How to acces data from a database and return it as an array?











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I'm new to Javascript and I have to solve a task for my Homework.
I have to get specific data (album titles and the album IDs) from a Database in one class, return this Data to another class and format it with template literals there.



getAlbums: function (db) {
sql = `SELECT DISTINCT Title, AlbumId FROM albums`;
let title = , id = ;
db.all(sql, , (err, rows) => {
if (err) throw err;
rows.forEach((row)=>{
title.push(row.Title);
id.push(row.AlbumId);
});
});
return [title, id];
}


this is the function where I get the data from the database. When I put a console.log(title) inside the db.all function, the titles array is filled correctly. But it does not return this array to the other class, I get an error:




TypeError: Cannot read property 'forEach' of undefined.




If I put a console.log(title) outside the db.all function, it returns an empty array and I don't get an error. The output is just undefined.



The method call in my other class:



showAlbum: function (db) {
let albumID = model.getAlbums(db);
//let album = "";
//let albId = "";

albumID.forEach((element) => {
//album = element.title;
//albId = element.id;
console.log(`Albumtitle: ${element.title} AlbumID: ${element.id}n`);
});
}


How can I transfer the arrays correctly?










share|improve this question




























    up vote
    0
    down vote

    favorite












    I'm new to Javascript and I have to solve a task for my Homework.
    I have to get specific data (album titles and the album IDs) from a Database in one class, return this Data to another class and format it with template literals there.



    getAlbums: function (db) {
    sql = `SELECT DISTINCT Title, AlbumId FROM albums`;
    let title = , id = ;
    db.all(sql, , (err, rows) => {
    if (err) throw err;
    rows.forEach((row)=>{
    title.push(row.Title);
    id.push(row.AlbumId);
    });
    });
    return [title, id];
    }


    this is the function where I get the data from the database. When I put a console.log(title) inside the db.all function, the titles array is filled correctly. But it does not return this array to the other class, I get an error:




    TypeError: Cannot read property 'forEach' of undefined.




    If I put a console.log(title) outside the db.all function, it returns an empty array and I don't get an error. The output is just undefined.



    The method call in my other class:



    showAlbum: function (db) {
    let albumID = model.getAlbums(db);
    //let album = "";
    //let albId = "";

    albumID.forEach((element) => {
    //album = element.title;
    //albId = element.id;
    console.log(`Albumtitle: ${element.title} AlbumID: ${element.id}n`);
    });
    }


    How can I transfer the arrays correctly?










    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I'm new to Javascript and I have to solve a task for my Homework.
      I have to get specific data (album titles and the album IDs) from a Database in one class, return this Data to another class and format it with template literals there.



      getAlbums: function (db) {
      sql = `SELECT DISTINCT Title, AlbumId FROM albums`;
      let title = , id = ;
      db.all(sql, , (err, rows) => {
      if (err) throw err;
      rows.forEach((row)=>{
      title.push(row.Title);
      id.push(row.AlbumId);
      });
      });
      return [title, id];
      }


      this is the function where I get the data from the database. When I put a console.log(title) inside the db.all function, the titles array is filled correctly. But it does not return this array to the other class, I get an error:




      TypeError: Cannot read property 'forEach' of undefined.




      If I put a console.log(title) outside the db.all function, it returns an empty array and I don't get an error. The output is just undefined.



      The method call in my other class:



      showAlbum: function (db) {
      let albumID = model.getAlbums(db);
      //let album = "";
      //let albId = "";

      albumID.forEach((element) => {
      //album = element.title;
      //albId = element.id;
      console.log(`Albumtitle: ${element.title} AlbumID: ${element.id}n`);
      });
      }


      How can I transfer the arrays correctly?










      share|improve this question















      I'm new to Javascript and I have to solve a task for my Homework.
      I have to get specific data (album titles and the album IDs) from a Database in one class, return this Data to another class and format it with template literals there.



      getAlbums: function (db) {
      sql = `SELECT DISTINCT Title, AlbumId FROM albums`;
      let title = , id = ;
      db.all(sql, , (err, rows) => {
      if (err) throw err;
      rows.forEach((row)=>{
      title.push(row.Title);
      id.push(row.AlbumId);
      });
      });
      return [title, id];
      }


      this is the function where I get the data from the database. When I put a console.log(title) inside the db.all function, the titles array is filled correctly. But it does not return this array to the other class, I get an error:




      TypeError: Cannot read property 'forEach' of undefined.




