MDX calculated measure slow when adding operations
I have created a calculated measure through BIDS in a SSAS cube and it's like the following:
IIF([Measures].[RatePct] >= 0.90, [Measures].[measureA], [Measures].[measureB])
The point is that if I convert the above to this:
IIF([Measures].[RatePct] >= 0.90, [Measures].[measureA], 0)
or that:
IIF([Measures].[RatePct] >= 0.90, [Measures].[measureA] + 100, [Measures].[measureB])
the measure becomes extremely slow when using it in the cube.
Any ideas why this is happening and how can it be addressed?
Many thanks
mdx mdx-query
asked Nov 12 '18 at 23:37
Yiannis AYiannis A
32
add a comment |
I have created a calculated measure through BIDS in a SSAS cube and it's like the following:
IIF([Measures].[RatePct] >= 0.90, [Measures].[measureA], [Measures].[measureB])
The point is that if I convert the above to this:
IIF([Measures].[RatePct] >= 0.90, [Measures].[measureA], 0)
or that:
IIF([Measures].[RatePct] >= 0.90, [Measures].[measureA] + 100, [Measures].[measureB])
the measure becomes extremely slow when using it in the cube.
Any ideas why this is happening and how can it be addressed?
Many thanks
mdx mdx-query
asked Nov 12 '18 at 23:37
Yiannis AYiannis A
32
add a comment |
I have created a calculated measure through BIDS in a SSAS cube and it's like the following:
IIF([Measures].[RatePct] >= 0.90, [Measures].[measureA], [Measures].[measureB])
The point is that if I convert the above to this:
IIF([Measures].[RatePct] >= 0.90, [Measures].[measureA], 0)
or that:
IIF([Measures].[RatePct] >= 0.90, [Measures].[measureA] + 100, [Measures].[measureB])
the measure becomes extremely slow when using it in the cube.
Any ideas why this is happening and how can it be addressed?
Many thanks
mdx mdx-query
asked Nov 12 '18 at 23:37
Yiannis AYiannis A
32
I have created a calculated measure through BIDS in a SSAS cube and it's like the following:
IIF([Measures].[RatePct] >= 0.90, [Measures].[measureA], [Measures].[measureB])
The point is that if I convert the above to this:
IIF([Measures].[RatePct] >= 0.90, [Measures].[measureA], 0)
or that:
IIF([Measures].[RatePct] >= 0.90, [Measures].[measureA] + 100, [Measures].[measureB])
the measure becomes extremely slow when using it in the cube.
Any ideas why this is happening and how can it be addressed?
Many thanks
mdx mdx-query
mdx mdx-query
asked Nov 12 '18 at 23:37
Yiannis AYiannis A
32
asked Nov 12 '18 at 23:37
Yiannis AYiannis A
32
asked Nov 12 '18 at 23:37
Yiannis AYiannis A
32
asked Nov 12 '18 at 23:37
Yiannis AYiannis A
32
asked Nov 12 '18 at 23:37
Yiannis AYiannis A
32
32
add a comment |
add a comment |
1 Answer
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That is because in both cases you are returning values that were earlier a possible null. Now the number of empty combinations have decreaded. Consider a case where [Measures].[measureA] was null but since you now have [Measures].[measureA] + 100 this will return 100 as a value. Now you UI will not be able to remove it as a null combination
answered Nov 25 '18 at 0:10
MoazRubMoazRub
31927
Thanks! it's pretty much that. I managed though to make it quick with the below workaround: [Measures].[measureA] + 100*([Measures].[measureA]/[Measures].[measureA]) Now, it became very fast...
– Yiannis A
Nov 26 '18 at 14:02
You are welcome. You might want to consider marking my suggestion as answer
– MoazRub
Nov 26 '18 at 15:01
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
That is because in both cases you are returning values that were earlier a possible null. Now the number of empty combinations have decreaded. Consider a case where [Measures].[measureA] was null but since you now have [Measures].[measureA] + 100 this will return 100 as a value. Now you UI will not be able to remove it as a null combination
answered Nov 25 '18 at 0:10
MoazRubMoazRub
31927
Thanks! it's pretty much that. I managed though to make it quick with the below workaround: [Measures].[measureA] + 100*([Measures].[measureA]/[Measures].[measureA]) Now, it became very fast...
– Yiannis A
Nov 26 '18 at 14:02
You are welcome. You might want to consider marking my suggestion as answer
– MoazRub
Nov 26 '18 at 15:01
add a comment |
That is because in both cases you are returning values that were earlier a possible null. Now the number of empty combinations have decreaded. Consider a case where [Measures].[measureA] was null but since you now have [Measures].[measureA] + 100 this will return 100 as a value. Now you UI will not be able to remove it as a null combination
answered Nov 25 '18 at 0:10
MoazRubMoazRub
31927
Thanks! it's pretty much that. I managed though to make it quick with the below workaround: [Measures].[measureA] + 100*([Measures].[measureA]/[Measures].[measureA]) Now, it became very fast...
– Yiannis A
Nov 26 '18 at 14:02
You are welcome. You might want to consider marking my suggestion as answer
– MoazRub
Nov 26 '18 at 15:01
add a comment |
That is because in both cases you are returning values that were earlier a possible null. Now the number of empty combinations have decreaded. Consider a case where [Measures].[measureA] was null but since you now have [Measures].[measureA] + 100 this will return 100 as a value. Now you UI will not be able to remove it as a null combination
answered Nov 25 '18 at 0:10
MoazRubMoazRub
31927
That is because in both cases you are returning values that were earlier a possible null. Now the number of empty combinations have decreaded. Consider a case where [Measures].[measureA] was null but since you now have [Measures].[measureA] + 100 this will return 100 as a value. Now you UI will not be able to remove it as a null combination
answered Nov 25 '18 at 0:10
MoazRubMoazRub
31927
answered Nov 25 '18 at 0:10
MoazRubMoazRub
31927
answered Nov 25 '18 at 0:10
MoazRubMoazRub
31927
answered Nov 25 '18 at 0:10
MoazRubMoazRub
31927
31927
Thanks! it's pretty much that. I managed though to make it quick with the below workaround: [Measures].[measureA] + 100*([Measures].[measureA]/[Measures].[measureA]) Now, it became very fast...
– Yiannis A
Nov 26 '18 at 14:02
You are welcome. You might want to consider marking my suggestion as answer
– MoazRub
Nov 26 '18 at 15:01
add a comment |
Thanks! it's pretty much that. I managed though to make it quick with the below workaround: [Measures].[measureA] + 100*([Measures].[measureA]/[Measures].[measureA]) Now, it became very fast...
– Yiannis A
Nov 26 '18 at 14:02
You are welcome. You might want to consider marking my suggestion as answer
– MoazRub
Nov 26 '18 at 15:01
Thanks! it's pretty much that. I managed though to make it quick with the below workaround: [Measures].[measureA] + 100*([Measures].[measureA]/[Measures].[measureA]) Now, it became very fast...
– Yiannis A
Nov 26 '18 at 14:02
Thanks! it's pretty much that. I managed though to make it quick with the below workaround: [Measures].[measureA] + 100*([Measures].[measureA]/[Measures].[measureA]) Now, it became very fast...
– Yiannis A
Nov 26 '18 at 14:02
You are welcome. You might want to consider marking my suggestion as answer
– MoazRub
Nov 26 '18 at 15:01
You are welcome. You might want to consider marking my suggestion as answer
– MoazRub
Nov 26 '18 at 15:01
add a comment |
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