android Regex issue
I had an issue with this regex:
({(([^p{Space}][^p{Punct}])+)})
The problem is in number of chars. If I typing even number of chars it's works, when odd - not. I was trying to replace '+' with '?' or '*', but result still the same. How can I fix this?
I expect from this regex to block such strings: {%,$ #fd}. And allow this:
{F} or {F242fFSf23}.
android regex edited Nov 12 '18 at 8:53
Jayson Minard
37.9k15107170
asked Nov 8 '18 at 9:05
Skullper
19111
|
show 5 more comments
I had an issue with this regex:
({(([^p{Space}][^p{Punct}])+)})
The problem is in number of chars. If I typing even number of chars it's works, when odd - not. I was trying to replace '+' with '?' or '*', but result still the same. How can I fix this?
I expect from this regex to block such strings: {%,$ #fd}. And allow this:
{F} or {F242fFSf23}.
android regex edited Nov 12 '18 at 8:53
Jayson Minard
37.9k15107170
asked Nov 8 '18 at 9:05
Skullper
19111
What are the pattern requirements? What are you trying to match? Currently, it matches a{, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a}, hence you cannot use 1 char in between{...}
– Wiktor Stribiżew
Nov 8 '18 at 9:08
When you are trying to replace + then how even or odd numbers are coming into the picture?
– Ümañg ßürmån
Nov 8 '18 at 9:09
@WiktorStribiżew I'm trying to block user from entering such string: {%F ,2}. And allow only to type: {Ffrgr2443fdfd}
– Skullper
Nov 8 '18 at 9:09
Try{[^p{Punct}p{Space}]+}or{[^p{P}p{S}s]+}or even{p{Alnum}+}or{[A-Za-z0-9]+}
– Wiktor Stribiżew
Nov 8 '18 at 9:11
@WiktorStribiżew You're awesome. First and second regex working. Thank you!
– Skullper
Nov 8 '18 at 9:14
|
show 5 more comments
I had an issue with this regex:
({(([^p{Space}][^p{Punct}])+)})
The problem is in number of chars. If I typing even number of chars it's works, when odd - not. I was trying to replace '+' with '?' or '*', but result still the same. How can I fix this?
I expect from this regex to block such strings: {%,$ #fd}. And allow this:
{F} or {F242fFSf23}.
android regex edited Nov 12 '18 at 8:53
Jayson Minard
37.9k15107170
asked Nov 8 '18 at 9:05
Skullper
19111
I had an issue with this regex:
({(([^p{Space}][^p{Punct}])+)})
The problem is in number of chars. If I typing even number of chars it's works, when odd - not. I was trying to replace '+' with '?' or '*', but result still the same. How can I fix this?
I expect from this regex to block such strings: {%,$ #fd}. And allow this:
{F} or {F242fFSf23}.
android regex android regex edited Nov 12 '18 at 8:53
Jayson Minard
37.9k15107170
asked Nov 8 '18 at 9:05
Skullper
19111
edited Nov 12 '18 at 8:53
Jayson Minard
37.9k15107170
asked Nov 8 '18 at 9:05
Skullper
19111
edited Nov 12 '18 at 8:53
Jayson Minard
37.9k15107170
edited Nov 12 '18 at 8:53
Jayson Minard
37.9k15107170
edited Nov 12 '18 at 8:53
Jayson Minard
37.9k15107170
37.9k15107170
asked Nov 8 '18 at 9:05
Skullper
19111
asked Nov 8 '18 at 9:05
Skullper
19111
asked Nov 8 '18 at 9:05
Skullper
19111
19111
What are the pattern requirements? What are you trying to match? Currently, it matches a{, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a}, hence you cannot use 1 char in between{...}
– Wiktor Stribiżew
Nov 8 '18 at 9:08
When you are trying to replace + then how even or odd numbers are coming into the picture?
