print("Masukkan array kedua ke-" + j + ": ");
arr2[j] = sc.nextInt();
}
for(k = 0; k < 4; k++) {
int arr3 = new int[3];
System.out.println(arr3[k] = arr1[i] + arr2[j]);
}
answered Nov 13 '18 at 12:20
Jolaosho batmatJolaosho batmat
195
195
1
this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements
– Stultuske
Nov 13 '18 at 12:23
Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.
– Jolaosho batmat
Nov 13 '18 at 12:35
int arr1 = new int[3]; int arr2 = new int[3];
– Stultuske
Nov 13 '18 at 14:20
add a comment |
1
this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements
– Stultuske
Nov 13 '18 at 12:23
Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.
– Jolaosho batmat
Nov 13 '18 at 12:35
int arr1 = new int[3]; int arr2 = new int[3];
– Stultuske
Nov 13 '18 at 14:20
1
1
this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements
– Stultuske
Nov 13 '18 at 12:23
this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements
– Stultuske
Nov 13 '18 at 12:23
Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.
– Jolaosho batmat
Nov 13 '18 at 12:35
Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.
– Jolaosho batmat
Nov 13 '18 at 12:35
int arr1 = new int[3]; int arr2 = new int[3];
– Stultuske
Nov 13 '18 at 14:20
int arr1 = new int[3]; int arr2 = new int[3];
– Stultuske
Nov 13 '18 at 14:20
add a comment |
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arr3
is created on each loop iteration (which doesn't make sense) and surrounding for-loop has wrong conditional expression.– Michael Butscher
Nov 13 '18 at 12:12
for(k = 0; k < 4; k++)
is probably your issue. Shouldn't that bek < 3
?– OldCurmudgeon
Nov 13 '18 at 12:21