How can I query by sort key in AWS DynamoDB?
I have a database of users, and I'd like to return all users with the last name X. I currently have "last" as the sort key for my table. I'm running the following code, but getting a "Query condition missed key schema element" error.
var params = { TableName: 'Patients',
KeyConditionExpression: '#id = :idNum',
ExpressionAttributeNames: {
'#id': 'last'
},
ExpressionAttributeValues: {
':idNum': 'Test'
}
};
docClient.query(params, function(err, data) {
if (err) {
console.error("Unable to query. Error:", JSON.stringify(err, null, 2));
} else {
console.log("Query succeeded.");
res.json(data);
}
});
javascript node.js amazon-web-services amazon-dynamodb dynamodb-queries
asked Nov 11 at 22:55
Joe Smith
94
add a comment |
I have a database of users, and I'd like to return all users with the last name X. I currently have "last" as the sort key for my table. I'm running the following code, but getting a "Query condition missed key schema element" error.
var params = { TableName: 'Patients',
KeyConditionExpression: '#id = :idNum',
ExpressionAttributeNames: {
'#id': 'last'
},
ExpressionAttributeValues: {
':idNum': 'Test'
}
};
docClient.query(params, function(err, data) {
if (err) {
console.error("Unable to query. Error:", JSON.stringify(err, null, 2));
} else {
console.log("Query succeeded.");
res.json(data);
}
});
javascript node.js amazon-web-services amazon-dynamodb dynamodb-queries
asked Nov 11 at 22:55
Joe Smith
94
add a comment |
I have a database of users, and I'd like to return all users with the last name X. I currently have "last" as the sort key for my table. I'm running the following code, but getting a "Query condition missed key schema element" error.
var params = { TableName: 'Patients',
KeyConditionExpression: '#id = :idNum',
ExpressionAttributeNames: {
'#id': 'last'
},
ExpressionAttributeValues: {
':idNum': 'Test'
}
};
docClient.query(params, function(err, data) {
if (err) {
console.error("Unable to query. Error:", JSON.stringify(err, null, 2));
} else {
console.log("Query succeeded.");
res.json(data);
}
});
javascript node.js amazon-web-services amazon-dynamodb dynamodb-queries
asked Nov 11 at 22:55
Joe Smith
94
I have a database of users, and I'd like to return all users with the last name X. I currently have "last" as the sort key for my table. I'm running the following code, but getting a "Query condition missed key schema element" error.
var params = { TableName: 'Patients',
KeyConditionExpression: '#id = :idNum',
ExpressionAttributeNames: {
'#id': 'last'
},
ExpressionAttributeValues: {
':idNum': 'Test'
}
};
docClient.query(params, function(err, data) {
if (err) {
console.error("Unable to query. Error:", JSON.stringify(err, null, 2));
} else {
console.log("Query succeeded.");
res.json(data);
}
});
javascript node.js amazon-web-services amazon-dynamodb dynamodb-queries
javascript node.js amazon-web-services amazon-dynamodb dynamodb-queries
asked Nov 11 at 22:55
Joe Smith
94
asked Nov 11 at 22:55
Joe Smith
94
asked Nov 11 at 22:55
Joe Smith
94
asked Nov 11 at 22:55
Joe Smith
94
asked Nov 11 at 22:55
Joe Smith
94
94
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
To query you must provide a partition key, so with your table, as it is, your only option would be to do a Scan (which is expensive and almost never recommended).
However you can easily add Global Secondary Indexes to allow you to use another key as your partition.
In this case you can add a GSI with last as your partition key.
Then you would be able to Query the global secondary index (note the IndexName parameter) by last name.
If you want to go the scan route, however, you'll need to use:
docClient.scan({
TableName: 'Patients',
FilterExpression: '#l = :l',
ExpressionAttributeNames: { '#l': 'last' },
ExpressionAttributeValues: { ':l': 'Test' },
Limit: 1
}, (err, data) => { /* callback */ })
Just remember that using scans can get expensive and put a strain on your table quickly (more detail here)
answered Nov 12 at 9:08
thomasmichaelwallace
2,5251817
Thanks for the response! If I decided to go the route of doing a scan instead, how would I modify my code?
– Joe Smith
Nov 12 at 19:01
No worries- I've added an example- although you really should avoid frequent scans on a dynamo db table if you possibly can.