      If I put a console.log(title) outside the db.all function, it returns an empty array and I don't get an error. The output is just undefined.



      The method call in my other class:



      showAlbum: function (db) {
      let albumID = model.getAlbums(db);
      //let album = "";
      //let albId = "";

      albumID.forEach((element) => {
      //album = element.title;
      //albId = element.id;
      console.log(`Albumtitle: ${element.title} AlbumID: ${element.id}n`);
      });
      }


      How can I transfer the arrays correctly?







      javascript arrays foreach sqlite3






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 11 at 14:31

























      asked Nov 11 at 14:24









      anja-96

      13




      13
























          1 Answer
          1






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          up vote
          0
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          Try changing your JS code to the following.



          getAlbums: function (data) {
          sql = `SELECT DISTINCT Title, AlbumId FROM albums`;
          let title = , id = ;
          data.data.all(sql, , (err, rows) => {
          if (err) throw err;
          rows.forEach((row)=>{
          title.push(row.Title);
          id.push(row.AlbumId);
          });
          });
          return [title, id];
          }


          then



          showAlbum: function (data) {
          let albumID = model.getAlbums(data.data);
          //let album = "";
          //let albId = "";

          albumID.forEach((element) => {
          //album = element.title;
          //albId = element.id;
          console.log(`Albumtitle: ${element.title} AlbumID: ${element.id}n`);
          });
          }





          share|improve this answer























          • unfortunately, I now get the following Error: TypeError: Cannot read property 'all' of undefined
            – anja-96
            Nov 11 at 14:56












          • Change your db.all to data.db.all and check if it's working?
            – Yaseen Hussain
            Nov 11 at 14:58












          • Wherever you are using your db argument, try changing it to data.db
            – Yaseen Hussain
            Nov 11 at 15:00










          • Still the same, but now it is "TypeError: Cannot read property 'db' of undefined"
            – anja-96
            Nov 11 at 15:07










          • Please check the edited comment with update. Lemme know if it works.
            – Yaseen Hussain
            Nov 11 at 15:13











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          1 Answer
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          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          0
          down vote













          Try changing your JS code to the following.



          getAlbums: function (data) {
          sql = `SELECT DISTINCT Title, AlbumId FROM albums`;
          let title = , id = ;
          data.data.all(sql, , (err, rows) => {
          if (err) throw err;
          rows.forEach((row)=>{
          title.push(row.Title);
          id.push(row.AlbumId);
          });
          });
          return [title, id];
          }


          then



          showAlbum: function (data) {
          let albumID = model.getAlbums(data.data);
          //let album = "";
          //let albId = "";

          albumID.forEach((element) => {
          //album = element.title;
          //albId = element.id;
          console.log(`Albumtitle: ${element.title} AlbumID: ${element.id}n`);
          });
          }





          share|improve this answer























          • unfortunately, I now get the following Error: TypeError: Cannot read property 'all' of undefined
            – anja-96
            Nov 11 at 14:56












          • Change your db.all to data.db.all and check if it's working?
            – Yaseen Hussain
            Nov 11 at 14:58












          • Wherever you are using your db argument, try changing it to data.db
            – Yaseen Hussain
            Nov 11 at 15:00










          • Still the same, but now it is "TypeError: Cannot read property 'db' of undefined"
            – anja-96
            Nov 11 at 15:07










          • Please check the edited comment with update. Lemme know if it works.
            – Yaseen Hussain
            Nov 11 at 15:13















          up vote
          0
          down vote













          Try changing your JS code to the following.



          getAlbums: function (data) {
          sql = `SELECT DISTINCT Title, AlbumId FROM albums`;
          let title = , id = ;
          data.data.all(sql, , (err, rows) => {
          if (err) throw err;
          rows.forEach((row)=>{
          title.push(row.Title);
          id.push(row.AlbumId);
          });
          });
          return [title, id];
          }


          then



          showAlbum: function (data) {
          let albumID = model.getAlbums(data.data);
          //let album = "";
          //let albId = "";

          albumID.forEach((element) => {
          //album = element.title;
          //albId = element.id;
          console.log(`Albumtitle: ${element.title} AlbumID: ${element.id}n`);
          });
          }





          share|improve this answer























          • unfortunately, I now get the following Error: TypeError: Cannot read property 'all' of undefined
            – anja-96
            Nov 11 at 14:56












          • Change your db.all to data.db.all and check if it's working?
            – Yaseen Hussain
            Nov 11 at 14:58