– Ümañg ßürmån
Nov 8 '18 at 9:09
@WiktorStribiżew I'm trying to block user from entering such string: {%F ,2}. And allow only to type: {Ffrgr2443fdfd}
– Skullper
Nov 8 '18 at 9:09
Try{[^p{Punct}p{Space}]+}or{[^p{P}p{S}s]+}or even{p{Alnum}+}or{[A-Za-z0-9]+}
– Wiktor Stribiżew
Nov 8 '18 at 9:11
@WiktorStribiżew You're awesome. First and second regex working. Thank you!
– Skullper
Nov 8 '18 at 9:14
|
show 5 more comments
What are the pattern requirements? What are you trying to match? Currently, it matches a{, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a}, hence you cannot use 1 char in between{...}
– Wiktor Stribiżew
Nov 8 '18 at 9:08
When you are trying to replace + then how even or odd numbers are coming into the picture?
– Ümañg ßürmån
Nov 8 '18 at 9:09
@WiktorStribiżew I'm trying to block user from entering such string: {%F ,2}. And allow only to type: {Ffrgr2443fdfd}
– Skullper
Nov 8 '18 at 9:09
Try{[^p{Punct}p{Space}]+}or{[^p{P}p{S}s]+}or even{p{Alnum}+}or{[A-Za-z0-9]+}
– Wiktor Stribiżew
Nov 8 '18 at 9:11
@WiktorStribiżew You're awesome. First and second regex working. Thank you!
– Skullper
Nov 8 '18 at 9:14
What are the pattern requirements? What are you trying to match? Currently, it matches a
{, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a }, hence you cannot use 1 char in between {...}– Wiktor Stribiżew
Nov 8 '18 at 9:08
What are the pattern requirements? What are you trying to match? Currently, it matches a
{, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a }, hence you cannot use 1 char in between {...}– Wiktor Stribiżew
Nov 8 '18 at 9:08
When you are trying to replace + then how even or odd numbers are coming into the picture?
– Ümañg ßürmån
Nov 8 '18 at 9:09
When you are trying to replace + then how even or odd numbers are coming into the picture?
– Ümañg ßürmån
Nov 8 '18 at 9:09
@WiktorStribiżew I'm trying to block user from entering such string: {%F ,2}. And allow only to type: {Ffrgr2443fdfd}
– Skullper
Nov 8 '18 at 9:09
@WiktorStribiżew I'm trying to block user from entering such string: {%F ,2}. And allow only to type: {Ffrgr2443fdfd}
– Skullper
Nov 8 '18 at 9:09
Try
{[^p{Punct}p{Space}]+} or {[^p{P}p{S}s]+} or even {p{Alnum}+} or {[A-Za-z0-9]+}– Wiktor Stribiżew
Nov 8 '18 at 9:11
Try
{[^p{Punct}p{Space}]+} or {[^p{P}p{S}s]+} or even {p{Alnum}+} or {[A-Za-z0-9]+}– Wiktor Stribiżew
Nov 8 '18 at 9:11
@WiktorStribiżew You're awesome. First and second regex working. Thank you!
– Skullper
Nov 8 '18 at 9:14
@WiktorStribiżew You're awesome. First and second regex working. Thank you!
– Skullper
Nov 8 '18 at 9:14
|
show 5 more comments
2 Answers
2
active
oldest
votes
Currently, it matches a {, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a }, hence you cannot use 1 char in between {...}.
To fix that, you need to use both the character classes inside bracket expression:
{[^p{Punct}p{Space}]+}
or
{[^p{P}p{S}s]+}
Details
{- a{char
[^p{Punct}p{Space}]+- 1 or more repetitons (+) of any char that does not belong to thep{Punct}(punctuation) orp{Space}(whitespace) class.
}- a}.