– thomasmichaelwallace
Nov 13 at 8:24
Awesome, thank you. I'll take a look at the global index option as well.
– Joe Smith
Nov 14 at 1:51
Good luck! Don't forget to mark the question answered!
– thomasmichaelwallace
Nov 14 at 7:25
1
FYI, a GSI does not require the primary key to be unique, so you don't need to provide a sort key for a GSI. (Though it never hurts to add one.) docs.aws.amazon.com/amazondynamodb/latest/developerguide/…
– Matthew Pope
Nov 26 at 0:11
|
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votes
To query you must provide a partition key, so with your table, as it is, your only option would be to do a Scan (which is expensive and almost never recommended).
However you can easily add Global Secondary Indexes to allow you to use another key as your partition.
In this case you can add a GSI with last as your partition key.
Then you would be able to Query the global secondary index (note the IndexName parameter) by last name.
If you want to go the scan route, however, you'll need to use:
docClient.scan({
TableName: 'Patients',
FilterExpression: '#l = :l',
ExpressionAttributeNames: { '#l': 'last' },
ExpressionAttributeValues: { ':l': 'Test' },
Limit: 1
}, (err, data) => { /* callback */ })
Just remember that using scans can get expensive and put a strain on your table quickly (more detail here)
answered Nov 12 at 9:08
thomasmichaelwallace
2,5251817
Thanks for the response! If I decided to go the route of doing a scan instead, how would I modify my code?
– Joe Smith
Nov 12 at 19:01
No worries- I've added an example- although you really should avoid frequent scans on a dynamo db table if you possibly can.
– thomasmichaelwallace
Nov 13 at 8:24
Awesome, thank you. I'll take a look at the global index option as well.
– Joe Smith
Nov 14 at 1:51
Good luck! Don't forget to mark the question answered!
– thomasmichaelwallace
Nov 14 at 7:25
1
FYI, a GSI does not require the primary key to be unique, so you don't need to provide a sort key for a GSI. (Though it never hurts to add one.) docs.aws.amazon.com/amazondynamodb/latest/developerguide/…
– Matthew Pope
Nov 26 at 0:11
|
show 1 more comment
To query you must provide a partition key, so with your table, as it is, your only option would be to do a Scan (which is expensive and almost never recommended).
However you can easily add Global Secondary Indexes to allow you to use another key as your partition.
In this case you can add a GSI with last as your partition key.
Then you would be able to Query the global secondary index (note the IndexName parameter) by last name.
If you want to go the scan route, however, you'll need to use:
docClient.scan({
TableName: 'Patients',
FilterExpression: '#l = :l',
ExpressionAttributeNames: { '#l': 'last' },
ExpressionAttributeValues: { ':l': 'Test' },
Limit: 1
}, (err, data) => { /* callback */ })
Just remember that using scans can get expensive and put a strain on your table quickly (more detail here)
answered Nov 12 at 9:08
thomasmichaelwallace
2,5251817
Thanks for the response! If I decided to go the route of doing a scan instead, how would I modify my code?
– Joe Smith
Nov 12 at 19:01
No worries- I've added an example- although you really should avoid frequent scans on a dynamo db table if you possibly can.
– thomasmichaelwallace
Nov 13 at 8:24
Awesome, thank you. I'll take a look at the global index option as well.
– Joe Smith
Nov 14 at 1:51
Good luck! Don't forget to mark the question answered!
– thomasmichaelwallace
Nov 14 at 7:25
1
FYI, a GSI does not require the primary key to be unique, so you don't need to provide a sort key for a GSI. (Though it never hurts to add one.) docs.aws.amazon.com/amazondynamodb/latest/developerguide/…
– Matthew Pope
Nov 26 at 0:11
|
show 1 more comment
To query you must provide a partition key, so with your table, as it is, your only option would be to do a Scan (which is expensive and almost never recommended).
However you can easily add Global Secondary Indexes to allow you to use another key as your partition.
In this case you can add a GSI with last as your partition key.
Then you would be able to Query the global secondary index (note the IndexName parameter) by last name.
If you want to go the scan route, however, you'll need to use:
docClient.scan({
TableName: 'Patients',
FilterExpression: '#l = :l',
ExpressionAttributeNames: { '#l': 'last' },
ExpressionAttributeValues: { ':l': 'Test' },
Limit: 1
}, (err, data) => { /* callback */ })
Just remember that using scans can get expensive and put a strain on your table quickly (more detail here)
answered Nov 12 at 9:08
thomasmichaelwallace
2,5251817
To query you must provide a partition key, so with your table, as it is, your only option would be to do a Scan (which is expensive and almost never recommended).
