Updating a Realtime Database object in Firebase iOS SDK












1















I have a database that looks like this:
enter image description here



I want to update let's say the second user, the one with uid 5p3XT8TVFbVYNmFt0Kbu1ticaUT2, and change its name to "James". Using the iOS SDK I can do:



let ref = Database.database().reference()
let id = 5p3XT8TVFbVYNmFt0Kbu1ticaUT2
let databaseQuery = ref.child("users").queryOrdered(byChild: "uid").queryEqual(toValue: id)


In order to query the database so it will filter out all users apart from the one I want to change. But this query will now point to a filtered list of users which contains only the user I want to update, not to the user itself. So if I try



databaseQuery.ref.updateChildValues(...)


The database will look like this:



enter image description here



I can't understand from the api reference how to get straight to the queried child. How do I do that?










share|improve this question























  • Possible duplicate of Update child values in Firebase with Swift

    – Rameez
    Nov 15 '18 at 5:44
















1















I have a database that looks like this:
enter image description here



I want to update let's say the second user, the one with uid 5p3XT8TVFbVYNmFt0Kbu1ticaUT2, and change its name to "James". Using the iOS SDK I can do:



let ref = Database.database().reference()
let id = 5p3XT8TVFbVYNmFt0Kbu1ticaUT2
let databaseQuery = ref.child("users").queryOrdered(byChild: "uid").queryEqual(toValue: id)


In order to query the database so it will filter out all users apart from the one I want to change. But this query will now point to a filtered list of users which contains only the user I want to update, not to the user itself. So if I try



databaseQuery.ref.updateChildValues(...)


The database will look like this:



enter image description here



I can't understand from the api reference how to get straight to the queried child. How do I do that?










share|improve this question























  • Possible duplicate of Update child values in Firebase with Swift

    – Rameez
    Nov 15 '18 at 5:44














1












1








1








I have a database that looks like this:
enter image description here



I want to update let's say the second user, the one with uid 5p3XT8TVFbVYNmFt0Kbu1ticaUT2, and change its name to "James". Using the iOS SDK I can do:



let ref = Database.database().reference()
let id = 5p3XT8TVFbVYNmFt0Kbu1ticaUT2
let databaseQuery = ref.child("users").queryOrdered(byChild: "uid").queryEqual(toValue: id)


In order to query the database so it will filter out all users apart from the one I want to change. But this query will now point to a filtered list of users which contains only the user I want to update, not to the user itself. So if I try



databaseQuery.ref.updateChildValues(...)


The database will look like this:



enter image description here



I can't understand from the api reference how to get straight to the queried child. How do I do that?










share|improve this question














I have a database that looks like this:
enter image description here



I want to update let's say the second user, the one with uid 5p3XT8TVFbVYNmFt0Kbu1ticaUT2, and change its name to "James". Using the iOS SDK I can do:



let ref = Database.database().reference()
let id = 5p3XT8TVFbVYNmFt0Kbu1ticaUT2
let databaseQuery = ref.child("users").queryOrdered(byChild: "uid").queryEqual(toValue: id)


In order to query the database so it will filter out all users apart from the one I want to change. But this query will now point to a filtered list of users which contains only the user I want to update, not to the user itself. So if I try



databaseQuery.ref.updateChildValues(...)


The database will look like this:



enter image description here



I can't understand from the api reference how to get straight to the queried child. How do I do that?







ios swift firebase firebase-realtime-database






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share|improve this question










asked Nov 13 '18 at 15:40









LiranTLiranT

313




313













  • Possible duplicate of Update child values in Firebase with Swift

    – Rameez
    Nov 15 '18 at 5:44



















  • Possible duplicate of Update child values in Firebase with Swift

    – Rameez
    Nov 15 '18 at 5:44

















Possible duplicate of Update child values in Firebase with Swift

– Rameez
Nov 15 '18 at 5:44





Possible duplicate of Update child values in Firebase with Swift

– Rameez
Nov 15 '18 at 5:44












1 Answer
1






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oldest

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0














You can set value to be changed in the values dictionary



func updateValues(){
let ref = Database.database().reference()
let id = 5p3XT8TVFbVYNmFt0Kbu1ticaUT2

let values = ["name": txf_Name.text ?? "", “email”: txf_email.text ?? "", “role”: txf_Role.text ?? ""]
ref.child(id).updateChildValues(values, withCompletionBlock: { (error, ref) in
if(error != nil){
print(error?.localizedDescription ?? "")
return
}
print("Values Updated")

})

}





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    1 Answer
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    You can set value to be changed in the values dictionary



    func updateValues(){
    let ref = Database.database().reference()
    let id = 5p3XT8TVFbVYNmFt0Kbu1ticaUT2

    let values = ["name": txf_Name.text ?? "", “email”: txf_email.text ?? "", “role”: txf_Role.text ?? ""]
    ref.child(id).updateChildValues(values, withCompletionBlock: { (error, ref) in
    if(error != nil){
    print(error?.localizedDescription ?? "")
    return
    }
    print("Values Updated")

    })

    }





    share|improve this answer




























      0














      You can set value to be changed in the values dictionary



      func updateValues(){
      let ref = Database.database().reference()
      let id = 5p3XT8TVFbVYNmFt0Kbu1ticaUT2

      let values = ["name": txf_Name.text ?? "", “email”: txf_email.text ?? "", “role”: txf_Role.text ?? ""]
      ref.child(id).updateChildValues(values, withCompletionBlock: { (error, ref) in
      if(error != nil){
      print(error?.localizedDescription ?? "")
      return
      }
      print("Values Updated")

      })

      }





      share|improve this answer


























        0












        0








        0







        You can set value to be changed in the values dictionary



        func updateValues(){
        let ref = Database.database().reference()
        let id = 5p3XT8TVFbVYNmFt0Kbu1ticaUT2

        let values = ["name": txf_Name.text ?? "", “email”: txf_email.text ?? "", “role”: txf_Role.text ?? ""]
        ref.child(id).updateChildValues(values, withCompletionBlock: { (error, ref) in
        if(error != nil){
        print(error?.localizedDescription ?? "")
        return
        }
        print("Values Updated")

        })

        }





        share|improve this answer













        You can set value to be changed in the values dictionary



        func updateValues(){
        let ref = Database.database().reference()
        let id = 5p3XT8TVFbVYNmFt0Kbu1ticaUT2

        let values = ["name": txf_Name.text ?? "", “email”: txf_email.text ?? "", “role”: txf_Role.text ?? ""]
        ref.child(id).updateChildValues(values, withCompletionBlock: { (error, ref) in
        if(error != nil){
        print(error?.localizedDescription ?? "")
        return
        }
        print("Values Updated")

        })

        }






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 '18 at 5:35









        Yogesh TandelYogesh Tandel

        664811




        664811






























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