          • Wherever you are using your db argument, try changing it to data.db
            – Yaseen Hussain
            Nov 11 at 15:00










          • Still the same, but now it is "TypeError: Cannot read property 'db' of undefined"
            – anja-96
            Nov 11 at 15:07










          • Please check the edited comment with update. Lemme know if it works.
            – Yaseen Hussain
            Nov 11 at 15:13













          up vote
          0
          down vote










          up vote
          0
          down vote









          Try changing your JS code to the following.



          getAlbums: function (data) {
          sql = `SELECT DISTINCT Title, AlbumId FROM albums`;
          let title = , id = ;
          data.data.all(sql, , (err, rows) => {
          if (err) throw err;
          rows.forEach((row)=>{
          title.push(row.Title);
          id.push(row.AlbumId);
          });
          });
          return [title, id];
          }


          then



          showAlbum: function (data) {
          let albumID = model.getAlbums(data.data);
          //let album = "";
          //let albId = "";

          albumID.forEach((element) => {
          //album = element.title;
          //albId = element.id;
          console.log(`Albumtitle: ${element.title} AlbumID: ${element.id}n`);
          });
          }





          share|improve this answer














          Try changing your JS code to the following.



          getAlbums: function (data) {
          sql = `SELECT DISTINCT Title, AlbumId FROM albums`;
          let title = , id = ;
          data.data.all(sql, , (err, rows) => {
          if (err) throw err;
          rows.forEach((row)=>{
          title.push(row.Title);
          id.push(row.AlbumId);
          });
          });
          return [title, id];
          }


          then



          showAlbum: function (data) {
          let albumID = model.getAlbums(data.data);
          //let album = "";
          //let albId = "";

          albumID.forEach((element) => {
          //album = element.title;
          //albId = element.id;
          console.log(`Albumtitle: ${element.title} AlbumID: ${element.id}n`);
          });
          }






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 11 at 15:13

























          answered Nov 11 at 14:50









          Yaseen Hussain

          114




          114












          • unfortunately, I now get the following Error: TypeError: Cannot read property 'all' of undefined
            – anja-96
            Nov 11 at 14:56












          • Change your db.all to data.db.all and check if it's working?
            – Yaseen Hussain
            Nov 11 at 14:58












          • Wherever you are using your db argument, try changing it to data.db
            – Yaseen Hussain
            Nov 11 at 15:00










          • Still the same, but now it is "TypeError: Cannot read property 'db' of undefined"
            – anja-96
            Nov 11 at 15:07










          • Please check the edited comment with update. Lemme know if it works.
            – Yaseen Hussain
            Nov 11 at 15:13


















          • unfortunately, I now get the following Error: TypeError: Cannot read property 'all' of undefined
            – anja-96
            Nov 11 at 14:56












          • Change your db.all to data.db.all and check if it's working?
            – Yaseen Hussain
            Nov 11 at 14:58












          • Wherever you are using your db argument, try changing it to data.db
            – Yaseen Hussain
            Nov 11 at 15:00










          • Still the same, but now it is "TypeError: Cannot read property 'db' of undefined"
            – anja-96
            Nov 11 at 15:07










          • Please check the edited comment with update. Lemme know if it works.
            – Yaseen Hussain
            Nov 11 at 15:13
















          unfortunately, I now get the following Error: TypeError: Cannot read property 'all' of undefined
          – anja-96
          Nov 11 at 14:56






          unfortunately, I now get the following Error: TypeError: Cannot read property 'all' of undefined
          – anja-96
          Nov 11 at 14:56














          Change your db.all to data.db.all and check if it's working?
          – Yaseen Hussain
          Nov 11 at 14:58






          Change your db.all to data.db.all and check if it's working?
          – Yaseen Hussain
          Nov 11 at 14:58














          Wherever you are using your db argument, try changing it to data.db
          – Yaseen Hussain
          Nov 11 at 15:00




          Wherever you are using your db argument, try changing it to data.db
          – Yaseen Hussain
          Nov 11 at 15:00












          Still the same, but now it is "TypeError: Cannot read property 'db' of undefined"
          – anja-96
          Nov 11 at 15:07




          Still the same, but now it is "TypeError: Cannot read property 'db' of undefined"
          – anja-96
          Nov 11 at 15:07












          Please check the edited comment with update. Lemme know if it works.
          – Yaseen Hussain
          Nov 11 at 15:13




          Please check the edited comment with update. Lemme know if it works.
          – Yaseen Hussain
          Nov 11 at 15:13


















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