Note that if the contents between the braces can only include ASCII letters or digits (in regex, [A-Za-z0-9]+), you may even use a mere
{[A-Za-z0-9]+}
answered Nov 8 '18 at 9:15
Wiktor Stribiżew
309k16126202
1
yep, the last regex works too
– Skullper
Nov 8 '18 at 9:18
add a comment |
Disassembling your regex... the reason why it only accepts an even number in between is the following part:
([^p{Space}][^p{Punct}])+
This basically means: something which isn't a space, exactly 1 character and something which isn't a ~punct, exactly 1 character and this several times... so exactly 1 + exactly another 1 are exactly 2 characters... and this several times will always be even.
So what you probably rather want is the following:
[^p{Space}p{Punct}]+
for the part shown above... which will result in the following for your complete regex:
{[^p{Space}p{Punct}]+}
that of course can be simplified even more. I leave that up to you.
answered Nov 8 '18 at 9:14
Roland
9,43711141
add a comment |
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2 Answers
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active
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2 Answers
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active
oldest
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oldest
votes
Currently, it matches a {, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a }, hence you cannot use 1 char in between {...}.
To fix that, you need to use both the character classes inside bracket expression:
{[^p{Punct}p{Space}]+}
or
{[^p{P}p{S}s]+}
Details
{- a{char
[^p{Punct}p{Space}]+- 1 or more repetitons (+) of any char that does not belong to thep{Punct}(punctuation) orp{Space}(whitespace) class.
}- a}.
Note that if the contents between the braces can only include ASCII letters or digits (in regex, [A-Za-z0-9]+), you may even use a mere
{[A-Za-z0-9]+}
answered Nov 8 '18 at 9:15
Wiktor Stribiżew
309k16126202
1
yep, the last regex works too
– Skullper
Nov 8 '18 at 9:18
add a comment |
Currently, it matches a {, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a }, hence you cannot use 1 char in between {...}.
To fix that, you need to use both the character classes inside bracket expression:
{[^p{Punct}p{Space}]+}
or
{[^p{P}p{S}s]+}
Details
{- a{char
[^p{Punct}p{Space}]+- 1 or more repetitons (+) of any char that does not belong to thep{Punct}(punctuation) orp{Space}(whitespace) class.
}- a}.
Note that if the contents between the braces can only include ASCII letters or digits (in regex, [A-Za-z0-9]+), you may even use a mere
{[A-Za-z0-9]+}
answered Nov 8 '18 at 9:15
Wiktor Stribiżew
309k16126202
1
yep, the last regex works too
– Skullper
Nov 8 '18 at 9:18
add a comment |
Currently, it matches a {, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a }, hence you cannot use 1 char in between {...}.
To fix that, you need to use both the character classes inside bracket expression:
{[^p{Punct}p{Space}]+}
or
{[^p{P}p{S}s]+}
Details
{- a{char
[^p{Punct}p{Space}]+- 1 or more repetitons (+) of any char that does not belong to thep{Punct}(punctuation) orp{Space}(whitespace) class.
}- a}.
Note that if the contents between the braces can only include ASCII letters or digits (in regex, [A-Za-z0-9]+), you may even use a mere
{[A-Za-z0-9]+}
answered Nov 8 '18 at 9:15
Wiktor Stribiżew
309k16126202
Currently, it matches a {, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a }, hence you cannot use 1 char in between {...}.
To fix that, you need to use both the character classes inside bracket expression:
{[^p{Punct}p{Space}]+}
or
{[^p{P}p{S}s]+}
Details
{- a{char
[^p{Punct}p{Space}]+- 1 or more repetitons (+) of any char that does not belong to thep{Punct}(punctuation) orp{Space}(whitespace) class.
}- a}.
