Nrthugu

I'm trying to bring a menu with a choice of users to a WordPress page using wordcode, but I don't fully understand how to insert PHP code so that it runs inside the wordcode so that I can display this menu in any part of the topic for that I wrote like this.

add_shortcode ('T1','A2'); // шорд код

function A2(){



   $S1='session_start()';

    $R1='

    ' . $S1 . '

    <form method="POST" >

        <p>Option filter</p>

        Option 1: <input type="radio" name="p1" value="1"' . <?php  if ($_SESSION["p1"] == 1){echo "checked"; } ?> . ' />

        Option 2: <input type="radio" name="p1" value="2"' . <?php  if ($_SESSION["p1"] == 2){echo "checked"; } ?> . ' /> 

        Option 3: <input type="radio" name="p1" value="3"' . <?php  if ($_SESSION["p1"] == 3){echo "checked"; } ?> . '/>  

       <p><input type="submit" value="User"></p>

   </form>

   ';



   return  $R1;

}

but it caused an error

Parse error: syntax error, unexpected '<' in
C:xampphtdocsworwp-contentpluginsGOG11GOG11.php on line 19

after deleting php, it gives an error:

Parse error: syntax error, unexpected 'if' (T_IF) in
C:xampphtdocsworwp-contentpluginsGOG11GOG11.php on line 19

And I cannot start session_start(), it is executed as plain text and if I delete ''; gives an error message:

Warning: session_start(): Cannot start session when headers already
sent in C:xampphtdocsworwp-contentpluginsGOG11GOG11.php on line
15

Is there a way to fix this?

I tried to rewrite the code:

  session_start();





 add_shortcode ('T1','A2'); // шорд код

function A2(){









    $R1='



    <form method="POST" >

        <p>Option filter</p>

        Option 1: <input type="radio" name="p1" value="1"' . ($_SESSION["p1"] == 1 ? 'checked' : '') . ' />

        Option 2: <input type="radio" name="p1" value="2"' . ($_SESSION["p1"] == 3 ? 'checked' : '') . ' /> 

        Option 3: <input type="radio" name="p1" value="3"' . ($_SESSION["p1"] == 2 ? 'checked' : '') . '/>  

       <p><input type="submit" value="User"></p>

   </form>

   ';



   return  $R1;

}     

but now when I send something, 3 is always displayed

You don't want to insert the PHP opening and closing tags here, since you already are in a PHP context.
Basically, you are trying to concatenate two strings, depending on your session content. You can do this with either a ternary operator (basically an inline if-else) like this:

$R1 = ' ...some text... ' . ($_SESSION["p1"] == 1 ? 'checked' : '') . ' ...some more text... ';

(read like "if session p1 equals one, append string checked, otherwise append empty string")

or you can also split things up like this:

$R1 = ' ...some text...';



if( $_SESSION["p1"] == 1 ){

    $R1 .= 'checked';

}



$1 .= ' ...some more text...';

It seems there is string concatenation issue.

add_shortcode ('T1','A2'); // шорд код

 function A2(){

  $p1 = ($_SESSION["p1"] == 1)?"checked":"";

  $p2 = ($_SESSION["p2"] == 2)?"checked":"";

  $p3 = ($_SESSION["p3"] == 3)?"checked":"";



$R1 =''. $S1 .'

 <form method="POST" >

 <p>Option filter</p>

Option 1: <input type="radio" name="p1" value="1" '.$p1.' />

Option 2: <input type="radio" name="p1" value="2" '.$p2.' /> 

Option 3: <input type="radio" name="p1" value="3" '.$p3.'/>  

   <p><input type="submit" value="User"></p>

</form>';



 $S1='session_start()';

     return  $R1;

 }

You didn't say what the error is but first, You need to start the session before using $_SESSION not after, You need also to check if the key exists in the session using isset()

  add_shortcode ('T1','A2'); // шорд код

 function A2(){

     $S1 = '';

     if ( ! session_id() ) {

         $S1 = session_start();

     }

$R1=' 

' . $S1 . '





 <form method="POST" >

 <p>Option filter</p>



Option 1: <input type="radio" name="p1" value="1"' . <?php  if ( isset( $_SESSION['p1'] ) && $_SESSION["p1"] == 1){echo "checked"; } ?> . ' />

Option 2: <input type="radio" name="p1" value="2"' . <?php  if ( isset( $_SESSION['p1'] ) && $_SESSION["p1"] == 2){echo "checked"; } ?> . ' /> 

Option 3: <input type="radio" name="p1" value="3"' . <?php  if ( isset( $_SESSION['p1'] ) && $_SESSION["p1"] == 3){echo "checked"; } ?> . '/>  



   <p><input type="submit" value="User"></p>

</form>

 ';



     return  $R1;



 }

I think I figured out thanks for all the help.

  session_start();

  if ($_POST['p1']){    

$_SESSION['p1'] = $_POST['p1'];

}



 add_shortcode ('T1','A2');  

function A2(){









    $R1='



    <form method="POST" >

        <p>Option filter</p>

        Option 1: <input type="radio" name="p1" value="1"' . ($_SESSION["p1"] == 1 ? 'checked' : '') . ' />

        Option 2: <input type="radio" name="p1" value="2"' . ($_SESSION["p1"] == 2 ? 'checked' : '') . ' /> 

        Option 3: <input type="radio" name="p1" value="3"' . ($_SESSION["p1"] == 3 ? 'checked' : '') . '/>  

       <p><input type="submit" value="User"></p>

   </form>

   ';



   return  $R1;

}