How to index a subdictionary and creating a nested for loop












3














I have a list of lists just like below:



>> new_pd[:3]
[['PokedexNumber',
'Name',
'Type',
'Total',
'HP',
'Attack',
'Defense',
'SpecialAttack',
'SpecialDefense',
'Speed'],
[1.0, 'Bulbasaur', 'GrassPoison', 318.0, 45.0, 49.0, 49.0, 65.0, 65.0, 45.0],
[2.0, 'Ivysaur', 'GrassPoison', 405.0, 60.0, 62.0, 63.0, 80.0, 80.0, 60.0]]


What I want to create is below:



{1.0: {'Attack': 49.0,
'Defense': 49.0,
'HP': 45.0,
'Name': 'Bulbasaur',
'PokedexNumber': 1.0,
'SpecialAttack': 65.0,
'SpecialDefense': 65.0,
'Speed': 45.0,
'Total': 318.0,
'Type': 'GrassPoison'},
2.0: {'Attack': 62.0,
'Defense': 63.0,
'HP': 60.0,
'Name': 'Ivysaur',


So from list of lists, I want to have a big nested dictionary.



To create this, I have written the below code in Python:



new_pd_keys = 
for i in range(1, len(new_pd)):
new_pd_keys.append(new_pd[i][0])


Above, I get all the keys from column 1 and save them to a list called new_pd_keys.



Then use the below code to assign each keys' values:



for i in range(1,len(new_pd)):
new_pd_dict = {key:{'Attack':new_pd[i][5], 'Defense':new_pd[i][6], 'HP':new_pd[i][4],
'Name':new_pd[i][1], 'PokedexNumber':new_pd[i][0], 'SpecialAttack':new_pd[i][7],
'SpecialDefense':new_pd[i][8], 'Speed':new_pd[i][9], 'Total':new_pd[i][3],
'Type':new_pd[i][2]} for key in new_pd_keys }


But what I have is the attributes from my last row. You can see the output below, which are all the same.



{1.0: {'Attack': 110.0,
'Defense': 120.0,
'HP': 80.0,
'Name': 'Volcanion',
'PokedexNumber': 721.0,
'SpecialAttack': 130.0,
'SpecialDefense': 90.0,
'Speed': 70.0,
'Total': 600.0,
'Type': 'FireWater'},
2.0: {'Attack': 110.0,
'Defense': 120.0,
'HP': 80.0,
'Name': 'Volcanion',
'PokedexNumber': 721.0,
'SpecialAttack': 130.0,
'SpecialDefense': 90.0,
'Speed': 70.0,
'Total': 600.0,
'Type': 'FireWater'},


Can you suggest a way to perform the indexing in a better way than mine?










share|improve this question






















  • if you are using a dict where the keys are ascending sequentially, you should be using a list. in this case a list of dicts
    – aydow
    Nov 11 at 22:10
















3














I have a list of lists just like below:



>> new_pd[:3]
[['PokedexNumber',
'Name',
'Type',
'Total',
'HP',
'Attack',
'Defense',
'SpecialAttack',
'SpecialDefense',
'Speed'],
[1.0, 'Bulbasaur', 'GrassPoison', 318.0, 45.0, 49.0, 49.0, 65.0, 65.0, 45.0],
[2.0, 'Ivysaur', 'GrassPoison', 405.0, 60.0, 62.0, 63.0, 80.0, 80.0, 60.0]]


What I want to create is below:



{1.0: {'Attack': 49.0,
'Defense': 49.0,
'HP': 45.0,
'Name': 'Bulbasaur',
'PokedexNumber': 1.0,
'SpecialAttack': 65.0,
'SpecialDefense': 65.0,
'Speed': 45.0,
'Total': 318.0,
'Type': 'GrassPoison'},
2.0: {'Attack': 62.0,
'Defense': 63.0,
'HP': 60.0,
'Name': 'Ivysaur',


So from list of lists, I want to have a big nested dictionary.



To create this, I have written the below code in Python:



new_pd_keys = 
for i in range(1, len(new_pd)):
new_pd_keys.append(new_pd[i][0])


Above, I get all the keys from column 1 and save them to a list called new_pd_keys.