However you can easily add Global Secondary Indexes to allow you to use another key as your partition.
In this case you can add a GSI with last as your partition key.
Then you would be able to Query the global secondary index (note the IndexName parameter) by last name.
If you want to go the scan route, however, you'll need to use:
docClient.scan({
TableName: 'Patients',
FilterExpression: '#l = :l',
ExpressionAttributeNames: { '#l': 'last' },
ExpressionAttributeValues: { ':l': 'Test' },
Limit: 1
}, (err, data) => { /* callback */ })
Just remember that using scans can get expensive and put a strain on your table quickly (more detail here)
answered Nov 12 at 9:08
thomasmichaelwallace
2,5251817
edited Nov 26 at 9:21
answered Nov 12 at 9:08
thomasmichaelwallace
2,5251817
answered Nov 12 at 9:08
thomasmichaelwallace
2,5251817
answered Nov 12 at 9:08
thomasmichaelwallace
2,5251817
2,5251817
Thanks for the response! If I decided to go the route of doing a scan instead, how would I modify my code?
– Joe Smith
Nov 12 at 19:01
No worries- I've added an example- although you really should avoid frequent scans on a dynamo db table if you possibly can.
– thomasmichaelwallace
Nov 13 at 8:24
Awesome, thank you. I'll take a look at the global index option as well.
– Joe Smith
Nov 14 at 1:51
Good luck! Don't forget to mark the question answered!
– thomasmichaelwallace
Nov 14 at 7:25
1
FYI, a GSI does not require the primary key to be unique, so you don't need to provide a sort key for a GSI. (Though it never hurts to add one.) docs.aws.amazon.com/amazondynamodb/latest/developerguide/…
– Matthew Pope
Nov 26 at 0:11
|
show 1 more comment
Thanks for the response! If I decided to go the route of doing a scan instead, how would I modify my code?
– Joe Smith
Nov 12 at 19:01
No worries- I've added an example- although you really should avoid frequent scans on a dynamo db table if you possibly can.
– thomasmichaelwallace
Nov 13 at 8:24
Awesome, thank you. I'll take a look at the global index option as well.
– Joe Smith
Nov 14 at 1:51
Good luck! Don't forget to mark the question answered!
– thomasmichaelwallace
Nov 14 at 7:25
1
FYI, a GSI does not require the primary key to be unique, so you don't need to provide a sort key for a GSI. (Though it never hurts to add one.) docs.aws.amazon.com/amazondynamodb/latest/developerguide/…
– Matthew Pope
Nov 26 at 0:11
Thanks for the response! If I decided to go the route of doing a scan instead, how would I modify my code?
– Joe Smith
Nov 12 at 19:01
Thanks for the response! If I decided to go the route of doing a scan instead, how would I modify my code?
– Joe Smith
Nov 12 at 19:01
No worries- I've added an example- although you really should avoid frequent scans on a dynamo db table if you possibly can.
– thomasmichaelwallace
Nov 13 at 8:24
No worries- I've added an example- although you really should avoid frequent scans on a dynamo db table if you possibly can.
– thomasmichaelwallace
Nov 13 at 8:24
Awesome, thank you. I'll take a look at the global index option as well.
– Joe Smith
Nov 14 at 1:51
Awesome, thank you. I'll take a look at the global index option as well.
– Joe Smith
Nov 14 at 1:51
Good luck! Don't forget to mark the question answered!
– thomasmichaelwallace
Nov 14 at 7:25
Good luck! Don't forget to mark the question answered!
– thomasmichaelwallace
Nov 14 at 7:25
1
1
FYI, a GSI does not require the primary key to be unique, so you don't need to provide a sort key for a GSI. (Though it never hurts to add one.) docs.aws.amazon.com/amazondynamodb/latest/developerguide/…
– Matthew Pope
Nov 26 at 0:11
FYI, a GSI does not require the primary key to be unique, so you don't need to provide a sort key for a GSI. (Though it never hurts to add one.) docs.aws.amazon.com/amazondynamodb/latest/developerguide/…
– Matthew Pope
Nov 26 at 0:11
|
show 1 more comment
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