Note that if the contents between the braces can only include ASCII letters or digits (in regex, [A-Za-z0-9]+), you may even use a mere
{[A-Za-z0-9]+}
answered Nov 8 '18 at 9:15
Wiktor Stribiżew
309k16126202
answered Nov 8 '18 at 9:15
Wiktor Stribiżew
309k16126202
answered Nov 8 '18 at 9:15
Wiktor Stribiżew
309k16126202
answered Nov 8 '18 at 9:15
Wiktor Stribiżew
309k16126202
309k16126202
1
yep, the last regex works too
– Skullper
Nov 8 '18 at 9:18
add a comment |
1
yep, the last regex works too
– Skullper
Nov 8 '18 at 9:18
1
1
yep, the last regex works too
– Skullper
Nov 8 '18 at 9:18
yep, the last regex works too
– Skullper
Nov 8 '18 at 9:18
add a comment |
Disassembling your regex... the reason why it only accepts an even number in between is the following part:
([^p{Space}][^p{Punct}])+
This basically means: something which isn't a space, exactly 1 character and something which isn't a ~punct, exactly 1 character and this several times... so exactly 1 + exactly another 1 are exactly 2 characters... and this several times will always be even.
So what you probably rather want is the following:
[^p{Space}p{Punct}]+
for the part shown above... which will result in the following for your complete regex:
{[^p{Space}p{Punct}]+}
that of course can be simplified even more. I leave that up to you.
answered Nov 8 '18 at 9:14
Roland
9,43711141
add a comment |
Disassembling your regex... the reason why it only accepts an even number in between is the following part:
([^p{Space}][^p{Punct}])+
This basically means: something which isn't a space, exactly 1 character and something which isn't a ~punct, exactly 1 character and this several times... so exactly 1 + exactly another 1 are exactly 2 characters... and this several times will always be even.
So what you probably rather want is the following:
[^p{Space}p{Punct}]+
for the part shown above... which will result in the following for your complete regex:
{[^p{Space}p{Punct}]+}
that of course can be simplified even more. I leave that up to you.
answered Nov 8 '18 at 9:14
Roland
9,43711141
add a comment |
Disassembling your regex... the reason why it only accepts an even number in between is the following part:
([^p{Space}][^p{Punct}])+
This basically means: something which isn't a space, exactly 1 character and something which isn't a ~punct, exactly 1 character and this several times... so exactly 1 + exactly another 1 are exactly 2 characters... and this several times will always be even.
So what you probably rather want is the following:
[^p{Space}p{Punct}]+
for the part shown above... which will result in the following for your complete regex:
{[^p{Space}p{Punct}]+}
that of course can be simplified even more. I leave that up to you.
answered Nov 8 '18 at 9:14
Roland
9,43711141
Disassembling your regex... the reason why it only accepts an even number in between is the following part:
([^p{Space}][^p{Punct}])+
This basically means: something which isn't a space, exactly 1 character and something which isn't a ~punct, exactly 1 character and this several times... so exactly 1 + exactly another 1 are exactly 2 characters... and this several times will always be even.
So what you probably rather want is the following:
[^p{Space}p{Punct}]+
for the part shown above... which will result in the following for your complete regex:
{[^p{Space}p{Punct}]+}
that of course can be simplified even more. I leave that up to you.
answered Nov 8 '18 at 9:14
Roland
9,43711141
answered Nov 8 '18 at 9:14
Roland
9,43711141
answered Nov 8 '18 at 9:14
Roland
9,43711141
answered Nov 8 '18 at 9:14
Roland
9,43711141
9,43711141
add a comment |
add a comment |
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What are the pattern requirements? What are you trying to match? Currently, it matches a
{, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a}, hence you cannot use 1 char in between{...}– Wiktor Stribiżew
Nov 8 '18 at 9:08
When you are trying to replace + then how even or odd numbers are coming into the picture?
– Ümañg ßürmån
Nov 8 '18 at 9:09
@WiktorStribiżew I'm trying to block user from entering such string: {%F ,2}. And allow only to type: {Ffrgr2443fdfd}
– Skullper
Nov 8 '18 at 9:09
Try
{[^p{Punct}p{Space}]+}or{[^p{P}p{S}s]+}or even{p{Alnum}+}or{[A-Za-z0-9]+}– Wiktor Stribiżew
Nov 8 '18 at 9:11
@WiktorStribiżew You're awesome. First and second regex working. Thank you!
– Skullper
Nov 8 '18 at 9:14