Then use the below code to assign each keys' values:



for i in range(1,len(new_pd)):
new_pd_dict = {key:{'Attack':new_pd[i][5], 'Defense':new_pd[i][6], 'HP':new_pd[i][4],
'Name':new_pd[i][1], 'PokedexNumber':new_pd[i][0], 'SpecialAttack':new_pd[i][7],
'SpecialDefense':new_pd[i][8], 'Speed':new_pd[i][9], 'Total':new_pd[i][3],
'Type':new_pd[i][2]} for key in new_pd_keys }


But what I have is the attributes from my last row. You can see the output below, which are all the same.



{1.0: {'Attack': 110.0,
'Defense': 120.0,
'HP': 80.0,
'Name': 'Volcanion',
'PokedexNumber': 721.0,
'SpecialAttack': 130.0,
'SpecialDefense': 90.0,
'Speed': 70.0,
'Total': 600.0,
'Type': 'FireWater'},
2.0: {'Attack': 110.0,
'Defense': 120.0,
'HP': 80.0,
'Name': 'Volcanion',
'PokedexNumber': 721.0,
'SpecialAttack': 130.0,
'SpecialDefense': 90.0,
'Speed': 70.0,
'Total': 600.0,
'Type': 'FireWater'},


Can you suggest a way to perform the indexing in a better way than mine?










share|improve this question






















  • if you are using a dict where the keys are ascending sequentially, you should be using a list. in this case a list of dicts
    – aydow
    Nov 11 at 22:10














3












3








3







I have a list of lists just like below:



>> new_pd[:3]
[['PokedexNumber',
'Name',
'Type',
'Total',
'HP',
'Attack',
'Defense',
'SpecialAttack',
'SpecialDefense',
'Speed'],
[1.0, 'Bulbasaur', 'GrassPoison', 318.0, 45.0, 49.0, 49.0, 65.0, 65.0, 45.0],
[2.0, 'Ivysaur', 'GrassPoison', 405.0, 60.0, 62.0, 63.0, 80.0, 80.0, 60.0]]


What I want to create is below:



{1.0: {'Attack': 49.0,
'Defense': 49.0,
'HP': 45.0,
'Name': 'Bulbasaur',
'PokedexNumber': 1.0,
'SpecialAttack': 65.0,
'SpecialDefense': 65.0,
'Speed': 45.0,
'Total': 318.0,
'Type': 'GrassPoison'},
2.0: {'Attack': 62.0,
'Defense': 63.0,
'HP': 60.0,
'Name': 'Ivysaur',


So from list of lists, I want to have a big nested dictionary.



To create this, I have written the below code in Python:



new_pd_keys = 
for i in range(1, len(new_pd)):
new_pd_keys.append(new_pd[i][0])


Above, I get all the keys from column 1 and save them to a list called new_pd_keys.



Then use the below code to assign each keys' values:



for i in range(1,len(new_pd)):
new_pd_dict = {key:{'Attack':new_pd[i][5], 'Defense':new_pd[i][6], 'HP':new_pd[i][4],
'Name':new_pd[i][1], 'PokedexNumber':new_pd[i][0], 'SpecialAttack':new_pd[i][7],
'SpecialDefense':new_pd[i][8], 'Speed':new_pd[i][9], 'Total':new_pd[i][3],
'Type':new_pd[i][2]} for key in new_pd_keys }


But what I have is the attributes from my last row. You can see the output below, which are all the same.



{1.0: {'Attack': 110.0,
'Defense': 120.0,
'HP': 80.0,
'Name': 'Volcanion',
'PokedexNumber': 721.0,
'SpecialAttack': 130.0,
'SpecialDefense': 90.0,
'Speed': 70.0,
'Total': 600.0,
'Type': 'FireWater'},
2.0: {'Attack': 110.0,
'Defense': 120.0,
'HP': 80.0,
'Name': 'Volcanion',
'PokedexNumber': 721.0,
'SpecialAttack': 130.0,
'SpecialDefense': 90.0,
'Speed': 70.0,
'Total': 600.0,
'Type': 'FireWater'},


Can you suggest a way to perform the indexing in a better way than mine?










share|improve this question













I have a list of lists just like below:



>> new_pd[:3]
[['PokedexNumber',
'Name',
'Type',
'Total',
'HP',
'Attack',
'Defense',
'SpecialAttack',
'SpecialDefense',
'Speed'],
[1.0, 'Bulbasaur', 'GrassPoison', 318.0, 45.0, 49.0, 49.0, 65.0, 65.0, 45.0],
[2.0, 'Ivysaur', 'GrassPoison', 405.0, 60.0, 62.0, 63.0, 80.0, 80.0, 60.0]]


What I want to create is below:



{1.0: {'Attack': 49.0,
'Defense': 49.0,
'HP': 45.0,
'Name': 'Bulbasaur',
'PokedexNumber': 1.0,
'SpecialAttack': 65.0,
'SpecialDefense': 65.0,
'Speed': 45.0,
'Total': 318.0,
'Type': 'GrassPoison'},
2.0: {'Attack': 62.0,
'Defense': 63.0,
'HP': 60.0,
'Name': 'Ivysaur',


So from list of lists, I want to have a big nested dictionary.



To create this, I have written the below code in Python:



new_pd_keys = 
for i in range(1, len(new_pd)):
new_pd_keys.append(new_pd[i][0])


Above, I get all the keys from column 1 and save them to a list called new_pd_keys.



Then use the below code to assign each keys' values:



for i in range(1,len(new_pd)):
new_pd_dict = {key:{'Attack':new_pd[i][5], 'Defense':new_pd[i][6], 'HP':new_pd[i][4],
'Name':new_pd[i][1], 'PokedexNumber':new_pd[i][0], 'SpecialAttack':new_pd[i][7],
'SpecialDefense':new_pd[i][8], 'Speed':new_pd[i][9], 'Total':new_pd[i][3],
'Type':new_pd[i][2]} for key in new_pd_keys }


But what I have is the attributes from my last row. You can see the output below, which are all the same.



{1.0: {'Attack': 110.0,
'Defense': 120.0,
'HP': 80.0,
'Name': 'Volcanion',
'PokedexNumber': 721.0,
'SpecialAttack': 130.0,
'SpecialDefense': 90.0,
'Speed': 70.0,
'Total': 600.0,
'Type': 'FireWater'},
2.0: {'Attack': 110.0,
'Defense': 120.0,
'HP': 80.0,
'Name': 'Volcanion',
'PokedexNumber': 721.0,
'SpecialAttack': 130.0,
'SpecialDefense': 90.0,
'Speed': 70.0,
'Total': 600.0,
'Type': 'FireWater'},


Can you suggest a way to perform the indexing in a better way than mine?







python dictionary for-loop indexing






share|improve this question













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asked Nov 11 at 21:52









ykesen

795




795












  • if you are using a dict where the keys are ascending sequentially, you should be using a list. in this case a list of dicts
    – aydow
    Nov 11 at 22:10


















  • if you are using a dict where the keys are ascending sequentially, you should be using a list. in this case a list of dicts
    – aydow
    Nov 11 at 22:10
















if you are using a dict where the keys are ascending sequentially, you should be using a list. in this case a list of dicts
– aydow
Nov 11 at 22:10




if you are using a dict where the keys are ascending sequentially, you should be using a list. in this case a list of dicts
– aydow
Nov 11 at 22:10












1 Answer
1






active

oldest

votes


















2














new_thing = {q[0]: dict(zip(thing[0], q[1:])) for q in thing[1:]}





share|improve this answer























  • Thanks! It works, I will just make small changes to update the column order.
    – ykesen
    Nov 11 at 23:40











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1 Answer
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oldest

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oldest

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active

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new_thing = {q[0]: dict(zip(thing[0], q[1:])) for q in thing[1:]}





share|improve this answer























  • Thanks! It works, I will just make small changes to update the column order.
    – ykesen
    Nov 11 at 23:40
















2














new_thing = {q[0]: dict(zip(thing[0], q[1:])) for q in thing[1:]}





share|improve this answer























  • Thanks! It works, I will just make small changes to update the column order.
    – ykesen
    Nov 11 at 23:40














2












2








2






new_thing = {q[0]: dict(zip(thing[0], q[1:])) for q in thing[1:]}





share|improve this answer














new_thing = {q[0]: dict(zip(thing[0], q[1:])) for q in thing[1:]}






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share|improve this answer



share|improve this answer








edited Nov 11 at 22:04

























answered Nov 11 at 21:58









MegaBluejay

35118




35118












  • Thanks! It works, I will just make small changes to update the column order.
    – ykesen
    Nov 11 at 23:40


















  • Thanks! It works, I will just make small changes to update the column order.
    – ykesen
    Nov 11 at 23:40
















Thanks! It works, I will just make small changes to update the column order.
– ykesen
Nov 11 at 23:40




Thanks! It works, I will just make small changes to update the column order.
– ykesen
Nov 11 at 23:40


















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